vue3: control property with a timed function - vue.js

Question

First of all, I am a new vuejs developer and my purpose is to get acquainted with Vue, so, not going to use any external plugins or components.
I am writing a simple alert component, which looks like this:
<Alert :show="showAlert" />
I want the show property to return back to false after 2 seconds. How can I do this from inside the component (i.e., not in the page where this component is used). I tried this:
import { computed } from 'vue';
export default {
props: ['show'],
setup(props) {
const shown = computed(() => {
if (props.show) {
setTimeout(() => {
console.log("hiding the alert...")
props.show = false
}, 2000);
}
return props.show.value
})
return { shown }
}
};
the compiler said:
14:15 error Unexpected timed function in computed function vue/no-async-in-computed-properties
16:19 error Unexpected mutation of "show" prop vue/no-mutating-props
My rational is that the delay of alert should be controlled by the alert component (which could be changed by a prop), but not forcing the caller to write some thing like:
function Alert(delay) {
showAlert = true
setTimeout(() => showAlert = false, delay)
}

Answer 1

There are 2 errors.
First vue/no-mutating-props, props are read only so you are not supposed to change it from within the component. It is still possible to change props from outside the component and pass down to it.
For this you should copy the value of props to your data()
data() {
return {
showAlert
}
}
You should be able to update showAlert with no problem.
The second error vue/no-async-in-computed-properties, you cannot write async function inside computed(), so the alternative is to use watch instead.