Select cases from long table by key variable grouping - sql

Question

I have a table like below:
caseid | ncode | code | test
1 1 ABC TRUE
1 2 DEF TRUE
2 1 ABC TRUE
3 1 DEF TRUE
3 2 HIJ FALSE
Where caseid represents an individual case. This table creates the relationship that each individual case can have multiple codes associated with it (ncode and code). test is just a variable that tracks a boolean value of interest.
I have specific requirements for my query:
I need all cases where code = ABC and ncode = 1 and test = TRUE. This criteria has the highest priority.
Of those cases from #1, I need to create an additional column called hasdef that is a boolean that indicates if that specific caseid has any other rows where code = DEF and test = TRUE. It should be TRUE if so, otherwise FALSE.
So from the above table, what should return is:
caseid | ncode | code | test | hasdef
1 1 ABC TRUE TRUE
2 1 ABC TRUE FALSE
caseid = 1 returns because code = ABC, ncode = 1, and test = TRUE. hasdef = TRUE because in the second row, caseid = 1, code = DEF and test = TRUE.
caseid = 2 returns because code = ABC, ncode = 1, and test = TRUE. hasdef = FALSE because there is no other row with caseid = 2 where code = DEF.
caseid = 3 does not return. Even though there is a row where code = DEF and test = TRUE, the first criteria (code = ABC and ncode = 1) is not first satisfied.
This is what I have so far, but I am not confident it is working as desired:
select tab1.*, tab2.code is not null as hasdef from
(select * from mytable
where code = 'ABC' and ncode = 1) as tab1
left join (
select caseid, any_value(code) code, any_value(test) test
from mytable
group by caseid
having code = 'DEF' and test is true
) as tab2
using(caseid)
order by caseid

Answer 1

Below is for BigQuery Standard SQL
#standardSQL
select * from (
select *,
0 < countif(code = 'DEF' and test is true) over(partition by caseid) as hasdef
from `project.dataset.table`
)
where code = 'ABC' and ncode = 1 and test is true
if to apply to sample data from your question - output is
Note: you can replace test is true with just test as in below
select * from (
select *,
0 < countif(code = 'DEF' and test) over(partition by caseid) as hasdef
from `project.dataset.table`
)
where code = 'ABC' and ncode = 1 and test