Select rows where day is less than today - sql

How do I select rows in the past starting from yesterday in Oracle DB where a field like created_date is a timestamp(6)?
I don't want to compare time, just date.


If you want exactly one day prior to the current time:
select *
from table t
where created_date < sysdate - 1;
If you want times before today:
select *
from table t
where created_date <= trunc(sysdate);


From the Oracle documentation on SELECT :
SELECT * FROM orders
WHERE created_date < TO_DATE('2014-04-28', 'YYYY-MM-DD');
I can pass this date format from my application, worked like a charm.


As you want to compare just date:
select *
from table t
where date(created_date) < DATE_SUB(CURRENT_DATE(), INTERVAL 1 DAY);


you can use cast function to deal with timestamp as date:
SELECT cast(SYSTIMESTAMP(6) as date)
FROM dual;
so you can select rows with "yesterdate" date by:
select ....
where cast(SYSTIMESTAMP(6) as date) like sysdate - 1
note: replace SYSTIMESTAMP(6) with column name which has timestamp type.

Related

Timestamp to date query oracle

I use the query bellow in DB2. How do I do the same query in oracle?
SELECT *
FROM Table
WHERE DATE(field) = CURRENT DATE - 1 DAY

If field is a DATE or TIMESTAMP data type (both of which have year, month, day, hour, minute and second components and the TIMESTAMP can also have fractional seconds) then you can use:
SELECT *
FROM table_name
WHERE field < TRUNC( SYSDATE )
AND field >= TRUNC( SYSDATE ) - INTERVAL '1' DAY;

How to convert current time to date without time in sql?

I want to select data where the operation_date between '01-Jan-2016' and yesterday. I used code as follows:
select *
where operation_date between '01-Jan-2016' and sysdate-1
from TABLE
But sysdate returns both date and time. Therefore, the above output includes all the data between '01-Jan-2016' and say, 14 Nov-2017 09:50:51. I only want the data before today. How to convert current time to date without time? Thanks.

Seems that you are looking for trunc().
Example
SELECT sysdate - 1 AS current_Date_Time
,trunc(sysdate) - 1 AS CURRENT_DATE1
,trunc(sysdate - 1) AS CURRENT_DATE2
FROM dual
Result
CURRENT_DATE_TIME CURRENT_DATE1 CURRENT_DATE2
----------------------------------------------------------
13.11.2017 18:08:41 13.11.2017 00:00:00 13.11.2017 00:00:00
DEMO
So the correct query will be as below.
SELECT *
WHERE operation_date BETWEEN DATE '2016-01-01' -- ANSI Date Literal
AND trunc(sysdate - 1)
FROM TABLE
OR
SELECT *
WHERE operation_date BETWEEN DATE '2016-01-01' -- ANSI Date Literal
AND trunc(sysdate) - 1
FROM TABLE

How to search by to_date function?

I have table as below:
Table Temp:
ID MAX MIN DATE_C
1 34 24 21-APR-17 02.41.38.520000 PM
2 32 26 20-APR-17 02.42.44.569000 PM
I execute the below SQL query to get temperature details on respective date:
SELECT *
FROM Temp t
WHERE t.date_c = TO_DATE( '2017-04-21', 'YYYY-MM-DD')
order by t.id
But it's returning empty records. Whats wrong with my query?

You need to remove the time component on the column. Here is one way:
SELECT *
FROM Temp t
WHERE TRUNC(t.date_c) = DATE '2017-04-21'
ORDER BY t.id;
However, I usually recommend using inequalities, rather than a function on the column:
SELECT *
FROM Temp t
WHERE t.date_c >= DATE '2017-04-21' AND
t.date_c < DATE '2017-04-22'
ORDER BY t.id;
This allows the query to use an index on date_c. I should add that the original version can use an index on (trunc(date_c, id).

21-APR-17 02.41.38.520000 PM is not a DATE; it has a fractional seconds component so it is a TIMESTAMP.
So, if you want to find items that are on a particular day (inputting the TIMESTAMP using an ISO/ANSI timestamp literal):
SELECT *
FROM Temp
WHERE date_c >= TIMESTAMP '2017-04-21 00:00:00' AND
date_c < TIMESTAMP '2017-04-21 00:00:00' + INTERVAL '1' DAY;
or
SELECT *
FROM Temp
WHERE date_c >= TO_TIMESTAMP( :your_date_string, 'YYYY-MM-DD' ) AND
date_c < TO_TIMESTAMP( :your_date_string, 'YYYY-MM-DD' ) + INTERVAL '1' DAY;
it's returning empty records. Whats wrong with my query?
date_c = TO_DATE( '2017-04-21', 'YYYY-MM-DD') matches all rows where the date_c value is exactly 2017-04-21 00:00:00.000000 (including the time component); if you do not have any rows with exactly that date and time then, as you noticed, it will return nothing. If you want to get records matching that day then you need to get values within a range of times between the start and end of the day.

