I have a column that contains multiple values in a delimited(comma-separated) format -
id | code
------------
1 11,19,21
2 55,87,33
3 3,11
4 11
I want to be able to compare to each value inside the 'code' column as below -
SELECT id FROM myTbl WHERE code = '11'
This should return -
1
3
4
I've tried the solution below but it does not work for all cases -
SELECT id FROM myTbl WHERE POSITION('11' IN code) <> 0
This will work with a 2 digit number like '11' as it will return a value that is <> 0 if it finds a match. But it will fail when searching for say '3' because rows with 'id' 2 and 3 both will be returned.
Here is link that talks about the POSITION function in REDSHIFT.
Any other approach that will solve this problem?
you can get the count of this string
SELECT id FROM myTbl WHERE regexp_count(user_action, '[11]') > 0
I think we can use regexp_substr() as follow.
select tb .id from myTbl tb where '11' in (
select regexp_substr( (select code from myTbl where id=tb.id),'[^,]+', 1, LEVEL) from dual
connect by regexp_substr((select code from myTbl where id=tb.id) , '[^,]+', 1, LEVEL) is not null);
just try this.
Use split_part() function
SELECT distinct id
FROM myTbl
WHERE '11' in ( split_part( code||',' , ',', 1 ),
split_part( code||',' , ',', 2 ),
split_part( code||',' , ',', 3 ) )
This is a very, very bad data model. You should be storing this information in a junction/association table, with one row per value.
But, if you have no choice, you can use like:
SELECT id
FROM myTbl
WHERE ',' || code || ',' LIKE '%,11,%';
In H2 Database when i have applied order by on varchar column Numbers are coming first then Alphabets. But need to come Alphabets first then Numbers.
I have tried with
ORDER BY IF(name RLIKE '^[a-z]', 1, 2), name
but getting error like If condition is not available in H2.
My Column Data is Like
A
1-A
3
M
2-B
5
B-2
it should come like
A
B-2
M
1-A
2-B
3
5
try this out
SELECT MYCOLUMN FROM MYTABLE ORDER BY REGEXP_REPLACE (MYCOLUMN,'(*)(\d)(*)','}\2') , MYCOLUMN
One thing can be done is by altering the ASCII in order by clause.
WITH tab
AS (SELECT 'A' col FROM DUAL
UNION ALL
SELECT '1-A' FROM DUAL
UNION ALL
SELECT '3' FROM DUAL
UNION ALL
SELECT 'M' FROM DUAL
UNION ALL
SELECT '2-B' FROM DUAL
UNION ALL
SELECT '5' FROM DUAL
UNION ALL
SELECT 'B-2' FROM DUAL)
SELECT col
FROM tab
ORDER BY CASE WHEN SUBSTR (col, 1, 1) < CHR (58) THEN CHR (177) || col ELSE col END;
I have Used CHR(58) as ASCII value of numbers end at 57. and CHR(177) is used as this is the maximum in the ASCII table.
FYR : ASCII table
Given the example dataset, I'm not sure if you need further logic than this- so I'll refrain from making further assumptions:
DECLARE #temp TABLE (myval char(3))
INSERT INTO #temp VALUES
('A'), ('1-A'), ('3'), ('M'), ('2-B'), ('5'), ('B-2')
SELECT myval
FROM #temp
ORDER BY CASE WHEN LEFT(myval, 1) LIKE '[a-Z]'
THEN 1
ELSE 2
END
,LEFT(myval, 1)
Gives output:
myval
A
B-2
M
1-A
2-B
3
5
I have a Table - Product In Oracle, wherein p_spc_cat_id is stored as comma separated values.
p_id p_name p_desc p_spc_cat_id
1 AA AAAA 26,119,27,15,18
2 BB BBBB 0,0,27,56,57,4
3 BB CCCC 26,0,0,15,3,8
4 CC DDDD 26,0,27,7,14,10
5 CC EEEE 26,119,0,48,75
Now I want to search p_name which have p_spc_cat_id in '26,119,7' And this search value are not fixed it will some time '7,27,8'. The search text combination change every time
my query is:
select p_id,p_name from product where p_spc_cat_id in('26,119,7');
when i execute this query that time i can't find any result
I am little late in answering however i hope that i understood the question correctly.
Read further if: you have a table storing records like
1. 10,20,30,40
2. 50,40,20,70
3. 80,60,30,40
And a search string like '10,60', in which cases it should return rows 1 & 3.
Please try below, it worked for my small table & data.
create table Temp_Table_Name (some_id number(6), Ab varchar2(100))
insert into Temp_Table_Name values (1,'112,120')
insert into Temp_Table_Name values (2,'7,8,100,26')
Firstly lets breakdown the logic:
The table contains comma separated data in one of the columns[Column AB].
