I'm using react navigation in a react native project and i am unable to find how to go back to navigation root (first screen in app) from an arbitrary screen. Navigation is like this:
<NavigationContainer>
<Stack.Navigator>
{!loggedIn ? (
// Login
<Stack.Group>
<Stack.Screen name="LogInScreen" component={LogInScreen} />
</Stack.Group>
) : (
// App Screens
<Stack.Group>
// This Tab navigator may have more stacks inside
<Stack.Screen name="AppTabsNavigator" component={AppTabsNavigator} />
<Stack.Screen name="SomeErrorOutsideTabs" component={SomeErrorOutsideTabs} />
</Stack.Group>
)}
// Error Modals
<Stack.Group>
<Stack.Screen name="SomeErrorScreen" component={SomeErrorScreen} />
</Stack.Group>
<Stack.Navigator>
</NavigationContrainer>
Use cases are:
User in LogInScreen causes some error -> SomeErrorScreen shows -> User press button to go back to LogInScreen.
User in anywhere else causes some error -> SomeErrorScreen shows -> User press button to go back to first screen in AppTabsNavigator (sometimes does not work depending on inner stacks).
The summary is, no matter where you are, when you press button in SomeErrorScreen you must go back to "first app screen", which is LogInScreen if not logged in or first tab of AppTabsNavigator if logged in.
I have tried using popToTop() but it does not work when there are inners Stacks like SomeResourceStack inside AppTabsNavigator to contain index and show of resource, for example:
User in AppTabsNavigator > SomeResourceStack > index access to AppTabsNavigator > SomeResourceStack > show, cause SomeErrorScreen to appear and when going back, he goes back to AppTabsNavigator > SomeResourceStack > show instead of AppTabsNavigator first tab.
Answer:
The right answer is to use reset like Anthony Marino said and combine it with Ararat Ispiroglu suggestion. I controlled Android's back button behavior as well:
...
import { BackHandler } from 'react-native'
import { useFocusEffect } from '#react-navigation/native'
import { useSelector } from 'react-redux'
...
const SomeErrorScreen = ({ navigation }) => {
...
const loggedIn = useSelector(state => state.auth.loggedIn)
const onGoingBackButtonPress = React.useCallback(() => {
navigation.reset({
index: 0,
routes: [{ name: !loggedIn ? 'LogInScreen' : 'AppTabsNavigator' }]
})
}, [navigation, loggedIn])
const androidBackButtonCallback = React.useCallback(() => {
const onBackPress = () => {
onGoingBackButtonPress()
return true
}
BackHandler.addEventListener('hardwareBackPress', onBackPress)
return () => BackHandler.removeEventListener('hardwareBackPress', onBackPress)
}, [onGoingBackButtonPress])
useFocusEffect(androidBackButtonCallback)
...
return <View>
<Button onPress={onGoingBackButtonPress } />
</View>
}
export default SomeErrorScreen
You can reset your navigator
navigation.reset({
index: 0,
routes: [
{
name: 'SomeStackScreen',
params: { someParam: 'Param1' },
},
],
})
As seen in the docs here
You have two options to do that with your current navigation setup;
a) When you need to go back to root you can check if it's logged in or not
simply navigation.navigate(loggedIn ? "AppTabsNavigator" : "LogInScreen")
b) You can set the same name for the top level screen in the navigation for both logged and non-logged in screens. And navigation will pickup whichever screen is mouthed.
{!loggedIn ? (
// Login
<Stack.Group>
<Stack.Screen name="RootScreen" component={LogInScreen} />
</Stack.Group>
) : (
// App Screens
<Stack.Group>
// This Tab navigator may have more stacks inside
<Stack.Screen name="RootScreen" component={AppTabsNavigator} />
<Stack.Screen name="SomeErrorOutsideTabs" component={SomeErrorOutsideTabs} />
</Stack.Group>
)}
Can't pass params to the nested navigator. I keep getting errors undefined is not an object evaluating route.params.data
I do have different stack navigators for homeDrawer and LiveModeDrawer. I am using React navigation version 6. I looked over the documents however what I have read is not working.
