BELOW IS SNIPPET OF MY DATA
Here is the sample creation code of testing.
CREATE TABLE MYGROUP ( Category,PERSON,Flag ) AS
SELECT 'Cat1','A','1' FROM DUAL
UNION ALL SELECT 'Cat1','A','0' FROM DUAL
UNION ALL SELECT 'Cat1','A','1' FROM DUAL
UNION ALL SELECT 'Cat1','B','1' FROM DUAL
UNION ALL SELECT 'Cat1','B','0' FROM DUAL
UNION ALL SELECT 'Cat2','A','0' FROM DUAL
UNION ALL SELECT 'Cat2','A','0' FROM DUAL
UNION ALL SELECT 'Cat2','A','0' FROM DUAL
UNION ALL SELECT 'Cat2','B','1' FROM DUAL
UNION ALL SELECT 'Cat2','B','1' FROM DUAL
UNION ALL SELECT 'Cat2','B','0' FROM DUAL
UNION ALL SELECT 'Cat3','X','0' FROM DUAL
UNION ALL SELECT 'Cat3','Y','0' FROM DUAL;
Desired Output:
Category - Count of Distinct Persons with Flag = 1
Cat1 - 2
Cat2 - 1
Cat3 - 0
I need to get my code in Big query to get distinct counts of persons. It shouldnt double count.
You can use conditional aggregation
SELECT
Category,
COUNT(DISTINCT CASE WHEN Flag = 1 THEN PERSON END)
FROM MYGROUP
GROUP BY Category;
Related
I know a little bit of sql, only the basic, now I need to create a analytic query but can't do this yet.
I have 2 tables on my db oracle, client and exams:
I am tried a lot of ways to get the mean of exams by client, but no success yet.4
The result expected is:
exams = 13
clients = 6
13/6= 2.166666666...7
How can I do that?
If you have clients who have not taken any exams then you want:
SELECT AVG(COUNT(e.nu_ordem)) AS avg_exames_by_client
FROM cliente c
LEFT OUTER JOIN exames e
ON (c.id = e.id_cliente)
GROUP BY c.id;
or:
SELECT (SELECT COUNT(*) FROM exames) / (SELECT COUNT(*) FROM cliente)
AS avg_exames_by_client
FROM DUAL;
Which, for the sample data:
CREATE TABLE cliente (id PRIMARY KEY) AS
SELECT 1 FROM DUAL UNION ALL
SELECT 2 FROM DUAL UNION ALL
SELECT 3 FROM DUAL UNION ALL
SELECT 4 FROM DUAL UNION ALL
SELECT 5 FROM DUAL UNION ALL
SELECT 6 FROM DUAL;
CREATE TABLE exames (nu_ordem PRIMARY KEY, id_cliente) AS
SELECT 1, 1 FROM DUAL UNION ALL
SELECT 2, 5 FROM DUAL UNION ALL
SELECT 3, 5 FROM DUAL UNION ALL
SELECT 4, 2 FROM DUAL UNION ALL
SELECT 5, 6 FROM DUAL UNION ALL
SELECT 6, 1 FROM DUAL UNION ALL
SELECT 7, 1 FROM DUAL UNION ALL
SELECT 8, 4 FROM DUAL UNION ALL
SELECT 9, 5 FROM DUAL UNION ALL
SELECT 10, 3 FROM DUAL UNION ALL
SELECT 11, 6 FROM DUAL UNION ALL
SELECT 12, 2 FROM DUAL UNION ALL
SELECT 13, 1 FROM DUAL;
Both output:
AVG_EXAMES_BY_CLIENT
2.166666666666666667
If you then add a couple of clients but no more exams:
INSERT INTO cliente (id)
SELECT 7 FROM DUAL UNION ALL
SELECT 8 FROM DUAL
Then the average is:
AVG_EXAMES_BY_CLIENT
1.625
db<>fiddle here
You can try below formula to get the result -
SELECT COUNT(*)/COUNT(DISTINCT id_cliente)
FROM exams;
Query:
SELECT teamid
FROM team
WHERE teamid NOT IN (SELECT team_teamid FROM gymnast);
Tables:
TEAM table
Gymnast table
I have been trying to figure this out for a while, any information would be greatly appreciated. Thank you!
The fiddle for oracle
val NOT IN (some list) means the value does NOT match every entry in the list.
