I have a table, a timetable, with check-in and check-out times of the employees:
ID Date Check-in Check out
1 1-1-2011 11:00 18:00
2 1-1-2011 11:00 19:00
3 1-1-2011 16:00 18:30
4 1-1-2011 17:00 20:00
Now I want to know how many employees are working, every (half) hour.
The result I want to see:
Hour Count
11 2
12 2
13 2
14 2
15 2
16 3
17 3
18 2,5
19 1
Every 'Hour' you must read as 'till the next full hour', ex. 11 -> 11:00 - 12:00
Any ideas?
Build an additional table, called Hours, containing the following data:
h
00:00
00:30
01:00
...
23:30
then, run
Select h as 'hour' ,count(ID) as 'count' from timetable,hours where [Check_in]<=h and h<=[Check_out] group by h
Related
I have a table that is currently in the following format
ID
Title
CreatedOn
1
Test 1
2021-04-26 08:00:00
2
Test 2
2021-04-26 10:00:00
3
Test 3
2021-04-27 09:00:00
4
Test 4
2021-04-28 14:00:00
5
Test 5
2021-04-28 16:00:00
6
Test 6
2021-04-28 12:00:00
7
Test 7
2021-04-29 13:00:00
8
Test 8
2021-04-30 06:00:00
9
Test 9
2021-05-17 10:00:00
10
Test 10
2021-05-18 19:00:00
11
Test 11
2021-05-18 23:00:00
12
Test 12
2021-05-19 16:00:00
13
Test 13
2021-05-20 07:00:00
14
Test 14
2021-05-21 14:00:00
15
Test 15
2021-05-21 10:00:00
16
Test 16
2021-04-30 10:00:00
What I would like to do is a query that would tell me how many requests have been Monday to Friday per hour. So aggregate all the data into just rows of Monday to Friday.
So the query should return
Day
Hour
Count
Monday
08:00
1
Monday
10:00
2
Tuesday
10:00
1
Tuesday
19:00
1
Tuesday
23:00
1
Wednesday
14:00
1
Wednesday
16:00
2
Wednesday
12:00
1
etc.. How do I achieve this?
So far I have the following
SELECT
DATENAME(WEEK, CreatedOn) AS Week,
DATEPART(Hour, CreatedOn) AS Hour,
COUNT(*) AS Requests
FROM [Enterprise32].[dbo].[nav_EmailEstimateRequests]
where CreatedOn > '2021-01-01'
GROUP BY DATENAME(WK, CreatedOn),DATEPART(Hour, CreatedOn)
ORDER BY DATENAME(WK, CreatedOn);
But the above query returns each week so Week 1 up until Week 21. Please guide me in the right direction.
Thank you!
You want weekday for the date part:
SELECT DATENAME(WEEKDAY, CreatedOn) AS Weekday,
DATEPART(Hour, CreatedOn) AS Hour,
COUNT(*) AS Requests
FROM [Enterprise32].[dbo].[nav_EmailEstimateRequests]
WHERE CreatedOn > '2021-01-01'
GROUP BY DATENAME(WEEKDAY, CreatedOn), DATEPART(Hour, CreatedOn), DATEPART(WEEKDAY, CreatedOn)
ORDER BY DATEPART(WEEKDAY, CreatedOn), Hour;
Note: I included DATEPART(weekday, ) in the GROUP BY, so you could use it in the ORDER BY.
I have table in which Sunday to Saturdy "Doctor Start" and "End Time" is given.
I want to create time slots of 15 minutes.
On the basis of that, the patient clicks on calendar datetime interval which shows slots that have already been booked.
The following example shows how to split time into slices of 15 minutes. It uses hierarchical query. A little bit of explanation:
line 2: trunc function, applied to a date value, returns "beginning" of that day (at midnight). Adding 15 / (24*60) adds 15 minutes (as there are 24 hours in a day and 60 minutes in an hour). Multiplying 15 by level works as a "loop", i.e. adds 15-by-15-by-15 ... minutes to previous value.
line 4: similar to line 2, but it makes sure that a day (24 hours * 60 minutes) is divided to 15-minutes parts
line 6: start time is trivial
line 7: end time just adds 15 minutes to start_time
line 9: return only time between 10 and 16 hours (you don't have patients at 02:15 AM, right?)
