In this table there are three colum and in need the value for of data which are lesser than code = 28,this is my query
SELECT value,code,date
FROM table
order by date,vchcode
but when i ad where clouse like
SELECT value,code,date
FROM table
where code < 28
order by date,vchcode
is only shows 2 row with code 26 and 27... i need 26,27 and 32.. and table colums are variable its not fix..
I think you wnat to take the date into account -- what you really want are all rows before the date of the row with code 28.
One method uses a subquery:
SELECT t.value, t.code, t.date
FROM table t
WHERE date < (SELECT date FROM table t2 WHERE t2.code = 28)
ORDER BY t.date, t.vchcode
Related
I'm after some help on how best to write a query that does the following. I think I need a subquery but I don't know how to use the data returned in the row to feed back into the subquery without hardcoding values? A subquery may not be the right thing here?
Ideally I only want 1 variable ...WHERE t_Date = '2018-01-01'
Desired Output:
The COUNT Criteria column has the following rules
Date < current row
Area = current row
Name = current row
Value = 1
For example, the first row indicates there are 2 records with Date < '2018-01-01' AND Area = 'Area6' AND Name = 'Name1' AND Value = 1
Example Data:
SQLFiddle: http://sqlfiddle.com/#!18/92ba3/4
Effectively I only want to return the first 2 rows but summarise the historic data into a column based on the output in that column.
The right way to do this is to use the cumulative sum functionality in ANSI SQL and SQL Server since 2012:
select t.*,
sum(case when t.value = 1 then 1 else 0 end) over (partition by t_area, t_name order by t_date)
from t;
This actually includes the current row. If you have only one row per date (for the area/name combo), then you can just subtract it or use a windowing clause:
select t.*,
sum(case when t.value = 1 then 1 else 0 end) over
(partition by t_area, t_name
order by t_date
rows between unbounded preceding and 1 preceding
)
from t;
Use a self join to find records in the same table that are related to a particular record:
SELECT t1.t_Date, t1.t_Area, t1.t_Name, t1.t_Value,
COUNT(t2.t_Name) AS COUNTCriteria
FROM Table1 as t1
LEFT OUTER JOIN Table1 as t2
ON t1.t_Area=t2.t_Area
AND t1.t_Name=t2.T_Name
AND t2.t_Date<t1.t_Date
AND t2.t_Value=1
GROUP BY t1.t_Date, t1.t_Area, t1.t_Name, t1.t_Value
Query:
SELECT *
FROM [MemberBackup].[dbo].[OriginalBackup]
where ration_card_id in
(
1247881,174772,
808454,2326154
)
Right now the data is ordered by the auto id or whatever clause I'm passing in order by.
But I want the data to come in sequential format as per id's I have passed
Expected Output:
All Data for 1247881
All Data for 174772
All Data for 808454
All Data for 2326154
Note:
Number of Id's to be passed will 300 000
One option would be to create a CTE containing the ration_card_id values and the orders which you are imposing, and the join to this table:
WITH cte AS (
SELECT 1247881 AS ration_card_id, 1 AS position
UNION ALL
SELECT 174772, 2
UNION ALL
SELECT 808454, 3
UNION ALL
SELECT 2326154, 4
)
SELECT t1.*
FROM [MemberBackup].[dbo].[OriginalBackup] t1
INNER JOIN cte t2
ON t1.ration_card_id = t2.ration_card_id
ORDER BY t2.position DESC
Edit:
If you have many IDs, then neither the answer above nor the answer given using a CASE expression will suffice. In this case, your best bet would be to load the list of IDs into a table, containing an auto increment ID column. Then, each number would be labelled with a position as its record is being loaded into your database. After this, you can join as I have done above.
If the desired order does not reflect a sequential ordering of some preexisting data, you will have to specify the ordering yourself. One way to do this is with a case statement:
SELECT *
FROM [MemberBackup].[dbo].[OriginalBackup]
where ration_card_id in
(
1247881,174772,
808454,2326154
)
ORDER BY CASE ration_card_id
WHEN 1247881 THEN 0
WHEN 174772 THEN 1
WHEN 808454 THEN 2
WHEN 2326154 THEN 3
END
Stating the obvious but note that this ordering most likely is not represented by any indexes, and will therefore not be indexed.
Insert your ration_card_id's in #temp table with one identity column.
Re-write your sql query as:
SELECT a.*
FROM [MemberBackup].[dbo].[OriginalBackup] a
JOIN #temps b
on a.ration_card_id = b.ration_card_id
order by b.id
i have table as shown here in this picture --> http://www.directupload.net/file/d/3710/lj7etq5j_png.htm
I need the correct Query to get only data_id 10.
The query should be like this: Compare the latest date rows (2014-08-08) with the earliest date rows (2014-08-06). If there is a row on 2014-08-08 which is NOT at 2014-08-06, this row should returned.
I already tried it with self-joins and Sub-Selects, but i did't get it work.
Thx for any help!
Maybe something like this is what you're looking for?
select * from Table1
where
data not in (
select data from Table1
where dataOfDate = (select min(dataofdate) from Table1)
)
and dataOfDate = (select max(dataofdate) from Table1)
The first where clause compares the data field of the returned rows to the data field in the set of oldest rows and the second where clause limits the set of rows the the newest.
