is that anyway to write similar query without using union?
select sum(decode(p.sumsend,0,1,0)) recvcnt,
sum(decode(p.sumsend,0,1,0)*p.sumserv) recvsum
from some_table p
where p.polefilter = 5
union
select sum(decode(p.sumsend,0,1,0)) recvcnt,
sum(decode(p.sumsend,0,1,0)*p.sumserv) recvsum
from some_table p
where p.polefilter != 5
If you are OK with having all 4 columns on one row, then one option is conditional aggregation:
select
sum(case when polefilter = 5 and sumsend = 0 then 1 else 0 end) recvcnt1,
sum(case when polefilter = 5 and sumsend = 0 then 1 else 0 end * sumserv) recvsum1,
sum(case when polefilter <> 5 and sumsend = 0 then 1 else 0 end) recvcnt2,
sum(case when polefilter <> 5 and sumsend = 0 then 1 else 0 end * sumserv) recvsum2
from some_table p
where polefilter is not null
On the other hand, if you want two rows in the resultset, then you can use aggregation and a case expression to define the groups:
select
case when polefilter = 5 then 1 else 0 end as polefilter_is_5
sum(case when sumsend = 0 then 1 else 0 end) recvcnt,
sum(case when sumsend = 0 then 1 else 0 end * sumserv) recvsum1
from some_table p
where p.polefilter is not null
group by case when polefilter = 5 then 1 else 0 end
Note that I changed the decode() functions to case expressions; both do the same thing, but the latest is standard SQL (and is somehow more flexible).
A query like the one below should work. Please provide sample data and expected output when asking a question next time.
SELECT SUM (CASE WHEN p.sumsend = 0 THEN 1 ELSE 0 END) recvcnt,
SUM (CASE WHEN p.sumsend = 0 THEN 1 ELSE 0 END * p.sumserv) recvsum
FROM some_table p
GROUP BY CASE p.polefilter WHEN 5 THEN 1 ELSE 0 END;
Related
I want to create a calculated field at the end of the columns where it will count all the Columns having values greater than 0.
Below is a sample Data Set.
Account_number DAY_0 DAY_30 DAY_60 DAY_90 DAY_120
acc_001 99 10 0 0.2 0
You can use case expressions:
select t.*,
( (case when day_0 > 0 then 1 else 0 end) +
(case when day_30 > 0 then 1 else 0 end) +
(case when day_60 > 0 then 1 else 0 end) +
(case when day_90 > 0 then 1 else 0 end) +
(case when day_120 > 0 then 1 else 0 end)
) as num_gt_zero
from t;
That said, you probably constructed this from a group by query. You might be able to put this logic directly into that query. If that is the case, ask a new question, with sample data, desired results, and an appropriate database tag.
How to total count?
SELECT
COUNT(CASE WHEN SHP.id = 1 then 1 ELSE NULL END) as "New",
COUNT(CASE WHEN SHP.id = 2 then 5 ELSE NULL END) as "Accepted"
from SHP
RESULT:
NEW Accepted
1 5
But I need a total count
result: 6
I'd do something like this;
SELECT
COUNT(CASE WHEN id = 1 THEN 1 END) as New,
COUNT(CASE WHEN id = 2 THEN 5 END) as Accepted,
COUNT(CASE WHEN id = 1 THEN 1
WHEN id = 2 THEN 5 END) as Total
FROM SHP
This is exactly what the CASE statement should be used for, the logic is very simple. This will avoid having to perform multiple calculations on the same fields.
As a note, the value in your THEN statement isn't used in this instance at all, it's just doing a COUNT of the number rather than performing a SUM. I've also removed the ELSE NULL because this is what the CASE will do by default anyway.
If your intention was to SUM the values then do this;
SELECT
SUM(CASE WHEN id = 1 THEN 1 END) as New,
SUM(CASE WHEN id = 2 THEN 5 END) as Accepted,
SUM(CASE WHEN id = 1 THEN 1
WHEN id = 2 THEN 5 END) as Total
FROM SHP
Example
Assuming you have only two values in your database, 1 and 2, we can create test data like this;
CREATE TABLE #SHP (id int)
INSERT INTO #SHP (id)
VALUES (1),(2)
And use this query;
SELECT
SUM(CASE WHEN id = 1 then 1 END) as New,
SUM(CASE WHEN id = 2 then 5 END) as Accepted,
SUM(CASE WHEN id = 1 THEN 1
WHEN id = 2 THEN 5 END) as Total
FROM #SHP
Gives this result;
New Accepted Total
1 5 6
Try this:
SELECT
COUNT(CASE WHEN SHP.id = 1 then 1 ELSE NULL END) +
COUNT(CASE WHEN SHP.id = 2 then 5 ELSE NULL END) as "Total"
from SHP
You could wrap your query into a subquery and do something like this:
SELECT SUM(New) as New, Sum(Accepted) as Accepted, Sum(New + Accepted) as Total FROM
(SELECT
COUNT(CASE WHEN SHP.id = 1 then 1 ELSE NULL END) as "New",
COUNT(CASE WHEN SHP.id = 2 then 5 ELSE NULL END) as "Accepted"
from SHP) as SubQuery
That's if you don't want to duplicate doing the counts and just adding the two together.
