I have column with below data:
Change
18 MCO-005329
A ECO-12239
0 ECO-25126
X1 ECO-05963
NA MCO-003778
C ECO-08399
MCO-003759
ECO-00643217
NULL
I want to extract the output like below:
MCO-005329
ECO-12239
ECO-25126
ECO-05963
MCO-003778
ECO-08399
MCO-003759
ECO-00643217
I have implemented the code like below:
select DISTINCT change,
case when change like 'MCO%' THEN change when change like 'ECO-%' THEN change
when change like '%MCO-%' then LTRIM(RTRIM(SUBSTRING(change,10,19) ))
when change like '%ECO-%' then LTRIM(RTRIM(SUBSTRING(change,10,19) ))
else '' end x from table
You can parse out the values from your requirements using SPLIT_STRING, outer apply, and a simple where clause without relying on hard coding any specific string length or position values, its dynamic.
SELECT D2.*
FROM
(
select '18 MCO-005329'
union select 'A ECO-12239'
union select '0 ECO-25126'
union select 'X1 ECO-05963'
union select 'NA MCO-003778'
union select 'C ECO-08399'
union select 'MCO-003759'
union select 'ECO-00643217'
union select NULL
) T(Change)
outer apply
(
select value
from
string_split(Change, ' ') d
) d2
where d2.value like '%-%' or d2.value is null
If you dont want nulls then smiply remove or d2.value is null
https://learn.microsoft.com/en-us/sql/t-sql/queries/from-transact-sql?view=sql-server-ver15
https://learn.microsoft.com/en-us/sql/t-sql/functions/string-split-transact-sql?view=sql-server-ver15
You could use CHARINDEX() and RIGHT() as
SELECT *, RIGHT(Change, CHARINDEX('-', REVERSE(Change)) + 3)
FROM
(
VALUES
('18 MCO-005329'),
('A ECO-12239'),
('0 ECO-25126'),
('X1 ECO-05963'),
('NA MCO-003778'),
('C ECO-08399'),
('MCO-003759'),
('ECO-00643217'), ('hhh kkk-k'),
(NULL)
) T(Change)
Related
In H2 Database when i have applied order by on varchar column Numbers are coming first then Alphabets. But need to come Alphabets first then Numbers.
I have tried with
ORDER BY IF(name RLIKE '^[a-z]', 1, 2), name
but getting error like If condition is not available in H2.
My Column Data is Like
A
1-A
3
M
2-B
5
B-2
it should come like
A
B-2
M
1-A
2-B
3
5
try this out
SELECT MYCOLUMN FROM MYTABLE ORDER BY REGEXP_REPLACE (MYCOLUMN,'(*)(\d)(*)','}\2') , MYCOLUMN
One thing can be done is by altering the ASCII in order by clause.
WITH tab
AS (SELECT 'A' col FROM DUAL
UNION ALL
SELECT '1-A' FROM DUAL
UNION ALL
SELECT '3' FROM DUAL
UNION ALL
SELECT 'M' FROM DUAL
UNION ALL
SELECT '2-B' FROM DUAL
UNION ALL
SELECT '5' FROM DUAL
UNION ALL
SELECT 'B-2' FROM DUAL)
SELECT col
FROM tab
ORDER BY CASE WHEN SUBSTR (col, 1, 1) < CHR (58) THEN CHR (177) || col ELSE col END;
I have Used CHR(58) as ASCII value of numbers end at 57. and CHR(177) is used as this is the maximum in the ASCII table.
FYR : ASCII table
Given the example dataset, I'm not sure if you need further logic than this- so I'll refrain from making further assumptions:
DECLARE #temp TABLE (myval char(3))
INSERT INTO #temp VALUES
('A'), ('1-A'), ('3'), ('M'), ('2-B'), ('5'), ('B-2')
SELECT myval
FROM #temp
ORDER BY CASE WHEN LEFT(myval, 1) LIKE '[a-Z]'
THEN 1
ELSE 2
END
,LEFT(myval, 1)
Gives output:
myval
A
B-2
M
1-A
2-B
3
5
I have a master table that contains a list of strings to search for. it returns TRUE/FALSE if any string in the cell contains text from the master lookup table. Currently I use excel's
=SUMPRODUCT(--ISNUMBER(SEARCH(masterTable,[#searchString])))>0
is there a way to do something like this in SQL? LEFT JOIN or OUTER APPLY would be simple solutions if the strings were equal; but they need be contains..
