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I'm trying to write a SP that will allow users to search on multiple name strings, but supports LIKE functionality. For example, the user's input might be a string 'Scorsese, Kaurismaki, Tarkovsky'. I use a split function to turn that string into a table var, with one column, as follows:
part
------
Scorsese
Kaurismaki
Tarkovsky
Then, normally I would return any values from my table matching any of these values in my table var, with an IN statement:
select * from myTable where lastName IN (select * from #myTableVar)
However, this only returns exact matches, and I need to return partial matches. I'm looking for something like this, but that would actually compile:
select * from myTable where CONTAINS(lastName, select * from #myTableVar)
I've found other questions where it's made clear that you can't combine LIKE and IN, and it's recommended to use CONTAINS. My specific question is, is it possible to combine CONTAINS with a table list of values, as above? If so, what would that syntax look like? If not, any other workarounds to achieve my goal?
I'm using SQL Server 2016, if it makes any difference.
You can use EXISTS
SELECT * FROM myTable M
WHERE
EXISTS( SELECT * FROM #myTableVar V WHERE M.lastName like '%'+ V.part +'%' )
Can your parser built the entire statement? Will that get you what you want?
select *
from myTable
where CONTAINS
(lastName,
'"Scorsese" OR "Kaurismaki" OR "Tarkovsky"'
)
This can be done using CHARINDEX function combined with EXISTS:
select *
from myTable mt
where exists(select 1 from #myTableVar
where charindex(mt.lastName, part) > 0
or charindex(part, mt.lastName) > 0)
You might want to omit one of the conditions in the inner query, but I think this is what you want.
Is there anyway to use wildcards in a clause similar to a "in", like this
select * from table where columnx xxxxxxx ('%a%','%b%')?
I know I can do:
select * from table where (columnx like '%a%' or columnx like '%b%')
But I'm looking for an alternative to make the querystring shorter.
BTW: I'm not able to register any custom functions, nor temp tables, it should be a native DB2 function.
I found this similar answer for oracle and SQLServer:
Is there a combination of "LIKE" and "IN" in SQL?
There's no native regular expression support in "pureSQL" for DB2, you can either create your own as in:
http://www.ibm.com/developerworks/data/library/techarticle/0301stolze/0301stolze.html
or use pureXML as in: http://publib.boulder.ibm.com/infocenter/db2luw/v9r7/topic/com.ibm.db2.luw.xml.doc/doc/xqrfnmat.html
Example:
where xmlcast(xmlquery('fn:matches(\$TEXT,''^[A-Za-z 0-9]*$'')') as integer) = 0
Yet another variant that may be shorter:
select t.*
from table t
join ( values '%a%', '%b%' ) u (columnx)
on t.columnx like u.columnx
I know I can write a query that will return all rows that contain any number of values in a given column, like so:
Select * from tbl where my_col in (val1, val2, val3,... valn)
but if val1, for example, can appear anywhere in my_col, which has datatype varchar(300), I might instead write:
select * from tbl where my_col LIKE '%val1%'
Is there a way of combing these two techniques. I need to search for some 30 possible values that may appear anywhere in the free-form text of the column.
Combining these two statements in the following ways does not seem to work:
select * from tbl where my_col LIKE ('%val1%', '%val2%', 'val3%',....)
select * from tbl where my_col in ('%val1%', '%val2%', 'val3%',....)
What would be useful here would be a LIKE ANY predicate as is available in PostgreSQL
SELECT *
FROM tbl
WHERE my_col LIKE ANY (ARRAY['%val1%', '%val2%', '%val3%', ...])
Unfortunately, that syntax is not available in Oracle. You can expand the quantified comparison predicate using OR, however:
SELECT *
FROM tbl
WHERE my_col LIKE '%val1%' OR my_col LIKE '%val2%' OR my_col LIKE '%val3%', ...
Or alternatively, create a semi join using an EXISTS predicate and an auxiliary array data structure (see this question for details):
SELECT *
FROM tbl t
WHERE EXISTS (
SELECT 1
-- Alternatively, store those values in a temp table:
FROM TABLE (sys.ora_mining_varchar2_nt('%val1%', '%val2%', '%val3%'/*, ...*/))
WHERE t.my_col LIKE column_value
)
For true full-text search, you might want to look at Oracle Text: http://www.oracle.com/technetwork/database/enterprise-edition/index-098492.html
A REGEXP_LIKE will do a case-insensitive regexp search.
select * from Users where Regexp_Like (User_Name, 'karl|anders|leif','i')
This will be executed as a full table scan - just as the LIKE or solution, so the performance will be really bad if the table is not small. If it's not used often at all, it might be ok.
