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I have a month number and year: month 2 and year 2022.
How can I get the first day of that month like 2022-02-01 and last day of month 2022-02-28?
I have seen many posts on getting first and last date of month based on given date or the current date, but I need it based on given month and year.
Thanks in advance
Here is my stored procedure:
ALTER PROCEDURE [dbo].[Rpt_ItemsSales_DayMonthYear_year]-- 2022
#year int = NULL
AS
;WITH months(MonthNumber) AS
(
SELECT 1
UNION ALL
SELECT MonthNumber + 1
FROM months
WHERE MonthNumber < 12
)
SELECT
SalesPos_Dtls.ItemName,
SUM(SalesPos_Dtls.Qty) AS SumQty,
SUM(SalesPos_Dtls.TotalPrice) AS SumTotal,
SalesPos_Dtls.ItemCode,
DATENAME(month, DATEADD(month, m.MonthNumber, 0) - 1) AS MonthName,
m.MonthNumber
FROM
months AS m
LEFT JOIN
SalesPos ON MONTH(SalesPos.StartDate) = m.MonthNumber
AND (status = 'IsPosted')
AND (#year = YEAR(salespos.startdate) OR #year IS NULL)
LEFT JOIN
[dbo].SalesPos_Dtls ON SalesPos.ID = SalesPos_Dtls.OrderId
GROUP BY
m.MonthNumber, dbo.SalesPos_Dtls.ItemName, dbo.SalesPos_Dtls.ItemCode
And this is as far as I got
ALTER PROCEDURE [dbo].[Rpt_ItemsSales_DayMonthYear_year] --2022,1
#year int = NULL,
#month int = NULL
AS
DECLARE #yearr int = #year
DECLARE #monthh int = #month
;WITH months(MonthNumber) AS
(
SELECT 1
UNION ALL
SELECT MonthNumber + 1
FROM months
WHERE MonthNumber < 12
)
SELECT
SalesPos_Dtls.ItemName,
SUM(SalesPos_Dtls.Qty) AS SumQty,
SUM(SalesPos_Dtls.TotalPrice) AS SumTotal,
SalesPos_Dtls.ItemCode,
DATENAME(month, DATEADD(month, m.MonthNumber, 0) - 1) AS MonthName,
m.MonthNumber,
DATEFROMPARTS (#yearr, #monthh, 1) AS MonthStart,
EOMONTH (DATEFROMPARTS (#yearr, #monthh, 1)) AS MonthEnd
FROM
months AS m
LEFT JOIN
SalesPos ON MONTH(SalesPos.StartDate) = m.MonthNumber
AND (status = 'IsPosted')
AND (#year = YEAR(salespos.startdate) OR #year IS NULL)
LEFT JOIN
[dbo].SalesPos_Dtls ON SalesPos.ID = SalesPos_Dtls.OrderId
WHERE
(MONTH(SalesPos.StartDate) = #month OR #month IS NULL)
GROUP BY
m.MonthNumber, dbo.SalesPos_Dtls.ItemName, dbo.SalesPos_Dtls.ItemCode
Screenshot with the sample data:
But I want my data this way :
هوت دوج لارج 3.0000 75.0000
76 January 1 2022-1-01 2022-1-31
هوت دوج ميديم 1.0000 20.0000 77 January 1 2022-1-01 2022-1-31
NULL NULL NULL NULL February 2 2022-2-01 2022-2-28
NULL NULL NULL NULL March 3 NULL 2022-3-01 2022-3-31
SET DATEFIRST 1
DECLARE #Month smallint= 3, #Year smallint = 2022;
/*First and Last day of month as DATE */
select DATEFROMPARTS(#Year, #MONTH, 1)FirstDayOfMonth , EOMONTH(DATEFROMPARTS(#Year, #MONTH, 1)) LastDayofMonth
/*First and Last Weekday of Month */
select DATEPART( dw, DATEFROMPARTS(#Year, #MONTH, 1) ) FirstWeekDayOfMonth , DATEPART(dw, (EOMONTH(DATEFROMPARTS(#Year, #MONTH, 1)))) LastWeekDayofMonth
i dont know if this is the right way to update the question but here is the solution that worked for me.
SELECT DATEADD(month, DATEDIFF(month, 0, #mydate), 0) AS StartOfMonth
SELECT EOMONTH(#mydate) as LastOFMonth
And thanks
edit:
this is the stored procedure. all i wanted is to have 2 columns infront of each item that have the firstday of the month and the last day witch this item was purchased.
i hope this and the stored procedure explain what i mean.
