I want to use the like clause to search all columns in a row.
something like
SELECT * FROM test WHERE '%something%' IN *
also, I don't know the exact columns that I have, this is why i need a wildcard (*)
there is a way to do that with snowflake / SQL?
You may consider using array_construct and array_contains:
CREATE or REPLACE TABLE test ( id number, v varchar, z varchar )
as SELECT * FROM VALUES
(1, 'Gokhan', 'Aylin'),
(2, 'Joe', 'Black');
SELECT *, ARRAY_CONSTRUCT( * ) combined
FROM test where ARRAY_CONTAINS( 'Gokhan'::variant, combined );
You can also convert this array to varchar to search partly matching strings:
SELECT *, ARRAY_CONSTRUCT( * ) combined
FROM test
WHERE combined::VARCHAR LIKE '%Go%';
+----+--------+-------+------------------------+
| ID | V | Z | COMBINED |
+----+--------+-------+------------------------+
| 1 | Gokhan | Aylin | [ 1, "Gokhan", "Aylin" |
+----+--------+-------+------------------------+
If you want to search for 'something' in all columns you can try to concatenate all columns in the where clause:
SELECT * from TABLE where CONCAT(colum1,column2,column3) LIKE '%something%'
Remember to cast to string type any non string type column.
You have to little tweak the SQL, concat takes all data types
select a.* from (
select *, concat(*) as all_col_data from snowflake.schema.table_name
) as a
where a.all_col_data like '%something%'
Related
I'm trying to create a single row starting from multiple ones and combining them based on different column values; here is the result i reached based on the following query:
select distinct ID, case info when 'name' then value end as 'NAME', case info when 'id' then value end as 'serial'
FROM TABLENAME t
WHERE info = 'name' or info = 'id'
Howerver the expected result should be something along the lines of
I tried with group by clauses but that doesn't seem to work.
The RDBMS is Microsoft SQL Server.
Thanks
SELECT X.ID,MAX(X.NAME)NAME,MAX(X.SERIAL)AS SERIAL FROM
(
SELECT 100 AS ID, NULL AS NAME, '24B6-97F3'AS SERIAL UNION ALL
SELECT 100,'A',NULL UNION ALL
SELECT 200,NULL,'8113-B600'UNION ALL
SELECT 200,'B',NULL
)X
GROUP BY X.ID
For me GROUP BY works
A simple PIVOT operator can achieve this for dynamic results:
SELECT *
FROM
(
SELECT id AS id_column, info, value
FROM tablename
) src
PIVOT
(
MAX(value) FOR info IN ([name], [id])
) piv
ORDER BY id ASC;
Result:
| id_column | name | id |
|-----------|------|------------|
| 100 | a | 24b6-97f3 |
| 200 | b | 8113-b600 |
Fiddle here.
I'm a fan of a self join for things like this
SELECT tName.ID, tName.Value AS Name, tSerial.Value AS Serial
FROM TableName AS tName
INNER JOIN TableName AS tSerial ON tSerial.ID = tName.ID AND tSerial.Info = 'Serial'
WHERE tName.Info = 'Name'
This initially selects only the Name rows, then self joins on the same IDs and now filter to the Serial rows. You may want to change the INNER JOIN to a LEFT JOIN if not everything has a Name and Serial and you want to know which Names don't have a Serial
Let's say I have the following as a starting point:
select * from (values (1,'a'),(2,'b'))
Is it possible to provide column names to the value columns up-stream, for example something like:
select
col1 AS id,
col2 AS letter
from (
<anonymous values>
)
Or is it basically once you have an anonymous values clause you cannot name it.
You can use a table alias that also specifies column names:
select *
from (
values (1,'a'),(2,'b')
) as v(id, letter);
use an alias:
select * from (values (1,'a'),(2,'b')) as foo(id,txt);
id | txt
----+-----
1 | a
2 | b
(2 rows)
Absolutely
Just add the column names to the query alias
select q.id, q.col
from (values
(1,'a'),
(2,'b')
) q(id, col)
(I want to perform a group-by based on the distinct values in a string column that has multiple values
The said column has a list of strings in a standard format separated by commas. The potential values are only a,b,c,d.
