I'm having some troubles trying to create a view from two tables, which includes a sum + case for the first table. I've tried multiple different joins/unions, and I can get just the XTS table to come over, or just the case count scenarios to work, but I cannot get both.
here are the tables. For Table 1, UWI is non-unique. For Table 2, UWI is Unique. new_view is what I'm hoping to achieve for my view.
TABLE 1
UWI ET
1 A
1 B
1 B
2 B
2 C
2 C
TABLE 2
UWI XTS
1 10
2 20
3 10
4 30
new_view
UWI XTS B_COUNT C_COUNT
1 10 4 3
2 20 3 4
3 10 4 5
4 30 3 2
Here's what I'm currently working with.
CREATE VIEW new_view AS
SELECT t1.UWI,
sum(case when t1.ET='B' then 1 else 0 end) as B_COUNT,
sum(case when t1.ET='C' then 1 else 0 end) as C_COUNT,
sum(case when t1.ET='D' then 1 else 0 end) as D_COUNT,
sum(case when t1.ET='E' then 1 else 0 end) as E_COUNT,
sum(case when t1.ET='F' then 1 else 0 end) as F_COUNT
FROM TABLE_1 t1
INNER JOIN (SELECT t2.UWI, t2.XTS AS TSC
from TABLE_2 t2)
on t1.UWI = t2.UWI
group by t1.UWI;
Your sample select does not match your sample data, so this is a guess but I think you just need to move the aggregation into an apply()
select t2.UWI, t2.XTS, s.*
from Table_2 t2
outer apply (
select
sum(case when t1.ET='B' then 1 else 0 end) as B_COUNT,
sum(case when t1.ET='C' then 1 else 0 end) as C_COUNT,
sum(case when t1.ET='D' then 1 else 0 end) as D_COUNT,
sum(case when t1.ET='E' then 1 else 0 end) as E_COUNT,
sum(case when t1.ET='F' then 1 else 0 end) as F_COUNT
from table_1 t1
where t1.UWI = t2.UWI
group by t1.UWI
)s
Related
I have a pretty complex query I need to do which requires data from 6 different tables. The tables look like this:
Table 1
id
name
1
first_row
Table 2
id
table1_id
count
1
1
3
2
1
5
3
1
8
Table 3
id
table1_id
1
1
2
1
Table 4
id
table3_id
count
1
1
2
2
2
4
Table 5
id
table4_id
count
Table 6
id
table5_id
count
status
And I basically want to collect the count and sums from each of the table into 1 row such as:
Result
table1_id
table1_name
SUM(table2_count)
SUM(table4_count)
SUM(table5_count)
SUM(case when table6.status = 3 THEN 1 ELSE NULL END)
SUM(case when table6.status != 3 THEN 1 ELSE NULL END)
Tables 5 and 6 are empty
This is the latest thing I have tried, I hope it is clear:
SELECT table1.*, COUNT(distinct tbl3.id), SUM(table2.count::int), (SUM(table2.count::int) - SUM(table4.count::int))
, COUNT(table5.count), COUNT(table6.count)
FROM table1
LEFT JOIN table2
ON (table1.id = table2.table1_id AND table2.deleted_at IS NULL)
LEFT JOIN (
SELECT distinct table3.id, table3.table1_id, table3.deleted_at,
SUM(table4.total_count::int),
COUNT(case when table6.status != 3 THEN 1 ELSE NULL END),
COUNT(case when table6.status = 3 THEN 1 ELSE NULL END)
FROM table3
LEFT JOIN table4 ON (table3.id = table4.visa_id AND table4.deleted_at IS NULL)
LEFT JOIN (
SELECT table5.id, table5.table4_id,
COUNT(case when table6.status != 3 THEN 1 ELSE 0 END),
COUNT(case when table6.status = 3 THEN 1 ELSE 0 END)
FROM table5
LEFT JOIN table6 ON (table5.id = table6.table5_id AND table6.deleted_at IS NULL)
GROUP BY 1
) tbl3 ON table4.id = table5.table4_id
WHERE table2.deleted_at IS NULL
GROUP BY 1
) tbl2 ON (table1.id = tbl2.table1_id AND tbl2.deleted_at IS NULL);
The result I get based on the data added on top and the above query:
table1_id
table1_name
SUM(table2_count)
SUM(table4_count)
SUM(table5_count)
SUM(case when table6.status = 3 THEN 1 ELSE NULL END)
SUM(case when table6.status != 3 THEN 1 ELSE NULL END)
1
first_row
3
32
18
2
2
I do not get any errors but all the count come out wrong, either doubled or tripled and sometimes completely wrong (not even just doubled or something).
