I have the following XML:
<Main>
<ResultOutput>
<Name>TEST1</Name>
<Value>D028</Value>
</ResultOutput>
<ResultOutput>
<Name>TEST2</Name>
<Value>Accept</Value>
</ResultOutput>
<ResultOutput>
<Name>TEST3</Name>
<Value />
</ResultOutput>
</Main>
What I want is to get the value of the <value> tag in SQL.
Basically want to say get <value> where <Name> has the value of TEST1, as an example
This is what I have at the moment, but this depends on the position of the XML tag:
XMLResponse.value(Main/ResultOutput/Value)[5]', nvarchar(max)')
The best way to do this is not to put extra where .value clauses, but to do it directly in XQuery.
Use [nodename] to filter by a child node, you can even nest such predicates. text() gets you the inner text of the node:
XMLResponse.value('(/Main/ResultOutput[Name[text()="TEST1"]]/Value/text())[1]', 'nvarchar(max)')
Below is an example using the sample XML in your question. You'll need to extend this to add namespace declarations and the proper xpath expressions that may be present in your actual XML as your query attempt suggests.
SELECT ResultOutput.value('Value[1]', 'nvarchar(100)')
FROM #xml.nodes('Main/ResultOutput') AS Main(ResultOutput)
WHERE ResultOutput.value('Name[1]', 'nvarchar(100)') = N'TEST1';
Related
I have something like the following XML in a column of a table:
<?xml version="1.0" encoding="utf-8"?>
<container>
<param name="paramA" value="valueA" />
<param name="paramB" value="valueB" />
...
</container>
I am trying to get the valueB part out of the XML via TSQL
So far I am getting the right node, but now I can not figure out how to get the attribute.
select xmlCol.query('/container/param[#name="paramB"]') from LogTable
I figure I could just add /#value to the end, but then SQL tells me attributes have to be part of a node. I can find a lot of examples for selecting the child nodes attributes, but nothing on the sibling atributes (if that is the right term).
Any help would be appreciated.
Try using the .value function instead of .query:
SELECT
xmlCol.value('(/container/param[#name="paramB"]/#value)[1]', 'varchar(50)')
FROM
LogTable
The XPath expression could potentially return a list of nodes, therefore you need to add a [1] to that potential list to tell SQL Server to use the first of those entries (and yes - that list is 1-based - not 0-based). As second parameter, you need to specify what type the value should be converted to - just guessing here.
Marc
Depending on the the actual structure of your xml, it may be useful to put a view over it to make it easier to consume using 'regular' sql eg
CREATE VIEW vwLogTable
AS
SELECT
c.p.value('#name', 'varchar(10)') name,
c.p.value('#value', 'varchar(10)') value
FROM
LogTable
CROSS APPLY x.nodes('/container/param') c(p)
GO
-- now you can get all values for paramB as...
SELECT value FROM vwLogTable WHERE name = 'paramB'
I have a table in my database with a column containing xml. The column type is nvarchar(max). The xml is formed in this way
<root>
<child>....</child>
.
.
<special>
<event><![CDATA[text->text]]></event>
<event><![CDATA[text->text]]></event>
...
</special>
</root>
I have not created the db, I cannot change the way information is stored in it but I can retrieve it with a select. For the extraction I use
select cast(replace(xml,'utf-8','utf-16')as xml)
from table
It works well except for cdata, whose content in the query output is: text -> text
Is there a way to retrieve also the CDATA tags?
Well, this is - as far as I know - not possible on normal ways...
The CDATA section has one sole reason: include invalid characters within XML for lazy people...
CDATA is not seen as needed at all and therefore is not really supported by normal XML methods. Or in other words: It is supported in the way, that the content is properly escaped. There is no difference between correctly escaped content and not-escaped content within CDATA actually! (Okay, there are some minor differences like including ]]> within a CDATA-section and some more tiny specialties...)
The big question is: Why?
What are you trying to do with this afterwards?
Try this. the included text is given as is:
DECLARE #xml XML =
'<root>
<special>
<event><![CDATA[text->text]]></event>
<event><![CDATA[text->text]]></event>
</special>
</root>'
SELECT t.c.query('text()')
FROM #xml.nodes('/root/special/event') t(c);
So: Please explain some more details: What do you really want?
If your really need nothing more than the wrapping CDATA you might use this:
SELECT '<![CDATA[' + t.c.value('.','varchar(max)') + ']]>'
FROM #xml.nodes('/root/special/event') t(c);
Update: Same with outdated FROM OPENXML
I just tried how the outdated approach with FROM OPENXML handles this and found, that there is absolutely no indication in the resultset, that the given text was within a CDATA section originally. The "Some value here" is exactly returned in the same way as the text within CDATA:
DECLARE #doc XML =
'<root>
<child>Some value here </child>
<special>
<event><![CDATA[text->text]]></event>
<event><![CDATA[text->text]]></event>
</special>
</root>';
DECLARE #hnd INT;
EXEC sp_xml_preparedocument #hnd OUTPUT, #doc;
SELECT * FROM OPENXML (#hnd, '/root',0);
EXEC sp_xml_removedocument #hnd;
This is how to include cdata on child nodes in XML, using pure SQL. But; it's not ideal.