ALTER proc [dbo].[Rpt_ItemsSales_DayMonthYear_year]--Rpt_ItemsSales_DayMonthYear_year 2022
#year int=null
as
;WITH months(MonthNumber) AS
(
SELECT 1
UNION ALL
SELECT MonthNumber+1
FROM months
WHERE MonthNumber < 12
)
select SalesPos_Dtls.ItemName,sum(SalesPos_Dtls.Qty) as SumQty,sum(SalesPos_Dtls.TotalPrice) as SumTotal,SalesPos_Dtls.ItemCode,DateName( month , DateAdd( month , m.MonthNumber , 0 ) - 1 ) as MonthName,
m.MonthNumber, cast(DATEADD(month, DATEDIFF(month, 0, SalesPos.StartDate), 0) as date) AS StartOfMonth,EOMONTH(SalesPos.StartDate) as LastOFMonth
from months as m
left join SalesPos on month(SalesPos.StartDate) = m.MonthNumber and (status = 'IsPosted') and (#year = year(salespos.startdate) or #year is null)
left JOIN [dbo].SalesPos_Dtls on SalesPos.ID=SalesPos_Dtls.OrderId
group by m.MonthNumber,dbo.SalesPos_Dtls.ItemName,dbo.SalesPos_Dtls.ItemCode,cast(DATEADD(month, DATEDIFF(month, 0, SalesPos.StartDate), 0) as date),EOMONTH(SalesPos.StartDate)
I am trying to get the fiscal period and year out of an invoice date. Using the month() function together with the Case I am able to get the period. since Period 1 is in November I need to do a +1 1 the year when this is true
Using the IF function together with the date functions are now working for me.
My query is
Select a.OrderAccount
,a.InvoiceAccount
,a.InvoiceDate
,year(a.InvoiceDate) as Year
,month(a.InvoiceDate) as Month,
Case month(a.InvoiceDate)
WHEN '11' THEN '1' -- increase year by +1
WHEN '12' THEN '2'-- increase year by +1
WHEN '1' THEN '3'
WHEN '2' THEN '4'
WHEN '3' THEN '5'
Any advice would be appreciated. Thanks
Use DATEADD to just add 2 months to the original date:
MONTH(DATEADD(month,2,a.InvoiceDate)) as FiscalMonth,
YEAR(DATEADD(month,2,a.InvoiceDate)) AS FiscalYear,
Create and populate a Calendar Table (it makes working with dates much easier).
create table Calendar
(
id int primary key identity,
[date] datetime,
[day] as datepart(day, [date]) persisted,
[month] as datepart(month, [date]) persisted,
[year] as datepart(year, [date]) persisted,
day_of_year as datepart(dayofyear, [date]) persisted,
[week] as datepart(week, [date]),
day_name as datename(dw, [date]),
is_weekend as case when datepart(dw, [date]) = 7 or datepart(dw, [date]) = 1 then 1 else 0 end,
[quarter] as datepart(quarter, [date]) persisted
--etc...
)
--populate the calendar
declare #date datetime
set #date = '1-1-2000'
while #date <= '12-31-2100'
begin
insert Calendar select #date
set #date = dateadd(day, 1, #date)
end
Then, create a FiscalYear view:
create view FiscalYear
as
select
id,
case when month = 11 or month = 12 then year + 1 else year end as [year]
from Calendar
So, whenever you need the fiscal year of a given date, just use something like the following query:
select C.*, FY.year fiscal_year from Calendar C inner join FiscalYear FY on FY.id = C.id
Of course, since fiscal year is just a computation on a column, you could also just make it a part of the calendar table itself. Then, it's simply:
select * from Calendar
If you want to stick with arithmetic: The fiscal month is ( Month( a.InvoiceDate ) + 1 ) % 12 + 1 and the value to add to the calendar year to get the fiscal year is Month( a.InvoiceDate ) / 11.
The following code demonstrates 12 months:
with Months as (
select 1 as M
union all
select M + 1
from Months
where M < 12 )
select M, ( M + 1 ) % 12 + 1 as FM, M / 11 as FYOffset
from Months;
D Stanley's answer makes your intention clearer, always a consideration for maintainability.
If you have this logic in 10 different places and the logic changes starting (say) on 1/1/2018 you will have a mess on your hands.
Create a function that has the logic and then use the function like:
SELECT InvoiceDate, dbo.FiscalPeriod(InvoiceDate) AS FP
FROM ...