We have a comma separated string which we need to search individually in that string column. ['26,119,7,18'-X_STRING]
ID column is primary key in the table.
1.) Lets multiple each record in the table x times where x is the count of comma separated values in the search string [X_STRING]. We can use below query to create the cartesian join sub-query table.
Select Rownum Sequencer,'26,119,7,18' X_STRING
from dual
CONNECT BY ROWNUM <= (LENGTH( '26,119,7,18') - LENGTH(REPLACE( '26,119,7,18',',',''))) + 1
Small note: Calculating count of comma separated values =
Length of string - length of string without ',' + 1 [add one for last value]
2.) Create a function PARSING_STRING such that PARSING_STRING(string,position). So If i pass:
PARSING_STRING('26,119,7,18',3) it should return 7.
CREATE OR REPLACE Function PARSING_STRING
(String_Inside IN Varchar2, Position_No IN Number)
Return Varchar2 Is
OurEnd Number; Beginn Number;
Begin
If Position_No < 1 Then
Return Null;
End If;
OurEnd := Instr(String_Inside, ',', 1, Position_No);
If OurEnd = 0 Then
OurEnd := Length(String_Inside) + 1;
End If;
If Position_No = 1 Then
Beginn := 1;
Else
Beginn := Instr(String_Inside, ',', 1, Position_No-1) + 1;
End If;
Return Substr(String_Inside, Beginn, OurEnd-Beginn);
End;
/
3.) Main query, with the join to multiply records.:
select t1.*,PARSING_STRING(X_STRING,Sequencer)
from Temp_Table_Name t1,
(Select Rownum Sequencer,'26,119,7,18' X_STRING from dual
CONNECT BY ROWNUM <= (Select (LENGTH( '26,119,7,18') - LENGTH(REPLACE(
'26,119,7,18',',',''))) + 1 from dual)) t2
Please note that with each multiplied record we are getting 1 particular position value from the comma separated string.
4.) Finalizing the where condition:
Where
/* For when the value is in the middle of the strint [,value,] */
AB like '%,'||PARSING_STRING(X_STRING,Sequencer)||',%'
OR
/* For when the value is in the start of the string [value,]
parsing the first position comma separated value to match*/
PARSING_STRING(AB,1) = PARSING_STRING(X_STRING,Sequencer)
OR
/* For when the value is in the end of the string [,value]
parsing the last position comma separated value to match*/
PARSING_STRING(AB,(LENGTH(AB) - LENGTH(REPLACE(AB,',',''))) + 1) =
PARSING_STRING(X_STRING,Sequencer)
5.) Using distinct in the query to get unique ID's
[Final Query:Combination of all logic stated above: 1 Query to find them all]
select distinct Some_ID
from Temp_Table_Name t1,
(Select Rownum Sequencer,'26,119,7,18' X_STRING from dual
CONNECT BY ROWNUM <= (Select (LENGTH( '26,119,7,18') - LENGTH(REPLACE( '26,119,7,18',',',''))) + 1 from dual)) t2
Where
AB like '%,'||PARSING_STRING(X_STRING,Sequencer)||',%'
OR
PARSING_STRING(AB,1) = PARSING_STRING(X_STRING,Sequencer)
OR
PARSING_STRING(AB,(LENGTH(AB) - LENGTH(REPLACE(AB,',',''))) + 1) = PARSING_STRING(X_STRING,Sequencer)
You can use like to find it:
select p_id,p_name from product where p_spc_cat_id like '%26,119%'
or p_spc_cat_id like '%119,26%' or p_spc_cat_id like '%119,%,26%' or p_spc_cat_id like '%26,%,119%';
Use the Oracle function instr() to achieve what you want. In your case that would be:
SELECT p_name
FROM product
WHERE instr(p_spc_cat_id, '26,119') <> 0;
Oracle Doc for INSTR
If the string which you are searching will always have 3 values (i.e. 2 commas present) then you can use below approach.
where p_spc_cat_id like regexp_substr('your_search_string, '[^,]+', 1, 1)
or p_spc_cat_id like regexp_substr('your_search_string', '[^,]+', 1, 2)
or p_spc_cat_id like regexp_substr('your_search_string', '[^,]+', 1, 3)
If you cant predict how many values will be there in your search string
(rather how many commas) in that case you may need to generate dynamic query.
Unfortunately sql fiddle is not working currently so could not test this code.
