Dividing sum results - sql

I'm really sorry as this was probably answered before, but I couldn't find something that solved the problem.
In this case, I'm trying to get the result of dividing two sums in the same column.
| Id | month | budget | sales |
| -- | ----- | ------ | ----- |
| 1 | jan | 1000 | 800 |
| 2 | jan | 1000 | 850 |
| 1 | feb | 1200 | 800 |
| 2 | feb | 1100 | 850 |
What i want is to get the % of completition for each id and month (example: get 0,8 or 80% in a fifth column for id 1 in jan)
I have something like
sel
id,
month,
sum (daily_budget) as budget,
sum (daily_sales) as sales,
budget/sales over (partition by 1,2) as efectivenes
from sales
group by 1,2
I know im doing this wrong but I'm kinda new with sql and cant find the way :|
Thanks!

This should do it
CAST(ROUND(SUM(daily_sales) * 100.00 / SUM(daily_budget), 1) AS DECIMAL(5,2)) AS Effectiveness

I'm new at SQL too but maybe I can help. Try this?
sel
id,
month,
sum (daily_budget) as budget,
sum (daily_sales) as sales,
(sum(daily_budget)/sum(daily_sales)) over (partition by id) as efectivenes
from sales
group by id

If you want to ALTER your table so that it contains a fifth column where the result of budget/sales is automatically calculated, all you need to do this add the formula to this auto-generated column. The example I am about to show is based on MySQL.
Open MySQL
Find the table you wish to modify in the Navigator Pane, right-click on it and select "Alter Table"
Add a new row to your table. Make sure you select NN (Not Null) and G (Generated Column) check boxes
In the Default/Expression column, simply enter the expression budget / sales.
Once you run your next query, you should see your column generated and populated with the calculated results. If you simply want the SQL statement to do the same from the console, it will be something like this: ALTER table YOUR_TABLE_NAME add result FLOAT as (budget / sales);

Related

SQL Query to return a distinct count of one column while allowing a full summation of a second column, grouped by a third

I'm writing a query in access 2010 and i can't use count(distinct... so I'm running into a bit of trouble with what can be found below:
An example of my table is as follows
Provider | Member ID | Dollars | Status
FacilityA | 1001 | 50 | Pended
FacilityA | 1001 | 100 | Paid
FacilityA | 1002 | 200 | Paid
FacilityB | 1005 | 30 | Pended
FacilityB | 1009 | 90 | Pended
FacilityC | 1001 | 100 | Paid
FacilityC | 1008 | 500 | Paid
I want to return the total # of unique members that have visited each facility, but I also want to get the total dollar amount that is Pended, so for this example the ideal output would be
Provider | # members | Total Pended charges
FacilityA | 2 | 50
FacilityB | 2 | 120
FacilityC | 2 | 0
I tried using some code I found here: Count Distinct in a Group By aggregate function in Access 2007 SQL
and here:
SQL: Count distinct values from one column based on multiple criteria in other columns
Copying the code from the first link provided by gzaxx:
SELECT cd.DiagCode, Count(cd.CustomerID)
FROM (select distinct DiagCode, CustomerID from CustomerTable) as cd
Group By cd.DiagCode;
I can make this work for counting the members:
SELECT cd.Provider_Number, Count(cd.Member_ID)
FROM (select distinct Provider_Number, Member_ID from Claims_Table) as cd
ON claims_table.Provider_Number=cd.Provider_Number
Group By cd.Provider_Number;
However, no matter what I try I can't get a second portion dealing with the dollars to work without causing an error or messing up the calculation on the member count.
SELECT cd.Provider_Number,
-- claims_table.Member_ID, claims_table.Dollars
SUM(IIF ( Claims_Table.Status = 'Pended' , Claims_Table.Dollars , 0 )) as Dollars_Pending,
Count(cd.Member_ID) as Uniq_Members,
Sum(Dollars) as Dollar_Wrong
FROM (select distinct Provider_Number, Member_ID from Claims_Table) as cd inner join #claims_table
ON claims_table.Provider_Number=cd.Provider_Number and claims_table.Member_ID = cd.Member_ID
Group By cd.Provider_Number;
This should work fine based only on the table you described (named Tabelle1):
SELECT Provider, count(MemberID) as [# Members],
NZ(SUM(SWITCH([Status]='Pended', Dollars)),0) as [Total pending charges]
FROM Tabelle1
GROUP BY Provider;
Explanation
I think the first and second column are self-explanatory.
The third column is where most things are done. The SWITCH([Status]='Pended', Dollars) returns the Dollars only if the status is pending. This then gets summed up by SUM. The NZ(..,0) will set the column to 0 if the SUM returns a NULL.
EDIT: This was tested on Access 2016