try this
with s1 as(
SELECT
COUNT(CASE WHEN SHP.id = 1 then 1 ELSE 0 END) as "New"
from SHP
),s2 as
(
SELECT
COUNT(CASE WHEN SHP.id = 2 then 5 ELSE 0 END) as "Accepted"
from SHP
)
select sum("New"+ "Accepted") from s1,s2
I have this query :
SELECT WorkId, RegisterDate, sum(RoomType1) As RoomType1, sum(RoomType2) As RoomType2, sum(RoomType3) As RoomType3, sum(RoomType4) As RoomType4, sum(RoomType5) As RoomType5, sum(RoomType6) As RoomType6, sum(RoomType7) As RoomType7, sum(RoomType8) As RoomType8
FROM (
SELECT dbo.[Work].WorkId, dbo.[Work].RegisterDate,
case dbo.Floor.RoomType when 1 then 1 else 0 end as RoomType1,
case dbo.Kat.RoomType when 2 then 1 else 0 end as RoomType2,
FROM dbo.Belediye INNER JOIN
dbo.[Is] ON dbo.Municipality.MunicipalityId= dbo.[Is].MunicipalityWorkId INNER JOIN
dbo.Look ON dbo.[Work].LookWorkId = dbo.Look.LookId ,
WHERE (dbo.Look.LocationIS NOT NULL)
) E
GROUP BY WorkId,
This query works as expected, but I can't understand why it has two selects, why does it need them? Please explain it to me. Thanks.
As you suspected this query dont need two selects and could be rewritten without sub-query:
SELECT i.IsId,
i.KayitTarihi,
SUM(case k.OdaTipi when 1 then 1 else 0 end) as RoomType1,
SUM(case k.OdaTipi when 2 then 1 else 0 end) as RoomType2,
SUM(case k.OdaTipi when 3 then 1 else 0 end) as RoomType3,
SUM(case k.OdaTipi when 4 then 1 else 0 end) as RoomType4,
SUM(case k.OdaTipi when 5 then 1 else 0 end) as RoomType5,
SUM(case k.OdaTipi when 6 then 1 else 0 end) as RoomType6,
SUM(case k.OdaTipi when 7 then 1 else 0 end) as RoomType7,
SUM(case k.OdaTipi when 8 then 1 else 0 end) as RoomType8
FROM dbo.Belediye b
INNER JOIN dbo.[Is] i
ON b.BelediyeId = i.BelediyeIsId
INNER JOIN dbo.YerGorme yg
ON i.YerGormeIsId = yg.YerGormeId
INNER JOIN dbo.Kat k
ON yg.YerGormeId = k.YerGorme_YerGormeId
WHERE yg.Lokasyon IS NOT NULL
GROUP BY i.IsId, i.KayitTarihi
Note: use table aliases
Hej,
I needed help with a case when statement in SQL Server.
Basically, I got three products and when the sum is equal to 2, then I want it to it be counted as 1 else 0. I wanted to know if the logic is write with this code or can it be improved?
case when sum(hase=1 OR hasd=1 OR hasf=1)=2 then 1 else 0 end as Xavc
What I was trying with this code is this: The customer might not have all three products however, if he has two products or the three the three , then it is equal to 2 and count is 1.
Something like this?
SELECT
CASE
WHEN hase + hasd + hasf = 2 THEN 1
ELSE 0
END AS Xavc
I think you are trying to do something like this...
CASE WHEN SUM(CASE WHEN hase=1 THEN 1 ELSE 0 END)
+ SUM(CASE WHEN hasd=1 THEN 1 ELSE 0 END)
+ SUM(CASE WHEN hasf=1 THEN 1 ELSE 0 END) = 2
THEN 1 ELSE 0 END AS Xavc
In this case try this ..