app.js
<Drawer.Navigator>
<Drawer.Screen
name="HomeDrawer"
options={{ headerShown: false }}
component={MainNavigator}
/>
<Drawer.Screen
name="LiveModeDrawer"
options={{ headerShown: false }}
component={LiveModeStackNavigator}
/>
</Drawer.Navigator>;
todo.js
this.props.navigation.navigate("LiveModeDrawer", {
screen: "LiveModeAlertOnly",
params: { data: "jane" },
});
live.js
export default function LiveModeAlertsNotifications({ route, navigation }) {
const { data } = route.params;
console.info(data);
}
AFAIK the second parameter already are the Params
Change this:
this.props.navigation.navigate('LiveModeDrawer', {
screen: 'LiveModeAlertOnly',
params: {data: 'jane'},
});
To:
this.props.navigation.navigate('LiveModeDrawer', {
data: 'jane,
});
Or:
export default function LiveModeAlertsNotifications({route, navigation}) {
const {data} = route.params.params; // Add another params
console.info(data)
I forgot to pass the prop into a sub component
I'm following this guide: https://www.freecodecamp.org/news/react-native-firebase-tutorial/ in attempt to learn how to use firebase, and even though I've followed the code very closely, I'm receiving a NAVIGATION error:
The action 'NAVIGATE' with payload {"name":"Home","params":{"user":{"id":"AWSKEmmUsua5koR1V3x5bapc3Eq2","email":"tk#gmail.com","fullName":"t"}}} was not handled by any navigator.
Do you have a screen named 'Home'?
I do however, have a screen named Home. App.js:
import Home from './src/Home';
import Login from './src/Login/Login';
import Registration from './src/Registration/Registration';
const Stack = createStackNavigator();
export default function App() {
const [loading, setLoading] = useState(true);
const [user, setUser] = useState(null);
return (
<NavigationContainer>
<Stack.Navigator>
{ user ? (
<Stack.Screen name="Home">
{props => <Home {...props} extraData={user} />}
</Stack.Screen>
) : (
<>
<Stack.Screen name="Login" component={Login} />
<Stack.Screen name="Registration" component={Registration} />
</>
)}
</Stack.Navigator>
</NavigationContainer>
);
}
When I use the Registration form to register a new user and Navigate to the Home page is when I get the error. Registration.js:
import { firebase } from '../firebase/config';
export default function Registration({ navigation }) {
const [fullName, setFullName] = useState('');
const [email, setEmail] = useState('');
const [password, setPassword] = useState('');
const [confirmPassword, setConfirmPassword] = useState('');
const onFooterLinkPress = () => {
navigation.navigate('Login');
}
const onRegisterPress = () => {
if (password !== confirmPassword) {
alert("Passwords do not match!");
return
}
// This works. However, navigation does not for some reason
firebase.auth()
.createUserWithEmailAndPassword(email, password)
.then((response) => {
const uid = response.user.uid
const data = {
id: uid,
email,
fullName
}
const usersRef = firebase.firestore().collection("users");
usersRef.doc(uid).set(data).then(() => {
// This is where the navigation error lies. It has nothing to do with the component
// This error happened even when I created a new plain Home component
navigation.navigate("Home", { user: data})
})
.catch((error) => alert(error))
})
.catch((error) => alert(error))
}
return (
....Input Forms
<TouchableOpacity
style={styles.loginButton}
onPress={() => onRegisterPress()}
>
<Text style={styles.buttonTitle}>Create Account</Text>
</TouchableOpacity>
I have used React Navigation before and haven't run into this issue. I am not using nested navigators and cannot see where the issue lies. Thank you for reading.
Adding to Göksel Pırnal answers:
At first, suppose there is no user. So We are in Registration Screen. At that stage, our navigator doesn’t even know whether there is any “Home” Screen. At this stage, our navigator only knows 2 screens: “Login” and “Registration” screens.
You need to notify our app.js whether anyone registered in the Registration screen or not. After that our app.js should change the value of 'user' in [user,setUser].
