I have below JSON from which i need to fetch the value of issuedIdentValue where issuedIdentType = PANCARD
{
"issuedIdent": [
{"issuedIdentType":"DriversLicense","issuedIdentValue":"9797979797979797"},
{"issuedIdentType":"SclSctyNb","issuedIdentValue":"078-01-8877"},
{"issuedIdentType":"PANCARD","issuedIdentValue":"078-01-8877"}
]
}
I can not hard-code the index value [2] in my below query as the order of these records can be changed. So want to get rid off any hardcoded index.
select json_value(
'{"issuedIdent": [{"issuedIdentType":"DriversLicense","issuedIdentValue":"9797979797979797"},{"issuedIdentType":"SclSctyNb","issuedIdentValue":"078-01-8877"}, {"issuedIdentType":"PANCARDSctyNb","issuedIdentValue":"078-01-8877"}]}',
'$.issuedIdent[2].issuedIdentValue'
) as output
from d1entzendev.ExternalEventLog
where
eventname = 'CustomerDetailsInqSVC'
and applname = 'digitalBANKING'
and requid = '4fe1fa1b-abd4-47cf-834b-858332c31618';
What changes will need to apply in json_value function to achieve the expected result
In Oracle 12c or higher, you can use JSON_TABLE() for this:
select value
from json_table(
'{"issuedIdent": [{"issuedIdentType":"DriversLicense","issuedIdentValue":"9797979797979797"},{"issuedIdentType":"SclSctyNb","issuedIdentValue":"078-01-8877"}, {"issuedIdentType":"PANCARD","issuedIdentValue":"078-01-8877"}]}',
'$.issuedIdent[*]' columns
type varchar(50) path '$.issuedIdentType',
value varchar(50) path '$.issuedIdentValue'
) t
where type = 'PANCARD'
This returns:
| VALUE |
| :---------- |
| 078-01-8877 |
Related
Let's suppose I have a table my_table with a field named data, of type jsonb, which thus contains a json data structure.
let's suppose that if I run
select id, data from my_table where id=10;
I get
id | data
------------------------------------------------------------------------------------------
10 | {
|"key_1": "value_1" ,
|"key_2": ["value_list_element_1", "value_list_element_2", "value_list_element_3" ],
|"key_3": {
| "key_3_1": "value_3_1",
| "key_3_2": {"key_3_2_1": "value_3_2_1", "key_3_2_2": "value_3_2_2"},
| "key_3_3": "value_3_3"
| }
| }
so in pretty formatting, the content of column data is
{
"key_1": "value_1",
"key_2": [
"value_list_element_1",
"value_list_element_2",
"value_list_element_3"
],
"key_3": {
"key_3_1": "value_3_1",
"key_3_2": {
"key_3_2_1": "value_3_2_1",
"key_3_2_2": "value_3_2_2"
},
"key_3_3": "value_3_3"
}
}
I know that If I want to get directly in a column the value of a key (of "level 1") of the json, I can do it with the ->> operator.
For example, if I want to get the value of key_2, what I do is
select id, data->>'key_2' alias_for_key_2 from my_table where id=10;
which returns
id | alias_for_key_2
------------------------------------------------------------------------------------------
10 |["value_list_element_1", "value_list_element_2", "value_list_element_3" ]
Now let's suppose I want to get the value of key_3_2_1, that is value_3_2_1.
How can I do it?
I have tryed with
select id, data->>'key_3'->>'key_3_2'->>'key_3_2_1' alias_for_key_3_2_1 from my_table where id=10;
but I get
select id, data->>'key_3'->>'key_3_2'->>'key_3_2_1' alias_for_key_3_2_1 from my_table where id=10;
^
HINT: No operators found with name and argument types provided. Types may need to be converted explicitly.
what am I doing wrong?
The problem in the query
select id, data->>'key_3'->>'key_3_2'->>'key_3_2_1' alias_for_key_3_2_1 --this is wrong!
from my_table
where id=10;
was that by using the ->> operand I was turning a json to a string, so that with the next ->> operand I was trying to get a json key object key_3_2 out of a string object, which makes no sense.
Thus one has to use the -> operand, which does not convert json into string, until one gets to the "final" key.
so the query I was looking for was
select id, data->'key_3'->'key_3_2'->>'key_3_2_1' alias_for_key_3_2_1 --final ->> : this gets the value of 'key_3_2_1' as string
from my_table
where id=10;
or either
select id, data->'key_3'->'key_3_2'->'key_3_2_1' alias_for_key_3_2_1 --final -> : this gets the value of 'key_3_2_1' as json / jsonb
from my_table
where id=10;
More info on JSON Functions and Operators can be find here
Folks, I'm trying to extract value of 'status' from below string(column name: people) in hive. The problem is, the column is neither a complete JSON nor stored as an Array.
I tried to make it look like a JSON by replacing '=' with ':', which didnt help.
