Laravel where, orWhereHas and whereNotIn - sql

Hello great people of SO!
I hope you all have a good day and have a good health
Note: I'm not good at SQL
Sorry for bad english, but I will try my best to explain my issue
I'm using Laravel v8.x for my app, and after setting up model relationships, events, queues, etc, now I'm working for SQL
ATM, I have 2 Models,
User
Post
Relationships:
User hasMany Post
User belongsToMany User (Block)
User belongsToMany User (Follow)
Post belongsTo User
Database:
5 record for User
2 record for Block
3 records for Post
Table: (Using faker)
users
[
{ id: 1, name: 'Jonathan Beatrice', username: 'kiana.fay', ... },
{ id: 2, name: 'Lacey Kirlin', username: 'kenna.turner', ... },
{ id: 3, name: 'Alexander Schiller', username: 'cassandra95', ... },
{ id: 4, name: 'Daniel Wickozky', username: 'nkoepp', ... },
{ id: 5, name: 'Maymie Lehner', username: 'frami.felton', ... }
]
block
[
{ id: 1, by_id: 1, to_id: 2 }, // User #1 block user #2
{ id: 2, by_id: 4, to_id: 1 } // User #4 block user #1
]
posts
[
{ id: 1, user_id: 2, body: 'Test post', ... },
{ id: 2, user_id: 5, body: 'Lorem ipsum dolor sit amet ...', ... },
{ id: 3, user_id: 4, body: 'ABCD festival soon! ...', ... },
]
Everything works fine and smooth
Now that I want to implement search system, I have a problem, since I'm not good with SQL
Here's my code
SearchController.php
use ...;
use ...;
...
public function posts(Request $request)
{
// For testing purpose
$user = User::with(['userBlocks', 'blocksUser'])->find(1);
// Get all id of user that $user block
// return [2]
$user_blocks = $user->userBlocks->pluck('pivot')->pluck('to_id')->toArray();
// Get all id of user that block $user
// return [4]
$blocks_user = $user->blocksUser->pluck('pivot')->pluck('by_id')->toArray();
// Merge all ids above (must be unique())
// return [2, 4]
$blocks = array_merge($user_blocks, $blocks_user);
// .../search?q=xxx
$query = $request->query('q');
$sql = Post::query();
// Search for posts that has `posts`.`body` LIKE ? ($query)
$sql->where('body', 'LIKE', "%$query%");
// This is where I got confused
$sql->orWhereHas('user', function ($post_user) use ($blocks, $query) {
$post_user
->whereNotIn('id', $blocks) // Exclude posts that has user and their id not in (x, x, x, x, ... ; $block variable above)
->where('name', 'LIKE', "%$query%") // Find user that has name LIKE ? ($query)
->orWhere('username', 'LIKE', "%$query%"); // or Find user that has username LIKE ? ($query)
});
$sql->orderBy('created_at', 'DESC');
$sql->with(['user']);
$posts = $sql->simplePaginate(10, ['*'], 'p');
return $posts;
}
I run the code, .../search?q=e
Note:
All users has alphabet E in their names
And also all posts has alphabet E in their body
We (as User #1), block User #2, and User #4, block us (User #1)
Result: Controller returned all posts
This is the query when I use DB::enableQueryLog() and DB::getQueryLog()
SELECT
*
FROM
`posts`
WHERE `body` LIKE ?
AND EXISTS
(SELECT
*
FROM
`users`
WHERE `posts`.`user_id` = `users`.`id`
AND (
`id` NOT IN (?)
AND `username` LIKE ?
OR `name` LIKE ?
))
ORDER BY `created_at` ASC
LIMIT 11 OFFSET 0
Goal: Search all posts that has body LIKE ?, OR posts that has user; username LIKE ? or name LIKE ? (But also exclude the user we block and the user that block us
Thanks in advance
If there's any unclear explanation, I will edit it A.S.A.P

