I have three 5 columns in my query:
Count(ID)
Min(Date)
Max(Date)
Hours: DateDiff("h",Min([Date]),Max([Date]))
UPH: Count([ID])/[Hours]
I want the query to return the count per day, for example:
Count(ID) | Min(Date) | Max(Date) | Hours | UPH
30 | 9/29/2020 11:00:00 AM | 9/29/2020 11:00:00 PM | 12 | 2.5
I have tried the following code but had no luck
Between #9/29/2020 12:00:01 AM# And #9/29/2020 11:59:59 PM#
Seems like I can only get it to run within a day range, not an hourly range.
Related
I want to take the value that falls between the current day (today) and yesterday but only when after 9 am yesterday and before 9 am today. The current day must be only on Tuesday - Friday. But, if the current day is Monday, it will take value from Friday after 9 am to Monday before 9 am.
Samples
+---------+------------------------------+
| ID | registration_started_at |
+---------+------------------------------+
| 1 | 2021-05-13 07:00:00.000 |
| 2 | 2021-05-13 11:00:00.000 |
| 3 | 2021-05-14 08:00:00.000 |
| 4 | 2021-05-14 10:00:00.000 |
| 5 | 2021-05-15 12:00:00.000 |
| 6 | 2021-05-16 13:00:00.000 |
| 7 | 2021-05-17 08:00:00.000 |
| 8 | 2021-05-17 10:00:00.000 |
+---------+------------------------------+
So let say when the current_day (today) is Friday (14 May 2021),
When I run the query it must return
Desired Result 1
+---------+------------------------------+
| ID | registration_started_at |
+---------+------------------------------+
| 2 | 2021-05-13 11:00:00.000 |
| 3 | 2021-05-14 08:00:00.000 |
+---------+------------------------------+
But when current_day (today) is Monday (17 May 2021) it should return
Desired Result 2
+---------+------------------------------+
| ID | registration_started_at |
+---------+------------------------------+
| 4 | 2021-05-14 10:00:00.000 |
| 5 | 2021-05-15 12:00:00.000 |
| 6 | 2021-05-16 13:00:00.000 |
| 7 | 2021-05-17 08:00:00.000 |
+---------+------------------------------+
I only manage to get the desired result 1 with this query and I think this still not correct tho for desired result 2
SELECT ID,
DATETIME(registration_started_at, 'Asia/Jakarta') as registration_started_at
FROM `table`
WHERE
DATETIME_DIFF(CURRENT_DATETIME('Asia/Jakarta'), DATETIME(registration_started_at, 'Asia/Jakarta'), week) = 0
AND DATE(DATETIME_ADD(DATETIME(registration_started_at, 'Asia/Jakarta'), INTERVAL -9 HOUR)) = CURRENT_DATE('Asia/Jakarta') - 1
---------edit 1
Using the Mr. Caius Jard answer
WHERE
(DATETIME(registration_started_at, 'Asia/Jakarta') BETWEEN (
(CASE
WHEN EXTRACT(
DAYOFWEEK
FROM CURRENT_DATE('Asia/Jakarta')
) = 2 -- if Monday
THEN DATETIME_ADD(
CURRENT_DATETIME('Asia/Jakarta'),
INTERVAL -63 HOUR
) -- then 63 hours back from midnight today
ELSE DATETIME_ADD(
CURRENT_DATETIME('Asia/Jakarta'),
INTERVAL -15 HOUR
)
END)
) -- else 15 hours back from midnight today
AND DATETIME_ADD(
CURRENT_DATETIME('Asia/Jakarta'),
INTERVAL 9 HOUR
)) -- 9am today
It returns the 63 hours before today's time for Monday or 15 hours before today's time if not Monday, which is incorrect because if I run the query on 15.00 it only returns value from 00.00 today
I think this captures the logic you want:
WHERE DATETIME(registration_started_at, 'Asia/Jakarta') < DATETIME_ADD(DATETIME(DATE(CURRENT_DATETIME('Asia/Jakarta'))), INTERVAL 9 HOUR) AND
(EXTRACT(DAYOFWEEK, DATE(CURRENT_DATETIME('Asia/Jakarta'))) = 2 AND
DATETIME(registration_started_at, 'Asia/Jakarta') > DATETIME_ADD(DATETIME_ADD(DATETIME(DATE(CURRENT_DATETIME('Asia/Jakarta'))), INTERVAL 9 HOUR), INTERVAL -3 DAY) OR
DATETIME(registration_started_at, 'Asia/Jakarta') > DATETIME_ADD(DATETIME_ADD(DATETIME(DATE(CURRENT_DATETIME('Asia/Jakarta'))), INTERVAL 9 HOUR), INTERVAL -1 DAY)
)
What are the important components of this?