For example the column collection (type: String) contains:
Row 1: ["a","b"]
Row 2: ["b","c"]
Row 3: ["b","c","a"]
Row 4: ["d"]`
The expected output is a count of unique values:
collection | count
a | 2
b | 3
c | 2
d | 1
For all the below i used this table:
create table tmp (
id INT auto_increment,
test VARCHAR(255),
PRIMARY KEY (id)
);
insert into tmp (test) values
("a,b"),
("b,c"),
("b,c,a"),
("d")
;
If the possible values are only a,b,c,d you can try one of this:
Tke note that this will only works if you have not so similar values like test and test_new, because then the test would be joined also with all test_new rows and the count would not match
select collection, COUNT(*) as count from tmp JOIN (
select CONCAT("%", tb.collection, "%") as like_collection, collection from (
select "a" COLLATE utf8_general_ci as collection
union select "b" COLLATE utf8_general_ci as collection
union select "c" COLLATE utf8_general_ci as collection
union select "d" COLLATE utf8_general_ci as collection
) tb
) tb1
ON tmp.test LIKE tb1.like_collection
GROUP BY tb1.collection;
Which will give you the result you want
collection | count
a | 2
b | 3
c | 2
d | 1
or you can try this one
SELECT
(SELECT COUNT(*) FROM tmp WHERE test LIKE '%a%') as a_count,
(SELECT COUNT(*) FROM tmp WHERE test LIKE '%b%') as b_count,
(SELECT COUNT(*) FROM tmp WHERE test LIKE '%c%') as c_count,
(SELECT COUNT(*) FROM tmp WHERE test LIKE '%d%') as d_count
;
The result would be like this
a_count | b_count | c_count | d_count
2 | 3 | 2 | 1
What you need to do is to first explode the collection column into separate rows (like a flatMap operation). In redshift the only way to generate new rows is to JOIN - so let's CROSS JOIN your input table with a static table having consecutive numbers, and take only ones having id less or equal to number of elements in the collection. Then we'll use split_part function to read the item at correct index. Once we have the exploaded table, we'll do a simple GROUP BY.
If your items are stored as JSON array strings ('["a", "b", "c"]') then you can use JSON_ARRAY_LENGTH and JSON_EXTRACT_ARRAY_ELEMENT_TEXT instead of REGEXP_COUNT and SPLIT_PART respectively.
with
index as (
select 1 as i
union all select 2
union all select 3
union all select 4 -- could be substituted with 'select row_number() over () as i from arbitrary_table limit 4'
),
agg as (
select 'a,b' as collection
union all select 'b,c'
union all select 'b,c,a'
union all select 'd'
)
select
split_part(collection, ',', i) as item,
count(*)
from index,agg
where regexp_count(agg.collection, ',') + 1 >= index.i -- only get rows where number of items matches
group by 1
I have a table where one column has an array - but stored in a text format:
mytable
id ids
-- -------
1 '[3,4]'
2 '[3,5]'
3 '[3]'
etc ...
I want to find all records that have the value 5 as an array element in the ids column.
I was trying to achieve this by using the "string to array" function and removing the [ symbols with the translate function, but couldn't find a way.
You can do this: http://www.sqlfiddle.com/#!1/5c148/12
select *
from tbl
where translate(ids, '[]','{}')::int[] && array[5];
Output:
| ID | IDS |
--------------
| 2 | [3,5] |
You can also use bool_or: http://www.sqlfiddle.com/#!1/5c148/11
with a as
(
select id, unnest(translate(ids, '[]','{}')::int[]) as elem
from tbl
)
select id
from a
group by id
having bool_or(elem = 5);
To see the original elements:
with a as
(
select id, unnest(translate(ids, '[]','{}')::int[]) as elem
from tbl
)
select id, '[' || array_to_string(array_agg(elem), ',') || ']' as ids
from a
group by id
having bool_or(elem = 5);
Output:
| ID | IDS |
--------------
| 2 | [3,5] |
Postgresql DDL is atomic, if it's not late yet in your project, just structure your stringly-typed array to a real array: http://www.sqlfiddle.com/#!1/6e18c/2
alter table tbl
add column id_array int[];
update tbl set id_array = translate(ids,'[]','{}')::int[];
alter table tbl drop column ids;
Query:
select *
from tbl
where id_array && array[5]
Output:
| ID | ID_ARRAY |
-----------------
| 2 | 3,5 |
You can also use contains operator: http://www.sqlfiddle.com/#!1/6e18c/6
select *
from tbl
where id_array #> array[5];
I prefer the && syntax though, it directly connotes intersection. It reflects that you are detecting if there's an intersection between two sets(array is a set)
http://www.postgresql.org/docs/8.2/static/functions-array.html
If you store the string representation of your arrays slightly differently, you can cast to array of integer directly:
INSERT INTO mytable
VALUES
(1, '{3,4}')
,(2, '{3,5}')
,(3, '{3}');
SELECT id, ids::int[]
FROM mytable;
Else, you have to put in one more step:
SELECT (translate(ids, '[]','{}'))::int[]
FROM mytable
I would consider making the column an array type to begin with.
