I can select a list of rows from a table. but I want to show them by swapping upside down.
Explaination:
with table1 as
(
select 1 ID, 'txt1' value from dual
union all
select 2, 'txt2' from dual
union all
select 7, 'txt7' from dual
union all
select 5, 'txt5' from dual
union all
select 3, 'txt3' from dual
)
select * from table1;
in above query I can obtain following result
ID | VALUE
------------------
1 txt1
2 txt2
7 txt7
5 txt5
3 txt3
but I want to show them as follows
ID | VALUE
------------------
3 txt3
5 txt5
7 txt7
2 txt2
1 txt1
How to do that?
One approach would be to add a computed column to your set of union queries, then order by that column:
WITH table1 AS (
SELECT 1 ID, 'txt1' value, 1 AS position FROM dual
UNION ALL
SELECT 2, 'txt2', 2 FROM dual
UNION ALL
SELECT 7, 'txt7', 3 FROM dual
UNION ALL
SELECT 5, 'txt5', 4 FROM dual
UNION ALL
SELECT 3, 'txt3', 5 FROM dual
)
SELECT *
FROM table1
ORDER BY pos DESC;
Note that there is no internal order to a SQL table in general. Actually, even the current ordering you are observing is not necessarily guaranteed by Oracle. If you expect a certain order in a result set, you need to impose it via a ORDER BY clause.
How's this?
with table1 as
(
select 1 ID, 'txt1' value from dual
union all
select 2, 'txt2' from dual
union all
select 7, 'txt7' from dual
union all
select 5, 'txt5' from dual
union all
select 3, 'txt3' from dual
)
select * from table1 order by rownum desc;
Actually this is not working for this perticular example. but it is working for normal table.
Related
I know a little bit of sql, only the basic, now I need to create a analytic query but can't do this yet.
I have 2 tables on my db oracle, client and exams:
I am tried a lot of ways to get the mean of exams by client, but no success yet.4
The result expected is:
exams = 13
clients = 6
13/6= 2.166666666...7
How can I do that?
If you have clients who have not taken any exams then you want:
SELECT AVG(COUNT(e.nu_ordem)) AS avg_exames_by_client
FROM cliente c
LEFT OUTER JOIN exames e
ON (c.id = e.id_cliente)
GROUP BY c.id;
or:
SELECT (SELECT COUNT(*) FROM exames) / (SELECT COUNT(*) FROM cliente)
AS avg_exames_by_client
FROM DUAL;
Which, for the sample data:
CREATE TABLE cliente (id PRIMARY KEY) AS
SELECT 1 FROM DUAL UNION ALL
SELECT 2 FROM DUAL UNION ALL
SELECT 3 FROM DUAL UNION ALL
SELECT 4 FROM DUAL UNION ALL
SELECT 5 FROM DUAL UNION ALL
SELECT 6 FROM DUAL;
CREATE TABLE exames (nu_ordem PRIMARY KEY, id_cliente) AS
SELECT 1, 1 FROM DUAL UNION ALL
SELECT 2, 5 FROM DUAL UNION ALL
SELECT 3, 5 FROM DUAL UNION ALL
SELECT 4, 2 FROM DUAL UNION ALL
SELECT 5, 6 FROM DUAL UNION ALL
SELECT 6, 1 FROM DUAL UNION ALL
SELECT 7, 1 FROM DUAL UNION ALL
SELECT 8, 4 FROM DUAL UNION ALL
SELECT 9, 5 FROM DUAL UNION ALL
SELECT 10, 3 FROM DUAL UNION ALL
SELECT 11, 6 FROM DUAL UNION ALL
SELECT 12, 2 FROM DUAL UNION ALL
SELECT 13, 1 FROM DUAL;
Both output:
AVG_EXAMES_BY_CLIENT
2.166666666666666667
If you then add a couple of clients but no more exams:
INSERT INTO cliente (id)
SELECT 7 FROM DUAL UNION ALL
SELECT 8 FROM DUAL
Then the average is:
AVG_EXAMES_BY_CLIENT
1.625
db<>fiddle here
You can try below formula to get the result -
SELECT COUNT(*)/COUNT(DISTINCT id_cliente)
FROM exams;
Query:
SELECT teamid
FROM team
WHERE teamid NOT IN (SELECT team_teamid FROM gymnast);
Tables:
TEAM table
Gymnast table
I have been trying to figure this out for a while, any information would be greatly appreciated. Thank you!
The fiddle for oracle
val NOT IN (some list) means the value does NOT match every entry in the list.
But if one entry in the list is null, value <> null can never be true for that entry, which means the entire NOT IN expression can never be true.