This expressoin:
DATETIME_ADD(DATETIME(DATE(CURRENT_DATETIME('Asia/Jakarta'))), INTERVAL 9 HOUR)
Returns 9:00 on the current date in Jakarata. No matter what, you want registration_started_at before that date/time.
This expression
EXTRACT(DAYOFWEEK, DATE(CURRENT_DATETIME('Asia/Jakarta')))
Returns the current day of the week, with 2 for Monday.
These expressions:
DATETIME_ADD(DATETIME_ADD(DATETIME(DATE(CURRENT_DATETIME('Asia/Jakarta'))), INTERVAL 9 HOUR), INTERVAL -3 DAY)
DATETIME_ADD(DATETIME_ADD(DATETIME(DATE(CURRENT_DATETIME('Asia/Jakarta'))), INTERVAL 9 HOUR), INTERVAL -1 DAY)
Just subtract 1 or 3 days from the current 9:00 datetime.
Perhaps something like:
WHERE
registration_started_at
BETWEEN
CASE WHEN EXTRACT(DAYOFWEEK FROM CURRENT_DATE()) = 2 -- if Monday
THEN DATETIME_ADD(CURRENT_DATE(), INTERVAL -63 HOUR)) -- then 63 hours back from midnight today
ELSE DATETIME_ADD(CURRENT_DATE(), INTERVAL -15 HOUR)) END -- else 15 hours back from midnight today
AND
DATETIME_ADD(CURRENT_DATE(), INTERVAL 9 HOUR)) -- 9am today
Never used bigquery, so it might need some fiddling, but the basic idea is that we ask via case when what the current day is and use it to change how much we go back in time
Using Mr. Caius Jard idea, I am able to make it works. I just need to cast CURRENT_DATE to DATETIME() to take the today's 00:00
WHERE
(DATETIME(registration_started_at, 'Asia/Jakarta') BETWEEN (
(CASE
WHEN EXTRACT(
DAYOFWEEK
FROM CURRENT_DATE('Asia/Jakarta')
) = 2 -- if Monday
THEN DATETIME_ADD(
DATETIME(CURRENT_DATE('Asia/Jakarta')),
INTERVAL -63 HOUR
) -- then 63 hours back from midnight today
ELSE DATETIME_ADD(
DATETIME(CURRENT_DATE('Asia/Jakarta')),
INTERVAL -15 HOUR
)
END)
) -- else 15 hours back from midnight today
AND DATETIME_ADD(
DATETIME(CURRENT_DATE('Asia/Jakarta')),
INTERVAL 9 HOUR
)) -- 9am today
I am using SQL Server 2014.
What I'm trying to do is add a new time to an old datetime.
I'm not even sure if it's possible but I thought I'd ask the experts.
So these are what my columns look like:
CurrentDate | Hours | NewDate
2017-03-10 08:00:00 | 25 | ??
2017-01-01 10:00:00 | 27 | ??
What I want is the Hours to be converted to days and hours so it can be added to the CurrentDate to create a NewDate.
So the NewDate would be: 2017-03-11 09:00:00 because 25 hours equates to 1 day and 1 hour. And the second NewDate would be: 2017-01-02 01:00:00 because 27 equates to 1 day and 3 hours.
I actually don't think this is possible and there's a chance I might have to put the hours already converted into days and times but if that's the case, how would I write 25 hours? Would it be 00-00-01 01:00:00? And would 27 hours be 00-00-01 03:00:00 and then just add those values into CurrentDate?
Thanks! Feel free to tell me this has been asked before (I looked, but couldn't find anything as unique as this or maybe I didn't look hard enough) or if this can't be done.
