I have these 3 tables:
CREATE TABLE DimEmployee(EmployeeID INT)
CREATE TABLE DimDepartment(DepartmentID INT)
CREATE TABLE DimDocteur(PositionID INT)
INSERT INTO DimEmployee(EmployeeID) VALUES (1),(2),(3)
INSERT INTO DimDepartment(DepartmentID) VALUES (1),(5),(6)
INSERT INTO DimPosition(PositionID) VALUES (7),(8),(9)
I want to randomly join the 3 tables and get output like below : (example)
First execute:
EmployeeID DepartmentID PositionID RandomDate
1 4 7 2020-07-24 00:00:00.000
2 5 9 2020-11-25 00:00:00.000
Second execute:
EmployeeID DepartmentID PositionID RandomDate
1 4 7 2020-05-04 00:00:00.000
2 5 9 2020-10-30 00:00:00.000
If you want a random join :
SELECT DP.EmployeeID, Q.Department INTO #T1
FROM DimEmployee AS DP
CROSS APPLY (SELECT TOP 1 Dd.DepartmentID FROM DimDepartment AS DD
ORDER BY NEWID() ) AS Q
SELECT *
INTO #T2
FROM #T1 AS T
CROSS APPLY (SELECT TOP 1 DP.PositionID FROM DimPosition AS DP
ORDER BY NEWID() ) AS Q
Or if you want all possibilities :
SELECT
a.EmployeeID, b.DepartmentID, c.PositionID
FROM
DimEmployee AS a
CROSS JOIN
DimDepartment AS b
CROSS JOIN
DimPosition AS c
You need to row-number each table and join on row-number:
CREATE TABLE DimEmployee(EmployeeID INT)
CREATE TABLE DimDepartment(DepartmentID INT)
CREATE TABLE DimDocteur(PositionID INT)
SELECT
emp.EmployeeID,
dep.DepartmentID,
doc.PositionID,
DATEADD(day, (ABS(CHECKSUM(NEWID())) % 65530), 0) RandomDate
FROM (
SELECT *, ROW_NUMBER() OVER(ORDER BY (SELECT 1)) rn
FROM DimEmployee
) emp
JOIN (
SELECT *, ROW_NUMBER() OVER(ORDER BY (SELECT 1)) rn
FROM DimDepartment
) dep ON dep.rn = emp.rn
JOIN (
SELECT *, ROW_NUMBER() OVER(ORDER BY (SELECT 1)) rn
FROM DimDocteur
) doc ON doc.rn = emp.rn
You can also change the ORDER BY to ORDER BY NEWID() to get a more random ordering.
Related
If I have two tables:
id_table entry_table
-------- -----------
[Id] [entries]
1 a
2 b
3 c
4 d
5
Is there a way to select the results into another table where I get:
select_results
--------------
[Id] [entries]
1 a
2 b
3 c
I'm trying e.g.
Select top 3 * from id_table, entry_table
and vice versa, but that gives:
1 a
1 b
1 c
These two tables SHOULD have the same amount of entries but I'm using "top 3" at the minute to see if it's possible.
Maybe I need a cross join with a where clause?
you can use row_number() and then use join
select a.*,b.* from
(select *,row_number() over(order by Id) rn1
from id_table
) a
join
(select *,row_number() over(order by entries) rn1
from entry_table
) b on a.rn=b.rn1
Alternatively you can use row_number() window analytic function with top keyword as
select top 3
[Id], [entries]
from id_table i
join ( select row_number() over (order by [entries]) as row_id,
[entries]
from entry_table ) e
on i.[Id]=e.row_id;
Demo
This is in reference to below Question
Loop through each value to the seq num
But now Client want to see the data differently and started a new thread for this question.
below is the requirement.
This is the data .
ID seqNum DOS Service End Date
1 1 1/1/2017 1/15/2017
1 2 1/16/2017 1/16/2017
1 3 1/17/2017 1/21/2017
1 4 1/22/2017 2/13/2017
1 5 2/14/2017 3/21/2017
1 6 2/16/2017 3/21/2017
Expected outPut:
ID SeqNum DOSBeg DOSEnd
1 1 1/1/2017 1/30/2017
1 2 1/31/2017 3/1/2017
1 3 3/2/2017 3/31/2017
For each DOSBeg, add 29 and that is DOSEnd. then Add 1 to DOSEnd (1/31/2017) is new DOSBeg.
Now add 29 to (1/31/2017) and that is 3/1/2017 which is DOSEnd . Repeat this untill DOSend >=Max End Date i.e 3/21/2017.
Basically, we need episode of 29 days for each ID.