Something like:
CREATE FUNCTION dbo.FiscalPeriod(#InvoiceDate DateTime)
RETURNS int
AS BEGIN
DECLARE #FiscalDate DateTime
SET #FiscalDate = DATEADD(month, 2, #InvoiceDate)
RETURN YEAR(#FiscalDate) * 100 + MONTH(#FiscalDate)
END
This returns values like 201705, but you could have dbo.FiscalPeriodMonth() and dbo.FiscalPeriodYear() if you needed. And you can have as complicated logic as you need in one place.
I have a date field that needs to return in fiscal year format. example
Start_Date Year
04/01/2012 - 2013
01/01/2012 - 2012
09/15/2013 - 2014
We need to calculate
04/01/2012 to 03/31/2013 is FY 2013
and
04/01/2013 to 03/31/2014 is FY 2014
How can we do that in select statement?
David has a very good solution. A simpler expression is:
select year(dateadd(month, -3, start_date)) as FiscalYear
That is, subtract 3 months and take the year.
EDIT:
As noted in the comment, this seems to produce one year too early. Here are two solutions:
select year(dateadd(month, 9, start_date)) as FiscalYear
select 1 + year(dateadd(month, -3, start_date)) as FiscalYear
SELECT CASE WHEN DatePart(Month, Start_Date) >= 4
THEN DatePart(Year, Start_Date) + 1
ELSE DatePart(Year, Start_Date)
END AS Fiscal_Year
FROM data
I just chose to do it this way. It's easy and you can replace the 09,30 with whatever you want your fiscal year end to be. Not sure if this works in anything but SQL Server though.
CASE
WHEN CAST(GETDATE() AS DATE) >
SMALLDATETIMEFROMPARTS(DATEPART(YEAR,GETDATE()),09,30,00,000)
THEN
DATEPART(YEAR,GETDATE()) + 1 ELSE DATEPART(YEAR,GETDATE())
END AS FY
For Australian financial year, use the following:
SELECT
year(dateadd(MONTH, 6, DateColumn)) AS FY,
...
FROM ...
Assuming that you have a table Fiscal_Year with Start_Date per Year, and you want to find the fiscal year for a given date #Date:
SELECT MIN(Year) WHERE #Date >= Start_Date FROM Fiscal_Year
Declare #t table(StartDate date ,Year1 int)
insert into #t values('04/01/2012',2013),('01/01/2012',2012),('09/15/2013',2014)
;with CTE as
(select max(year1) maxyear from #t)
, cte1 as
(select cast('04/01/'+convert(varchar(4),a.year1) as date) FromFY,dateadd(day,-1,dateadd(year,1,cast('04/01/'+convert(varchar(4),a.year1) as date))) ToFY
,b.year1 from #t a inner join (select min(year1)year1 from #t) b on a.year1=b.year1
union all
select cast(dateadd(day,1,ToFY) as date),cast(dateadd(year,1,ToFY) as date),year1+1 year1 from cte1 where year1<=(select maxyear from cte)
)
select * from cte1
DECLARE #STARTDATE DATETIME, #ENDDATE DATETIME,#CURR_DATE DATETIME
SET #CURR_DATE='2015-01-30'
IF MONTH(#CURR_DATE) IN (1,2,3)
BEGIN
SET #STARTDATE= CAST( CAST(YEAR(#CURR_DATE)-1 AS VARCHAR)+'/04/01' AS DATE)
SET #ENDDATE= CAST( CAST(YEAR(#CURR_DATE) AS VARCHAR)+'/03/31' AS DATE)
END
ELSE
BEGIN
SET #STARTDATE= CAST( CAST(YEAR(#CURR_DATE) AS VARCHAR)+'/04/01' AS DATE)
SET #ENDDATE= CAST( CAST(YEAR(#CURR_DATE)+1 AS VARCHAR)+'/03/31' AS DATE)
END
SELECT #STARTDATE AS ST_FI,#ENDDATE AS END_FY
...something simple :)
(YEAR(DATEADD(Month,-((DATEPART(Month,[Date])+5) %12),[Date]))+) AS Financial_Year
declare #Date smalldatetime, #FiscalYearStartMonth tinyint
set #Date = GETDATE();
set #FiscalYearStartMonth = 1; -- Jan
print convert(varchar(4),
case when MONTH(#Date) < #FiscalYearStartMonth
then YEAR(#Date) -1
else YEAR(#Date) end)
assuming #Date is your [Start_Date] field, you can:
select * from yourTable
group by convert(varchar(4),
case when MONTH([Start_Date]) < #FiscalYearStartMonth
then YEAR([Start_Date]) -1
else YEAR([Start_Date]) end)
Hope this helps
This is what would look like in oracle to get current financial year. Enter the date for which you want to find fiscal year in place of sysdate
SELECT '01-APR-'
||TO_CHAR((add_months(**sysdate**,-3)),'YYYY') FIN_YEAR_START_DATE,
'31-MAR-'
||(TO_CHAR((add_months(**sysdate**,-3)),'YYYY')+1) FIN_YEAR_END_DATE
FROM dual;
For only year format (FY 2020) use following query:
SELECT tender_opening_date,CASE WHEN MONTH( order_date) >= 4
THEN CONCAT('FY ',YEAR(( order_date)) +1 )
ELSE CONCAT('FY ',YEAR( order_date)-1 )
END AS Fiscal_Year
FROM orders_tbl
For full financial Year (FY 2019-20) use following query:
SELECT tender_opening_date,CASE WHEN MONTH( order_date) >= 4
THEN CONCAT('FY ',YEAR( order_date),'-',DATE_FORMAT( order_date,'%y') +1 )
ELSE CONCAT('FY ',YEAR( order_date)-1,'-',DATE_FORMAT( order_date,'%y') )
END AS Fiscal_Year
FROM orders_tbl
I need a select to return Month and year Within a specified date range where I would input the start year and month and the select would return month and year from the date I input till today.