In your, App.js put this lines of code:
const [initializing,setInitializing]=useState(true)
useEffect(()=>{
const subscriber=firebase.auth().onAuthStateChanged((user)=>{
setUser(user)
setInitializing(false)
})
return subscriber
},[])
if (initializing) return null //Here you may use an Activity indicator
Then after rerendering our navigator will see the value of “user” has changed and it should navigate to the Home screen.
And guess what! You do not need to navigate manually from Registration Screen as you already put a condition in App.js ( in return () ).
You have a problem where you check the user value in App.js. After the registration is done, you did not assign the state in the App.js page and it will always be null. The Home page will not be added to the stack because the user value is null. That's why you got the error.
Solution: You need to notify App.js after registration.
how to give dynamic initial route name in the react-navigation? if the unit exists we have to redirect to another route or else we have to take user another route.
Note: I'm creating a bottom tab navigator in which I have to set an initial route to that particular bottom tab navigator.
(Not the authentication flow)
import React, {Component} from 'react';
import {createAppContainer} from 'react-navigation';
import {createMaterialBottomTabNavigator} from 'react-navigation-material-bottom-tabs';
... imports
function getInitialScreen() {
AsyncStorage.getItem('unit')
.then(unit => {
return unit ? 'Home' : 'secondTab';
})
.catch(err => {
});
}
const TabNavigator = createMaterialBottomTabNavigator(
{
Home: {
screen: HomeScreen,
navigationOptions: {
.....navigation options
},
},
secondTab: {
screen: secondTab,
},
},
{
initialRouteName: getInitialScreen(),
},
);
export default createAppContainer(TabNavigator);
See according to the docs, initialRoute name should not be a async func .
So ideally what you should do is , anyways you need a splashscreen for your app right, where you display the logo and name of app. Make that page the initialRoute and in its componentDidMount, check for the async function and navigate to ddesired page.
Like what ive done :
createSwitchNavigator(
{
App: TabNavigator,
Auth: AuthStack,
SplashScreen: SplashScreen,
},
{
initialRouteName: 'SplashScreen',
},
),
And inside SplashScreen im doing :
componentDidMount(){
if (token) {
this.props.navigation.navigate('App');
} else {
this.props.navigation.navigate('Auth');
}
}
Hope its clear. Feel free for doubts
As you can see here:
If you need to set the initialRouteName as a prop it is because there
is some data that you need to fetch asynchronously before you render
the app navigation. another way to handle this is to use a
switchnavigator and have a screen that you show when you are fetching
the async data, then navigate to the appropriate initial route with
params when necessary. see docs for a full example of this.
Take a look at here.
You'll find more description!
Also quick fix for this situation is check your condition inside SplashScreen componentDidMount() function
Example of SplashScreen :
componentDidMount(){
AsyncStorage.getItem('unit')
.then(unit => {
if(unit){
this.props.navigation.navigate('Home')
}else{
this.props.navigation.navigate('secondTab')
}
})
.catch(err => {
});
}
You can check the condition on the main page or App.js
render() {
const status = get AsyncStorage.getItem('unit');
if(status != null)
{ return <Home/> }
else
{ return <AnotherScreen/> }
}
But we can switch between pages if we use stacknavigator or switchnavigator..
We cant goto the particular tabs directly according to my knowledge. (Correct me if I am wrong).
The official documentation gives you this example to achieve pretty much what you want:
isSignedIn ? (
<>
<Stack.Screen name="Home" component={HomeScreen} />
<Stack.Screen name="Profile" component={ProfileScreen} />
<Stack.Screen name="Settings" component={SettingsScreen} />
</>
) : (
<>
<Stack.Screen name="SignIn" component={SignInScreen} />
<Stack.Screen name="SignUp" component={SignUpScreen} />
</>
)
Ok So in your navigation page create state and change its value accordingly AsyncStorage like
render() {
const status = get AsyncStorage.getItem('unit');
if(status != null)
{ setState({ name : 'Home'}) }
else
{ setState({ name : 'anotherTab'}) }
}
then pass that state to tabNavigation
initialRouteName: this.state.name,
and this state , setState functions are classed based so you have to use useState instead to initial state on your page
The Goal
Using react navigation, navigate from a screen in a navigator to a screen in a different navigator.
