I have an a table with two columns birthday and anniversary. I want to get alerts about birthdays and anniversaries between a 7 day period of time but, that should not include year (obviously if I include year, it would always be less than the current date). I want to get the alerts 7 days in advance.
That is, the query should compare the birthday and anniversary with the current date and return a list if their birthday or anniversary falls between 7 days of the same month so that it alerts me in advance about the upcoming birthdays and anniversaries.
Subtract the year difference from now to the requested date and then use datediff to calculate the date difference of the result with the requested date.
SELECT *
FROM Table
WHERE DATEDIFF(dd,DATEADD(yyyy,-DATEDIFF(yyyy,Birthday,GETDATE()),GETDATE()),Birthday) BETWEEN 0 AND 7
OR DATEDIFF(dd,DATEADD(yyyy,-DATEDIFF(yyyy,Anniversary,GETDATE()),GETDATE()),Anniversary) BETWEEN 0 AND 7
Try This
SELECT Name,max(Table .birthdate)
FROM Table group by Table .Name having (datediff(day,max(birthdate),getutcdate())>7 and datediff(day,max(birthdate),getutcdate())<8)
Related
My table has the following columns:
SerialNo
ProductNo
WarrantyBeginDt
WarrantyEndDT
I would like to get a monthly in warranty count looking back about 6 months. I know how to get a month by specifying in the where clause. Would like to have a query that generates the last 6 months with out having to specify the month in the where clause.
SELECT count(*)
FROM Supplemental_Warranty
WHERE WarrantyBeginDt <= '6-15-2022' AND WarrantyEndDt >= '6-15-2022'
How could I create a query that looks back 6 months from the current date?
UPDATED to add group by month for 6 months to get count by month.
This should give you 6 months worth of data using system date (subtract 6 months from today) and end date/time is now so you dont have to specify specific dates, just using date add functionality to subtract 6 months from stating date.
SELECT count(*), MONTH(WarrantyBeginDt) AS CountPerMonth
FROM Supplemental_Warranty
WHERE WarrantyBeginDt BETWEEN DATEADD(MONTH, -6, GETDATE()) AND GETDATE()
--if you have any flags or other logic to identify if it is underwarranty or not
AND IsUnderWarranty = 1
GROUP BY MONTH(WarrantyBeginDt)
NOTE: Not tested but this should do it depending on your SQL technology.
So I want to make a query to show me if a certain calendar week has all 7 Day.
It would be okay if it just returns the numbers 1-7.
The table that I have contains articles of the 3 month of 2020 but even so the first week just contains Wednesday to Sunday it still counts it as a calendar week.
With that select I would make pl/sql Script to check it and if yes something happens.
This is an example of the Table:
Date Articel_Id
14.10.2020 78
15.10.2020 80
16.10.2020 96
17.10.2020 100
18.10.2020 99
Can I Use to_char() to check if Calendar Week has all 7 Days ?
If yes, how ?
The challenging is actually defining the weeks. If you want to define them using the ISO standard, then aggregate:
select to_char(date, 'IYYYY-IW') as yyyyww,
count(distinct trunc(date)) as num_days
from t
group by to_char(date, 'IYYYY-IW')
order by yyyyww;
This counts the number of days per week. I'm not sure if you want to filter, have a flag, or what the result set should look like. For filtering, using a having clause, such as having count(distinct trunc(date)) = 7.
When the client select start date ,end date and group by : weekly is there any way to force to show in the week column as first day of the week. For example if I choose 10/1/2019 as start date and 10/2/2019 as end date and group by : weekly then the week column should show 9/29/2019
Right now the expression I am using is
= Switch(Parameters!GroupbyTime=“4”, CDate(Fields!groupweek.value).ToString(“Mm/Dd/yyyy”)
But it’s giving error can somebody help me ??
You can subtract the number of the weekday from the date plus one day for the first day of the week.
=DATEADD("D", 1 - WEEKDAY(Parameters!START.Value), Parameters!START.Value)
I have a date in sql which will always fall on a Monday and I'm subtracting 13 weeks to get a weekly report. I am trying to get the same 13 week report but for last year's figures as well.
At the moment, I'm using the following:
calendar_date >= TRUNC(sysdate) - 91
which is working fine.
I need the same for last year.
However, when I split this into calendar weeks, there will also be a partially complete week as it will include 1 or 2 days from the previous week. I need only whole weeks.
e.g. the dates that will be returned for last year will be 14-Feb-2015 to 16-May-2015. I need it to start on the Monday and be 16-Feb-2015. This will change each week as I am only interested in complete weeks...
I would do this:
Get the date by substracting 91 days as you're already doing.
Get the number of the day of the week with TO_CHAR(DATE,'d')
Add the number of days until the next monday to the date.
Something like this:
SELECT TO_DATE(TO_DATE('16/05/2015','DD/MM/YYYY'),'DD/MM/YYYY')-91 + MOD(7 - TO_NUMBER(TO_CHAR(TO_DATE(TO_DATE('16/05/2015','DD/MM/YYYY'),'DD/MM/RRRR')-91,'d'))+1,7) d
FROM dual
next_day - returns date of first weekday named by char.
with dates as (select to_date('16/05/2015','DD/MM/YYYY') d from dual)
select
trunc(next_day( trunc(d-91) - interval '1' second,'MONDAY'))
from dates;
I want to get next monday from calculated date. In situation when calculated date is monday i have to move back to previous week ( -1 second).
I want to perform an operation in crystal report.
I have a db table contains a date column.
I want to filter and get the rows having data created in last week(last sunday to last saturday = 7 days).For example if today is 24th August Wednesday, then I need data from 14th August(Sunday) to 20th August(Saturday).
Basically I want to find 2 dates and filter the date column.
Date1 = Date(CurrentDate)-Day(7 + WeekDayinNum(CurrentDate)) ; (Ex:for my example it will be 10)
Date2 = Date(CurrentDate)-Day(WeekDayinNum(CurrentDate))
I do not know the Date APIs properly,can anybody help me in this.
This is a common enough date range that CR provides it for you. In your record selection formula, you can just add {table.date} in LastFullWeek
From CR, "LastFullWeek specifies a range of Date values that includes all dates from Sunday to Saturday of the previous week."
Add this to the record selection formula:
{table.date_field} IN Last7Days
If today is Sunday(1) you want rows that are between 7 and 1 days old,
If today is Monday(2) you want rows that are between 8 and 2 days old,
If today is Tuesday(3) you want rows that are between 9 and 3 days old,
etc.
SELECT *
FROM `tablename`
WHERE `somedatefield` >= DATE_SUB(NOW(),INTERVAL (DAYOFWEEK(NOW()) + 6) DAY)
AND `somedatefield` <= DATE_SUB(NOW(),INTERVAL (DAYOFWEEK(NOW())) DAY)