If I run on my recent laravel install, with my proposed change for one of your issues, version 7.19.1, I get this query:
SELECT
*
FROM
`posts`
WHERE `body` LIKE ?
OR EXISTS <- line of interest
(SELECT
*
FROM
`users`
WHERE `posts`.`user_id` = `users`.`id`
AND (
`id` NOT IN (?)
AND (`username` LIKE ?
OR `name` LIKE ?) <- extra brackets ive added
))
ORDER BY `created_at` ASC
LIMIT 11 OFFSET 0
Have a look at the line of interest, and compare it with the query your version of laravel is running. The AND EXISTS line is being incorrectly generated by laravel. OrWhereHas isnt behaving correctly in your version, I can't find the release number to see where it was fixed.
Id recommend upgrading to latest if possible, but thats not always an option. I've had a dig around, and it looks like the user in this question here encountered a similar problem:
WhereHas() / orWhereHas not constraining the query as expected
You can try moving your $sql->with(['user']); to before you OrWhereHas clause. I'm not sure if that will change it to OR, but its worth a try.
Second thing, I've added whereNested to your OR clause to ensure the precedence is correct, which adds the extra brackets in the query above, as in you dont want:
(`id` NOT IN (1, 2, 3)
AND `name` LIKE % test %)
OR `username` LIKE % test %
Since then it would include your blocked posts in the exists clause.
So final changes look like this, which I think fufills your description:
$sql->with(['user']); //deleted from original position and move here
$sql->where('body', 'LIKE', "%$query%")->whereNotIn('id', $blocks); //additional line
$sql->orWhereHas('ambience', function ($post_user) use ($blocks, $query) {
$post_user
->whereNotIn('id', $blocks);
$post_user->whereNested(function($post_user) use ($query) { //new bit
$post_user->where('name', 'LIKE', "%$query%")
->orWhere('username', 'LIKE', "%$query%");
});
});

Related

Get Empty Rows in TypeORM

I'm trying to write a typeORM query which includes multiple where clauses. I am able to achieve this via where option as follows:
const categories = [
{ name: 'master', categoryTypeId: 2, parentId: 1, locationId: null },
{ name: 'food', categoryTypeId: 3, parentId: null, locationId: null }];
const rows = await Repo.find({
where: categories.map((category) => ({
name: category.name,
categoryTypeId: category.categoryTypeId,
locationId: category.locationId
})),
});
I would want to maintain the mapping b/w the input array and the rows returned. For example, I know that the second category doesn't exist in the DB. I would want to have an empty object in the rows variable so that I know which categories didn't yield any result.
Upon research I have found that we can do something with SQL as mentioned here. But, I'm not sure how do I translate into typeORM if I can.

TypeORM relationquerybuilder of remove with Not(IsNull()) not removing anything

Good day everyone,
I ran into a strange problem with typeORM. I have a many-to-many relation on Offer with User named pending, which creates a table offer_pending_user that looks like:
userId
offerId
0
1
1
0
I basically want to completely clear this table. I tried to achieve this by using the RelationQueryBuilder like follows:
await Offer.createQueryBuilder()
.relation("pending")
.of({ id: Not(IsNull()) }) //offer id
.remove({ id: Not(IsNull()) }); //user id
For some reason. It does not clear the offer_pending_user table at all. The query that it is executing looks like:
DELETE FROM "offer_pending_user" WHERE ("offerId" = ? AND "userId" = ?) -- PARAMETERS:
[{
"_type":"not",
"_value": {
"_type":"isNull",
"_useParameter":false,
"_multipleParameters":false
},
"_useParameter":true,
"_multipleParameters":false
},{
"_type":"not",
"_value": {
"_type":"isNull",
"_useParameter":false,
"_multipleParameters":false
},
"_useParameter":true,
"_multipleParameters":false
}]
I would like to use this RelationQueryBuilder, and would like to know what I'm missing here.

