Im trying to to figure out what I need to write on sql command oracle [closed] - sql

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For every customer that lives in Florida, list customer number, last name, first name,
and region.

I will assume that you are trying to get the information from a table called "table".
select customer_number,
last_name,
first_name,
region
from table
where city = 'Florida'

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How to pull list of all the customer with first_name as alphanumeric value [closed]

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I have a table name clients, now I want to pull a list of all the customers having first_name as alphanumeric value as an example, jriqbal23, sam45del etc.
If I need to pull the details of single customer, I can run below SQL:
select customer_id,email,first_name,last_name,middle_name from clients
where
email='jriqbal23#gmail.com';
how to change this query for pulling the list of all the customer having first name in similar way ?
thanks in advance.
If you use Oracle database, you can query client data with regexp_like:
Alphanumeric case:
select *
from clients
where regexp_like(first_name, '\w+');
Digits case:
select *
from clients
where regexp_like(first_name, '\d+');

POSTGRESQL: Insert Data from another table [closed]

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In above table customer ids are listed what I want to do is to get those ids from this table,
create another table named PROMOTION CLASSES where PREMIUM, PLUS AND NORMAL are in columns and put first 100 ids under PREMIUM COLUMN and soon.
Please help.
This creates you table with classification
CREATE TABLE promotion_classes as
SELECT customer_id,
case when customer_id < 100 then
'PREMIUM'
else
'NORMAL'
END as CLASSES
FROM CUSTOMER_TBL

Filter in SQL from search keyword [closed]

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I have one table student. If I filter a student using a keyword "ann", then 1st preference should be student name starts with "ann", then student name contains "ann" in SQL Server.
Use LIKE
SELECT * FROM TABLE WHERE NAME LIKE 'ann%' OR NAME LIKE '%ann%'
ORDER BY CASE
WHEN Name LIKE 'ann%' THEN 1
WHEN Name LIKE '%ann%' THEN 2
ELSE 3
END

How to get total count of orders placed on spesific date using Raw query [closed]

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I have ORDER Table in which I am saving Orders date wise.
Now I want total number of orders placed on specific date
How to do that
Pls Help...
Try this:-
SELECT COUNT(*)
FROM TABLE_NAME
WHERE DATE_COL = 'YOUR_DATE'

Problems with SQL query finding three names with the most records [closed]

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I have a table and I want to display the 3 names (Ted, Ringo, Paul) that have the most records using an SQL query.
It's a primitive question, but please help me.
my table:
SELECT TOP 3 Name
FROM YourTable
GROUP BY Name
ORDER BY COUNT(*) DESC