I want to select a date that gives me 18 months from the current date, but I am not getting exactly 18 months.
Before Running the query, min and max dates are.
MIN Date: 02/22/2018
MAX Date: 03/26/2021
Query
SELECT DATEADD(dd,-548,cast(GETDATE() as datetime));
Above query returns the min date as 10/15/2019. So from 10/15/2019 to 03/26/2021 is 17 months and 12 days. While my expectation is to get 10/05/2019 from this query so that I get exactly 18 months or 548 days.
SELECT DATEADD(month,-18,cast(GETDATE() as datetime))
The reason I wasn't getting a correct date was because the query looks for current date GETDATE() and in the database, I don't have data for the current date due to which I was encountering differences. I exported data from STAGE to DEV environment and now I am getting correct date.
Related
I apologize, I am new at SQL. I am using BigQuery. I have a field called "last_engaged_date", this field is a datetime value (2021-12-12 00:00:00 UTC). I am trying to perform a count on the number of records that were "engaged" 12 months ago, 18 months ago, and 24 months ago based on this field. At first, to make it simple for myself, I was just trying to get a count of the number of records per year, something like:
Select count(id), year(last_engaged_date) as last_engaged_year
from xyz
group by last_engaged_year
order by last_engaged_year asc
I know that there are a lot of things wrong with this query but primarily, BQ says that "Year" is not a valid function? Either way, What I really need is something like:
Date() - last_engaged_date = int(# of months)
count if <= 12 months as "12_months_count" (# of records where now - last engaged date is less than or equal to 12 months)
count if <= 18 months as "18_months_count"
count if <= 24 months as "24_months_count"
So that I have a count of how many records for each last_engaged_date period there are.
I hope this makes sense. Thank you so much for any ideas
[How to] Return the number of months between now and datetime value [in BigQuery] SQL
The simples way is just to use DATE_DIFF function as in below example
date_diff(current_date(), date(last_engaged_date), month)
I have a query which uses needs to know how many days passed since 1st of January in the current year.
Which means that if the query runs for example in:
2nd Jan 2017 than it should return 2 (as 2 days passed since 1st Jan
2017).
10th Feb 2016 than it should return 41 (as 41 days passed since 1st
Jan 2016).
basically it needs to take Current Year from Curent Date and count the days since 1/1/(Year).
i have the current year with: SELECT EXTRACT(year FROM CURRENT_DATE);
I created the 1st of Jan with:
select (SELECT EXTRACT(year FROM CURRENT_DATE)::text || '-01-01')::date
How do I get the difference from this date to Current_Date?
Basically this question can be Given two dates, how many days between them?
Something like age(timestamp '2016-01-01', timestamp '2016-06-15') isn't good because I need the result only in days. while age gives in years,months and days.
An easier approach may be to extract the day of year ("doy") field from the date:
db=> SELECT EXTRACT(DOY FROM CURRENT_DATE);
date_part
-----------
41
And if you need it as a number, you could just cast it:
db=> SELECT EXTRACT(DOY FROM CURRENT_DATE)::int;
date_part
-----------
41
Note: The result 41 was produced by running the query today, February 9th.
Given two dates, how many days between them
Just subtract one from the other.
In your case you could just round the current_date to the start of the year and subtract that from the current date:
select current_date - date_trunc('year', current_date)::date
The ::date cast is necessary to get the result as an integer, otherwise the result will be an interval.
Another solution is to use DATEDIFF
SELECT DATE_PART('day', now()::timestamp - '2016-01-01 00:00:00'::timestamp);
I'm executing the next query in sql server 2012.
select *
from table
where date > convert(date, '2015/02/12')
order by date asc
but I'm getting the next set:
2015-02-12 06:40:42.000
2015-02-12 06:45:44.000
2015-02-12 06:48:15.000
2015-02-12 07:06:28.000
2015-02-12 07:26:46.000
...
I can fix this by changing the date to '2015/02/13', but I have the doubt about this behavior, why am I getting dates from feb 12 when I am specifying that I need only later dates ?. I also tried using cast('2015/02/12' as date), but I could not have the answer I was looking for
Because dates without times are intepreted as 12:00 midnight on that date. If you want only dates after February 12, 2015, then select all dates greater than or equal to February 13, 2015 (which again will be interpreted as midnight on February 13th).
select *
from table
where date >= convert(date, '2015/02/13')
order by date asc
why am I getting dates from feb 12 when I am specifying that I need only later dates ?