I know I can do this in a loop but I was wondering if it is possible to do this in a series selects?
Year Month
---- -----
2010 1
2010 2
2010 3
2010 4
2010 5
2010 6
2010 7
and so on.
Gosh folks... using a "counting recursive CTE" or "rCTE" is as bad or worse than using a loop. Please see the following article for why I say that.
http://www.sqlservercentral.com/articles/T-SQL/74118/
Here's one way to do it without any RBAR including the "hidden RBAR" of a counting rCTE.
--===== Declare and preset some obviously named variables
DECLARE #StartDate DATETIME,
#EndDate DATETIME
;
SELECT #StartDate = '2010-01-14', --We'll get the month for both of these
#EndDate = '2020-12-05' --dates and everything in between
;
WITH
cteDates AS
(--==== Creates a "Tally Table" structure for months to add to start date
-- calulated by the difference in months between the start and end date.
-- Then adds those numbers to the start of the month of the start date.
SELECT TOP (DATEDIFF(mm,#StartDate,#EndDate) + 1)
MonthDate = DATEADD(mm,DATEDIFF(mm,0,#StartDate)
+ (ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) -1),0)
FROM sys.all_columns ac1
CROSS JOIN sys.all_columns ac2
)
--===== Slice each "whole month" date into the desired display values.
SELECT [Year] = YEAR(MonthDate),
[Month] = MONTH(MonthDate)
FROM cteDates
;
I know this is an old question, but I'm mildly horrified at the complexity of some of the answers. Using a CTE is definitely the simplest way to go for selecting these values:
WITH months(dt) AS
(SELECT getdate() dt
UNION ALL
SELECT dateadd(month, -1, dt)
FROM months)
SELECT
top (datediff(month, '2017-07-01' /* start date */, getdate()) + 1)
YEAR(months.dt) yr, MONTH(months.dt) mnth
FROM months
OPTION (maxrecursion 0);
Just slap in whichever start date you'd like in place of the '2017-07-01' above and you're good to go with an efficient and easily-integrated solution.
Edit: Jeff Moden's answer quite effectively advocates against using rCTEs. However, in this case it appears to be a case of premature optimization - we're talking about 10's of records in all likelihood, and even if you span back to 1900 from today, it's still a minuscule hit. Using rCTEs to achieve code maintainability seems to be worth the trade if the expected result set is small.
You can use something like this: Link
To generate the equivalent of a numbers table using date ranges.
But could you please clarify your inputs and outputs?
Do you want to input a start date, for example, '2010-5-1' and end date, for example, '2010-8-1' and have it return every month between the two? Do you want to include the start month and end month, or exclude them?
Here's some code that I wrote that will quickly generate an inclusive result of every month between two dates.