If you need some kind of performance, you will need Oracle Text (or some external indexer).
To get substring indexing with Oracle Text you will need a CONTEXT index. It's a bit involved as it's made for indexing large documents and text using a lot of smarts. If you have particular needs, such as substring searches in numbers and all words (including "the" "an" "a", spaces, etc) , you need to create custom lexers to remove some of the smart stuff...
If you insert a lot of data, Oracle Text will not make things faster, especially if you need the index to be updated within the transactions and not periodically.
No, you cannot do this. The values in the IN clause must be exact matches. You could modify the select thusly:
SELECT *
FROM tbl
WHERE my_col LIKE %val1%
OR my_col LIKE %val2%
OR my_col LIKE %val3%
...
If the val1, val2, val3... are similar enough, you might be able to use regular expressions in the REGEXP_LIKE operator.
Yes, you can use this query (Instead of 'Specialist' and 'Developer', type any strings you want separated by comma and change employees table with your table)
SELECT * FROM employees em
WHERE EXISTS (select 1 from table(sys.dbms_debug_vc2coll('Specialist', 'Developer')) mt
where em.job like ('%' || mt.column_value || '%'));
Why my query is better than the accepted answer: You don't need a CREATE TABLE permission to run it. This can be executed with just SELECT permissions.
In Oracle you can use regexp_like as follows:
select *
from table_name
where regexp_like (name, '^(value-1|value-2|value-3....)');
The caret (^) operator to indicate a beginning-of-line character &
The pipe (|) operator to indicate OR operation.
This one is pretty fast :
select * from listofvalue l
inner join tbl on tbl.mycol like '%' || l.value || '%'
Just to add on #Lukas Eder answer.
An improvement to avoid creating tables and inserting values
(we could use select from dual and unpivot to achieve the same result "on the fly"):
with all_likes as
(select * from
(select '%val1%' like_1, '%val2%' like_2, '%val3%' like_3, '%val4%' as like_4, '%val5%' as like_5 from dual)
unpivot (
united_columns for subquery_column in ("LIKE_1", "LIKE_2", "LIKE_3", "LIKE_4", "LIKE_5"))
)
select * from tbl
where exists (select 1 from all_likes where tbl.my_col like all_likes.united_columns)
I prefer this
WHERE CASE WHEN my_col LIKE '%val1%' THEN 1
WHEN my_col LIKE '%val2%' THEN 1
WHEN my_col LIKE '%val3%' THEN 1
ELSE 0
END = 1
I'm not saying it's optimal but it works and it's easily understood. Most of my queries are adhoc used once so performance is generally not an issue for me.
select * from tbl
where exists (select 1 from all_likes where all_likes.value = substr(tbl.my_col,0, length(tbl.my_col)))
You can put your values in ODCIVARCHAR2LIST and then join it as a regular table.
select tabl1.* FROM tabl1 LEFT JOIN
(select column_value txt from table(sys.ODCIVARCHAR2LIST
('%val1%','%val2%','%val3%')
)) Vals ON tabl1.column LIKE Vals.txt WHERE Vals.txt IS NOT NULL
You don't need a collection type as mentioned in https://stackoverflow.com/a/6074261/802058. Just use an subquery:
SELECT *
FROM tbl t
WHERE EXISTS (
SELECT 1
FROM (
SELECT 'val1%' AS val FROM dual
UNION ALL
SELECT 'val2%' AS val FROM dual
-- ...
-- or simply use an subquery here
)
WHERE t.my_col LIKE val
)
Since I believe this should be a basic question I know this question has probably been asked, but I am unable to find it. I'm probably about to earn my Peer Pressure badge, but I'll ask anyway:
Is there a way in SQL Server that I am not aware of for using the wildcard character % when using IN.
I realize that I can use OR's like:
select *
from jobdetails
where job_no like '0711%' or job_no like '0712%'
and in some cases I can use a subquery like:
select *
from jobdetails
where job_no in (select job_no from jobs where job_id = 39)
but I'm looking to do something like the following:
select *
from jobdetails
where job_no in ('0711%', '0712%')
In this case it uses the percent sign as a character instead of a wildcard character so no rows are returned. I currently just use a bunch of OR's when I have to do this, but I know there has to be a better way. What method do you use for this?
How about:
WHERE LEFT(job_no, 4) IN ('0711', '0712', ...)
