Multiple rows with Maximum Values in sql - sql

Can anyone help me with the below?
I'm trying to group by the (PO) and by (line) to get the Max of (Quantity) regardless of the value in (type).
I tried to group by PO and line both and it didn't work and showing this
error: "not group by function".
the data look like:
po
line
type
quantity
100
1
4
23
100
1
5
20
100
2
1
40
200
1
1
10
200
2
2
15
and I would like to get the below result:
po
line
type
quantity
100
1
4
23
100
2
1
40
200
1
1
10
200
2
2
15
the code:
select
orno "PO NUMBER",
pono "Line",
oltp "Line Type",
max(qoor) "Quantity"
from
table
group by orno;

One method is a correlated subquery:
select t.*
from t
where t.quantity = (select max(t2.quantity)
from t t2
where t2.po = t.po and t2.line = t.line
);
In Oracle, another option is aggregation:
select po, line,
max(type) keep (dense_rank first order by quantity desc) as type,
max(quantity) as quantity
from t
group by po, line;
The keep syntax is Oracle's fancy way of implementing a "first" aggregation function.

Related

How to get first row of each group without using window functions Oracle?

How can i get first row of each group with all attributes without using window functions like row_number etc.
Example Data is:
id amount
1 100
1 200
2 150
2 300
2 250
3 400
What I want as a result:
id amount
1 200
2 300
3 400
No need for a window function:
SELECT id, MAX( amount ) AS amount
FROM your_table
GROUP BY id

SQL - Counting over several groups

I have a list of transactions where the ID's are repeated and I have the quantity of items being bought. I need to count the number of times that a particular number of items were purchased at once.
Row
ItmNBR
TQTY
1
123
5
2
123
5
3
123
5
3
456
25
4
456
19
I need to produce an out put like this...
ItmNBR
QTY
Occurance
123
5
3
123
19
1
123
25
1
I can get the first two columns of my result but when I attempt to counting over a partition I end up counting getting repeating numbers since I'm only looking up 9 items I just count the number of rows in which the Cnt is the same.
TOT_IVO_ITM_QTY
Count(*) OVER (PARTITION BY QTY) AS CNT
FROM dataset
WHERE YEAR(bus_dt) = 2021
AND ITM_NBR IN (12639,12940,12949,12955,13485,13666,43950,631343,1103731)
AND QTY BETWEEN 5 AND 25
ORDER BY ITM_NBR
,QTY
GROUP BY ITM_NBR, TOT_IVO_ITM_QTY```
I think you just want group by:
select ItmNBR, QTY, count(*)
from t
group by ItmNBR, QTY
order by count(*) desc;
This assumes that you want the count by item and quantity, which seems to be the gist of the question.

Duplicate id rows with few columns to unique id row with many columns Oracle SQL

I have a pole table that can have one to four streetlights on it. Each row has a pole ID and the type (a description) of streetlight. I need the ID's to be unique with a column for each of the possible streetlights. The type/description can anyone of 26 strings.
I have something like this:
ID Description
----------------
1 S 400
1 M 200
1 HPS 1000
1 S 400
2 M 400
2 S 250
3 S 300
What I need:
ID Description_1 Description_2 Description_3 Description_4
------------------------------------------------------------------
1 S 400 M 200 HPS 1000 S 400
2 M 400 S 250
3 S 300
The order the descriptions get populated in the description columns is not important, e.g. for ID = 1 the HPS 1000 value could be in description column 1, 2, 3, or 4. So, long as all values are present.
I tried to pivot it but I don't think that is the right tool.
select * from table t
pivot (
max(Description) for ID in (1, 2, 3))
Because there are ~3000 IDs I would end up with a table that is ~3001 rows wide...
I also looked at this Oracle SQL Cross Tab Query But it is not quite the same situation.
What is the right way to solve this problem?
You can use row_number() and conditional aggregation:
select
id,
max(case when rn = 1 then description end) description_1,
max(case when rn = 2 then description end) description_2,
max(case when rn = 3 then description end) description_3,
max(case when rn = 4 then description end) description_4
from (
select t.*, row_number() over(partition by id order by description) rn
from mytable t
) t
group by id
This handles up to 4 descriptions per id. To handle more, you can just expand the select clause with more conditional max()s.

Use aggregation only on rows where count(ID) is greater than one

Hi I have the following table
Cash_table
ID Cash Rates
1 50 3
2 100 4
3 70 10
3 60 10
4 13 7
5 20 8
5 10 10
6 10 5
What I want as a result is to cumulate all the entries that have a Count(id)>1 like this:
ID New_Cash New_Rates
1 50 3
2 100 4
3 (70+60)/(10+10) 10+10
4 13 7
5 (20+10)/(8+10) 8+10
6 10 5
So I only want to change the rows where Count(id)>1 and leave the rest like it was.
For the rows with count(id)>1 I want to sum up the rates and take the sum of the cash and divide it by the sum of the rates. The Rates alone aren't a problem since I can sum them up and group by id and get the desired result.
The problem is with the cash column:
I am trying to do it with a case statement but it isn't working:
select id, sum(rates) as new_rates, case
when count(id)>1 then sum(cash)/nullif(sum(rates),0))
else cash
end as new_cash
from Cash_table
group by id
You only need group by id and aggregate:
select
id,
sum(cash) / (case count(*) when 1 then 1 else sum(rates) end) as new_cash,
sum(rates) as new_rates
from Cash_table
group by id
order by id
See the demo.
You can aggregate rate and cash columns by sum() function with grouping by id
select
id,
sum(cash)/decode( sum( nvl(rates,0) ), 0 ,1, sum( nvl(rates,0) )) as new_cash,
sum(rates) as new_rates
from cash_table
group by id
there's no nullif() function in Oracle, use nvl() instead
switch case part ( where decode() function is used ) against the
possibility of division by zero

complex paratition sum in postgresql

I have tables as follow:
A deliveries
delveryid clientid deliverydate
1 10 2015-01-01
2 10 2015-02-02
3 11 2015-04-08
B items in deliveris
itemid deliveryid qty status
70 1 5 1
70 1 8 2
70 2 10 1
72 1 12 1
70 3 100 1
I need to add a column to my query that gives me the qty of each part in other deliveris of the same client.
meaning that for given data of client 10 and delivery id 1 I need to show:
itemid qty status qtyOther
70 5 1 10 //itemid 70 exists in delivery 2
70 8 2 10 //itemid 70 exists in delivery 2
72 12 1 0 //itemid 72 doesn't exists in other delivery of client 11
Since I need to add qtyOther to my existing qry i'm trying to avoid using Group By as it's a huge query and if I use SUM in select I will have to group by all items in select.
This is what I have so far:
Select ....., coalesce( SUM(a.qty) OVER (PARTITION BY a.itemid) ,0) AS qtyOther
FROM B b
LEFT JOIN A a USING
LEFT JOIN (other tables)
WHERE clientid=10 ....
This query gives me the total sum of qty per itemid for specific clientid, regardless of which delivery it is. How do I change it so it will consider the delivryid? I need something like:
coalesce( SUM(a.qty) OVER (PARTITION BY a.itemid) FROM B where deliveryid<>b.deliveryid ,0) AS qtyOther
Any suggestions how to do that?
Note: I can NOT change the condition in WHERE.
I think you just want to subtract out the total for the current delivery:
Select .....,
(coalesce( SUM(a.qty) OVER (PARTITION BY a.itemid), 0) -
coalesce( SUM(a.qty) OVER (PARTITION BY a.itemid, a.deliveryid), 0)
) as qtyOther