I have a variable varchar that always takes in 10 digits. How can I use the LIKE operator to find/use only the first 5 digits of the variable?
my query:
variable IN VARCHAR2
SELECT * FROM items WHERE name LIKE SUBSTRING(variable, 1, 5)
... WHERE name LIKE '12345%'
will match any string that starts 12345. the '%' is a wildcard. You can also use the wildcard to match anywhere in the string: ... WHERE name LIKE '%12345%' will match a string with 12345 anywhere within it.
Edit for completeness: WHERE name LIKE '%12345' will match any string that ends with those five characters.
Try this:
SELECT * FROM items WHERE name LIKE (SUBSTRING(variable, 1, 5) + '%')
I guess you can use LEFT() like this:
SELECT * FROM items WHERE LEFT(name,5)=LEFT(variable,5);
Or if you you want to use LIKE with a wildcard, you can do this:
SELECT * FROM items WHERE name LIKE CONCAT(LEFT(variable,5),'%')
A few more example in the Demo fiddle
Edit: The above solution is for MySQL/MariaDB because earlier the tag of this question have MySQL but it's also my fault for not recognizing OP description of the datatype VARCHAR2. I might as well just post a suggestion related to the rdbms.
So, my first suggestion there using LEFT() however Oracle don't have that function, therefore:
SELECT * FROM items WHERE SUBSTR(name,1,5)=SUBSTR(variable,1,5);
or using concatenation operator
SELECT * FROM items WHERE name LIKE SUBSTR(variable,1,5)||'%'
Demo fiddle
Related
IN SQL can you use the like operator to see if the first 2 letters of a value match the last 2 letters in another value ?
If a have attribute year and attribute phone number , i want to select these rows
which match the description above eg: year(1996) and phone number(9655771243);
No, at least not in a reasonable way. Most SQL engines support left() and right(), so you can do:
where right(year, 2) = left(phone_number, 2)
Databases that don't have other substring functions that do the same thing.
Using like, it would be something like:
where phone_number like right(year, 2) || '%'
I tryed some wildcards in Access in Where statement, but they don't works. For example:
This query SELECT staff.* FROM staff;returns:
I tryed to do a query with wildcard SELECT staff.* FROM staff WHERE (staff.s_name LIKE "A%");
but it returns an empty table:
What is the reason? My wildcard doesn't work
(s_name is the second column)
(look that "firstname" is the tag of "s_name" only for the view)
Wildcard character in Access is *, not % unlike in SQL Server.
See MSDN for details.
No, no, no, use '*', not '%'. Or, use 'Like'.
http://www.techrepublic.com/article/10-tips-for-using-wildcard-characters-in-microsoft-access-criteria-expressions/
https://www.techonthenet.com/access/queries/like.php
https://www.techonthenet.com/access/queries/like2007.php
For instance:
Like 'm*'
Result: all values that start with m
Like 'm'
Result: all values that contain m
Like '*m'
Result: all values that end with m
I had a table like bellow image. I want 2,3 letters from the column "name"
The result is like bc,da,bc,bc,bc,bc
SELECT SUBSTRING(name,2,2) AS ShortComp FROM table;
You can also use the string function LEFT() to return the leftmost specified number of characters, like this:
SELECT LEFT(name, 2) AS ShortComp FROM table;
I want to get only those rows that contain ONLY certain characters in a column.
Let's say the column name is DATA.