--Inputs here:
DECLARE #StartDate datetime;
DECLARE #EndDate datetime;
SET #StartDate = '2010-1-5 5:00PM';
SET #EndDate = GETDATE();
--Procedure here:
WITH RecursiveRowGenerator (Row#, Iteration) AS (
SELECT 1, 1
UNION ALL
SELECT Row# + Iteration, Iteration * 2
FROM RecursiveRowGenerator
WHERE Iteration * 2 < CEILING(SQRT(DATEDIFF(MONTH, #StartDate, #EndDate)+1))
UNION ALL
SELECT Row# + (Iteration * 2), Iteration * 2
FROM RecursiveRowGenerator
WHERE Iteration * 2 < CEILING(SQRT(DATEDIFF(MONTH, #StartDate, #EndDate)+1))
)
, SqrtNRows AS (
SELECT *
FROM RecursiveRowGenerator
UNION ALL
SELECT 0, 0
)
SELECT TOP(DATEDIFF(MONTH, #StartDate, #EndDate)+1)
DATEADD(month, DATEDIFF(month, 0, #StartDate) + A.Row# * POWER(2,CEILING(LOG(SQRT(DATEDIFF(MONTH, #StartDate, #EndDate)+1))/LOG(2))) + B.Row#, 0) Row#
FROM SqrtNRows A, SqrtNRows B
ORDER BY A.Row#, B.Row#;
Code below generates the values for the range between 21 Jul 2013 and 15 Jan 2014.
I usually use it in SSRS reports for generating lookup values for the Month parameter.
declare
#from date = '20130721',
#to date = '20140115';
with m as (
select * from (values ('Jan', '01'), ('Feb', '02'),('Mar', '03'),('Apr', '04'),('May', '05'),('Jun', '06'),('Jul', '07'),('Aug', '08'),('Sep', '09'),('Oct', '10'),('Nov', '11'),('Dec', '12')) as t(v, c)),
y as (select cast(YEAR(getdate()) as nvarchar(4)) [v] union all select cast(YEAR(getdate())-1 as nvarchar(4)))
select m.v + ' ' + y.v [value_field], y.v + m.c [label_field]
from m
cross join y
where y.v + m.c between left(convert(nvarchar, #from, 112),6) and left(convert(nvarchar, #to, 112),6)
order by y.v + m.c desc
Results:
value_field label_field
---------------------------
Jan 2014 201401
Dec 2013 201312
Nov 2013 201311
Oct 2013 201310
Sep 2013 201309
Aug 2013 201308
Jul 2013 201307
you can do the following
SELECT DISTINCT YEAR(myDate) as [Year], MONTH(myDate) as [Month]
FROM myTable
WHERE <<appropriate criteria>>
ORDER BY [Year], [Month]
---Here is a version that gets the month end dates typically used for accounting purposes
DECLARE #StartDate datetime;
DECLARE #EndDate datetime;
SET #StartDate = '2010-1-1';
SET #EndDate = '2020-12-31';
--Procedure here:
WITH RecursiveRowGenerator (Row#, Iteration)
AS ( SELECT 1, 1
UNION ALL
SELECT Row# + Iteration, Iteration * 2
FROM RecursiveRowGenerator
WHERE Iteration * 2 < CEILING(SQRT(DATEDIFF(MONTH, #StartDate, #EndDate)+1))
UNION ALL SELECT Row# + (Iteration * 2), Iteration * 2
FROM RecursiveRowGenerator
WHERE Iteration * 2 < CEILING(SQRT(DATEDIFF(MONTH, #StartDate, #EndDate)+1)) )
, SqrtNRows AS ( SELECT * FROM RecursiveRowGenerator
UNION ALL SELECT 0, 0 )
SELECT TOP(DATEDIFF(MONTH, #StartDate, #EndDate)+1)
DateAdd(d,-1,DateAdd(m,1, DATEADD(month, DATEDIFF(month, 0, #StartDate) + A.Row# * POWER(2,CEILING(LOG(SQRT(DATEDIFF(MONTH, #StartDate, #EndDate)+1))/LOG(2))) + B.Row#, 0) ))
Row# FROM SqrtNRows A, SqrtNRows B ORDER BY A.Row#, B.Row#;
DECLARE #Date1 DATE
DECLARE #Date2 DATE
SET #Date1 = '20130401'
SET #Date2 = DATEADD(MONTH, 83, #Date1)
SELECT DATENAME(MONTH, #Date1) "Month", MONTH(#Date1) "Month Number", YEAR(#Date1) "Year"
INTO #Month
WHILE (#Date1 < #Date2)
BEGIN
SET #Date1 = DATEADD(MONTH, 1, #Date1)
INSERT INTO #Month
SELECT DATENAME(MONTH, #Date1) "Month", MONTH(#Date1) "Month Number", YEAR(#Date1) "Year"
END
SELECT * FROM #Month
ORDER BY [Year], [Month Number]
DROP TABLE #Month
declare #date1 datetime,
#date2 datetime,
#date datetime,
#month integer,
#nm_bulan varchar(20)
create table #month_tmp
( bulan integer null, keterangan varchar(20) null )
select #date1 = '2000-01-01',
#date2 = '2000-12-31'
select #month = month(#date1)
while (#month < 13)
Begin
IF #month = 1
Begin
SELECT #date = CAST( CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(DATEADD(mm,0,#date1))-1),DATEADD(mm,0,#date1)),111) + ' 00:00:00' as DATETIME )
End
ELSE
Begin
SELECT #date = CAST( CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(DATEADD(mm,#month -1,#date1))-1),DATEADD(mm,#month -1,#date1)),111) + ' 00:00:00' as DATETIME )
End
select #nm_bulan = DATENAME(MM, #date)
insert into #month_tmp
select #month as nilai, #nm_bulan as nama
select #month = #month + 1
End
select * from #month_tmp
drop table #month_tmp
go
I need to determine the number of days in a month for a given date in SQL Server.