You need to pass date on the column. Here is a way...
SELECT *
FROM Temp t
WHERE CAST(t.CREATED_ON as date)= N'2017-04-22'
ORDER BY t.id

How to use Oracle SQL Date and Time

I have the following example :
select * from my_table
where date between ('19-06-2014 00:00:00,000000000 EUROPE/BUCHAREST') and ('19-06-2014 23:59:59,000000000 EUROPE/BUCHAREST'
If I run this query it returns the correct values . What I need is something like this :
select * from my_table
where date between ('today - 2DAYS ') and ('today - 1DAY')
Do you have any idea how I can achieve this?

Try following solution:
--for one day results
select * from my_table where date between sysdate - 2 and sysdate - 1
--If you wish to start from the beginning of the day:
select * from my_table where date between trunc(sysdate) - 2 and trunc(sysdate) - 1
FYI - sysdate referes the current date and substrating value will be counted in terms of day. If you wish to substract 12 hrs, you should substract 0.5.

How to select records from last 24 hours using SQL?

I am looking for a where clause that can be used to retrieve records for the last 24 hours?

In MySQL:
SELECT *
FROM mytable
WHERE record_date >= NOW() - INTERVAL 1 DAY
In SQL Server:
SELECT *
FROM mytable
WHERE record_date >= DATEADD(day, -1, GETDATE())
In Oracle:
SELECT *
FROM mytable
WHERE record_date >= SYSDATE - 1
In PostgreSQL:
SELECT *
FROM mytable
WHERE record_date >= NOW() - '1 day'::INTERVAL
In Redshift:
SELECT *
FROM mytable
WHERE record_date >= GETDATE() - '1 day'::INTERVAL
In SQLite:
SELECT *
FROM mytable
WHERE record_date >= datetime('now','-1 day')
In MS Access:
SELECT *
FROM mytable
WHERE record_date >= (Now - 1)

SELECT *
FROM table_name
WHERE table_name.the_date > DATE_SUB(CURDATE(), INTERVAL 1 DAY)

MySQL :
SELECT *
FROM table_name
WHERE table_name.the_date > DATE_SUB(NOW(), INTERVAL 24 HOUR)
The INTERVAL can be in YEAR, MONTH, DAY, HOUR, MINUTE, SECOND
For example, In the last 10 minutes
SELECT *
FROM table_name
WHERE table_name.the_date > DATE_SUB(NOW(), INTERVAL 10 MINUTE)

Which SQL was not specified, SQL 2005 / 2008
SELECT yourfields from yourTable WHERE yourfieldWithDate > dateadd(dd,-1,getdate())
If you are on the 2008 increased accuracy date types, then use the new sysdatetime() function instead, equally if using UTC times internally swap to the UTC calls.

in postgres, assuming your field type is a timestamp:
select * from table where date_field > (now() - interval '24 hour');

If the timestamp considered is a UNIX timestamp
You need to first convert UNIX timestamp (e.g 1462567865) to mysql timestamp or data
SELECT * FROM `orders` WHERE FROM_UNIXTIME(order_ts) > DATE_SUB(CURDATE(), INTERVAL 1 DAY)

select ...
from ...
where YourDateColumn >= getdate()-1

SELECT *
FROM tableName
WHERE datecolumn >= dateadd(hour,-24,getdate())

Hello i now it past a lot of time from the original post but i got a similar problem and i want to share.
I got a datetime field with this format YYYY-MM-DD hh:mm:ss, and i want to access a whole day, so here is my solution.
The function DATE(), in MySQL: Extract the date part of a date or datetime expression.
SELECT * FROM `your_table` WHERE DATE(`your_datatime_field`)='2017-10-09'
with this i get all the row register in this day.
I hope its help anyone.

In SQL Server (For last 24 hours):
SELECT *
FROM mytable
WHERE order_date > DateAdd(DAY, -1, GETDATE()) and order_date<=GETDATE()

In Oracle (For last 24 hours):
SELECT *
FROM my_table
WHERE date_column >= SYSDATE - 24/24
In case, for any reason, you have rows with future dates, you can use between, like this:
SELECT *
FROM my_table
WHERE date_column BETWEEN (SYSDATE - 24/24) AND SYSDATE