SELECT p_id,p_name
FROM product
WHERE p_spc_cat_id
LIKE '%'||'&i_str'||'%'`
where i_str is 26,119,7 or 7,27,8
This solution uses CTE's. "product" builds the main table. "product_split" turns products into rows so each element in p_spc_cat_id is in it's own row. Lastly, product_split is searched for each value in the string '26,119,7' which is turned into rows by the connect by.
with product(p_id, p_name, p_desc, p_spc_cat_id) as (
select 1, 'AA', 'AAAA', '26,119,27,15,18' from dual union all
select 2, 'BB', 'BBBB', '0,0,27,56,57,4' from dual union all
select 3, 'BB', 'CCCC', '26,0,0,15,3,8' from dual union all
select 4, 'CC', 'DDDD', '26,0,27,7,14,10' from dual union all
select 5, 'CC', 'EEEE', '26,119,0,48,75' from dual
),
product_split(p_id, p_name, p_spc_cat_id) as (
select p_id, p_name,
regexp_substr(p_spc_cat_id, '(.*?)(,|$)', 1, level, NULL, 1)
from product
connect by level <= regexp_count(p_spc_cat_id, ',')+1
and prior p_id = p_id
and prior sys_guid() is not null
)
-- select * from product_split;
select distinct p_id, p_name
from product_split
where p_spc_cat_id in(
select regexp_substr('26,119,7', '(.*?)(,|$)', 1, level, NULL, 1) from dual
connect by level <= regexp_count('26,119,7', ',') + 1
)
order by p_id;
P_ID P_
---------- --
1 AA
3 BB
4 CC
5 CC
SQL>
Is there a way to convert the first letter uppercase in Oracle SQl without using the Initcap Function?
I have the problem, that I must work with the DISTINCT keyword in SQL clause and the Initcap function doesn´t work.
Heres is my SQL example:
select distinct p.nr, initcap(p.firstname), initcap(p.lastname), ill.describtion
from patient p left join illness ill
on p.id = ill.id
where p.deleted = 0
order by p.lastname, p.firstname;
I get this error message: ORA-01791: not a SELECTed expression
When SELECT DISTINCT, you can't ORDER BY columns that aren't selected. Use column aliases instead, as:
select distinct p.nr, initcap(p.firstname) fname, initcap(p.lastname) lname, ill.describtion
from patient p left join illness ill
on p.id = ill.id
where p.deleted = 0
order by lname, fname
this would do it, but i think you need to post your query as there may be a better solution
select upper(substr(<column>,1,1)) || substr(<column>,2,9999) from dual
To change string to String, you can use this:
SELECT
regexp_replace ('string', '[a-z]', upper (substr ('string', 1, 1)), 1, 1, 'i')
FROM dual;
This assumes that the first letter is the one you want to convert. It your input text starts with a number, such as 2 strings then it won't change it to 2 Strings.
You can also use the column number instead of the name or alias:
select distinct p.nr, initcap(p.firstname), initcap(p.lastname), ill.describtion
from patient p left join illness ill
on p.id = ill.id
where p.deleted = 0
order by 3, 2;
WITH inData AS
(
SELECT 'word1, wORD2, word3, woRD4, worD5, word6' str FROM dual
),
inRows as
(
SELECT 1 as tId, LEVEL as rId, trim(regexp_substr(str, '([A-Za-z0-9])+', 1, LEVEL)) as str
FROM inData
CONNECT BY instr(str, ',', 1, LEVEL - 1) > 0
)
SELECT tId, LISTAGG( upper(substr(str, 1, 1)) || substr(str, 2) , '') WITHIN GROUP (ORDER BY rId) AS camelCase
FROM inRows
GROUP BY tId;
I have procedure that has parameter that takes comma separated value ,
so when I enter Parameter = '1,0,1'
I want to return ' one , Zero , One' ?
You could use REPLACE function.
For example,
SQL> WITH DATA(str) AS(
2 SELECT '1,0,1' FROM dual
3 )
4 SELECT str,
5 REPLACE(REPLACE(str, '0', 'Zero'), '1', 'One') new_str
6 FROM DATA;
STR NEW_STR
----- ------------------------------------------------------------
1,0,1 One,Zero,One
SQL>
This query splits list into into numbers, converts numbers into words and joins them again together with function listagg:
with t1 as (select '7, 0, 11, 132' col from dual),
t2 as (select level lvl,to_number(regexp_substr(col,'[^,]+', 1, level)) col
from t1 connect by regexp_substr(col, '[^,]+', 1, level) is not null)
select listagg(case
when col=0 then 'zero'
else to_char(to_date(col,'j'), 'jsp')
end,
', ') within group (order by lvl) col
from t2
Output:
COL
-------------------------------------------
seven, zero, eleven, one hundred thirty-two
The limitation of this solution is that values range is between 0 and 5373484 (because 5373484 is maximum value for function to_date).
If you need higher values you can find hints in this article.