Select the difference of two consecutive columns

I have a table car that looks like this:
| mileage | carid |
------------------
| 30 | 1 |
| 50 | 1 |
| 100 | 1 |
| 0 | 2 |
| 70 | 2 |
I would like to get the average difference for each car. So for example for car 1 I would like to get ((50-30)+(100-50))/2 = 35. So I created the following query
SELECT AVG(diff),carid FROM (
SELECT (mileage-
(SELECT Max(mileage) FROM car Where mileage<mileage AND carid=carid GROUP BY carid))
AS diff,carid
FROM car GROUP BY carid)
But this doesn't work as I'm not able to use current row for the other column. And I'm quite clueless on how to actually solve this in a different way.
So how would I be able to obtain the value of the next row somehow?
The average difference is the maximum minus he minimum divided by one less than the count (you can do the arithmetic to convince yourself this is true).
Hence:
select carid,
( (max(mileage) - min(mileage)) / nullif(count(*) - 1, 0)) as avg_diff
from cars
group by carid;

SQL payments matrix

I want to combine two tables into one:
The first table: Payments
id | 2010_01 | 2010_02 | 2010_03
1 | 3.000 | 500 | 0
2 | 1.000 | 800 | 0
3 | 200 | 2.000 | 300
4 | 700 | 1.000 | 100
The second table is ID and some date (different for every ID)
id | date |
1 | 2010-02-28 |
2 | 2010-03-01 |
3 | 2010-01-31 |
4 | 2011-02-11 |
What I'm trying to achieve is to create table which contains all payments before the date in ID table to create something like this:
id | date | T_00 | T_01 | T_02
1 | 2010-02-28 | 500 | 3.000 |
2 | 2010-03-01 | 0 | 800 | 1.000
3 | 2010-01-31 | 200 | |
4 | 2010-02-11 | 1.000 | 700 |
Where T_00 means payment in the same month as 'date' value, T_01 payment in previous month and so on.
Is there a way to do this?
EDIT:
I'm trying to achieve this in MS Access.
The problem is that I cannot connect name of the first table's column with the date in the second (the easiest way would be to treat it as variable)
I added T_00 to T_24 columns in the second (ID) table and was trying to UPDATE those fields
set T_00 =
iif(year(date)&"_"&month(date)=2010_10,
but I realized that that would be to much code for access to handle if I wanted to do this for every payment period and every T_xx column.
Even if I would write the code for T_00 I would have to repeat it for next 23 periods.
Your Payments table is de-normalized. Those date columns are repeating groups, meaning you've violated First Normal Form (1NF). It's especially difficult because your field names are actually data. As you've found, repeating groups are a complete pain in the ass when you want to relate the table to something else. This is why 1NF is so important, but knowing that doesn't solve your problem.
You can normalize your data by creating a view that UNIONs your Payments table.
Like so:
CREATE VIEW NormalizedPayments (id, Year, Month, Amount) AS
SELECT id,
2010 AS Year,
1 AS Month,
2010_01 AS Amount
FROM Payments
UNION ALL
SELECT id,
2010 AS Year,
2 AS Month,
2010_02 AS Amount
FROM Payments
UNION ALL
SELECT id,
2010 AS Year,
3 AS Month,
2010_03 AS Amount
FROM Payments
And so on if you have more. This is how the Payments table should have been designed in the first place.
It may be easier to use a date field with the value '2010-01-01' instead of a Year and Month field. It depends on your data. You may also want to add WHERE Amount IS NOT NULL to each query in the UNION, or you might want to use Nz(2010_01,0.000) AS Amount. Again, it depends on your data and other queries.
It's hard for me to understand how you're joining from here, particularly how the id fields relate because I don't see how they do with the small amount of data provided, so I'll provide some general ideas for what to do next.
Next you can join your second table with this normalized Payments table using a method similar to this or a method similar to this. To actually produce the result you want, include a calculated field in this view with the difference in months. Then, create an actual Pivot Table to format your results (like this or like this) which is the proper way to display data like your tables do.