More Detail
If I have the following Navigator structure:
Parent Navigator
Nested Navigator 1
screen A
screen B
Nested Navigator 2
screen C
screen D
how do I go from screen D under nested navigator 2, to screen A under nested navigator 1? Right now if I try to navigation.navigate to screen A from screen D there will be an error that says it doesn't know about a screen A, only screen C and D.
I know this has been asked in various forms in various places on this site as well as GitHub(https://github.com/react-navigation/react-navigation/issues/983, https://github.com/react-navigation/react-navigation/issues/335#issuecomment-280686611) but for something so basic, there is a lack of clear answers and scrolling through hundreds of GitHub comments searching for a solution isn't great.
Maybe this question can codify how to do this for everyone who's hitting this very common problem.
In React Navigation 5, this becomes much easier by passing in the screen as the second parameter:
navigation.navigate('Nested Navigator 2', { screen: 'screen D' });
You can also include additional levels if you have deeply nested screens:
navigation.navigate('Nested Navigator 2', {
screen: 'Nested Navigator 3', params: {
screen: 'screen E'
}
});
Update: For React Navigation v5, see #mahi-man's answer.
You can use the third parameter of navigate to specify sub actions.
For example, if you want to go from screen D under nested navigator 2, to screen A under nested navigator 1:
this.props.navigation.navigate(
'NestedNavigator1',
{},
NavigationActions.navigate({
routeName: 'screenB'
})
)
Check also:
https://reactnavigation.org/docs/nesting-navigators/
React Navigation v3:
Navigation.navigate now takes one object as the parameter. You set the stack name then navigate to the route within that stack as follows...
navigation.navigate(NavigationActions.navigate({
routeName: 'YOUR_STACK',
action: NavigationActions.navigate({ routeName: 'YOUR_STACK-subRoute' })
}))
Where 'YOUR_STACK' is whatever your stack is called when you create it...
YOUR_STACK: createStackNavigator({ subRoute: ... })
On React Navigation v5 you have here all the explanation:
https://reactnavigation.org/docs/nesting-navigators#navigating-to-a-screen-in-a-nested-navigator
Route definition
function Root() {
return (
<Stack.Navigator>
<Stack.Screen name="Profile" component={Profile} />
<Stack.Screen name="Settings" component={Settings} />
</Stack.Navigator>
);
}
function App() {
return (
<NavigationContainer>
<Drawer.Navigator>
<Drawer.Screen name="Home" component={Home} />
<Drawer.Screen name="Root" component={Root} />
</Drawer.Navigator>
</NavigationContainer>
);
}
Instruction
navigation.navigate('Root', { screen: 'Settings' });
In React Navigation v5, you can do something like:
navigation.navigate('Root', {
screen: 'Settings',
params: {
screen: 'Sound',
params: {
screen: 'Media',
},
},
});
In the above case, you're navigating to the Media screen, which is in a navigator nested inside the Sound screen, which is in a navigator nested inside the Settings screen.
In React Navigation v5/v6
Navigation to Specific Screen on a Stack
navigation.navigate('Home', {
screen: 'Profile',
params: {userID: 1}
}
)
What If We Nest More?
Consider this structure:
NAVIGATOR:
*StackA
*ScreenC
*ScreenD
*StackB
*ScreenI
*StackE
*ScreenF
*StackG
*ScreenJ
*ScreenH
We want to get from ScreenC inside StackA all the way to ScreenH in StackB.
We can actually chain the parameters together to access specific screens.
navigation.navigate('StackB',{
screen: 'StackE',
params: {
screen: 'StackG',
params: {
screen: 'ScreenH'
}
}
}
)
For more information
In React Navigation 3
#ZenVentzi, Here is the answer for multi-level nested navigators when Nested Navigator 1 has Nested Navigator 1.1.
