Timestamp to date query oracle - sql

I use the query bellow in DB2. How do I do the same query in oracle?
SELECT *
FROM Table
WHERE DATE(field) = CURRENT DATE - 1 DAY

If field is a DATE or TIMESTAMP data type (both of which have year, month, day, hour, minute and second components and the TIMESTAMP can also have fractional seconds) then you can use:
SELECT *
FROM table_name
WHERE field < TRUNC( SYSDATE )
AND field >= TRUNC( SYSDATE ) - INTERVAL '1' DAY;

Related

Oracle SQL Select Rows where column with date is at most one hour before now ( sysdate )

I have this table
invoice_number
creation_date
1
2023-02-06T10:38:37.000+00:00
2
2023-02-06T10:49:34.000+00:00
I want to fetch rows only where creation_Date is 1 hours ago or less, how to do that ?
Since you are comparing to a TIMESTAMP WITH TIME ZONE column, then you can use:
SELECT *
FROM table_name
WHERE creation_date >= SYSTIMESTAMP - INTERVAL '1' HOUR;
Check this one;
... where creation_Date>sysdate - interval '1' hour

Select Data From Multiple Days Between Certain Times (Spanning 2 days)

I need to know how many entries appear in my DB for the past 7 days with a timestamp between 23:00 & 01:00...
The Issue I have is the timestamp goes across 2 days and unsure if this is even possible in the one query.
So far I have come up with the below:
select trunc(timestamp) as DTE, extract(hour from timestamp) as HR, count(COLUMN) as Total
from TABLE
where trunc(timestamp) >= '12-NOV-19' and
extract(hour from timestamp) in ('23','00','01')
group by trunc(timestamp), extract(hour from timestamp)
order by 1,2 desc;
The result I am hoping for is something like this:
DTE | Total
20-NOV-19 5
19-NOV-19 4
18-NOV-19 4
17-NOV-19 6
Many thanks
Filter on the day first comparing it to TRUNC( SYSDATE ) - INTERVAL '7' DAY and then consider the hours by comparing the timestamp to itself truncated back to midnight with an offset of a number of hours.
select trunc(timestamp) as DTE,
extract(hour from timestamp) as HR,
count(COLUMN) as Total
from TABLE
WHERE timestamp >= TRUNC( SYSDATE ) - INTERVAL '7' DAY
AND ( timestamp <= TRUNC( timestamp ) + INTERVAL '01:00' HOUR TO MINUTE
OR timestamp >= TRUNC( timestamp ) + INTERVAL '23:00' HOUR TO MINUTE
)
group by trunc(timestamp), extract(hour from timestamp)
order by DTE, HR desc;
Subtract or add an hour to derive the date. I'm not sure what date you want to assign to each period, but the idea is:
select trunc(timestamp - interval '1' hour) as DTE,
count(*) as Total
from t
where trunc(timestamp - interval '1' hour) >= DATE '2019-11-12' and
extract(hour from timestamp) in (23, 0)
group by trunc(timestamp - interval '1' hour)
order by 1 desc;
Note: If you want times between 11:00 p.m. and 1:00 a.m., then you want the hour to be 23 or 0.

how to get current year to date and prior year to date in sql

Suppose my date range is current: 01-jan-2015 to 17-Feb-2015.
I need the data for 01-jan-2014 to 17-02-2014 also.
how to write the query in sql?
i want to get the data for these CYD and pYD.
Here is an example in Oracle :
select sysdate - interval '1' year from dual;
The key word 'interval' also exist in other SQL language, like postgres.
To select those ranges of dates from, say, a calendar table, I'd probably write this in standard SQL.
select cal_date from calendar
where cal_date between date '2015-01-01'
and current_date
or cal_date between date '2015-01-01' - interval '1' year
and current_date - interval '1' year
order by cal_date;
If I wanted to identify rows in each range, I'd add literal values.
select 'cyd', cal_date
from calendar
where cal_date between date '2015-01-01'
and current_date
union all
select 'pyd', cal_date
from calendar
where cal_date between date '2015-01-01' - interval '1' year
and current_date - interval '1' year
order by cal_date;