How to print page-wise totals at the end of every page using table

I'm trying make a report which contains some prices on every row, and I want to print the sum of prices -which are printed on the page- at the bottom of every page. I don't find it smart to print the grand totals in every page, for my situation at least.
Example:
First Page
Name | Price1 | Price2 | Price3 | Price4 -table header
Record 1 | 10 | 15 | 15 | 20
Record 2 | 15 | 15 | 15 | 15
Total 2 records | 25 | 30 | 30 | 35 -table footer for page 1
Second Page
Name | Price1 | Price2 | Price3 | Price4 -starting 2. page, table header
Record 3 | 20 | 30 | 30 | 30
Total 1 records | 20 | 30 | 30 | 30 -end of the table
Grand T. (3 rec) | 45 | 60 | 60 | 65 -end of the table
I put 2 records for the first page and 1 for second page, its just to demonstrate what I want. I did my best to make it look clear.
I can see two possible ways this could be done.
Since you say that there's a predictable number of rows per page (let's say, for ease of constructing an example, that there are 25), you could do the following:
In your query, assign each row a consecutive sequence number. You could do this like this:
WITH Cte
AS (
SELECT Name,
Price1,
Price2,
Price3,
Price4,
RecordNumber = Row_Number() OVER (ORDER BY [whatever])
FROM [tables]
)
SELECT Name,
Price1,
[etc]
RowGroup = Floor((RecordNumber * 1.0) / 25 )
FROM Cte
ORDER BY RecordNumber
Then, in your report, group by RowGroup, and subtotal your rows.
If you have other, higher-level groupings in the report, you will probably have to start a new page after each higher-level group, because otherwise it will throw the placement off for the page subtotals.
(You might also be able to do this with the RowNumber() function in SSRS without modifying the underlying query, but there are a lot of rules about what functions you can use when, and I don't know if that would be allowed.)
The other option I can think of is more complicated and involves using the report Code section and setting some module-level functions. Let me know if you think that's something you need to see.

Comparing in SQL and SUM

I really couldn't figure out a good title for this question, but I have a problem that I'm sure you can help me with!
I have a query which outputs something like this:
Month | Year | Subcategory | PrivateLabel | Price
-------------------------------------------------
1 | 2010 | 666 | No | -520
1 | 2010 | 666 | No | -499,75
1 | 2010 | 666 | No | -59,95
1 | 2010 | 666 | No | -49,73
1 | 2010 | 666 | No | -32,95
I want to SUM on the price because all the other data is the same. I thought I could do this with SUM and GROUP BY, but I can't figure out how to do it or at least it doesn't output the right result.
The query is an inner join between two tables, if that helps.
select
month
,year
,subcategory
,privatelabel
,sum(price) as [total sales]
from
a inner join b ...
where
any where clauses
group by
month
,year
,subcategory
,privatelabel
should work if i am understanding you correctly.. every colum in the select either needs to be part of the group by or an aggregate function on all rows in the group
added a fiddle.. mainly as i didn't know about he text to DDL functionality and wanted to test it ;-) (thanks Michael Buen)
http://sqlfiddle.com/#!3/35c1c/1
note the where clause is a place holder..
select month, year, subcategory, privatelabel, sum(price)
from (put your query in here) dummyName
group by month, year, subcategory, privatelabel
Basic idea is it will run your current query to get above output then do the sum and group by on the result.
You query has to be in parentheses and you have to give it some name e.g. dummyName. As long as it's unique in the sql and preferably not a key word, doesn't matter what it is.
There might be a way of doing all this in one go, but without the sql for your query we can't help.