Parent Navigator
Nested Navigator 1
Nested Navigator 1.1
screen A
screen B
Nested Navigator 2
screen C
screen D
We can just inject NavigationActions.navigate() several times as needed.
const subNavigateAction = NavigationActions.navigate({
routeName: 'NestedNavigator1.1',
action: NavigationActions.navigate({
routeName: 'ScreenB',
params: {},
}),
});
const navigateAction = NavigationActions.navigate({
routeName: 'NestedNavigator1',
action: subNavigateAction,
});
this.props.navigation.dispatch(navigateAction);
UPDATE
For React Navigation 5, please check #mahi-man's answer above.
https://stackoverflow.com/a/60556168/10898950
React Navigation v6
docs
function Home() {
return (
<Tab.Navigator>
<Tab.Screen name="Feed" component={Feed} />
<Tab.Screen name="Messages" component={Messages} />
</Tab.Navigator>
);
}
function App() {
return (
<NavigationContainer>
<Stack.Navigator>
<Stack.Screen
name="Home"
component={Home}
options={{ headerShown: false }}
/>
<Stack.Screen name="Profile" component={Profile} />
<Stack.Screen name="Settings" component={Settings} />
</Stack.Navigator>
</NavigationContainer>
);
}
navigation.navigate('Home', { screen: 'Messages' });
try this,
Parent Navigator
Nested Navigator 1
screen A
screen B
Nested Navigator 2
screen A
screen C
screen D
and then, there is no need to go A in 1 from D in 2, you can just go A from D both in 2, you can check here image or A stack navigator for each tab
Complete freedom: singleton w/ navigationOptions
If you have a situation where you have multiple navigation stacks and sub stacks, this can be frustrating to know how to get a reference to the desired stack given how React Navigation is setup. If you were simply able to reference any particular stack at any given time, this would be much easier. Here's how.
Create a singleton that is specific to the stack you want to reference anywhere.
// drawerNavigator.js . (or stackWhatever.js)
const nav = {}
export default {
setRef: ref => nav.ref = ref,
getRef: () => nav.ref
}
Set the reference on desired navigator using navigatorOptions
import { createBottomTabNavigator } from 'react-navigation'
import drawerNavigation from '../drawerNavigator'
const TabNavigation = createBottomTabNavigator(
{
// screens listed here
},
{
navigationOptions: ({ navigation }) => {
// !!! secret sauce set a reference to parent
drawerNavigation.setRef(navigation)
return {
// put navigation options
}
}
}
)
Now you can reference drawerNavigator anywhere inside or outside
// screen.js
import drawerNavigator from '../drawerNavigator'
export default class Screen extends React.Component {
render() {
return (
<View>
<TouchableHighlight onPress={() => drawerNavigator.getRef().openDrawer()}>
<Text>Open Drawer</Text>
</TouchableHighlight>
</View>
)
}
}
Explanation
Within Step 2, a Tab Navigator is one of the screens within a Drawer Navigator. Tab Navigator needs to close the drawer but also anywhere within your app, you can call drawerNavigator.getRef().closeDrawer() after this step is performed. You are not limited to having direct access to props.navigation after that step.
If nothing else works (as in my case), just do:
Main/Root/App.js:
<StackNavigator ref={(x) => (global.stackNavigator = x)} />
Anywhere:
global.stackNavigator.dispatch(
NavigationActions.navigate({
routeName: 'Player',
params: { },
}),
);
In React Navigation V5, you can do like this:
but remember to you placing this on the parent side
this.props.navigation.navigate(
'Nested Navigator 1',
{name: 'jane'},
this.props.navigation.navigate('Screen A', {id: 2219}),
);
While working on a react-native project, i came across same situation. I have tried multiple ways in navigating to screen but failed.
After many trials, I tried passing parents navigation object to children and made a navigation function call and it worked.
Now coming to your issues, If you want to navigation from screen D to screen A do follow these steps.
