If I have 3 tables A, B and C I understand how to use left join to join them like this:
SELECT *
FROM A LEFT JOIN
B
ON A.col = B.col LEFT JOIN
C
on B.col = C.col
So A to B then B to C
How would I do this:
SELECT *
FROM A LEFT JOIN
B
ON A.col = B.col LEFT JOIN
C
on A.col = C.col
So A to B and then A to C
Would really appreciate any help
I don't see anything wrong with what you're trying to accomplish.
A simple example is at: http://sqlfiddle.com/#!9/6dbbe2/2
There are three tables (A, B, and C):
Table A
id name
1 Alice
2 Bob
3 Carol
4 Don
5 Edith
Table B
id id_A pet
1 5 Tex
2 4 Socks
3 2 Rex
4 1 Percy
5 1 Quinlan
Table C
id id_A hobby
1 1 acting
2 2 boxing
3 4 dancing
4 5 eating
Tables B and C relate to Table A through the id_A foreign key.
A query like you have:
SELECT * FROM A LEFT JOIN B
ON A.id = B.id_a LEFT JOIN C
ON A.id = C.id_a;
works just fine.
Related
I have 3 tables:
table: a
id name
2 A
3 B
table: b
id a b
3 2 Asd Ter Gsdt
4 2 Gsd Gsdt Gsda
5 2 Asd Gsd
6 3 Uty Kggs
7 3 Tyud Hffddf
table: c
id a b
6 3 d
7 3 a
8 3 g
9 3 h
10 4 j
11 5 y
12 5 s
13 6 d
14 6 h
expected output:
a b c d
A 2019-04-06 3 a
B 2019-04-06 6 b
I am unsure how to proceed from this, how?
This query do the job, but there is always a question about speed and performance.
select a.name,
(select c_date from c
join b on (c.b_id = b.id)
where b.a = a.id order by c_date desc limit 1) last_c_date,
popular.b_id,
(select photos->0 from b where id = popular.b_id) photo
from a
join (
select distinct on (a)
b.id b_id, a from b
join c on (b.id = c.b_id)
group by b.id, a
order by a, count(*) desc, b.id
) popular on (popular.a = a.id)
order by a.name
If there will be 2 equaly popular b objects in a region, query takes this with smaller id.
If it will be no b object with entries in c than subquery for photo can be surrounded with coalesce (but now it should work too with null value).
I have 4 tables
A, B, C, D
Table A:
ct_no ct_type
1010. 1
1011. 1
1012. 2
1013. 3
Table B:
ct_no. jcode
1010. 4
1012. 3
1012. 4
1013. 7
1013. 6
1013. 4
Table C:
Jcode jname
4. ABC
3. lol
7. xyz
Table D:
filno orno. fildate. ct_no
12017. 1. 1010
12017. 2. 1010
12017. 3. 1012
42017. 1. 1010
Now I want table d record with table c jname where table c jcode is 3
Output should be
filno orno ctno jnames
12017 1 1012 lol,ABC
Try this:
select d.*, c.jname from tabled d
inner join tableb b on d.ct_no=b.ct_no and b.Jcode=3
inner join tablec c on b.Jcode =c.Jcode
You need a couple of joins:
SELECT d.*
FROM d
JOIN b ON d.ct_no = b.ct_no
JOIN c ON b.jcode = c.jcode
WHERE c.jcode = 3
Suppose I have a table A as a 'dictionary':
A type code name
1 a x
1 b y
2 a z
2 b t
I want to translate the following table B in to names:
B c1 c2
a a
a b
b b
Where B.c1 is the code of A.type=1 and B.c2 is the code of A.type=2.
The expected result is
x z
x t
y t
If there is only one column in B needs to be translated, it is easy.
SELECT A.name
FROM A, B
WHERE A.type = 1
AND B.c1=A.code
Using joins;
select a1.type,b.c1,a2.type,b.c2 from b
left outer join a as a1 on b.c1= a1.code and a1.type=1
left outer join a as a2 on b.c2= a2.code and a2.type=2
i have following SQL table A in my database:
index, group, foo
1 A 2
2 A 2
3 A 0
4 A 1
5 B 2
6 B 1
7 C 1
There are few more groups and I need to write a query based on this filter table B. For each group in table A it's index should be equal or greater than index_egt from table B for the same group.
If the group is not listed in table B, the group won't be filtered.
index_egt, group
3 A
5 B
Expected result:
index, group, foo
3 A 0
4 A 1
5 B 2
6 B 1
7 C 1
Try this, the A.index>=B.index_egt will handle cases where the group is listed in TableB and the B.index_egt IS NULL will handle cases where the group is not listed:
SELECT
A.index,
A.group,
A.foo
FROM TableA AS A
LEFT JOIN TableB AS B ON A.group=B.group
WHERE A.index>=B.index_egt
OR B.index_egt IS NULL
select
a.*
from
A a
left join
B b ON b.group = a.group
where
a.index >= b.index_egt OR b.index_egt IS NULL
I always like this trick with coalesce
SELECT a.*
FROM a_table_with_no_name a
LEFT JOIN b_table_with_no_name b ON b.group = a.group
WHERE a.index >= COALESCE(b.index_egt,a.index)
i have 3 tables (A,B,C)
Table A -
ID Name
1 Sam
2 Manuel
3 Jane
Table B
ID Tab_A_ID Name
1 1 Meer
2 1 Kutti
3 2 Mikaro
Table C
ID Tab_B_ID Price
1 1 255.11
2 1 30.52
3 3 125.22
I need a query that shall pick up the top price for TableA-Name from TableC. So only 1 top price for 1 nae record.
e.g.-
Sam - 255.11
Manuel - 125.22
How can i get this?
To get the max price per entry in A:
SELECT a.Name,
MAX(c.price)
FROM a
INNER JOIN b
ON a.id = b.tab_a_id
INNER JOIN c
ON b.id = c.tab_b_id
GROUP BY a.id, a.name
To get the max price per entry A per entry B:
SELECT a.Name,
b.Name
MAX(c.price)
FROM a
INNER JOIN b
ON a.id = b.tab_a_id
INNER JOIN c
ON b.id = c.tab_b_id
GROUP BY a.id, b.id, a.name, b.name
Note that entries in A without corresponding entires in B or entries in B without corresponding entries in C will not appear in the result. Use LEFT JOIN if you want to include these in the result.