Is there a built-in function? If not, what should I use as the user-defined function?
In SQL Server 2012 you can use EOMONTH (Transact-SQL) to get the last day of the month and then you can use DAY (Transact-SQL) to get the number of days in the month.
DECLARE #ADate DATETIME
SET #ADate = GETDATE()
SELECT DAY(EOMONTH(#ADate)) AS DaysInMonth
You can use the following with the first day of the specified month:
datediff(day, #date, dateadd(month, 1, #date))
To make it work for every date:
datediff(day, dateadd(day, 1-day(#date), #date),
dateadd(month, 1, dateadd(day, 1-day(#date), #date)))
Most elegant solution: works for any #DATE
DAY(DATEADD(DD,-1,DATEADD(MM,DATEDIFF(MM,-1,#DATE),0)))
Throw it in a function or just use it inline. This answers the original question without all the extra junk in the other answers.
examples for dates from other answers:
SELECT DAY(DATEADD(DD,-1,DATEADD(MM,DATEDIFF(MM,-1,'1/31/2009'),0))) Returns 31
SELECT DAY(DATEADD(DD,-1,DATEADD(MM,DATEDIFF(MM,-1,'2404-feb-15'),0))) Returns 29
SELECT DAY(DATEADD(DD,-1,DATEADD(MM,DATEDIFF(MM,-1,'2011-12-22'),0))) Returns 31
--Last Day of Previous Month
SELECT DATEPART(day, DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0)))
--Last Day of Current Month
SELECT DATEPART(day, DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE())+1,0)))
--Last Day of Next Month
SELECT DATEPART(day, DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE())+2,0)))
Personally though, I would make a UDF for it if there is not a built in function...
I would suggest:
SELECT DAY(EOMONTH(GETDATE()))
This code gets you the number of days in current month:
SELECT datediff(dd,getdate(),dateadd(mm,1,getdate())) as datas
Change getdate() to the date you need to count days for.
--- sql server below 2012---
select day( dateadd(day,-1,dateadd(month, 1, convert(date,'2019-03-01'))))
-- this for sql server 2012--
select day(EOMONTH(getdate()))
Solution 1: Find the number of days in whatever month we're currently in
DECLARE #dt datetime
SET #dt = getdate()
SELECT #dt AS [DateTime],
DAY(DATEADD(mm, DATEDIFF(mm, -1, #dt), -1)) AS [Days in Month]
Solution 2: Find the number of days in a given month-year combo
DECLARE #y int, #m int
SET #y = 2012
SET #m = 2
SELECT #y AS [Year],
#m AS [Month],
DATEDIFF(DAY,
DATEADD(DAY, 0, DATEADD(m, ((#y - 1900) * 12) + #m - 1, 0)),
DATEADD(DAY, 0, DATEADD(m, ((#y - 1900) * 12) + #m, 0))
) AS [Days in Month]
You do need to add a function, but it's a simple one. I use this:
CREATE FUNCTION [dbo].[ufn_GetDaysInMonth] ( #pDate DATETIME )
RETURNS INT
AS
BEGIN
SET #pDate = CONVERT(VARCHAR(10), #pDate, 101)
SET #pDate = #pDate - DAY(#pDate) + 1
RETURN DATEDIFF(DD, #pDate, DATEADD(MM, 1, #pDate))
END
GO
SELECT Datediff(day,
(Convert(DateTime,Convert(varchar(2),Month(getdate()))+'/01/'+Convert(varchar(4),Year(getdate())))),
(Convert(DateTime,Convert(varchar(2),Month(getdate())+1)+'/01/'+Convert(varchar(4),Year(getdate()))))) as [No.of Days in a Month]
select datediff(day,
dateadd(day, 0, dateadd(month, ((2013 - 1900) * 12) + 3 - 1, 0)),
dateadd(day, 0, dateadd(month, ((2013 - 1900) * 12) + 3, 0))
)
Nice Simple and does not require creating any functions Work Fine
You need to create a function, but it is for your own convenience. It works perfect and I never encountered any faulty computations using this function.