Trying to get the count of distinct people in the intersection of top two circles. (In the figure I am trying to get the count for the region labeled as d). Keys 1,2 and 3 belong to first circle and 4,5,6 belong to second circle and 7,8,9,10 belong to third circle.
Table structure is as follows:
customer key
A234 1
A345 4
A12 5
A989 6
This is the query I have tried:
select count(distinct(c.key))
from (select c.key
from tab1 c
group by c.key
having sum(case when key1 in (1,2,3) then 1 else 0 end) > 0 and
sum(case when key1 in (4,5,6,7,8) then 1 else 0 end) = 0
) c
I think you simply got your HAVING clause mixed up.
select count(*)
from
(
select key
from tab1
group by key
having sum(case when key1 in (1,2,3) then 1 else 0 end) > 0 -- in circle A
and sum(case when key1 in (4,5,6) then 1 else 0 end) > 0 -- in circle B
and sum(case when key1 in (7,8,9,10) then 1 else 0 end) = 0 -- not in circle C
) region_d;
I have two tables as below. Caseid from first table is referenced in second table along with accidents. What I am trying to get total different accidents for a case type. Below two tables I documented sample data and expected result.
Table case:
caseId CaseType
1 AB
2 AB
3 AB
4 CD
5 CD
6 DE
Table CaseAccidents:
AccidentId caseID AccidentRating
1 1 High
2 1 High
3 1 Medium
4 1 LOW
5 2 High
6 2 Medium
7 2 LOW
8 5 High
9 5 High
10 5 Medium
11 5 LOW
Result should look like:
CaseType TotalHIghrating TotalMediumRating TotalLOWRating
AB 3 2 2
CD 2 1 1
DE 0 0 0
To get the sum of every rating, you can Use a SUM(CASE WHEN) clause, adding 1 by every record that match the rating.
In your question, you have pointed out that you want to see all distinct CaseType, you can get it by using a RIGHT JOIN, this will include all records of case table.
select case.CaseType,
sum(case when caseAccidents.AccidentRating = 'High' then 1 else 0 end) as TotalHighRating,
sum(case when caseAccidents.AccidentRating = 'Medium' then 1 else 0 end) as TotalMediumRating,
sum(case when caseAccidents.AccidentRating = 'LOW' then 1 else 0 end) as TotalLowRating
from caseAccidents
right join case on case.caseId = caseAccidents.caseID
group by case.CaseType;
+----------+-----------------+-------------------+----------------+
| CaseType | TotalHighRating | TotalMediumRating | TotalLowRating |
+----------+-----------------+-------------------+----------------+
| AB | 3 | 2 | 2 |
+----------+-----------------+-------------------+----------------+
| CD | 2 | 1 | 1 |
+----------+-----------------+-------------------+----------------+
| DE | 0 | 0 | 0 |
+----------+-----------------+-------------------+----------------+
Check it: http://rextester.com/MCGJA9193
Have you use case in a select clause before?