FaunaDB: how to fetch a custom column

I'm just learning FaunaDB and FQL and having some trouble (mainly because I come from MySQL). I can successfully query a table (eg: users) and fetch a specific user. This user has a property users.expiry_date which is a faunadb Time() type.
What I would like to do is know if this date has expired by using the function LT(Now(), users.expiry_date), but I don't know how to create this query. Do I have to create an Index first?
So in short, just fetching one of the users documents gets me this:
{
id: 1,
username: 'test',
expiry_date: Time("2022-01-10T16:01:47.394Z")
}
But I would like to get this:
{
id: 1,
username: 'test',
expiry_date: Time("2022-01-10T16:01:47.394Z"),
has_expired: true,
}
I have this FQL query now (ignore oauthInfo):
Query(
Let(
{
oauthInfo: Select(['data'], Get(Ref(Collection('user_oauth_info'), refId))),
user: Select(['data'], Get(Select(['user_id'], Var('oauthInfo'))))
},
Merge({ oauthInfo: Var('oauthInfo') }, { user: Var('user') })
)
)
How would I do the equivalent of the mySQL query SELECT users.*, IF(users.expiry_date < NOW(), 1, 0) as is_expired FROM users in FQL?
Your use of Let and Merge show that you are thinking about FQL in a good way. These are functions that can go a long way to making your queries more organized and readable!
I will start with some notes, but they will be relevant to the final answer, so please stick with me.
The Query function
https://docs.fauna.com/fauna/current/api/fql/functions/query
First, you should not need to wrap anything in the Query function, here. Query is necessary for defining functions in FQL that will be run later, for example, in the User-Defined Function body. You will always see it as Query(Lambda(...)).
Fauna IDs
https://docs.fauna.com/fauna/current/learn/understanding/documents
Remember that Fauna assigns unique IDs for every Document for you. When I see fields named id, that is a bit of a red flag, so I want to highlight that. There are plenty of reasons that you might store some business-ID in a Document, but be sure that you need it.
Getting an ID
A Document in Fauna is shaped like:
{
ref: Ref(Collection("users"), "101"), // <-- "id" is 101
ts: 1641508095450000,
data: { /* ... */ }
}
In the JS driver you can use this id by using documentResult.ref.id (other drivers can do this in similar ways)
You can access the ID directly in FQL as well. You use the Select function.
Let(
{
user: Get(Select(['user_id'], Var('oauthInfo')))
id: Select(["ref", "id"], Var("user"))
},
Var("id")
)
More about the Select function.
https://docs.fauna.com/fauna/current/api/fql/functions/select
You are already using Select and that's the function you are looking for. It's what you use to grab any piece of an object or array.
Here's a contrived example that gets the zip code for the 3rd user in the Collection:
Let(
{
page: Paginate(Documents(Collection("user")),
},
Select(["data", 2, "data", "address", "zip"], Var("user"))
)
Bring it together
That said, your Let function is a great start. Let's break things down into smaller steps.
Let(
{
oauthInfo_ref: Ref(Collection('user_oauth_info'), refId)
oauthInfo_doc: Get(Var("oathInfoRef")),
// make sure that user_oath_info.user_id is a full Ref, not just a number
user_ref: Select(["data", "user_id"], Var("oauthInfo_doc"))
user_doc: Get(Var("user_ref")),
user_id: Select("id", Var("user_ref")),
// calculate expired
expiry_date: Select(["data", "expiry_date"], Var("user_doc")),
has_expired: LT(Now(), Var("expiry_date"))
},
// if the data does not overlap, Merge is not required.
// you can build plain objects in FQL
{
oauthInfo: Var("oauthInfo_doc"), // entire Document
user: Var("user_doc"), // entire Document
has_expired: Var("has_expired") // an extra field
}
)
Instead of returning the auth info and user as separate points if you do want to Merge them and/or add additional fields, then feel free to do that
// ...
Merge(
Select("data", Var("user_doc")), // just the data
{
user_id: Var("user_id"), // added field
has_expired: Var("has_expired") // added field
}
)
)

TypeORM activeRecord style query for "where (a & b) or (c & d)"?

I want to use TypeORM to run a query like
... WHERE (a=1 && b=true) OR (a=2 && b=false)
I see a bunch of references to doing this in the QueryBuilder style, but I need to know how to do this using the ActiveRecord style.
You can do this by providing an array of objects to the where: property:
Item.find({
where: [
{ user: { id: userId }, confirmed: "true" },
{ user: { id: userId }, status: "active" }
]
});
The query above would find items that belong to a user where
user matches user id AND is confirmed, or...
user matches user id AND is active
I do not know about TypeORM, however I found this on ruby on rail active query methods:
https://guides.rubyonrails.org/active_record_querying.html#conditions
raw code: ...where("orders_count = ? AND locked = ?", params[:orders], false)
Example Code: ...where(["(a= ? and b= ?) Or (a=? and b=?)", 1, true, 2, false])

how to use where condition in mongodb

I have a collection of mongodb, which contains "MoviesID, UserID, Rating", so this is to describe the how the users rate different movies, and a user can rate different movies, and certainly a movie can be rated by different users. Now I want to find all the users who rate similar movies with target user(For example : user 5). Rating similar movies means that they rate at least same movie, or more. So how should I find all the users who rate similar movie with user 5? I just start learning mongodb. Thanks!
Let's say you have a collection like this:
{
movie: 1,
user: 1,
rating: 5
}, {
movie: 2,
user: 5,
rating: 5
}, {
movie: 3,
user: 5,
rating: 3
}
What you can do here is to find all the movies that is rated by user 5, like this:
db.collection.distinct("movie", { user: 5 }, function(err, movies) {
// Will return array of distinct values for movies, where user is equal to 5.
// From our collection above, this query will return [ 2, 3 ].
})
then:
db.collection.find({ movie: { $in: movies } }, function(err, result) {
// Then we'll find the documents where movie is in the movies which
// returned on our first query.
// This will return [{ user: 5, ... }, { user: 1, ... }]
})
I can only think of doing this in two queries. I'm still thinking if this can be done by using aggregate.
I hope this helps.
To query data from MongoDB collection, you need to use MongoDB's find() method.
The basic syntax of find() method is as follows −
>db.COLLECTION_NAME.find()