CREATE FUNCTION [dbo].[get_days](#date datetime)
RETURNS int
AS
BEGIN
SET #date = DATEADD(MONTH, 1, #date)
DECLARE #result int = (select DAY(DATEADD(DAY, -DAY(#date), #date)))
RETURN #result
END
How it works: subtracting the date's day number from the date itself gives you the last day of previous month. So, you need to add one month to the given date, subtract the day number and get the day component of the result.
select add_months(trunc(sysdate,'MM'),1) - trunc(sysdate,'MM') from dual;
I upvoted Mehrdad, but this works as well. :)
CREATE function dbo.IsLeapYear
(
#TestYear int
)
RETURNS bit
AS
BEGIN
declare #Result bit
set #Result =
cast(
case when ((#TestYear % 4 = 0) and (#testYear % 100 != 0)) or (#TestYear % 400 = 0)
then 1
else 0
end
as bit )
return #Result
END
GO
CREATE FUNCTION dbo.GetDaysInMonth
(
#TestDT datetime
)
RETURNS INT
AS
BEGIN
DECLARE #Result int
DECLARE #MonthNo int
Set #MonthNo = datepart(m,#TestDT)
Set #Result =
case #MonthNo
when 1 then 31
when 2 then
case
when dbo.IsLeapYear(datepart(yyyy,#TestDT)) = 0
then 28
else 29
end
when 3 then 31
when 4 then 30
when 5 then 31
when 6 then 30
when 7 then 31
when 8 then 31
when 9 then 30
when 10 then 31
when 11 then 30
when 12 then 31
end
RETURN #Result
END
GO
To Test
declare #testDT datetime;
set #testDT = '2404-feb-15';
select dbo.GetDaysInMonth(#testDT)
here's another one...
Select Day(DateAdd(day, -Day(DateAdd(month, 1, getdate())),
DateAdd(month, 1, getdate())))
I know this question is old but I thought I would share what I'm using.
DECLARE #date date = '2011-12-22'
/* FindFirstDayOfMonth - Find the first date of any month */
-- Replace the day part with -01
DECLARE #firstDayOfMonth date = CAST( CAST(YEAR(#date) AS varchar(4)) + '-' +
CAST(MONTH(#date) AS varchar(2)) + '-01' AS date)
SELECT #firstDayOfMonth
and
DECLARE #date date = '2011-12-22'
/* FindLastDayOfMonth - Find what is the last day of a month - Leap year is handled by DATEADD */
-- Get the first day of next month and remove a day from it using DATEADD
DECLARE #lastDayOfMonth date = CAST( DATEADD(dd, -1, DATEADD(mm, 1, FindFirstDayOfMonth(#date))) AS date)
SELECT #lastDayOfMonth
Those could be combine to create a single function to retrieve the number of days in a month if needed.
SELECT DAY(SUBDATE(ADDDATE(CONCAT(YEAR(NOW()), '-', MONTH(NOW()), '-1'), INTERVAL 1 MONTH), INTERVAL 1 DAY))
Nice 'n' Simple and does not require creating any functions
Mehrdad Afshari reply is most accurate one, apart from usual this answer is based on formal mathematical approach given by Curtis McEnroe in his blog https://cmcenroe.me/2014/12/05/days-in-month-formula.html
DECLARE #date DATE= '2015-02-01'
DECLARE #monthNumber TINYINT
DECLARE #dayCount TINYINT
SET #monthNumber = DATEPART(MONTH,#date )
SET #dayCount = 28 + (#monthNumber + floor(#monthNumber/8)) % 2 + 2 % #monthNumber + 2 * floor(1/#monthNumber)
SELECT #dayCount + CASE WHEN #dayCount = 28 AND DATEPART(YEAR,#date)%4 =0 THEN 1 ELSE 0 END -- leap year adjustment
To get the no. of days in a month we can directly use Day() available in SQL.
Follow the link posted at the end of my answer for SQL Server 2005 / 2008.
The following example and the result are from SQL 2012
alter function dbo.[daysinm]
(
#dates nvarchar(12)
)
returns int
as
begin
Declare #dates2 nvarchar(12)
Declare #days int
begin
select #dates2 = (select DAY(EOMONTH(convert(datetime,#dates,103))))
set #days = convert(int,#dates2)
end
return #days
end
--select dbo.daysinm('08/12/2016')
Result in SQL Server SSMS
(no column name)
1 31
Process:
When EOMONTH is used, whichever the date format we use it is converted into DateTime format of SQL-server. Then the date output of EOMONTH() will be 2016-12-31 having 2016 as Year, 12 as Month and 31 as Days.
