I am doing just a simple conversion of timestamp column value to specific timezone and then getting the date out of it to create analytical charts based on the output of the query.
I am having the column of type timestamp in the bigquery and value for that column is in UTC. Now I need to convert that to PST (which is -8:00 GMT) and was looking straight forward to convert but I am seeing some dates up and down based on the output I get.
From the output that I was getting I took one abnormal output and wrote a query out of it as below:
select "2021-05-27 18:10:10" as timestampvalue ,
Date(Timestamp("2021-05-27 18:10:10" ,"-8:00")) as completed_date1,
Date(Timestamp("2021-05-27 18:10:10","America/Los_Angeles")) as completed_date2,
Date(TIMESTAMP_SUB("2021-05-27 18:10:10", INTERVAL 8 hour)) as completed_date3,
Date(Timestamp("2021-05-27 18:10:10","America/Tijuana")) as completed_date4
The output that I get is as below:
Based on my understanding I need to subtract 8 hours from the time in order to get the timestamp value for the timezone that I wanted and according to that completed_date3 column seems to show the correct value that should be there but if I use other timezone conversions as suggested in google documentation, the output gets changed to 2021-05-28 and I am not able to understand how that can happen.
Can anyone let me know what is the thing that I am doing wrong?
I was actually using it in a wrong way. I need to use it as below :
select "2021-05-27 18:10:10" as timestampvalue ,
Date(Timestamp("2021-05-27 18:10:10") ,"-8:00") as completed_date1,
Date(Timestamp("2021-05-27 18:10:10"),"America/Los_Angeles") as completed_date2,
Date(TIMESTAMP_SUB("2021-05-27 18:10:10", INTERVAL 8 hour)) as completed_date3,
Date(Timestamp("2021-05-27 18:10:10"),"America/Tijuana") as completed_date4
Initially I was converting that string timestamp to a specific timestamp based on the timezone and that is what I did not want.
Now if a convert a string to timestamp first without using time zone parameter and then apply timezone parameter when getting the date value out of it then it would return me correct date.
Please see the snapshot below :
Related
I am currently having a varchar tm column, that stores timestamps such as: '15.11.2021 11:07:27'
The datestyle is currently set to ISO,MDY
How can I transform that varchar using SELECT value in order to preserve its format?
If I use to_timestamp(tm, 'DD.MM.YYYY HH24:MI:SS')::timestamp without time zone I still get it in other format 2021-11-15 11:07:27
I also tried to do double to_timestamps, but then an error function to_timestamp(timestamp with time zone, unknown) does not exist appears.
So the question is: Is there any way to convert from varchar type "15.11.2021 11:07:27" to timestamp type 15.11.2021 11:07:27 using select statement?
DbFiddle
PS. Even though I used it in DBFiddle, I cant change datestyle on the target server
Postgres version 13.5
EDIT: also, if I use cast(tm as timestamp) I receive date/time field value out of range: "15.11.2021 11:07:27" error.
You could try using:
CONVERT(varchar, timestamp, 103) AS YOUR_VALUE
This way you would convert timestamp without changing its original form.
can anyone explain me the working of trunc(date) function in oracle.
my query is as below.
select trunc(tran_date) from tablename;
i have not passed any format type.
If i compare the date present in table without having trunc(date) it will not give any output.
and if compare date table with trunc(date) it will give me proper ouptut.
please explain how it is working.
and is there any replacement for trunc function as it is taking too much time.
trunc(tran_date) returns the date portion of the date column with no time component (which is midnight at the start of the day).
Despite its name, the date data type in Oracle includes the time. This is even more confusing because you sometimes do not see the time in the result set (depending on how you access the data).
The dates that you are comparing to have no time component. So, the comparison works with trunc(). But the time component on tran_date prevents the comparison from working without trunc().
I have a column in postgresql of type varchar that stores time in the format "ID:HH24:MI" and I would like to add/subtract time to it. For example, a value of "4:21:35" would translate to Thursday 9:35PM. If I wanted to add thirty minutes to it, I expect the string "4:22:05".