I tried with this code and it is giving me duplicates.
with cte as (
select ID, minDate as DOSBeg,dateadd(day,29,mindate) as DOSEnd
from #temp
union all
select ID,dateadd(day,1,DOSEnd) as DOSBeg,dateadd(day,29,dateadd(day,1,DOSEnd)) as DOSEnd
from cte
)
select ID,DOSBeg,DOSEnd
from cte
OPTION (MAXRECURSION 0)
Here mindate is Minimum DOS for this ID i.e. 1/1/2017
I came up with below logic and this is working fine for me. Is there any better way than this ?
declare #table table (id int, seqNum int identity(1,1), DOS date, ServiceEndDate date)
insert into #table
values
(1,'20170101','20170115'),
(1,'20170116','20170116'),
(1,'20170117','20170121'),
(1,'20170122','20170213'),
(1,'20170214','20170321'),
(1,'20170216','20170321'),
(2,'20170101','20170103'),
(2,'20170104','20170118')
select * into #temp from #table
--drop table #data
select distinct ID, cast(min(DOS) over (partition by ID) as date) as minDate
,row_Number() over (partition by ID order by ID, DOS) as SeqNum,
DOS,
max(ServiceEndDate) over (partition by ID)as maxDate
into #data
from #temp
--drop table #StartDateLogic
with cte as
(select ID,mindate as startdate,maxdate
from #data
union all
select ID,dateadd(day,30,startdate) as startdate,maxdate
from cte
where maxdate >= dateadd(day,30,startdate))
select distinct ID,startdate
into #StartDateLogic
from cte
OPTION (MAXRECURSION 0)
--final Result set
select ID
,ROW_NUMBER() over (Partition by ID order by ID,StartDate) as SeqNum
,StartDate
,dateadd(day,29,startdate) as EndDate
from #StartDateLogic
You were on the right track wit the recursive cte, but you forgot the anchor.
declare #table table (id int, seqNum int identity(1,1), DOS date, ServiceEndDate date)
insert into #table
values
(1,'20170101','20170115'),
(1,'20170116','20170116'),
(1,'20170117','20170121'),
(1,'20170122','20170213'),
(1,'20170214','20170321'),
(1,'20170216','20170321'),
(2,'20170101','20170103'),
(2,'20170104','20170118')
;with dates as(
select top 1 with ties id, seqnum, DOSBeg = DOS, DOSEnd = dateadd(day,29,DOS)
from #table
order by row_number() over (partition by id order by seqnum)
union all
select t.id, t.seqNum, DOSBeg = dateadd(day,1,d.DOSEnd), DOSEnd = dateadd(day,29,dateadd(day,1,d.DOSEnd))
from dates d
inner join #table t on
d.id = t.id and t.seqNum = d.seqNum + 1
)
select *
from dates d
where d.DOSEnd <= (select max(dateadd(month,1,ServiceEndDate)) from #table where id = d.id)
order by id, seqNum
Looking for help with a query using SQL 2008 R2... I have a table with client and date fields. Most clients have a record for most dates, however some don't.
For example I have this data:
CLIENTID DT
1 5/1/14
1 5/2/14
2 5/3/14
3 5/1/14
3 5/2/14
I can find the missing dates for each CLIENTID by creating a temp table with all possible dates for the period and then joining that to each CLIENTID and DT and only selecting where there is a NULL.
This is what I can get easily for the date range 5/1/14 to 5/4/14:
CLIENTID DTMISSED
1 5/3/14
1 5/4/14
2 5/1/14
2 5/2/14
2 5/4/14
3 5/3/14
3 5/4/14
However I want to group each consecutive missed period together and get the beginning of each period and the length.
For example, if I use the date range 5/1/14 to 5/4/14 I'd like to get:
CLIENTID DTSTART MISSED
1 5/3/14 2
2 5/1/14 2
2 5/4/14 1
3 5/3/14 2
Thanks for helping!
It's fascinating how more elegantly and also mere efficiently this kind of problems can be solved in 2012.