select C.CaseType,
sum(case when CA.AccidentRating = 'High' then 1 else 0 end)
from Case C join CaseAccidents CA on C.CaseId = CA.CaseId
group by C.CaseType
Please see this. Sample query of the table and also that result
create table #case(caseid int,casetype varchar(5))
insert into #case (caseid,casetype)
select 1,'AB' union all
select 2,'AB' union all
select 3,'AB' union all
select 4,'CD' union all
select 5,'CD' union all
select 6,'DE'
create table #CaseAccidents(AccidentId int, CaseId int,AccidentRating varchar(10))
insert into #CaseAccidents(AccidentId, CaseId, AccidentRating)
select 1,1,'High' union all
select 2,1,'High' union all
select 3,1,'Medium' union all
select 4,1,'Low' union all
select 5,2,'High' union all
select 6,2,'Medium' union all
select 7,2,'Low' union all
select 8,5,'High' union all
select 9,5,'High' union all
select 10,5,'Medium' union all
select 11,5,'Low'
My script
select c.casetype,
sum(case when ca.AccidentRating='High' then 1 else 0 end) as TotalHighRating,
sum(case when ca.AccidentRating='Medium' then 1 else 0 end) as TotalMediumRating,
sum(case when ca.AccidentRating='Low' then 1 else 0 end) as TotalLowRating
from #case c
Left join #CaseAccidents ca
on c.Caseid=ca.Caseid
group by c.casetype
Hope This could help!
Another approach using Pivot operator
SELECT casetype,
[High],
[Medium],
[Low]
FROM (SELECT c.casetype,
AccidentRating
FROM case c
LEFT JOIN CaseAccidents ca
ON ca.CaseId = c.caseid)a
PIVOT (Count(AccidentRating)
FOR AccidentRating IN ([High],
[Medium],
[Low]) ) p
Try This code once.
select casetype,
sum(case when ca.AccidentRating='High' then 1 else 0 end ) as TotalHIghrating,
sum(case when ca.AccidentRating='Medium' then 1 else 0 end ) as TotalMediumRating ,
sum(case when ca.AccidentRating='Low' then 1 else 0 end ) as TotalLOWRating
from #case c
left join #CaseAccidents ca on c.caseid=ca.CaseId
group by casetype
I have this query :
SELECT WorkId, RegisterDate, sum(RoomType1) As RoomType1, sum(RoomType2) As RoomType2, sum(RoomType3) As RoomType3, sum(RoomType4) As RoomType4, sum(RoomType5) As RoomType5, sum(RoomType6) As RoomType6, sum(RoomType7) As RoomType7, sum(RoomType8) As RoomType8
FROM (
SELECT dbo.[Work].WorkId, dbo.[Work].RegisterDate,
case dbo.Floor.RoomType when 1 then 1 else 0 end as RoomType1,
case dbo.Kat.RoomType when 2 then 1 else 0 end as RoomType2,
FROM dbo.Belediye INNER JOIN
dbo.[Is] ON dbo.Municipality.MunicipalityId= dbo.[Is].MunicipalityWorkId INNER JOIN
dbo.Look ON dbo.[Work].LookWorkId = dbo.Look.LookId ,
WHERE (dbo.Look.LocationIS NOT NULL)
) E
GROUP BY WorkId,
This query works as expected, but I can't understand why it has two selects, why does it need them? Please explain it to me. Thanks.
As you suspected this query dont need two selects and could be rewritten without sub-query:
SELECT i.IsId,
i.KayitTarihi,
SUM(case k.OdaTipi when 1 then 1 else 0 end) as RoomType1,
SUM(case k.OdaTipi when 2 then 1 else 0 end) as RoomType2,
SUM(case k.OdaTipi when 3 then 1 else 0 end) as RoomType3,
SUM(case k.OdaTipi when 4 then 1 else 0 end) as RoomType4,
SUM(case k.OdaTipi when 5 then 1 else 0 end) as RoomType5,
SUM(case k.OdaTipi when 6 then 1 else 0 end) as RoomType6,
SUM(case k.OdaTipi when 7 then 1 else 0 end) as RoomType7,
SUM(case k.OdaTipi when 8 then 1 else 0 end) as RoomType8
FROM dbo.Belediye b
INNER JOIN dbo.[Is] i
ON b.BelediyeId = i.BelediyeIsId
INNER JOIN dbo.YerGorme yg
ON i.YerGormeIsId = yg.YerGormeId
INNER JOIN dbo.Kat k
ON yg.YerGormeId = k.YerGorme_YerGormeId
WHERE yg.Lokasyon IS NOT NULL
GROUP BY i.IsId, i.KayitTarihi
Note: use table aliases
I am finding difficulty to frame a select query.