Either way, you can find your row like this:
SELECT id, ids
FROM (
SELECT id, ids, unnest(ids::int[]) AS elem
FROM mytable
) x
WHERE elem = 5
If I have to search for some data I can use wildcards and use a simple query -
SELECT * FROM TABLE WHERE COL1 LIKE '%test_string%'
And, if I have to look through many values I can use -
SELECT * FROM TABLE WHERE COL1 IN (Select col from AnotherTable)
But, is it possible to use both together. That is, the query doesn't just perform a WHERE IN but also perform something similar to WHERE LIKE? A query that just doesn't look through a set of values but search using wildcards through a set of values.
If this isn't clear I can give an example. Let me know. Thanks.
Example -
lets consider -
AnotherTable -
id | Col
------|------
1 | one
2 | two
3 | three
Table -
Col | Col1
------|------
aa | one
bb | two
cc | three
dd | four
ee | one_two
bb | three_two
Now, if I can use
SELECT * FROM TABLE WHERE COL1 IN (Select col from AnotherTable)
This gives me -
Col | Col1
------|------
aa | one
bb | two
cc | three
But what if I need -
Col | Col1
------|------
aa | one
bb | two
cc | three
ee | one_two
bb | three_two
I guess this should help you understand what I mean by using WHERE IN and LIKE together
SELECT *
FROM TABLE A
INNER JOIN AnotherTable B on
A.COL1 = B.col
WHERE COL1 LIKE '%test_string%'
Based on the example code provided, give this a try. The final select statement presents the data as you have requested.
create table #AnotherTable
(
ID int IDENTITY(1,1) not null primary key,
Col varchar(100)
);
INSERT INTO #AnotherTable(col) values('one')
INSERT INTO #AnotherTable(col) values('two')
INSERT INTO #AnotherTable(col) values('three')
create table #Table
(
Col varchar(100),
Col1 varchar(100)
);
INSERT INTO #Table(Col,Col1) values('aa','one')
INSERT INTO #Table(Col,Col1) values('bb','two')
INSERT INTO #Table(Col,Col1) values('cc','three')
INSERT INTO #Table(Col,Col1) values('dd','four')
INSERT INTO #Table(Col,Col1) values('ee','one_two')
INSERT INTO #Table(Col,Col1) values('ff','three_two')
SELECT * FROM #AnotherTable
SELECT * FROM #Table
SELECT * FROM #Table WHERE COL1 IN(Select col from #AnotherTable)
SELECT distinct A.*
FROM #Table A
INNER JOIN #AnotherTable B on
A.col1 LIKE '%'+B.Col+'%'
DROP TABLE #Table
DROP TABLE #AnotherTable
Yes. Use the keyword AND:
SELECT * FROM TABLE WHERE COL1 IN (Select col from AnotherTable) AND COL1 LIKE '%test_string%'
But in this case, you are probably better off using JOIN syntax:
SELECT TABLE.* FROM TABLE JOIN AnotherTable on TABLE.COL1 = AnotherTable.col WHERE TABLE.COL1 LIKE '%test_string'
no because each element in the LIKE clause needs the wildcard and there's not a way to do that with the IN clause
The pattern matching operators are:
IN, against a list of values,
LIKE, against a pattern,
REGEXP/RLIKE against a regular expression (which includes both wildcards and alternatives, and is thus closest to "using wildcards through a set of valuws", e.g. (ab)+a|(ba)+b will match all strings aba...ba or bab...ab),
FIND_IN_SET to get the index of a string in a set (which is represented as a comma separated string),
SOUNDS LIKE to compare strings based on how they're pronounced and
MATCH ... AGAINST for full-text matching.
That's about it for string matching, though there are other string functions.
For the example, you could try joining on Table.Col1 LIKE CONCAT(AnotherTable.Col, '%'), though performance will probably be dreadful (assuming it works).
Try a cross join, so that you can compare every row in AnotherTable to every row in Table:
SELECT DISTINCT t.Col, t.Col1
FROM AnotherTable at
CROSS JOIN Table t
WHERE t.col1 LIKE ('%' + at.col + '%')
To make it safe, you'll need to escape wildcards in at.col. Try this answer for that.
If I understand the question correctly you want the rows from "Table" when "Table.Col1" is IN "AnotherTable.Col" and you also want the rows when Col1 IS LIKE '%some_string%'.
If so you want something like:
SELECT
t.*
FROM
[Table] t
LEFT JOIN
[AnotherTable] at ON t.Col1 = at.Col
WHERE (at.Col IS NOT NULL
OR t.Col1 LIKE '%some_string%')
Something like this?
SELECT * FROM TABLE
WHERE
COL1 IN (Select col from AnotherTable)
AND COL1 LIKE '%test_string%'
Are you thinking about something like EXISTS?
SELECT * FROM TABLE t WHERE EXISTS (Select col from AnotherTable t2 where t2.col = t.col like '%test_string%' )