Note that I'm only comparing rows based on thedatafield, so you might have to change the query if you want to includenextTableIdin the comparison.
Here is a sample SQL Fiddle.
How about something like this:
SELECT d1.* FROM Dates d1 LEFT JOIN Dates d2 ON d1.nextTableId = d2.nextTableId WHERE d1.dataofDate = '2014-08-08' AND d2.dataofDate = '2014-08-06' AND d2.data_id IS NULL;
SELECT `data_id`
FROM `my_table`
WHERE `dataOfDate` = (SELECT MAX(`dataOfDate`) FROM `my_table`)
AND `nextTableId` NOT IN (
SELECT `nextTableId` FROM `my_table` WHERE `dataOfDate` = (SELECT MIN(`dataOfDate`) FROM `my_table`)
)
select all rows with max date
that don't have values amongst rows with min date
edit ops, too late
I have a table that contains dates and times. For example columns are Date, ExTime, NewTime, Status. I am ordering them based on a expkey column that makes them show in the right order.
I want to do a row by row comparison and compare the second row column of extime to the first row column NewTime. If extime < Newtime then I want to update status with a "1". And then traverse through the table row by row where second row in the above example becomes the first and a new second is pull and used. Here is a sample of what I have now - but it is not hitting and working all all of the rows for some reason.
UPDATE t
SET t.Status = 1
FROM MyTable t
CROSS APPLY (SELECT TOP 1 NewTime
FROM MyTable
WHERE ID = t.ID AND [Date] = t.[Date]
ORDER BY ExpKey) t1
WHERE t.Extime < t1.NewTime
This is not hitting all the rows like I want it to. I have the where clause comparing fields ID and Date to insure that the rows are attached to the same person. If the ID or Dates are not the same it is not attached to the same person so I would not want to update the status. So basically if the ID of Row 2 = ID of Row 1 and Date of Row 2 = Date of Row 1 I want to compare extime of row 2 and see if it is less than newtime of Row 1 - if so then update the status field of row 2.
Any help in figuring out why this sort of works but not on all would be appreciated.
Ad.
On SQL Server 2012 you can easily update status with window function lag():
with cte as (
select
extime,
lag(newtime) over(partition by id, date order by expKey) as newtime,
status
from table1
)
update cte set status = 1 where extime < newtime;
sql fiddle demo
I haven't tested this, but I've dealt with similar issues of comparing adjacent rows. I put this together off-the-cuff, so it may need tweaking, but give it a try.
;WITH CTE AS
( SELECT ID,[Date],ExpKey,ExTime,NewTime,
ROW_NUMBER()OVER(PARTITION BY ID,[Date] ORDER BY ExpKey) AS Sort
FROM MyTable
)
UPDATE row2
SET row2.[Status] = 2
WHERE row2.ExTime < row1.NewTime
FROM CTE row2
CROSS JOIN CTE row1
ON row1.ID = row2.ID
AND row1.[Date] = row2.[Date]
AND row1.Sort = row2.Sort-1 --Join to prior row
I have been trying to get this to work for 12 hrs now and I cannot :-( Can someone please show me how I can get the ssnumber to group and get the total for each ssnumber.
Here is what I have now. In Table number 1 I have this code
SELECT
UNIT_NO, SUM(RATEB) AS TOTALRTE
FROM TABLE1
WHERE
TRUCK_PAID = 1
AND PICK_UP_DATE >= '(fromdate)'
AND PICK_UP_DATE <= '(todate)'
GROUP BY
UNIT_NO
ORDER BY
UNIT_NO
But table number 2 is where the ssnumber column is, so what I'm trying to do is the rateB sum from all of the loads for each unit_no and then group them and then go into table number 2 and group the ssnumber with the unit number from table number 1 and sum the rateB from table number 1.
Something like this (see below) but its not working :-(
SELECT
UNIT_NO, SUM(RATEB)
FROM
TABLE1
WHERE
TRUCK_PAID = 1
AND PICK_UP_DATE >= '(fromdate)'
AND PICK_UP_DATE <= '(todate)'
GROUP BY
UNIT_NO
JOIN
TABLE TABLE1.UNIT_NO = TABLE2.UNIT_NO GROUP BY TABLE2.SS_NUM
or
SELECT
UNIT_NO, SUM(RATEB) AS TOTALRATE
FROM
TABLE1
GROUP BY
UNIT_NO
JOIN
TRUCKS ON (TABLE1.UNIT_NO = TABLE2.UNIT_NO)
GROUP BY
TABLE2.SSNUMBER
Thank you guys so much for any help...
As requested, it is hard to really understand what you are trying to accomplish without more info about table2 and maybe an example of what you are expecting. However, what I got from your description is that you are trying to accomplish something like this?
SELECT UNIT_NO, TOTALRTE, TOTALLDSRTE
FROM
(
SELECT UNIT_NO,SUM(RATEB) AS TOTALRTE
FROM LOADS
GROUP BY UNIT_NO
) AS tbl1
JOIN
(
SELECT SS_NUM, SUM(RATEB) AS TOTALLDSRTE
FROM LOADS
GROUP BY SS_NUM
) AS tbl2
ON tbl1.UNIT_NO = tbl2.SS_NUM
I would suggest instead of getting data from two select queries in one select query, try to fetch them as separate queries. This saves a lot of time. That, or you can create a table for the result and update the result of each query into the table.