How do I size and sapce - sql

Question

def function(foo):
print(foo)
``````python
def function(foo):
print(foo)
``````python
def function(foo):
print(foo)
this is what i needed and i appreciate it guys

Answer 1

For problems like these, try to associate the output with its indices (or in this case, current_row). Also, it seems like it's better to start from 0 for this one.
0: 1
1: 2 * 3
2: 4 * * * 5
3: 6 * * * * * 7
4: 8 * * * * * * * 9
max_row is 5, current_row is from 0 to 4.
There are max_row - current_row - 1 spaces on each row.
There are 2 * current_row - 1 stars on each row.
The numbers on the left is just twice current_row, or 2 * current_row. This is true for all except 0. We could use an if statement for that special case.
The numbers on the right is just left + 1, or 2 * current_row + 1.
space = '\t'
star = '*'
size = int(input("Enter number to make triangle: "))
def printRow(current_row, max_row) :
star_count = 2 * current_row - 1
line = space * (max_row - current_row - 1)
if current_row == 0 :
line += "1"
else :
line += str(2 * current_row) + space
line += (star + space) * star_count
if current_row > 0 :
line += str(2 * current_row + 1)
print(line)
if size <= 0 :
print("The value you entered is too small to display a triangle")
for i in range(0, size) :
printRow(i, size)

Answer 2

First of all you have to learn how to print python pyramid you can learn it from
This link , Then try to understand it after you can understand below code
space = '\t'
star = '*'
size = int(input("Enter number to make triangle: \n"))
def printRow(current_row, max_row) :
rPri = 0
lefNum = 0
star_count = 2*current_row - 3
if current_row == 1:
lefNum = 1
if current_row > 1:
lefNum = (current_row-1)*2
rPri = 1
rigNum = lefNum + 1
line = space * (max_row - current_row) + str(lefNum) + (space + star) * star_count + (space + str(rigNum))*rPri
print(line)
if size<=0 :
print("The value you entered is too small to display a triangle")
for i in range(1, size+1) :
printRow(i, size)