But if one entry in the list is null, value <> null can never be true for that entry, which means the entire NOT IN expression can never be true.
See the following examples:
WITH team (teamid) AS (
SELECT 1 FROM DUAL UNION
SELECT 2 FROM DUAL UNION
SELECT 3 FROM DUAL UNION
SELECT 4 FROM DUAL
)
, gymnast (team_teamid) AS (
SELECT 1 FROM DUAL UNION
SELECT 2 FROM DUAL UNION
SELECT 2 FROM DUAL UNION
SELECT 4 FROM DUAL
)
SELECT teamid FROM team WHERE teamid NOT IN (SELECT team_teamid FROM gymnast)
;
Result:
TEAMID
3
Case 2 with nulls in the list:
WITH team (teamid) AS (
SELECT 1 FROM DUAL UNION
SELECT 2 FROM DUAL UNION
SELECT 3 FROM DUAL UNION
SELECT 4 FROM DUAL
)
, gymnast (team_teamid) AS (
SELECT 1 FROM DUAL UNION
SELECT 2 FROM DUAL UNION
SELECT null FROM DUAL UNION
SELECT 4 FROM DUAL
)
SELECT teamid FROM team WHERE teamid NOT IN (SELECT team_teamid FROM gymnast)
;
Result:
TEAMID
No rows in result, due to the gymnast with a null team_teamid.
I am a newbie in oracle. Trying to group columns based on a specific text and sum other columns.
let's say I have below tables
I want to group by all people with the last name. Like below
I have no clue how should I proceed.
Note: There could be multiple names but I just want to filter for Sharma, Decosta and Liver.
Updating the question.
Sorry for updating the question. but in a real scenario search string is not always at last.
Let me give you another example.
Output.
The queries offered so far does seem to work to get what you need. But the below does:
With inputs as
(
select 'Rahul Kumar Sharma' as Name, 10 as No_of_beer_bottles from dual union all
select 'Rohith Kumar Sharma' as Name, 5 as No_of_beer_bottles from dual union all
select 'Sharma' as Name, 20 as No_of_beer_bottles from dual union all
select 'Rahul Kumar Varma' as Name, 10 as No_of_beer_bottles from dual
)
select SUBSTR(name,Instr(name,' ',-1)+1) as Name, sum(No_of_beer_bottles) as No_of_beer_bottles
from inputs
group by SUBSTR(name,Instr(name,' ',-1)+1);
Output:
You can use regexp_substr():
select regexp_substr(name, '[^ ]+$') as last_name, sum(num_beers)
from t
group by regexp_substr(name, '[^ ]+$');
If you use have a table with all the words you are searching for (or define them in a Common Table Expression like I did below), you can join on that search term then sum the numeric column.
Query 1
WITH
search_words (word)
AS
(SELECT 'Sharma' FROM DUAL
UNION ALL
SELECT 'Decosta' FROM DUAL
UNION ALL
SELECT 'Liver' FROM DUAL),
d (name, num_beers)
AS
(SELECT 'Ravi Sharma', 1 FROM DUAL
UNION ALL
SELECT 'Sam Decosta', 4 FROM DUAL
UNION ALL
SELECT 'Jhony Liver', 5 FROM DUAL
UNION ALL
SELECT 'Ravi Sharma', 2 FROM DUAL
UNION ALL
SELECT 'Rohul Sharma', 3 FROM DUAL
UNION ALL
SELECT 'Jhon Decosta', 3 FROM DUAL
UNION ALL
SELECT 'V Decosta', 3 FROM DUAL)
SELECT sw.word, SUM (d.num_beers) AS total_beer
FROM search_words sw, d
WHERE INSTR (UPPER (d.name), UPPER (sw.word)) > 0
GROUP BY sw.word;
Result 1
WORD TOTAL_BEER
__________ _____________
Decosta 10
Sharma 6
Liver 5
Query 2
WITH
search_words (word)
AS
(SELECT 'Pen' FROM DUAL
UNION ALL
SELECT 'Dog' FROM DUAL),
d (name, quantity)
AS
(SELECT 'Ravi have red pens', 2 FROM DUAL
UNION ALL
SELECT 'Sam''s grifriend have black dogs', 4 FROM DUAL
UNION ALL
SELECT 'Jhony has blue pen', 1 FROM DUAL
UNION ALL
SELECT 'Ravi has white dog', 1 FROM DUAL
UNION ALL
SELECT 'Rahul has small dogs', 3 FROM DUAL
UNION ALL
SELECT 'There are pens inside Jhon''s car', 3 FROM DUAL
UNION ALL
SELECT 'My dog and me are flying.', 1 FROM DUAL)
SELECT sw.word, SUM (d.quantity) AS total_quantity
FROM search_words sw, d
WHERE INSTR (UPPER (d.name), UPPER (sw.word)) > 0
GROUP BY sw.word;
Result 2
WORD TOTAL_QUANTITY
_______ _________________
Dog 9
Pen 6
I can select a list of rows from a table. but I want to show them by swapping upside down.