SQL> with fifteen as
2 (select trunc(sysdate) + (level * 15)/(24*60) c_time
3 from dual
4 connect by level <= (24*60) / 15
5 )
6 select to_char(c_time, 'hh24:mi') start_time,
7 to_char(c_time + 15 / (24 * 60), 'hh24:mi') end_time
8 from fifteen
9 where extract(hour from cast (c_time as timestamp)) between 10 and 15;
START_TIME END_TIME
---------- ----------
10:00 10:15
10:15 10:30
10:30 10:45
10:45 11:00
11:00 11:15
11:15 11:30
11:30 11:45
11:45 12:00
12:00 12:15
12:15 12:30
12:30 12:45
12:45 13:00
13:00 13:15
13:15 13:30
13:30 13:45
13:45 14:00
14:00 14:15
14:15 14:30
14:30 14:45
14:45 15:00
15:00 15:15
15:15 15:30
15:30 15:45
15:45 16:00
24 rows selected.
SQL>
I am working on building a query report where i have multiple types of segment with priority ranking on one table and second table with all types of segment with date, time etc. (as shown below) The duration for lower ranked segment during overlap should not be considered.
Please help me as I am unable to figure out query and get the duration of segment excluding the overlap based on ranking
table_Rank
Rank Code
1 x
2 y
3 z
4 a
5 b
6 c
7 d
8 r
9 f
Table_Segments
Code Date Start Time End Time Duration
a 18-Jul-15 17:30 17:45 0:15
c 18-Jul-15 18:00 19:00 1:00
y 18-Jul-15 18:45 19:00 0:15
a 18-Jul-15 20:15 20:20 0:05
b 18-Jul-15 23:45 1:00 1:15
z 19-Jul-15 0:30 1:15 0:45
f 19-Jul-15 2:00 3:00 1:00
Table With Ranks = Table_Rank
Table With Data = Table_Segments
What i am trying to achieves is, in an overlap situation overlap span should be considered for code with higher rank.
e.g.
Code Date Start Time End Time Duration
b 18-Jul-15 23:45 1:00 1:15
z 19-Jul-15 0:30 1:15 0:45
The actual duration output for b should 45 minutes as it has a lower rank compared to z and z should be 45 minutes
How to find the date difference in hours between two records with nearest datetime value and it must be compared in same group?
Sample Data as follows:
Select * from tblGroup
Group FinishedDatetime
1 03-01-2009 00:00
1 13-01-2009 22:00
1 08-01-2009 03:00
2 01-01-2009 10:00
2 13-01-2009 20:00
2 10:01-2009 10:00
3 27-10-2008 00:00
3 29-10-2008 00:00
Expected Output :
Group FinishedDatetime Hours
1 03-01-2009 00:00 123
1 13-01-2009 22:00 139
1 08-01-2009 03:00 117
2 01-01-2009 10:00 216
2 13-01-2009 20:00 82
2 10:01-2009 10:00 82
3 27-10-2008 00:00 48
3 29-10-2008 00:00 48
Try this:
Select t1.[Group], DATEDIFF(HOUR, z.FinishedDatetime, t1.FinishedDatetime)
FROM tblGroup t1
OUTER APPLY(SELECT TOP 1 *
FROM tblGroup t2
WHERE t2.[Group] = t1.[Group] AND t2.FinishedDatetime<t1.FinishedDatetime
ORDER BY FinishedDatetime DESC)z
I have a table which looks like you can see below:
Id Date ScheduledTimeFrom ScheduledTimeTo ActualTimeFrom ActualTimeTo
1 2013-01-01 1899-12-30 07:00:00 1899-12-30 18:00:00 1899-12-30 07:23:00 1899-12-30 17:15:00
I need to calculate per half hour how many records exists, the output should be like:
Time Actual Count:
7:00 4
7:30 4
8:00 4
8:30 4
9:00 4
9:30 5
10:00 5
10:30 6
11:00 7
11:30 8
12:00 8
12:30 8
13:00 8
13:30 8
14:00 8
14:30 8
15:00 7
15:30 7
16:00 7
16:30 6
17:00 5
17:30 4
18:00 4
I already tried to make a helper table which should hold the times per halfhour. I have joined this helpertable with the table that contains the data and after that I tried to use a group by function but it was not working.
My query was like:
Create table period (timefrom datetime, timeto datetime)
insert into period
select '1899-12-30 07:00:00.000', '1899-12-30 07:30:00.000'
Union all
select '1899-12-30 07:30:00.000', '1899-12-30 08:00:00.000'
select *
from period p left join table1 t on t.ActualTimeFrom < p.timeto and t.ActualTimeTo >=p.timefrom
Grouping this give me no desired result....
Anyone an idea how to come to the result?
P.s. I am using sql server 2005.
After snooping around and testing it on my side, looks like this date function could be the answer:
DATEADD(mi,DATEDIFF(mi,0,YOUR_DATE_COLUMN)/30*30,0)