[{name=abc, org=true, self=true, status=accepted, email=abc#gmail.com}, {name=cab abc, org=false, self=false, status=needsAction, email=cab#google.com}]
Below is the query I used:
SELECT
str.name,
str.org,
str.status
FROM table
LATERAL VIEW EXPLODE (TRANSLATE(people,'=',':')) exploded as str;
but I'm getting below error:
FAILED: UDFArgumentException explode() takes an array or a map as a parameter
Need output something like this:
name | org | status
-------- ------- ------------
abc | true | accepted
cab abc | false | needsAction
Note: There is a table already, the datatype is string, and I
can't change the table schema.
Solution for Hive. It possibly can be optimized. Read comments in the code:
with your_table as ( --your data example, you select from your table instead
select "[{name=abc, org=true, self=true, status=accepted, email=abc#gmail.com}, {name=cab abc, org=false, self=false, status=needsAction, email=cab#google.com}]" str
)
select --get map values
m['org'] as org ,
m['name'] as name ,
m['self'] as self ,
m['status'] as status ,
m['email'] as email
from
(--remove spaces after commas, convert to map
select str_to_map(regexp_replace(a.s,', +',','),',','=') m --map
from your_table t --replace w your table
lateral view explode(split(regexp_replace(str,'\\[|\\{|]',''),'}, *')) a as s --remove extra characters: '[' or '{' or ']', split and explode
)s;
Result:
OK
true abc true accepted abc#gmail.com
false cab abc false needsAction cab#google.com
Time taken: 1.001 seconds, Fetched: 2 row(s)
*outdated Oracle version
I have a table for receipt data.
I want to get some data from field EXT_ATTR. such as PAYMENT_RECEIPT_NO
The field "EXT_ATTR" is varchar(4000) stored JSON value
SerialId | EXT_ATTR
1 |
{
"PAYMENT_RECEIPT_NO": "PS00000000000000001",
"IS_CORPOR": "1",
"POSTCODE1": "51000",
"POSTCODE2": "51000",
"BILLADDR1PART1": "BILLADDR1PART1_DATA",
"BILLADDR1PART2": "BILLADDR1PART2_DATA",
"NEED_PRINT_WHT": "1",
"WHT_AMT": "0",
"TRXAMT": "2340600",
"LOCATIONID": "02140",
"PAYMENT_METHOD_NAME": "Cash",
"WITH_TAX": "1"
}
2 |
{
"PAYMENT_RECEIPT_NO": "PS00000000000000055",
"IS_CORPOR": "1",
"POSTCODE1": "51000",
"POSTCODE2": "51000",
"BILLADDR1PART1": "BILLADDR1PART1_DATA",
"BILLADDR1PART2": "BILLADDR1PART2_DATA",
"NEED_PRINT_WHT": "1",
"WHT_AMT": "0",
"TRXAMT": "2340600",
"LOCATIONID": "02140",
"PAYMENT_METHOD_NAME": "Cash",
"WITH_TAX": "1"
}
How can I extract varchar filed to get only value.
SerialId | PAYMENT_RECEIPT_NO
1 | PS00000000000000001
2 | PS00000000000000055
Thank you very much.
to work with json documents you can use PL/JSON
if you want to parse it without json Tools, than you can use substr, instr function in Oracle.
depending on what your string looks like, you have to adjust string positions.
create table tab (json varchar2(1000));
insert into tab values('{"PAYMENT_RECEIPT_NO": "PS00000000000000001","IS_CORPOR": "1","POSTCODE1": "51000","POSTCODE2": "51000","BILLADDR1PART1": "BILLADDR1PART1_DATA","BILLADDR1PART2": "BILLADDR1PART2_DATA","NEED_PRINT_WHT": "1","WHT_AMT": "0","TRXAMT": "2340600","LOCATIONID": "02140","PAYMENT_METHOD_NAME": "Cash","WITH_TAX": "1"}');
insert into tab values('{"PAYMENT_RECEIPT_NO": "PS00000000000000055","IS_CORPOR": "1","POSTCODE1": "51000","POSTCODE2": "51000","BILLADDR1PART1": "BILLADDR1PART1_DATA","BILLADDR1PART2": "BILLADDR1PART2_DATA","NEED_PRINT_WHT": "1","WHT_AMT": "0","TRXAMT": "2340600","LOCATIONID": "02140","PAYMENT_METHOD_NAME": "Cash","WITH_TAX": "1"}');
select substr(json,instr(json,': ',1,1)+3,instr(json,',',1,1)-instr(json,': ',1,1)-4)
from tab;
| SUBSTR(JSON,INSTR(JSON,':',1,1)+3,INSTR(JSON,',',1,1)-INSTR(JSON,':',1,1)-4) |
| :--------------------------------------------------------------------------- |
| PS00000000000000001 |
| PS00000000000000055 |
db<>fiddle here
JSON functions are defined for Database Oracle12c+ version. APEX_JSON package with release 5.0+ should be installed for the previous releases. Whenever installation complete, then the following code might be used as an XML data type manner through APEX_JSON.TO_XMLTYPE() function in order to extract the desired values :
WITH t AS
(
SELECT SerialId, APEX_JSON.TO_XMLTYPE(Payment_Receipt_No) AS xml_data
FROM tab
)
SELECT SerialId, Payment_Receipt_No
FROM t
CROSS JOIN
XMLTABLE('/json'
PASSING xml_data
COLUMNS
Payment_Receipt_No VARCHAR2(100) PATH 'PAYMENT_RECEIPT_NO'
)
I have this data as CLOB field in DB2. I am converting the data to char using cast:
SELECT CAST(CLOBColumn as VARCHAR(32000))
FROM Schema.MyTable;
Here is how the result XML comes out from the above:
<TreeList TreeNo="ABC">
<Tree ErrorCode="INVALID_TREE" ErrorDescription="Tree doesn’t exist." TreeID="123456"/>
<Tree ErrorCode="INVALID_TREE" ErrorDescription="Tree doesn’t exist." TreeID="1234567"/>
</TreeList>
And this is how I expect my output
|TreeNo | TreeID | ErrorCode | ErrorDescription
|ABC | 123456 | INVALID_TREE | Tree doesn’t exist
|ABC | 1234567 | INVALID_TREE | Tree doesn’t exist
How do I achieve this?
