SQL equivalent "$all" MongoDB operator on Repeated string - sql

Question

Suppose the following Data structure:
MongoDB: {id: ObjectId, colors: String[]}
SQL: Column ID (Integer), Column COLORS (Repeated String)
Suppose the following MongoDB query:
collection.find({colors: {$all: ["blue", "orange", "yellow"]} })
What is the equivalent operator/notation for "$all" in SQL? Notice that different from the $in, $all looks for documents (rows) having that field matching ALL the values, not only "some" of them.

Answer 1

Assuming there are no duplicates in the repeated values, you can use:
select s.*
from sql s
where (select count(*)
from unnest(s.colors) color
where color in ('blue', 'orange', 'yellow')
) = 3;
The "3" is the size of the list. If there are duplicates, then use count(distinct color) instead.
If you don't want to "remember" 3, you can use:
with color_list as (
select color
from unnest(array['blue', 'orange', 'yellow']) color
)
select s.*
from sql s
where (select count(*)
from unnest(s.colors) color join
color_list cl
using (color)
) = (select count(*) from color_list);
Or even:
select s.*
from sql s
where not exists (select 1
from unnest(array['blue', 'orange', 'yellow']) my_color left join
unnest(s.colors) color
on my_color = color
where color is null
);

Answer 2

Below is for BigQuery Standard SQL
#standardSQL
create temp function check_all(arr ANY TYPE, match ANY TYPE) as (
array_length(array(
select distinct m from unnest(match) m
join unnest(arr) m using(m)
)) = array_length(array(
select distinct m from unnest(match) m
))
);
select *
from `project.dataset.table`
where check_all(colors, ['blue', 'orange', 'yellow'])
if to apply to below dummy sample data
with `project.dataset.table` as (
select 1 id, ['blue', 'orange', 'yellow', 'black'] colors union all
select 2, ['blue', 'pink', 'yellow', 'green'] union all
select 3, ['red', 'orange', 'blue', 'pink', 'yellow', 'green']
)
the output is