I want to get all rows where in DATA are ONLY (must have all three conditions!):
Numeric characters (1 2 3 4 5 6 7 8 9 0)
Dash (-)
Comma (,)
For instance:
Value "10,20,20-30,30" IS OK
Value "10,20A,20-30,30Z" IS NOT OK
Value "30" IS NOT OK
Value "AAAA" IS NOT OK
Value "30-" IS NOT OK
Value "30," IS NOT OK
Value "-," IS NOT OK
Try patindex:
select * from(
select '10,20,20-30,30' txt union
select '10,20,20-30,40' txt union
select '10,20A,20-30,30Z' txt
)x
where patindex('%[^0-9,-]%', txt)=0
For you table, try like:
select
DATA
from
YourTable
where
patindex('%[^0-9,-]%', DATA)=0
As per your new edited question, the query should be like:
select
DATA
from
YourTable
where
PATINDEX('%[^0-9,-]%', DATA)=0 and
PATINDEX('%[0-9]%', LEFT(DATA, 1))=1 and
PATINDEX('%[0-9]%', RIGHT(DATA, 1))=1 and
PATINDEX('%[,-][-,]%', DATA)=0
Edit: Your question was edited, so this answer is no longer correct. I won't bother updating it since someone else already has updated theirs. This answer does not fulfil the condition that all three character types must be found.
You can use a LIKE expression for this, although it's slightly convoluted:
where data not like '%[^0123456789,!-]%' escape '!'
Explanation:
[^...] matches any character that is not in the ... part. % matches any number (including zero) of any character. So [^0123456789-,] is the set of characters that you want to disallow.
However: - is a special character inside of [], so we must escape it, which we do by using an escape character, and I've chosen !.
So, you match rows that do not contain (not like) any character that is not in your disallowed set.
Use option with PATINDEX and LIKE logic operator
SELECT *
FROM dbo.test70
WHERE PATINDEX('%[A-Z]%', DATA) = 0
AND PATINDEX('%[0-9]%', DATA) > 0
AND DATA LIKE '%-%'
AND DATA LIKE '%,%'
Demo on SQLFiddle
As already mentioned u can use a LIKE expression but it will only work with some minor modifications, otherwise too many rows will be filtered out.
SELECT * FROM X WHERE T NOT LIKE '%[^0-9!-,]%' ESCAPE '!'
see working example here:
http://sqlfiddle.com/#!3/474f5/6
edit:
to meet all 3 conditions:
SELECT *
FROM X
WHERE T LIKE '%[0-9]%'
AND T LIKE '%-%'
AND T LIKE '%,%'
see: http://sqlfiddle.com/#!3/86328/1
Maybe not the most beautiful but a working solution.
I would like to select all records that have an underscore character in their 11th character,
so i try this:
SELECT * FROM "BOM_SUB_LEVEL" where TOP_CODE like '%%%%%%%%%%_%%%'
but this doesnt work as expected, can someone help?
Just use the "SUBSTRING" function :
SELECT * FROM "BOM_SUB_LEVEL" where SUBSTRING(TOP_CODE, 11, 1) = "_"
Marc
For a single character wildcard use _. For multiple characters wildcards, use %. To escape a "real" appearance of _, use \_ (thanks Bill!).
Try the following code:
SELECT * FROM "BOM_SUB_LEVEL" where TOP_CODE like '___________\_%'
To further elaborate following Dav's comment, note that '%%%' is exactly the same as '%', since by definition '%' covers multiple characters.
pervasive uses _ to match any single character and \_ to actually match an underscore.
so the select would be:
SELECT * FROM "BOM_SUB_LEVEL" where TOP_CODE like '___________\_%'
LIKE % can mean any number of characters, use LIKE _ to mean just one. Since you're looking for an underscore, you need to escape it with !.
SELECT * FROM BOM_SUB_LEVEL WHERE TOP_CODE LIKE '__________!_%'
The % is not a per character wildcard, its a beginning and end of string wild card.
i.e. if I want to find all rows that have "car" in them, I would do this:
Select * from myTable where myCol LIKE '%car%'
If I wanted just the rows that STARTED with car:
Select * from myTable where myCol LIKE 'car%'
and ended with car:
Select * from myTable where myCol LIKE '%car'
% is a wildcard and can replace an character, or combination of characters. Use ? instead which replaces a single character.
You can try something like: (play with the numbers, I don't have pervasive to test with)
SELECT *
FROM BOM_SUB_LEVEL
where SUBSTRING(TOP_CODE, 11,1) = '-'