I think I have a solution to what the originator of this inquiry wanted in simple form. It works for me and actually it is the reason I came on here to begin with. I believe just using parentheses around the column like '%text%' in combination with ORs will do it.
select * from tableName
where (sameColumnName like '%findThis%' or sameColumnName like '%andThis%' or
sameColumnName like '%thisToo%' or sameColumnName like '%andOneMore%')
How about something like this?
declare #search table
(
searchString varchar(10)
)
-- add whatever criteria you want...
insert into #search select '0711%' union select '0712%'
select j.*
from jobdetails j
join #search s on j.job_no like s.searchString
You could try something like this:
select *
from jobdetails
where job_no like '071[12]%'
Not exactly what you're asking, but it has the same effect, and is flexible in other ways too :)
SELECT c.* FROM(
SELECT '071235' AS token UNION ALL SELECT '07113'
UNION ALL SELECT '071343'
UNION ALL SELECT '0713SA'
UNION ALL SELECT '071443') AS c
JOIN (
SELECT '0712%' AS pattern UNION ALL SELECT '0711%'
UNION ALL SELECT '071343') AS d
ON c.token LIKE d.pattern
071235
07113
071343
I had a similar goal - and came to this solution:
select *
from jobdetails as JD
where not exists ( select code from table_of_codes as TC
where JD.job_no like TC.code )
I'm assuming that your various codes ('0711%', '0712%', etc), including the %, are stored in a table, which I'm calling *table_of_codes*, with field code.
If the % is not stored in the table of codes, just concatenate the '%'. For example:
select *
from jobdetails as JD
where not exists ( select code from table_of_codes as TC
where JD.job_no like concat(TC.code, '%') )
The concat() function may vary depending on the particular database, as far as I know.
I hope that it helps. I adapted it from:
http://us.generation-nt.com/answer/subquery-wildcards-help-199505721.html
I firstly added one off static table with ALL possibilities of my wildcard results
(this company has a 4 character nvarchar code as their localities and they wildcard their locals)
i.e. they may have 456? which would give them 456[1] to 456[Z] i.e 0-9 & a-z
I had to write a script to pull the current user (declare them) and pull the masks for the declared user.
Create some temporary tables just basic ones to rank the row numbers for this current user
loop through each result (YOUR Or this Or that etc...)
Insert into the test Table.
Here is the script I used:
Drop Table #UserMasks
Drop Table #TESTUserMasks
Create Table #TESTUserMasks (
[User] [Int] NOT NULL,
[Mask] [Nvarchar](10) NOT NULL)
Create Table #UserMasks (
[RN] [Int] NOT NULL,
[Mask] [Nvarchar](10) NOT NULL)
DECLARE #User INT
SET #User = 74054
Insert Into #UserMasks
select ROW_NUMBER() OVER ( PARTITION BY ProntoUserID ORDER BY Id DESC) AS RN,
REPLACE(mask,'?','') Mask
from dbo.Access_Masks
where prontouserid = #User
DECLARE #TopFlag INT
SET #TopFlag = 1
WHILE (#TopFlag <=(select COUNT(*) from #UserMasks))
BEGIN
Insert Into #TestUserMasks
select (#User),Code from dbo.MaskArrayLookupTable
where code like (select Mask + '%' from #UserMasks Where RN = #TopFlag)
SET #TopFlag = #TopFlag + 1
END
GO
select * from #TESTUserMasks
As Jeremy Smith posted it, i'll recap, since I couldn't answer to that particular question of his.
select *
from jobdetails
where job_no like '071[1-2]%'
If you just need 0711% and 0712% you can also place a ranges within the brackets. For the NOT keyword you could also use [^1-2]%
The IN operator is nothing but a fancy OR of '=' comparisons. In fact it is so 'nothing but' that in SQL 2000 there was a stack overflow bug due to expansion of the IN into ORs when the list contained about 10k entries (yes, there are people writing 10k IN entries...). So you can't use any wildcard matching in it.
In Access SQL, I would use this. I'd imagine that SQLserver has the same syntax.
select *
from jobdetails
where job_no like "0711*" or job_no like "0712*"
A bit late to the party, but you could use STRING_SPLIT
SELECT jobdetails.*
FROM jobdetails
CROSS APPLY (select value
from STRING_SPLIT('540%,%144,orange,coconut',',')
WHERE jobdetails.job_no
like value) as leek
It wouldn't take very much more work to turn that into a reusable function
I had this same question and found a very simple solution using the SUBSTRING function in the WHERE clause. This will not affect how the job_no displays in the return, rather it just trims the IN search down based on the criteria entered for the substring function.
