How do I find elements in an array in BigQuery - sql

Question

I am trying to search for a row that has certain key value pairs in an array. A row in my BigQuery table would look something like this.
{
"ip": "192.168.1.1",
"cookie" [
{
"key": "apple",
"value: "red"
},
{
"key": "orange",
"value: "orange"
},
{
"key": "grape",
"value: "purple"
}
]
}
I thought about using implicit UNNEST or CROSS JOIN like the following, but it didn't work because unnesting it would just create multiple different rows.
SELECT ip
FROM table t, t.cookie c
WHERE (c.key = "grape" AND c.value ="purple") AND (c.key = "orange" AND c.value ="orange")
This link is really close to what I want to do, except they are using legacy SQL and not standardSQL

Answer 1

#standardSQL
SELECT ip
FROM yourTable
WHERE (
SELECT COUNT(1)
FROM UNNEST(cookie) AS pair
WHERE pair IN (('grape', 'purple'), ('orange', 'orange'))
) >= 2
you can test it with below dummy data
#standardSQL
WITH yourTable AS (
SELECT '192.168.1.1' AS ip, [('apple', 'red'), ('orange', 'orange'), ('grape', 'purple')] AS cookie UNION ALL
SELECT '192.168.1.2', [('abc', 'xyz')]
)
SELECT ip
FROM yourTable
WHERE (
SELECT COUNT(1)
FROM UNNEST(cookie) AS pair
WHERE pair IN (('grape', 'purple'), ('orange', 'orange'))
) >= 2
In case if you need output ip if at least one pair is in array - you need to change >= 2 to >=1 in WHERE clause

Answer 2

Mikhail's solution is good if it is guaranteed that there are no duplicate pairs in the cookie array. But if there could be duplicates, here is the alternative solution:
#standardSQL
WITH yourTable AS (
SELECT
'192.168.1.1' AS ip,
[('apple', 'red'), ('orange', 'orange'), ('grape', 'purple')] AS cookie UNION ALL
SELECT
'192.168.1.2',
[('abc', 'xyz'), ('orange', 'orange'), ('orange', 'orange')]
)
SELECT ip
FROM yourTable t
WHERE (
('grape', 'purple') IN UNNEST(t.cookie) AND
('orange', 'orange') IN UNNEST(t.cookie) )
Results in only
ip
-----------
192.168.1.1