-> Pass nested navigator 2 navigation props to its children using screenProps.
export default class Home extends Component {
static navigationOptions = {
header:null
};
constructor(props) {
super(props);
this.state = {
profileData: this.props.navigation.state.params,
route_index: '',
}
}
render() {
return (
<ParentNavigator screenProps={this.props.navigation} />
);
}
}
export const ParentNavigator = StackNavigator({
// ScreenName : { screen : importedClassname }
Nested1: { screen: nested1 },
Nested2: { screen : nestes1 }
});
export const nested1 = StackNavigator({
ScreenA: { screen: screenA },
ScreenB: { screen : screenB }
});
export const nested2 = StackNavigator({
ScreenC: { screen: screenC },
ScreenD: { screen : screenD }
});
You can receive the navigation in children using
const {navigate} = this.props.screenProps.navigation;
Now this navigate() can be used to navigate between children.
I accept that this process is little confusing but i couldn't find any solutions so had to go with this as i have to complete my requirement.
I've found also such solution here:
onPress={() =>
Promise.all([
navigation.dispatch(
NavigationActions.reset({
index: 0,
// TabNav is a TabNavigator nested in a StackNavigator
actions: [NavigationActions.navigate({ routeName: 'TabNav' })]
})
)
]).then(() => navigation.navigate('specificScreen'))
}
const subAction = NavigationActions.navigate({ routeName: 'SignInScreen' });
AsyncStorage.clear().then(() =>
this.props.navigation.navigate('LoggedOut', {}, subAction));
LoggedOut is the stack name where signIn screen is placed.
My goal was to have the authentication screens all share the same background and the rest of the app using the regular stack transition.
After hours I've found the solution is to have the createStackNavigator() in the same file as your component wrapper. So that you can successfully expose the static router as the document stated. This will avoid the You should only render one navigator explicitly in your app warning and you can use this.props.navigation.navigate('AnyScreen') to navigate to any nested screen.
AuthRouter.js
export const AuthNavigationStack = createStackNavigator(
{
Login: {
screen: Login
},
CreateAccount: {
screen: CreateAccount
}
}
);
export default class AuthContainer extends React.Component {
constructor( props ) {
super( props );
}
static router = AuthNavigationStack.router;
render() {
return (
<ImageBackground
style={ {
width: '100%',
height: '100%'
} }
source={ require( '../Images/johannes-andersson-yosimite.jpg' ) }
blurRadius={ 10 }
>
<StatusBar
barStyle="dark-content"
backgroundColor="transparent"
translucent={ true }
/>
<AuthNavigationStack navigation={ this.props.navigation } />
</ImageBackground>
);
}
}
MessengerRouter.js
export const MessengerStackNavigator = createStackNavigator(
{
Chat: {
screen: Chat,
},
User: {
screen: User,
},
}
);
export default class MainContainer extends React.Component {
constructor( props ) {
super( props );
}
static router = MessengerStackNavigator.router;
render() {
return <MessengerStackNavigator navigation={ this.props.navigation } />;
}
}
Router.js
import { createStackNavigator } from 'react-navigation';
import AuthRouter from './AuthRouter';
import MessengerRouter from './MessengerRouter';
export const RootNavigationStack = createStackNavigator( {
AuthContainer: {
screen: AuthRouter,
navigationOptions: () => ( {
header: null
} )
},
MessengerRouter: {
screen: MessengerRouter,
navigationOptions: () => ( {
header: null
} )
}
} );
RootContainer.js
import { RootNavigationStack } from '../Config/Router';
class RootContainer extends Component {
render() {
return <RootNavigationStack />;
}
}
Notes:
Pass header: null from the RootNaviagtionStack to the nested stacks to remove the overlapping header
If you navigate from Nested A to Nested B and use the back button, it will return you to the first screen in Nested B. Not a big problem but I haven't figured out how to fix it.
This is another way to navigate to nested screen using Version: 5.x. It worked without any additional configuration. More info here: https://reactnavigation.org/docs/use-link-to
const linkTo = useLinkTo();
// ...
// Just call this
linkTo(`/main/sub/subB`);