You're not specifying that you need only dates after Feb 12. You're asking for every row in which the value in the "date" column is greater than '2015-02-12'.
The value '2015-02-12 06:40:42.000' is greater than '2015-02-12'.
When comparing the date 2015/02/12 with your datetime data, this will implicitly compare the converted date 2015-02-12 00:00:000, the date at the beginning of the day with all of your data in column date.
But you are actually comparing datetime data, which has a time part as well, which gets compared.
And because you're comparing the beginning of the day (2015-02-12 00:00:000) with a value which is after it, for example 2015-02-12 06:40:42, all of the dates from will be displayed, because 6:40 AM is after (greater than) 0:00 AM.
Try this:
SELECT *
FROM TABLE
WHERE DATE >= DATEADD(SECOND, -1, '2015/02/13')
jarlh is right, though I'll clarify a little. Each of the "dates" you show above fall after 12:00 midnight starting 2015-02-12. They are actually timestamps.
If you don't want to see anything for the day specified in the filter, you add a day and use the greater-than-or-equal-to (>=) operator.
SELECT *
FROM table
WHERE (date >= DATEADD(d, 1, CONVERT(date, '2015/02/12')))
ORDER BY date ASC
I am trying to get the last of month, and in order to that i have written the following, to calculate the no. of days between today and the last date.
select datediff(DAY,GETDATE(),dateadd(m,1,getdate()))-GETDATE()
the bold part gives me the no. of days between today and a month from today, say 30 or 31. and then I am subtracting today's date from 30 or 31, which is " -getdate() "
The output for the above query is
1786-06-06 11:44:30.540
Could you please explain what is happening in the query? I am not looking for a solution, I would like to know how is SQL-Server interpreting the query.
Thanks. :)
The bold part of the expressions does not return a date, it returns a number of days:
31
Convert that to a datetime:
SELECT CONVERT(DATETIME, 31);
This is 31 days after day 0 (1900-01-01):
1900-02-01
Now, subtract GETDATE() as an integer (41512 days after day 0):
SELECT 31 - 41512 = -41481
Now add -41481 days to day 0:
SELECT DATEADD(DAY, -41481, 0);
-- or
SELECT DATEADD(DAY, -41481, '19000101');
Or:
SELECT CONVERT(DATETIME, 31 - CONVERT(INT, GETDATE()));
Now, I strongly recommend a couple of things:
Don't use implicit date math. #date_var_or_col - 1 for example fails with new data types like DATE and DATETIME2.
Don't use shorthand like m. If you mean MONTH, just take the massive productivity hit and type out MONTH. To see why, tell me if this provides the results you expect:
SELECT DATEPART(y, GETDATE()), DATEPART(w, GETDATE());
I am subtracting today's date from 30 or 31, which is " -getdate() "
Sounds like you understand exactly what is happening, but maybe don't understand the results.
You are implicitly converting GETDATE() to a number, which represents the number of days (and fractional days) since 1/1/1900 12:00:00 AM
When you "subtract" GETDATE() (41,511 as of 8/27/2013) from 30 or 31 you get an answer of -41,480, or 41,480 days before 1/1/1900, which would be about 6/6/1786 (plus or minus a few hours for the fractional part).
I have an a table with two columns birthday and anniversary. I want to get alerts about birthdays and anniversaries between a 7 day period of time but, that should not include year (obviously if I include year, it would always be less than the current date). I want to get the alerts 7 days in advance.
That is, the query should compare the birthday and anniversary with the current date and return a list if their birthday or anniversary falls between 7 days of the same month so that it alerts me in advance about the upcoming birthdays and anniversaries.
Subtract the year difference from now to the requested date and then use datediff to calculate the date difference of the result with the requested date.
SELECT *
FROM Table
WHERE DATEDIFF(dd,DATEADD(yyyy,-DATEDIFF(yyyy,Birthday,GETDATE()),GETDATE()),Birthday) BETWEEN 0 AND 7
OR DATEDIFF(dd,DATEADD(yyyy,-DATEDIFF(yyyy,Anniversary,GETDATE()),GETDATE()),Anniversary) BETWEEN 0 AND 7
Try This
SELECT Name,max(Table .birthdate)
FROM Table group by Table .Name having (datediff(day,max(birthdate),getutcdate())>7 and datediff(day,max(birthdate),getutcdate())<8)