This output when passed into Day() it gives you the total days count in the month.
If we want to get the instant result for checking we can directly run the below code,
select DAY(EOMONTH(convert(datetime,'08/12/2016',103)))
or
select DAY(EOMONTH(convert(datetime,getdate(),103)))
for reference to work in SQL Server 2005/2008/2012, please follow the following external link ...
Find No. of Days in a Month in SQL
DECLARE #date DATETIME = GETDATE(); --or '12/1/2018' (month/day/year)
SELECT DAY(EOMONTH ( #date )) AS 'This Month';
SELECT DAY(EOMONTH ( #date, 1 )) AS 'Next Month';
result:
This Month
31
Next Month
30
DECLARE #m int
SET #m = 2
SELECT
#m AS [Month],
DATEDIFF(DAY,
DATEADD(DAY, 0, DATEADD(m, +#m -1, 0)),
DATEADD(DAY, 0, DATEADD(m,+ #m, 0))
) AS [Days in Month]
RETURN day(dateadd(month, 12 * #year + #month - 22800, -1))
select day(dateadd(month, 12 * year(date) + month(date) - 22800, -1))
A cleaner way of implementing this is using the datefromparts function to construct the first day of the month, and calculate the days from there.
CREATE FUNCTION [dbo].[fn_DaysInMonth]
(
#year INT,
#month INT
)
RETURNS INT
AS
BEGIN
IF #month < 1 OR #month > 12 RETURN NULL;
IF #year < 1753 OR #year > 9998 RETURN NULL;
DECLARE #firstDay DATE = datefromparts(#year, #month, 1);
DECLARE #lastDay DATE = dateadd(month, 1, #firstDay);
RETURN datediff(day, #firstDay, #lastDay);
END
GO
Similarily, you can calculate the days in a year:
CREATE FUNCTION [dbo].[fn_DaysInYear]
(
#year INT
)
RETURNS INT
AS
BEGIN
IF #year < 1753 OR #year > 9998 RETURN NULL;
DECLARE #firstDay DATE = datefromparts(#year, 1, 1);
DECLARE #lastDay DATE = dateadd(year, 1, #firstDay);
RETURN datediff(day, #firstDay, #lastDay);
END
GO
use SQL Server EOMONTH Function nested with day to get last day of month
select Day(EOMONTH('2020-02-1')) -- Leap Year returns 29
select Day(EOMONTH('2021-02-1')) -- returns 28
select Day(EOMONTH('2021-03-1')) -- returns 31
For any date
select DateDiff(Day,#date,DateAdd(month,1,#date))
select first_day=dateadd(dd,-1*datepart(dd,getdate())+1,getdate()),
last_day=dateadd(dd,-1*datepart(dd,dateadd(mm,1,getdate())),dateadd(mm,1,getdate())),
no_of_days = 1+datediff(dd,dateadd(dd,-1*datepart(dd,getdate())+1,getdate()),dateadd(dd,-1*datepart(dd,dateadd(mm,1,getdate())),dateadd(mm,1,getdate())))
replace any date with getdate to get the no of months in that particular date
DECLARE #Month INT=2,
#Year INT=1989
DECLARE #date DateTime=null
SET #date=CAST(CAST(#Year AS nvarchar) + '-' + CAST(#Month AS nvarchar) + '-' + '1' AS DATETIME);
DECLARE #noofDays TINYINT
DECLARE #CountForDate TINYINT
SET #noofDays = DATEPART(MONTH,#date )
SET #CountForDate = 28 + (#noofDays + floor(#noofDays/8)) % 2 + 2 % #noofDays + 2 * floor(1/#noofDays)
SET #noofDays= #CountForDate + CASE WHEN #CountForDate = 28 AND DATEPART(YEAR,#date)%4 =0 THEN 1 ELSE 0 END
PRINT #noofDays
DECLARE #date nvarchar(20)
SET #date ='2012-02-09 00:00:00'
SELECT DATEDIFF(day,cast(replace(cast(YEAR(#date) as char)+'-'+cast(MONTH(#date) as char)+'-01',' ','')+' 00:00:00' as datetime),dateadd(month,1,cast(replace(cast(YEAR(#date) as char)+'-'+cast(MONTH(#date) as char)+'-01',' ','')+' 00:00:00' as datetime)))
simple query in SQLServer2012 :
select day(('20-05-1951 22:00:00'))
i tested for many dates and it return always a correct result