SELECT 1 AS tag,
null AS parent,
'10001' AS 'Customer!1!Customer_ID!Element',
'AirBallon Captain' AS 'Customer!1!Title!cdata',
'Customer!1' = (
SELECT
2 AS tag,
NULL AS parent,
'Wrapped in cdata, using explicit' AS 'Location!2!Title!cdata'
FOR XML EXPLICIT)
FOR XML EXPLICIT, ROOT('Customers')
CDATA is included, but Child element is encoded using
>
instead of >
Which is so weird from a sensable point of view. I'm sure there are technical explanations, but they are stupid, because there is no difference in the FOR XML specification.
You could include the option type on the inner child node and then loose cdata too..
BUT WHY OH WHY?!?!?!?! would you (Microsoft) remove cdata, when I just added it?
<Customers>
<Customer>
<Customer_ID>10001</Customer_ID>
<Title><![CDATA[AirBallon Captain]]></Title>
<Location>
<Title><![CDATA[wrapped in cdata, using explicit]]></Title>
</Location>
</Customer>
</Customers>
I have a table with a mix of escaped and non-escaped XML. Of course, the data I need is escaped. For example, I have:
<Root>
<InternalData>
<Node>
<ArrayOfComment>
<Comment>
<SequenceNo>1</SequenceNo>
<IsDeleted>false</IsDeleted>
<TakenByCode>397</TakenByCode>
</Comment>
</ArrayOfComment>
</Node>
</InternalData>
</Root>
As you can see, the data in the Node tag is all escaped. I can use a query to obtain the Node data, but how can I convert it to XML in SQL so that it can be parsed and broken up? I'm pretty new to using XML in SQL, and I can't seem to find any examples of this.
Thanks
You have not given enough information about your end goal, but this will get you very close. FYI - You had two missing ; both after comment>
declare #xml xml
set #xml = '
<Root>
<InternalData>
<Node>
<ArrayOfComment>
<Comment>
<SequenceNo>1</SequenceNo>
<IsDeleted>false</IsDeleted>
<TakenByCode>397</TakenByCode>
</Comment>
</ArrayOfComment>
</Node>
</InternalData>
</Root>
'
select convert(xml, n.c.value('.', 'varchar(max)'))
from #xml.nodes('Root/InternalData/Node/text()') n(c)
Output
<ArrayOfComment>
<Comment>
<SequenceNo>1</SequenceNo>
<IsDeleted>false</IsDeleted>
<TakenByCode>397</TakenByCode>
</Comment>
</ArrayOfComment>
The result is an XML column that you can put into a variable or cross-apply into directly to get data from the XML fragment.
Your best bet might be to look into a HTML Decoding UDF. I did a quick search and found this one:
http://www.andreabertolotto.net/Articles/HTMLDecodeUDF.aspx
You may want to modify it so it only decodes > and <. The one above seems to go above and beyond your needs.
UPDATE
#Cyberkiwi's solution seems to be a bit cleaner. I will leave this up in case the version of SQL Server you are running doesn't support his solution.
In my SQL 2008 database table, I have one column name AUTHOR that contains XML data. The XML is not well formed and has data like below
<Author>
<ID>172-32-1176</ID>
<LastName>White</LastName>
<FirstName>Johnson</FirstName>
<Address>
<Street>10932 Bigge Rd.</Street>
<City>Menlo Park</City>
<State>CA</State>
</Address>
</Author>
Some XML have all of above data and some have just one tag.
<ID>172-32-1176</ID>
I want to write query that returns me a column as identiry.
I tried using AUTHOR.query('data(/Author/ID)') as identity but it fails when XML does not have Author node.
Thanks,
Vijay
Have you tried something like /Author/ID|/ID ? i.e. try for the first scenario, and with no match, the second ?
(note that the | operator is a set union operator, as described here)
In case that nothing "certain" can be maintained about the XML, except that a unique ID element contains the required identity value, then the following XPath expression selects the ID element:
//ID
a sample of xml document:
<xml>
<list>
<item refid="1" />
<item refid="3" />
</list>
<catalogue>
<model id="1"><details /></model>
<model id="2"><details /></model>
<model id="3"><details /></model>
</catalogue>
</xml>
I'd like to query something like //model[ #id = (//item/#refid) ]
to obtain all "model" having a referenced id in "list"
I'd like to query something like
//model[ #id = (//item/#refid) ] to
obtain all "model" having a referenced
id in "list"
The main problem here is your lack of confidence and not actually running an XPath engine to evaluate the expressions you've come up with.
If you evaluate the XPath expression you proposed:
//model[ #id = (//item/#refid) ]
You'll see that it selects exactly the (two) model elements, whose id attributes are referenced by the refid attributes of item elements that are children of list.
#Jörn-Horstmann in his answer already explained why you get these results.
A minor remark is to generally avoid using the // abbreviation. It causes the whole document to be scanned and is very inefficient. In this case I would use the equivalent but probably faster to evaluate XPath expression:
/*/catalogue/model[#id = /*/list/item/#refid]
Your xpath expression should already return exactly what you want. Quoting from http://www.w3.org/TR/xpath/#booleans, 5th paragraph:
If one object to be compared is a node-set and the other is a string, then the comparison will be true if and only if there is a node in the node-set such that the result of performing the comparison on the string-value of the node and the other string is true