CASE WHEN SUM(CASE WHEN hase=1 THEN 1 ELSE 0 END) + SUM(CASE WHEN hasd=1 THEN 1 ELSE 0 END) = 2
OR SUM(CASE WHEN hasd=1 THEN 1 ELSE 0 END) + SUM(CASE WHEN hasf=1 THEN 1 ELSE 0 END) = 2
OR SUM(CASE WHEN hase=1 THEN 1 ELSE 0 END) + SUM(CASE WHEN hasf=1 THEN 1 ELSE 0 END) = 2
THEN 1 ELSE 0 END AS Xavc
I am using SQL Server 2008.
I am trying to do some basic math in some basic queries. I need to add up wins, losses, total, and percentages. I usually ask for the raw numbers and then do the calculations once I return my query to page. I would like to give SQL Server the opportunity to work a little harder.
What I want to do is something like this:
SELECT SUM(case when vote = 1 then 1 else 0 end) as TotalWins,
SUM(case when vote = 0 then 1 else 0 end) as TotalLosses,
TotalWins + TotalLosses as TotalPlays,
TotalPlays / TotalWins as PctWins
Here's what I am doing now:
SELECT SUM(case when vote = 1 then 1 else 0 end) as TotalWins,
SUM(case when vote = 0 then 1 else 0 end) as TotalLosses,
SUM(case when vote = 1 then 1 else 0 end) + SUM(case when vote = 0 then 1 else 0 end) as Votes
What is the easiest, cleanest way to do simple math calculations like this in a query?
*EDIT: *
While I got some great answers, I didn't get what I was looking for.
The scores that I will be calculating are for a specific team, so, my results need to be like this:
TeamID Team Wins Losses Totals
1 A's 5 3 8
2 Bee's 7 9 16
3 Seas 1 3 4
SELECT T.TeamID,
T.Team,
V.TotalWins,
V.TotalLosses,
V.PctWins
FROM Teams T
JOIN
SELECT V.TeamID,
SUM(case when vote = 1 then 1 else 0 end) as V.TotWin,
SUM(case when vote = 0 then 1 else 0 end) as V.TotLoss
FROM Votes V
GROUP BY V.TeamID
I tried a bunch of things, but don't quite know what wrong. I am sure the JOIN part is where the problem is though. How do I bring these two resultsets together?
One way is to wrap your query in an external one:
SELECT TotalWins,
TotalLosses,
TotalWins + TotalLosses as TotalPlays,
TotalPlays / TotalWins as PctWins
FROM
( SELECT SUM(case when vote = 1 then 1 else 0 end) as TotalWins,
SUM(case when vote = 0 then 1 else 0 end) as TotalLosses
FROM ...
)
Another way (suggested by #Mike Christensen) is to use Common Table Expressions (CTE):
; WITH Calculation AS
( SELECT SUM(case when vote = 1 then 1 else 0 end) as TotalWins,
SUM(case when vote = 0 then 1 else 0 end) as TotalLosses
FROM ...
)
SELECT TotalWins,
TotalLosses,
TotalWins + TotalLosses as TotalPlays,
TotalPlays / TotalWins as PctWins
FROM
Calculation
Sidenote: No idea if this would mean any preformance difference in SQL-Server but you can also write these sums:
SUM(case when vote = 1 then 1 else 0 end)
as counts:
COUNT(case when vote = 1 then 1 end) --- the ELSE NULL is implied
try
select a, b, a+b as total
from (
select
case ... end as a,
case ... end as b
from realtable
) t
To answer your second question, this is the code you put forward with corrections to the syntax:
SELECT
T.TeamID,
T.Team,
V.TotalWins,
V.TotalLosses,
PctWins = V.TotalWins * 100 / CAST(V.TotalWins + V.TotalLosses AS float)
FROM Teams T
JOIN (
SELECT
TeamID,
SUM(case when vote = 1 then 1 else 0 end) as TotalWins,
SUM(case when vote = 0 then 1 else 0 end) as TotalLosses
FROM Votes
GROUP BY TeamID
) as V on T.TeamID = V.TeamID
Note the brackets around the inner select.
It might help you if you're doing this sort of thing more than once to create a view...
CREATE VIEW [Totals]
SELECT
SUM(case when T.vote = 1 then 1 else 0 end) as TotalWins,
SUM(case when T.vote = 0 then 1 else 0 end) as TotalLosses,
T.SomeGroupColumn
FROM SomeTable T
GROUP BY T.SomeGroupColumn