First, the tables:
create table #t (CLIENTID int, DT date)
go
insert #t values
(1, '5/1/14'),
(1, '5/2/14'),
(2, '5/3/14'),
(3, '5/1/14'),
(3, '5/2/14')
go
create table #calendar (dt date)
go
insert #calendar values ('5/1/14'),('5/2/14'),('5/3/14'),('5/4/14')
go
Here's the 2008 solution:
;with x as (
select *, row_number() over(order by clientid, dt) as rn
from #calendar c
cross join (select distinct clientid from #t) x
where not exists (select * from #t where c.dt=#t.dt and x.clientid=#t.clientid)
),
y as (
select x1.*, x2.dt as x2_dt, x2.clientid as x2_clientid
from x x1
left join x x2 on x1.clientid=x2.clientid and x1.dt=dateadd(day,1,x2.dt)
),
z as (
select *, (select sum(case when x2_dt is null then 1 else 0 end) from y y2 where y2.rn<=y.rn) as grp
from y
)
select clientid, min(dt), count(*)
from z
group by clientid, grp
order by clientid
Compare it to 2012:
;with x as (
select *, row_number() over(order by dt) as rn
from #calendar c
cross join (select distinct clientid from #t) x
where not exists (select * from #t where c.dt=#t.dt and x.clientid=#t.clientid)
),
y as (
select x1.*, sum(case when x2.dt is null then 1 else 0 end) over(order by x1.clientid,x1.dt) as grp
from x x1
left join x x2 on x1.clientid=x2.clientid and x1.dt=dateadd(day,1,x2.dt)
)
select clientid, min(dt), count(*)
from y
group by clientid, grp
order by clientid
I have a simple table with some dummy data setup like:
|id|user|value|
---------------
1 John 2
2 Ted 1
3 John 4
4 Ted 2
I can select a running total by executing the following sql(MSSQL 2008) statement:
SELECT a.id, a.user, a.value, SUM(b.value) AS total
FROM table a INNER JOIN table b
ON a.id >= b.id
AND a.user = b.user
GROUP BY a.id, a.user, a.value
ORDER BY a.id
This will give me results like:
|id|user|value|total|
---------------------
1 John 2 2
3 John 4 6
2 Ted 1 1
4 Ted 2 3
Now is it possible to only retrieve the most recent rows for each user? So the result would be:
|id|user|value|total|
---------------------
3 John 4 6
4 Ted 2 3
Am I going about this the right way? any suggestions or a new path to follow would be great!
No join is needed, you can speed up the query this way:
select id, [user], value, total
from
(
select id, [user], value,
row_number() over (partition by [user] order by id desc) rn,
sum(value) over (partition by [user]) total
from users
) a
where rn = 1
try this:
;with cte as
(SELECT a.id, a.[user], a.value, SUM(b.value) AS total
FROM users a INNER JOIN users b
ON a.id >= b.id
AND a.[user] = b.[user]
GROUP BY a.id, a.[user], a.value
),
cte1 as (select *,ROW_NUMBER() over (partition by [user]
order by total desc) as row_num
from cte)
select id,[user],value,total from cte1 where row_num=1
SQL Fiddle Demo
add where statement:
select * from
(
your select statement
) t
where t.id in (select max(id) from table group by user)
also you can use this query:
SELECT a.id, a.user, a.value,
(select max(b.value) from table b where b.user=a.user) AS total
FROM table a
where a.id in (select max(id) from table group by user)
ORDER BY a.id
Adding a right join would perform better than nested select.
Or even simpler:
SELECT MAX(id), [user], MAX(value), SUM(value)
FROM table
GROUP BY [user]
Compatible with SQL Server 2008 or later
DECLARE #AnotherTbl TABLE
(
id INT
, somedate DATE
, somevalue DECIMAL(18, 4)
, runningtotal DECIMAL(18, 4)
)
INSERT INTO #AnotherTbl
(
id
, somedate
, somevalue
, runningtotal
)
SELECT LEDGER_ID
, LL.LEDGER_DocDate
, LL.LEDGER_Amount
, NULL
FROM ACC_Ledger LL
ORDER BY LL.LEDGER_DocDate
DECLARE #RunningTotal DECIMAL(18, 4)
SET #RunningTotal = 0
UPDATE #AnotherTbl
SET #RunningTotal=runningtotal = #RunningTotal + somevalue
FROM #AnotherTbl
SELECT *
FROM #AnotherTbl
Can I limit rows by sum of a column in a SQL Server database?
For example:
Type | Time (in minutes)
-------------------------
A | 50
B | 10
C | 30
D | 20
E | 70
...
And I want to limit the selection by sum of time. For example maximum of 100 minutes. Table must look like this:
Type | Time (in minutes)
-------------------------
A | 50
B | 10
C | 30
Any ideas? Thanks.
DECLARE #T TABLE
(
[Type] CHAR(1) PRIMARY KEY,
[Time] INT
)
INSERT INTO #T
SELECT 'A',50 UNION ALL
SELECT 'B',10 UNION ALL
SELECT 'C',30 UNION ALL
SELECT 'D',20 UNION ALL
SELECT 'E',70;
WITH RecursiveCTE
AS (
SELECT TOP 1 [Type], [Time], CAST([Time] AS BIGINT) AS Total
FROM #T
ORDER BY [Type]
UNION ALL
SELECT R.[Type], R.[Time], R.Total
FROM (
SELECT T.*,
T.[Time] + Total AS Total,
rn = ROW_NUMBER() OVER (ORDER BY T.[Type])
FROM #T T
JOIN RecursiveCTE R
ON R.[Type] < T.[Type]
) R
WHERE R.rn = 1 AND Total <= 100
)
SELECT [Type], [Time], Total
FROM RecursiveCTE
OPTION (MAXRECURSION 0);
Or if your table is small
SELECT t1.[Type],
t1.[Time],
SUM(t2.[Time])
FROM #T t1
JOIN #T t2
ON t2.[Type] <= t1.[Type]
GROUP BY t1.[Type],t1.[Time]
HAVING SUM(t2.[Time]) <=100