The advantage of using SUBSTRING versus LEFT or RIGHT is that you can define the starting character so if you just want to search the middle of a string, you can do so.
SELECT *
FROM jobdetails
WHERE SUBSTRING(job_no, 1, 4) IN ('0711', '0712')
You have the answer right there in your question. You cannot directly pass wildcard when using IN. However, you can use a sub-query.
Try this:
select *
from jobdetails
where job_no in (
select job_no
from jobdetails
where job_no like '0711%' or job_no like '0712%')
)
I know that this looks crazy, as you can just stick to using OR in your WHERE clause. why the subquery? How ever, the subquery approach will be useful when you have to match details from a different source.
Raj
Try this
select *
from jobdetails
where job_no between '0711' and '0713'
the only problem is that job '0713' is going to be returned as well
so can use '07299999999999' or just add and job_no <> '0713'
Dan zamir
I'm just learning this stuff but would this work?
select *
from jobdetails
where job_no regexp "^(071)[1|2]";
This might me the most simple solution use like any
select *
from jobdetails
where job_no like any ('0711%', '0712%')
In Teradata this works fine.
I am trying to find a way, if possible, to use IN and LIKE together. What I want to accomplish is putting a subquery that pulls up a list of data into an IN statement. The problem is the list of data contains wildcards. Is there any way to do this?
Just something I was curious on.
Example of data in the 2 tables
Parent table
ID Office_Code Employee_Name
1 GG234 Tom
2 GG654 Bill
3 PQ123 Chris
Second table
ID Code_Wildcard
1 GG%
2 PQ%
Clarifying note (via third-party)
Since I'm seeing several responses which don't seems to address what Ziltoid asks, I thought I try clarifying what I think he means.
In SQL, "WHERE col IN (1,2,3)" is roughly the equivalent of "WHERE col = 1 OR col = 2 OR col = 3".
He's looking for something which I'll pseudo-code as
WHERE col IN_LIKE ('A%', 'TH%E', '%C')
which would be roughly the equivalent of
WHERE col LIKE 'A%' OR col LIKE 'TH%E' OR col LIKE '%C'
The Regex answers seem to come closest; the rest seem way off the mark.
I'm not sure which database you're using, but with Oracle you could accomplish something equivalent by aliasing your subquery in the FROM clause rather than using it in an IN clause. Using your example:
select p.*
from
(select code_wildcard
from second
where id = 1) s
join parent p
on p.office_code like s.code_wildcard
In MySQL, use REGEXP:
WHERE field1 REGEXP('(value1)|(value2)|(value3)')
Same in Oracle:
WHERE REGEXP_LIKE(field1, '(value1)|(value2)|(value3)')
Do you mean somethign like:
select * FROM table where column IN (
SELECT column from table where column like '%%'
)
Really this should be written like:
SELECT * FROM table where column like '%%'
Using a sub select query is really beneficial when you have to pull records based on a set of logic that you won't want in the main query.
something like:
SELECT * FROM TableA WHERE TableA_IdColumn IN
(
SELECT TableA_IdColumn FROM TableB WHERE TableA_IDColumn like '%%'
)
update to question:
You can't combine an IN statement with a like statement:
You'll have to do three different like statements to search on the various wildcards.
You could use a LIKE statement to obtain a list of IDs and then use that in the IN statement.
But you can't directly combine IN and LIKE.
Perhaps something like this?
SELECT DISTINCT
my_column
FROM
My_Table T
INNER JOIN My_List_Of_Value V ON
T.my_column LIKE '%' + V.search_value + '%'
In this example I've used a table with the values for simplicity, but you could easily change that to a subquery. If you have a large list (like tens of thousands) then performance might be rough.
select *
from parent
where exists( select *
from second
where office_code like trim( code_wildcard ) );
Trim code_wildcard just in case it has trailing blanks.
You could do the Like part in a subquery perhaps?
Select * From TableA Where X in (Select A from TableB where B Like '%123%')
tsql has the contains statement for a full-text-search enabled table.
CONTAINS(Description, '"sea*" OR "bread*"')
If I'm reading the question correctly, we want all Parent rows that have an Office_code that matches any Code_Wildcard in the "Second" table.
In Oracle, at least, this query achieves that:
SELECT *
FROM parent, second
WHERE office_code LIKE code_wildcard;
Am I missing something?