I tried the query below but it does not work because it returns the wrong day. I'm expecting 4:22:05 and it returns 6:22:05.
SELECT to_char(to_timestamp('4:21:35', 'ID:HH24:MI' ) + INTERVAL '30 minute', 'ID:HH24:MI');
6:22:05
How could I modify the query or change my approach to achieve the right output? I want to compare time strings in the format "ID:HH24:MI" and would like to be able to add/subtract time to those time strings. Any help would be greatly appreciated.
I can't understand how to convert this type of real - 42389.520752314813 to timestamp.
I got this data from one source, but I need to convert it to normal timestamp format.
I think you have received wrong input data.
this type of timestamp is only occurring when Destination tool is excel and which has CELL as "Number" type, and during Copy-Paste of timestamp, destination field has Calculated it as Mathematical function. Please re-verify your source. I am sure about this mathematical calculation. please check the below sample of such data. So practically you cannot perform its reverse operation.
Hard to do without knowing what timestamp should be returned.
If the date is sourced from a SQL Server it might be '2016-01-22 12:29:53':
cast( date '1900-01-01' + myCol as timestamp(3))
+ (cast(86400 * (myCol mod 1) as dec(12,6)) * interval '00:00:01.000000' hour to second)
If it's from Excel it's two days earlier and you must start at '1899-12-30'
I have rows with the following format and I would like to transform then into valid Hive timestamps. Format in my data:
28/04/2017 00:00:00|20550|22/05/2017 00:00:00|
I'm only interested in the first and third column, separated with |, in MY case the format is, then:
dd/MM/yy HH:mm:ss
I've discovered this can't be used as timestamp in Hive.
I find myself unable to transform all that first and third column to the proper format using queries similar to:
select from_unixtime(unix_timestamp('28/04/2017','dd/MM/yy HH:mm:ss'),'yyyy-MM-dd') from `20170428_f_pers_pers`
I'm trying different instances of that query but since I can't access the documentation (internet is capped here at work), I can't see how to properly use this two functions, from_unixtime and unix_timestamp
I've made the following assumptions:
I can reorder the days and years. If this isn't true, I have no idea how to transform my original data into proper Hive format
When I do this select, it affects the whole column. Further, after doing this with success I should be able to change the format of the whole column from string to timestamp (maybe I have to create a new column for that, not sure)
I do not care about doing both columns at once, but right now when I do the query showed first I get as many nulls as data has my table, and I'm unsure my assumptions are even partially right since every example I come accross is simpler (they do not change days and years arround, for instance).
I would like to know how to apply the query to a specific column, since I haven't understood how to do that from the examples studied so far. I do not see them using any type of column ID for that, which is weird to me, using data from the column to change the column itself.
Thanks in advance.
edit: I am now trying something like
select from_unixtime(unix_timestamp(f_Date, 'dd/MM/yyyy HH:mm:ss')) from `myTable`
But I get from HUE the following error:
Error while processing statement: FAILED: Execution Error, return code 2 from org.apache.hadoop.hive.ql.exec.mr.MapRedTask
The format should be completely covered by the input string.
In other words -
The format can be equal in length to the the input string or shorter, but not longer.
28/04/2017 00:00:00
|||||||||||||||||||
dd/MM/yyyy HH:mm:ss
select from_unixtime(to_unix_timestamp('28/04/2017 00:00:00', 'dd/MM/yyyy HH:mm:ss'))
2017-04-28 00:00:00
28/04/2017 00:00:00
||||||||||
dd/MM/yyyy
select from_unixtime(to_unix_timestamp('28/04/2017 00:00:00', 'dd/MM/yyyy'))
2017-04-28 00:00:00
The result can be converted from string to timestamp using cast
select cast (from_unixtime(to_unix_timestamp('28/04/2017 00:00:00', 'dd/MM/yyyy HH:mm:ss')) as timestamp)