PFB, for the table and corresponding data:
ID DLS MATCH_STATUS LAST_UPDATE_TIME BO CH FT
1 0 0 09-07-2013 00:00:00 IT TE NA
1 1 1 09-07-2013 00:01:01 IT TE NA
2 0 0 09-07-2013 10:00:00 IP TE NA
3 0 0 09-07-2013 11:00:00 IT YT NA
3 2 2 09-07-2013 11:01:00 IT YT NA
Here
Match_Status 0-->Initial Record
1-->Singel Match
2-->Multi Match
For every record there will be a initial entry with match_status 0 and subsequent matching process end other number such as 1,2 will be update.
I am trying to retrieve records such as total record , waiting match ,single match and multi match group by BO, CH and FT
Below is the expected out put:
BO CH FT TOTAL_RECORD AWAITNG_MATCH SINGLE_MATCH MULTI_MATCH
IT TE NA 1 0 1 0
IP TE NA 1 1 0 0
IT YT NA 1 0 0 2
I have tried below query :
select BO,CH,FT,sum(case when match_status=0 then 1 else 0 end) as TOTAL_RECORD,
sum(case when match_status = 0 then 1 else 0 end) as AWAITING_MATCH,
sum(case when match_status = 1 then 1 else 0 end) as SINGLE_MATCH,
sum(case when match_status = 2 then 1 else 0 end) as MULTI_MATCH from
table1 where last_update_time >= current_timestamp-1
group by BO,CH,FT;
problem with the above query is, awaiting_match is getting populated same as total record as I understand because of match_status=0
Similarly I tried with
select BO,CH,FT,sum(case when match_status=0 then 1 else 0 end) as TOTAL_RECORD,
select (sum(case when t1.ms=0 then 1 else 0 end) from
(select max(match_status) as ms from table1 where last_update_time >= current_timestamp-1 group by id)t1) )awaiting_match,
sum(case when match_status = 1 then 1 else 0 end) as SINGLE_MATCH,
sum(case when match_status = 2 then 1 else 0 end) as MULTI_MATCH from
table1 where last_update_time >= current_timestamp-1
group by BO,CH,FT;
problem with the approach is awaiting_match is getting populated with the same value for subsequent row entry.
Please help me with a suitable query for the desired format.
Thanks a lot in advance.
It seems that you want the last match status. I am guessing that this is actually the maximum of the statuses. If so, the following solves the problem by first grouping on id and then doing the grouping to summarize:
select BO, CH, FT,
count(*) as TOTAL_RECORD,
sum(case when lastms = 0 then 1 else 0 end) as AWAITING_MATCH,
sum(case when lastms = 1 then 1 else 0 end) as SINGLE_MATCH,
sum(case when lastms = 2 then 1 else 0 end) as MULTI_MATCH
from (select id, bo, ch, ft, MAX(match_status) as lastms
from table1
where last_update_time >= current_timestamp-1
group by id, bo, ch, ft
) t
group by BO, CH, FT;
If you actually want the last update to provide the status for the id, then you can use row_number() to enumerate the rows for each id, order by update time descending, and choose the first one:
select BO, CH, FT,
count(*) as TOTAL_RECORD,
sum(case when lastms = 0 then 1 else 0 end) as AWAITING_MATCH,
sum(case when lastms = 1 then 1 else 0 end) as SINGLE_MATCH,
sum(case when lastms = 2 then 1 else 0 end) as MULTI_MATCH
from (select id, bo, ch, ft, match_status,
ROW_NUMBER() over (partition by id order by last_update_time desc) as seqnum
from table1
where last_update_time >= current_timestamp-1
) t
where seqnum = 1
group by BO, CH, FT;