See the following examples:
WITH team (teamid) AS (
SELECT 1 FROM DUAL UNION
SELECT 2 FROM DUAL UNION
SELECT 3 FROM DUAL UNION
SELECT 4 FROM DUAL
)
, gymnast (team_teamid) AS (
SELECT 1 FROM DUAL UNION
SELECT 2 FROM DUAL UNION
SELECT 2 FROM DUAL UNION
SELECT 4 FROM DUAL
)
SELECT teamid FROM team WHERE teamid NOT IN (SELECT team_teamid FROM gymnast)
;
Result:
TEAMID
3
Case 2 with nulls in the list:
WITH team (teamid) AS (
SELECT 1 FROM DUAL UNION
SELECT 2 FROM DUAL UNION
SELECT 3 FROM DUAL UNION
SELECT 4 FROM DUAL
)
, gymnast (team_teamid) AS (
SELECT 1 FROM DUAL UNION
SELECT 2 FROM DUAL UNION
SELECT null FROM DUAL UNION
SELECT 4 FROM DUAL
)
SELECT teamid FROM team WHERE teamid NOT IN (SELECT team_teamid FROM gymnast)
;
Result:
TEAMID
No rows in result, due to the gymnast with a null team_teamid.
BELOW IS SNIPPET OF MY DATA
Here is the sample creation code of testing.
CREATE TABLE MYGROUP ( Category,PERSON,Flag ) AS
SELECT 'Cat1','A','1' FROM DUAL
UNION ALL SELECT 'Cat1','A','0' FROM DUAL
UNION ALL SELECT 'Cat1','A','1' FROM DUAL
UNION ALL SELECT 'Cat1','B','1' FROM DUAL
UNION ALL SELECT 'Cat1','B','0' FROM DUAL
UNION ALL SELECT 'Cat2','A','0' FROM DUAL
UNION ALL SELECT 'Cat2','A','0' FROM DUAL
UNION ALL SELECT 'Cat2','A','0' FROM DUAL
UNION ALL SELECT 'Cat2','B','1' FROM DUAL
UNION ALL SELECT 'Cat2','B','1' FROM DUAL
UNION ALL SELECT 'Cat2','B','0' FROM DUAL
UNION ALL SELECT 'Cat3','X','0' FROM DUAL
UNION ALL SELECT 'Cat3','Y','0' FROM DUAL;
Desired Output:
Category - Count of Distinct Persons with Flag = 1
Cat1 - 2
Cat2 - 1
Cat3 - 0
I need to get my code in Big query to get distinct counts of persons. It shouldnt double count.
You can use conditional aggregation
SELECT
Category,
COUNT(DISTINCT CASE WHEN Flag = 1 THEN PERSON END)
FROM MYGROUP
GROUP BY Category;
How can I retrieve values in a row as column values?
Example:
Consider the output of below query as INPUT :
Select 1,2,3,4,5,6,7,8,9,10
from dual;
I need a query that can give below output:
COL1
----
1
2
3
4
5
6
7
8
9
10
SELECT 1 AS "COL1" FROM dual
UNION
SELECT 2 FROM dual
UNION
SELECT 3 FROM dual
UNION
SELECT 4 FROM dual
UNION
SELECT 5 FROM dual
UNION
SELECT 6 FROM dual
UNION
SELECT 7 FROM dual
UNION
SELECT 8 FROM dual
UNION
SELECT 9 FROM dual
UNION
SELECT 10 FROM dual ;
If you want to generate a sequence of numbers in Oracle:
with n as (
select level as n
from dual
connect by level <= 10
)
select *
from n;
Or, if you have 10 columns, you can do an unpivot. An easy way is with union all:
select col1 from t union all
select col2 from t union al
. . .
select col10 from t;
I have a column in the database in the following format: yymmddhh24miss
Sample Data:
140203101241
140202101141
140102101240
143001101244
142801101245
142701131347
142601121542
142101131744
...
I need to get the nearest high value from the list. Ex: If I pass 142701131333, then it should return 142701131347 from the above list.
Any help appreciated!
SELECT data
FROM
(
SELECT data
FROM tbl
WHERE data > '142701131333'
ORDER BY data
) a
WHERE rownum = 1
SQL> with t (x) as (
2 select 140203101241 from dual union all
3 select 140202101141 from dual union all
4 select 140102101240 from dual union all
5 select 143001101244 from dual union all
6 select 142801101245 from dual union all
7 select 142701131347 from dual union all
8 select 142601121542 from dual union all
9 select 142101131744 from dual
10 )
11 select min(x) minx from t where x > 142701131333
12 /
MINX
-----------------
142701131347
SELECT MIN(sample_data)
FROM tableName
WHERE sample_data > 142701131333