I'm trying to save a string as a file (pdf), but it seems the encoding isn't what it seems.
I'm wondering if anyone knows what char encoding or converting is required for the following snippet?
%PDF-1.3
%����
1 0 obj
<</Title (Faktura 0)/Producer (ComponentOne C1Pdf)/CreationDate (D:20210122122339+01'00')/ModDate (D:20210122122339+01'00')>>
endobj
2 0 obj
<</Length 1789/Filter /FlateDecode>>stream
x��w6PH/��2P\00� w=S�r � �� �L M|�c��^.css=K##3V(J��
...more pdf code.
PDF is a binary format, and reading binary data into a string depending on the encoding assumed in that reading can damage the binary data.
Thus, if possible, don't retrieve the data as a string but instead as a byte array or byte buffer and store these bytes as they are.
As you confirmed in a comment,
I just received a array buffer and then wrote to file. It's working now!
Related
How do I read a file and turn it to a RAW bit string? For example I open an image that is 512kb, It reads the file byte by byte, and it spits out the long bit string that is the file? I would like to apply some functions to the strings but I can't figure a way to unpack files consistently.
I imagine what I need is something that reads a file byte by byte with no care of the original file format... As it reads byte by byte, a giant integer like thing file bit string is created.
I used a Python's bit generator and NumPy, that seemed to work well, but The program didn't behave well with actual files. What is the best way to unpack files into 1's and 0's?
How do I read any file and store the contents as an easy to read HEX file? or BIN file? And how do I stop the "open" function from truncating leading 0's!
UGH!
Using Python or GOLANG, how do I open any file and create an uninterrupted bit string of the contents where every leading zero in a BYTE read is significant?
After looking and asking everyone I'm acquainted to I found my answer. The best way to turn any file into a RAW HEX string is by
f = open("file_name", "rb")
content = f.read().hex()
with open("File HEX bitstream.txt", "w") as text_file:
print(f"HEX Bitstream Import", content, file=text_file)
f.close()
I am comparing to csv files to each other to produce the final file with fathered differences information its giving me error message. I have resaved all files to csv decoded with utf-8 and tried running - it does not work. Can someone help me.
The problem is that your file is not in UTF-8 format. Many tools will refuse to handle data that is claimed to be UTF-8, but isn’t. I’d check first if that file is actually UTF-8 or is stored in some different encoding.
So I have a file that I need to have in either binary or hex format. Everything that I've been able to find basically says to store the text in a string and convert it to binary or hex from there, but I cant do it this way. The file was written using its own private character set that uses null and system hex codes, so notepad doesn't know what to do with these characters and replaces it with wrong characters and spaces. This distorts the information so it wont be correct if I try to convert it to binary/hex.
I really just need to have the binary/hex information stored in a string or text box so I can work with it. I don't really need it to be saved as a file.
Never mind, I finally figured it out. I used a file stream to read the data byte by byte. I didn't understand how to convert this as the first byte data in the array was showing as 80 when i knew the binary data should've been "1010000" (i didn't realize at that time that 80 was the decimal format).
Anyways I used the bitconverter.tostring and it put everything together and converted it to hexadecimal format. So i'm all good now.
I have to read a file which in .dat format and separate data based on 2 first consecutive zero byte comes. first half is json data and other half is binary data.
How should I go about it?
I tried using NSData dataWithContentsOfFile method and read it and then convert it in byte array and compare bytes. Somehow, its not working.
You can use the same kind of procedure that you would use to read a file by lines. Here and here are earlier answers on SO regarding reading a file line-by-line. Just change \n to the byte sequence that is applicable.
I am trying to convert a file from binary to text, by simply replacing each character with the hexadecimal code. For example, character 'c' will be replaced by '63'.
I have a code which is working fine in normal systems, but it breaks down in the PC where I need to use it as it has default locale set to Chinese.
I am using the following statements to read a byte -
ch$ = " "
Get #f%, , ch$
I suspect there is a problem when I am reading the file byte by byte, as it is skipping certain bytes because they form composite characters. It's probably reading 2 bytes which form an Asian character as one byte. It is thus forming a much smaller file than the expected size.
How can I read the file byte by byte?
Full code is pasted here: http://pastebin.com/kjpSnqzV
Your suspicion is correct. VB file reading automatically converts strings into Unicode from the default code page on the PC. On an Asian code page, some characters are represented as more than one byte.
I advise you to use a Byte variable rather than a string - that will stop VB being over helpful.
Dim ch As Byte
Get #f%, , ch
Another possible problem with the original code is that some byte sequences are illegal on Asian code pages (they don't represent valid characters). So your code could experience errors for some input files, but presumably you want it to work with any file.