Select rows where day is less than today

How do I select rows in the past starting from yesterday in Oracle DB where a field like created_date is a timestamp(6)?
I don't want to compare time, just date.
If you want exactly one day prior to the current time:
select *
from table t
where created_date < sysdate - 1;
If you want times before today:
select *
from table t
where created_date <= trunc(sysdate);
From the Oracle documentation on SELECT :
SELECT * FROM orders
WHERE created_date < TO_DATE('2014-04-28', 'YYYY-MM-DD');
I can pass this date format from my application, worked like a charm.
As you want to compare just date:
select *
from table t
where date(created_date) < DATE_SUB(CURRENT_DATE(), INTERVAL 1 DAY);
you can use cast function to deal with timestamp as date:
SELECT cast(SYSTIMESTAMP(6) as date)
FROM dual;
so you can select rows with "yesterdate" date by:
select ....
where cast(SYSTIMESTAMP(6) as date) like sysdate - 1
note: replace SYSTIMESTAMP(6) with column name which has timestamp type.

How to select records from last 24 hours using SQL?

I am looking for a where clause that can be used to retrieve records for the last 24 hours?
In MySQL:
SELECT *
FROM mytable
WHERE record_date >= NOW() - INTERVAL 1 DAY
In SQL Server:
SELECT *
FROM mytable
WHERE record_date >= DATEADD(day, -1, GETDATE())
In Oracle:
SELECT *
FROM mytable
WHERE record_date >= SYSDATE - 1
In PostgreSQL:
SELECT *
FROM mytable
WHERE record_date >= NOW() - '1 day'::INTERVAL
In Redshift:
SELECT *
FROM mytable
WHERE record_date >= GETDATE() - '1 day'::INTERVAL
In SQLite:
SELECT *
FROM mytable
WHERE record_date >= datetime('now','-1 day')
In MS Access:
SELECT *
FROM mytable
WHERE record_date >= (Now - 1)
SELECT *
FROM table_name
WHERE table_name.the_date > DATE_SUB(CURDATE(), INTERVAL 1 DAY)
MySQL :
SELECT *
FROM table_name
WHERE table_name.the_date > DATE_SUB(NOW(), INTERVAL 24 HOUR)
The INTERVAL can be in YEAR, MONTH, DAY, HOUR, MINUTE, SECOND
For example, In the last 10 minutes
SELECT *
FROM table_name
WHERE table_name.the_date > DATE_SUB(NOW(), INTERVAL 10 MINUTE)
Which SQL was not specified, SQL 2005 / 2008
SELECT yourfields from yourTable WHERE yourfieldWithDate > dateadd(dd,-1,getdate())
If you are on the 2008 increased accuracy date types, then use the new sysdatetime() function instead, equally if using UTC times internally swap to the UTC calls.
in postgres, assuming your field type is a timestamp:
select * from table where date_field > (now() - interval '24 hour');
If the timestamp considered is a UNIX timestamp
You need to first convert UNIX timestamp (e.g 1462567865) to mysql timestamp or data
SELECT * FROM `orders` WHERE FROM_UNIXTIME(order_ts) > DATE_SUB(CURDATE(), INTERVAL 1 DAY)
select ...
from ...
where YourDateColumn >= getdate()-1
SELECT *
FROM tableName
WHERE datecolumn >= dateadd(hour,-24,getdate())
Hello i now it past a lot of time from the original post but i got a similar problem and i want to share.
I got a datetime field with this format YYYY-MM-DD hh:mm:ss, and i want to access a whole day, so here is my solution.
The function DATE(), in MySQL: Extract the date part of a date or datetime expression.
SELECT * FROM `your_table` WHERE DATE(`your_datatime_field`)='2017-10-09'
with this i get all the row register in this day.
I hope its help anyone.
In SQL Server (For last 24 hours):
SELECT *
FROM mytable
WHERE order_date > DateAdd(DAY, -1, GETDATE()) and order_date<=GETDATE()
In Oracle (For last 24 hours):
SELECT *
FROM my_table
WHERE date_column >= SYSDATE - 24/24
In case, for any reason, you have rows with future dates, you can use between, like this:
SELECT *
FROM my_table
WHERE date_column BETWEEN (SYSDATE - 24/24) AND SYSDATE