You need to use the XMLTABLE function which allows to map XML data to a table. You can pass in XML-typed data and it works if you directly parse the CLOB to XML. The SELECT would look like the following (you get the idea):
SELECT x.*
FROM schema.mytable, XMLTABLE(
'$CLOBColumn/TreeList'
COLUMNS
TreeNo VARCHAR(10) PATH '#TreeNo',
TreeID INT PATH 'Tree[#TreeID]',
...
) AS x
;
I am using Microsoft SQL Server 2012 and I would like to run this seemingly simple query:
SELECT
FirstEvent.id AS firstEventID,
SecondEvent.id AS secondEventID,
DATEDIFF(second, FirstEvent.WndFGEnd, SecondEvent.WndFGStart) AS gap,
FirstEvent.TitleID = SecondEvent.TitleID AS titlesSameCheck
FROM VibeFGEvents AS FirstEvent
RIGHT OUTER JOIN VibeFGEvents AS SecondEvent
ON
FirstEvent.intervalMode = SecondEvent.intervalMode
AND FirstEvent.id = SecondEvent.id - 1
AND FirstEvent.logID = SecondEvent.logID
However FirstEvent.TitleID = SecondEvent.TitleID AS titlesSameCheck in the SELECT clause is incorrect syntax. But the SELECT Clause (Transact-SQL) documentation includes this syntax:
SELECT [ ALL | DISTINCT ]
[ TOP ( expression ) [ PERCENT ] [ WITH TIES ] ]
<select_list>
<select_list> ::=
{
*
| { table_name | view_name | table_alias }.*
| {
[ { table_name | view_name | table_alias }. ]
{ column_name | $IDENTITY | $ROWGUID }
| udt_column_name [ { . | :: } { { property_name | field_name }
| method_name ( argument [ ,...n] ) } ]
| expression
[ [ AS ] column_alias ]
}
| column_alias = expression
} [ ,...n ]
I think that means an expression is valid in the select clause and indeed the examples given include things like 1 + 2. Looking at the documentation for expressions:
{ constant | scalar_function | [ table_name. ] column | variable
| ( expression ) | ( scalar_subquery )
| { unary_operator } expression
| expression { binary_operator } expression
| ranking_windowed_function | aggregate_windowed_function
}
boolean equality checks are valid expressions and indeed the example expression given in the = (Equals) (Transact-SQL) documentation includes one:
SELECT DepartmentID, Name
FROM HumanResources.Department
WHERE GroupName = 'Manufacturing'
albeit in the WHERE clause not the SELECT clause. It looks like I cannot use = the equality operator to compare expressions in my SELECT clause as they are being wrongly interpreted as assignment.
How do I include a Boolean equality column comparison equivalent to FirstEvent.TitleID = SecondEvent.TitleID AS titlesSameCheck in my SELECT clause?
Like this:
case when FirstEvent.TitleID = SecondEvent.TitleID then 1 else 0 end as titlesSameCheck
You cannot use the Boolean type directly except in conditional statements (case, where, having, etc.)
Best way to solve your problem is to do something like
select case when x = y then 'true' else 'false' end
The bit type is probably the closest to boolean.
select CAST(case when x = y then 1 else 0 end as bit)
Of course, use whichever two values best represent what you are after.
As the two existing answers state, boolean values can't be returned as a column value. This is documented in the Comparison Operators section:
Unlike other SQL Server data types, a Boolean data type cannot be
specified as the data type of a table column or variable, and cannot
be returned in a result set.
Given that restriction, using CASE to transform the value to something that can be displayed is your best alternative.