You can simply use DATEADD, no need to convert the hours to days first:
SELECT CurrentDate,
Hours,
DATEADD(HOUR,Hours,CurrentDate) NewDate
FROM dbo.YourTable;
You can try this:
select DATEADD(HOUR,25,'2017-03-10 08:00:00') -- 2017-03-11 09:00:00.000
select DATEADD(HOUR,27,'2017-01-01 10:00:00') -- 2017-01-02 13:00:00.000
This is the table in Postgresql:
mydb=# \d login_log
Table "public.login_log"
Column | Type | Modifiers
-------------+--------------------------+-----------
id | integer |
login_start | timestamp with time zone |
login_end | timestamp with time zone |
some rows:
1 | 2015-03-19 10:00:00 | 2015-03-19 13:30:00
2 | 2015-03-19 10:20:00 | 2015-03-19 13:20:00
3 | 2015-03-19 13:00:00 | 2015-03-19 16:00:00
4 | 2015-03-19 13:10:00 | 2015-03-19 16:00:00
5 | 2015-03-19 14:30:00 | 2015-03-19 15:30:00
6 | 2015-03-19 15:00:00 | 2015-03-19 15:30:00
7 | 2015-03-19 12:00:00 | 2015-03-19 18:00:00
I need a SQL to count out in which time range there is the max logged users.
with the example above, the result is:
in time range: 2015-03-19 13:10:00 ~ 2015-03-19 13:20:00,
5 users logged in. (1, 2, 3, 4, 7)
Use range types (construct them "on the fly"). They offer quite a few helpful functions and operators. You would only need to define a custom aggregate, which will provide you the overall intersection. So - you would end up with something like this:
with common as (
select (intersection(tsrange(login_start, login_end))) as period
from login_log
)
select
-- common.period,
-- array_agg(id)
*
from common, login_log
WHERE tsrange(login_start, login_end) && common.period
-- GROUP BY common.period
/*
for some reason, when uncommenting the "^--..." lines,
and commenting the "*" one - sqlfiddle shows an empty result.
Nevertheless it works on my local posgres...
*/
See the working example: http://sqlfiddle.com/#!15/0c9c6/10
Find different timestamps of interest using UNION ALL, count number of active users at these timestamps:
select ts,
(select count(*) from login_log t2
where timestamps.ts between t2.login_start and t2.login_end) as count
from (select login_start as ts
from login_log
union all
select login_end
from login_log) as timestamps
order by count desc
fetch first 1 row only
Finally order descending and pick the highest value only!
(From a non Postgresql user, so some details may be wrong... Please comment if that's the case and I'll edit!)
I have a table which looks like you can see below:
Id Date ScheduledTimeFrom ScheduledTimeTo ActualTimeFrom ActualTimeTo
1 2013-01-01 1899-12-30 07:00:00 1899-12-30 18:00:00 1899-12-30 07:23:00 1899-12-30 17:15:00
I need to calculate per half hour how many records exists, the output should be like:
Time Actual Count:
7:00 4
7:30 4
8:00 4
8:30 4
9:00 4
9:30 5
10:00 5
10:30 6
11:00 7
11:30 8
12:00 8
12:30 8
13:00 8
13:30 8
14:00 8
14:30 8
15:00 7
15:30 7
16:00 7
16:30 6
17:00 5
17:30 4
18:00 4
I already tried to make a helper table which should hold the times per halfhour. I have joined this helpertable with the table that contains the data and after that I tried to use a group by function but it was not working.
My query was like:
Create table period (timefrom datetime, timeto datetime)
insert into period
select '1899-12-30 07:00:00.000', '1899-12-30 07:30:00.000'
Union all
select '1899-12-30 07:30:00.000', '1899-12-30 08:00:00.000'
select *
from period p left join table1 t on t.ActualTimeFrom < p.timeto and t.ActualTimeTo >=p.timefrom
Grouping this give me no desired result....
Anyone an idea how to come to the result?
P.s. I am using sql server 2005.
After snooping around and testing it on my side, looks like this date function could be the answer:
DATEADD(mi,DATEDIFF(mi,0,YOUR_DATE_COLUMN)/30*30,0)
I have a table, a timetable, with check-in and check-out times of the employees:
ID Date Check-in Check out
1 1-1-2011 11:00 18:00
2 1-1-2011 11:00 19:00
3 1-1-2011 16:00 18:30
4 1-1-2011 17:00 20:00
Now I want to know how many employees are working, every (half) hour.
The result I want to see:
Hour Count
11 2
12 2
13 2
14 2
15 2
16 3
17 3
18 2,5
19 1
Every 'Hour' you must read as 'till the next full hour', ex. 11 -> 11:00 - 12:00
Any ideas?
Build an additional table, called Hours, containing the following data:
h
00:00
00:30
01:00
...
23:30
then, run
Select h as 'hour' ,count(ID) as 'count' from timetable,hours where [Check_in]<=h and h<=[Check_out] group by h