Oracle SQL get First Business Day date of given date - sql

Question

How can i get the date of the first business day of a given date .
For example:
01-AUG-21 is Sunday, so the first business day is 02-AUG-21 .

Answer 1

You can use a simple case statement in SQL or PL/SQL. In the example below, just replace SYSDATE + LEVEL with the date you would like to use.
SELECT SYSDATE + LEVEL AS some_date,
TO_CHAR (SYSDATE + LEVEL, 'DY') AS some_day_of_week,
SYSDATE
+ LEVEL
+ CASE TO_CHAR (SYSDATE + LEVEL, 'DY') WHEN 'SAT' THEN 2 WHEN 'SUN' THEN 1 ELSE 0 END AS business_day
FROM DUAL
CONNECT BY LEVEL <= 14;
SOME_DATE SOME_DAY_OF_WEEK BUSINESS_DAY
____________ ___________________ ________________
02-JUL-21 FRI 02-JUL-21
03-JUL-21 SAT 05-JUL-21
04-JUL-21 SUN 05-JUL-21
05-JUL-21 MON 05-JUL-21
06-JUL-21 TUE 06-JUL-21
07-JUL-21 WED 07-JUL-21
08-JUL-21 THU 08-JUL-21
09-JUL-21 FRI 09-JUL-21
10-JUL-21 SAT 12-JUL-21
11-JUL-21 SUN 12-JUL-21
12-JUL-21 MON 12-JUL-21
13-JUL-21 TUE 13-JUL-21
14-JUL-21 WED 14-JUL-21
15-JUL-21 THU 15-JUL-21
Here is a PL/SQL example of the same logic
DECLARE
FUNCTION get_business_day (p_date DATE)
RETURN DATE
IS
BEGIN
RETURN TRUNC (
p_date
+ CASE TO_CHAR (p_date, 'DY')
WHEN 'SAT' THEN 2
WHEN 'SUN' THEN 1
ELSE 0
END);
END;
BEGIN
DBMS_OUTPUT.put_line (get_business_day (p_date => SYSDATE));
END;
/

Answer 2

Here's one option: as it is only about 1 week, create a little one-week-calendar and fetch date which is larger than the one entered as a parameter, and which isn't a weekend.
with little_calendar as
(select to_date(:par_datum, 'dd.mm.yyyy') + level - 1 datum
from dual
connect by level <= 7
)
select min(datum)
from little_calendar
where datum > to_date(:par_datum, 'dd.mm.yyyy')
and to_char(datum, 'dy', 'nls_date_language = english')
not in ('sat', 'sun');
A few examples in SQL*Plus:
SQL> with little_calendar as
2 (select to_date('&&par_datum', 'dd.mm.yyyy') + level - 1 datum
3 from dual
4 connect by level <= 7
5 )
6 select min(datum)
7 from little_calendar
8 where datum > to_date('&&par_datum', 'dd.mm.yyyy')
9 and to_char(datum, 'dy', 'nls_date_language = english')
10 not in ('sat', 'sun');
Enter value for par_datum: 01.07.2021 --> the 1st working day after 01.07.2021 (Thursday) ...
MIN(DATUM)
---------------
02.07.2021, fri --> ... is 02.07.2021 (Friday)
SQL> undefine par_datum
SQL> /
Enter value for par_datum: 02.07.2021 --> working day that follows 02.07.2021 (Friday) ...
MIN(DATUM)
---------------
05.07.2021, mon --> ... is 05.07.2021 (Monday)
SQL>