Explaination:
with table1 as
(
select 1 ID, 'txt1' value from dual
union all
select 2, 'txt2' from dual
union all
select 7, 'txt7' from dual
union all
select 5, 'txt5' from dual
union all
select 3, 'txt3' from dual
)
select * from table1;
in above query I can obtain following result
ID | VALUE
------------------
1 txt1
2 txt2
7 txt7
5 txt5
3 txt3
but I want to show them as follows
ID | VALUE
------------------
3 txt3
5 txt5
7 txt7
2 txt2
1 txt1
How to do that?
One approach would be to add a computed column to your set of union queries, then order by that column:
WITH table1 AS (
SELECT 1 ID, 'txt1' value, 1 AS position FROM dual
UNION ALL
SELECT 2, 'txt2', 2 FROM dual
UNION ALL
SELECT 7, 'txt7', 3 FROM dual
UNION ALL
SELECT 5, 'txt5', 4 FROM dual
UNION ALL
SELECT 3, 'txt3', 5 FROM dual
)
SELECT *
FROM table1
ORDER BY pos DESC;
Note that there is no internal order to a SQL table in general. Actually, even the current ordering you are observing is not necessarily guaranteed by Oracle. If you expect a certain order in a result set, you need to impose it via a ORDER BY clause.
How's this?
with table1 as
(
select 1 ID, 'txt1' value from dual
union all
select 2, 'txt2' from dual
union all
select 7, 'txt7' from dual
union all
select 5, 'txt5' from dual
union all
select 3, 'txt3' from dual
)
select * from table1 order by rownum desc;
Actually this is not working for this perticular example. but it is working for normal table.
Please help to optimize my query. It looks too bulky.
I guess there is a better way to work with hours (datetime) in sql
There is a table dauditnew that is populated and population datetime is stored inside auditdate column.
Query returns rows count by hour.
SELECT t.Hour, COUNT(t.Hour) as Count FROM dauditnew d,
(SELECT 0 as Hour FROM DUAL UNION
SELECT 1 FROM DUAL UNION
SELECT 2 FROM DUAL UNION
SELECT 3 FROM DUAL UNION
SELECT 4 FROM DUAL UNION
SELECT 5 FROM DUAL UNION
SELECT 6 FROM DUAL UNION
SELECT 7 FROM DUAL UNION
SELECT 8 FROM DUAL UNION
SELECT 9 FROM DUAL UNION
SELECT 10 FROM DUAL UNION
SELECT 11 FROM DUAL UNION
SELECT 12 FROM DUAL UNION
SELECT 13 FROM DUAL UNION
SELECT 14 FROM DUAL UNION
SELECT 15 FROM DUAL UNION
SELECT 16 FROM DUAL UNION
SELECT 17 FROM DUAL UNION
SELECT 18 FROM DUAL UNION
SELECT 19 FROM DUAL UNION
SELECT 20 FROM DUAL UNION
SELECT 21 FROM DUAL UNION
SELECT 22 FROM DUAL UNION
SELECT 23 FROM DUAL) t
where
d.auditdate >= TO_DATE('25.04.2017 ' || t.Hour, 'dd.mm.yyyy HH24') and
d.auditdate <= TO_DATE('25.04.2017 ' || t.Hour || '_59_59', 'dd.mm.yyyy HH24_MI_SS')
group by t.Hour
You want to start with something like this:
select trunc(d.auditdate, 'HH24') as hh, count(*)
from dauditnew d
where d.auditdate >= '2017-04-25' and d.auditdate < '2017-04-26'
group by trunc(d.auditdate, 'HH24')
order by hh;
If this misses hours, then you can use a left join with this as a subquery.