SELECT *
FROM t
WHERE col1 contains(lookupString,lookupColumn)
--that 2nd table could be maintained and referenced from multiple queries
hop
bell
PRS
2017
My desired results would be a column that shows TRUE/FALSE if the row contains any string from the lookup table
SEARCH_STRING Contained_in_lookup_column
hopping TRUE
root FALSE
Job2017 TRUE
PRS_tool TRUE
hand FALSE
Sorry i dont have access to the DB now to confirm the syntax, but should be something like this:
SELECT t.name,
case when (select count(1) from data_table where data_col like '%' || t.name || '%' > 0) then 'TRUE' else 'FALSE' end
FROM t;
or
SELECT t.name,
case when exists(select null from data_table where data_col like '%' || t.name || '%') then 'TRUE' else 'FALSE' end
FROM t;
Sérgio
You can use a combination of % wildcards with LIKE and EXISTS.
Example (using Oracle syntax) - we have a v_data table containing the data and a v_queries table containing the query terms:
with v_data (pk, value) as (
select 1, 'The quick brown fox jumps over the lazy dog' from dual union all
select 2, 'Yabba dabba doo' from dual union all
select 3, 'forty-two' from dual
),
v_queries (text) as (
select 'quick' from dual union all
select 'forty' from dual
)
select * from v_data d
where exists (
select null
from v_queries q
where d.value like '%' || q.text || '%');
If I have a string with numbers separated by commas, like this:
Declare #string varchar(20) = '123,456,789'
And would like to return every possible combination + sort order of the values by doing this:
Select Combination FROM dbo.GetAllCombinations(#string)
Which would in result return this:
123
456
789
123,456
456,123
123,789
789,123
456,789
789,456
123,456,789
123,789,456
456,789,123
456,123,789
789,456,123
789,123,456
As you can see not only is every combination returned, but also each combination+sort order as well. The example shows only 3 values separated by commas, but should parse any amount--Recursive.
The logic needed would be somewhere in the realm of using a WITH CUBE statement, but the problem with using WITH CUBE (in a table structure instead of CSV of course), is that it won't shuffle the order of the values 123,456 456,123 etc., and will only provide each combination, which is only half of the battle.
Currently I have no idea what to try. If someone can provide some assistance it would be appreciated.
I use a User Defined Table-valued Function called split_delimiter that takes 2 values: the #delimited_string and the #delimiter_type.
CREATE FUNCTION [dbo].[split_delimiter](#delimited_string VARCHAR(8000), #delimiter_type CHAR(1))
RETURNS TABLE AS
RETURN
WITH cte10(num) AS
(
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
)
,cte100(num) AS
(
SELECT 1
FROM cte10 t1, cte10 t2
)
,cte10000(num) AS
(
SELECT 1
FROM cte100 t1, cte100 t2
)
,cte1(num) AS
(
SELECT TOP (ISNULL(DATALENGTH(#delimited_string),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL))
FROM cte10000
)
,cte2(num) AS
(
SELECT 1
UNION ALL
SELECT t.num+1
FROM cte1 t
WHERE SUBSTRING(#delimited_string,t.num,1) = #delimiter_type
)
,cte3(num,[len]) AS
(
SELECT t.num
,ISNULL(NULLIF(CHARINDEX(#delimiter_type,#delimited_string,t.num),0)-t.num,8000)
FROM cte2 t
)
SELECT delimited_item_num = ROW_NUMBER() OVER(ORDER BY t.num)
,delimited_value = SUBSTRING(#delimited_string, t.num, t.[len])
FROM cte3 t;
Using that I was able to parse the CSV to a table and join it back to itself multiple times and use WITH ROLLUP to get the permutations you are looking for.
WITH Numbers as
(
SELECT delimited_value
FROM dbo.split_delimiter('123,456,789',',')
)
SELECT CAST(Nums1.delimited_value AS VARCHAR)
,ISNULL(CAST(Nums2.delimited_value AS VARCHAR),'')
,ISNULL(CAST(Nums3.delimited_value AS VARCHAR),'')
,CAST(Nums4.delimited_value AS VARCHAR)
FROM Numbers as Nums1
LEFT JOIN Numbers as Nums2
ON Nums2.delimited_value not in (Nums1.delimited_value)
LEFT JOIN Numbers as Nums3
ON Nums3.delimited_value not in (Nums1.delimited_value, Nums2.delimited_value)
LEFT JOIN Numbers as Nums4
ON Nums4.delimited_value not in (Nums1.delimited_value, Nums2.delimited_value, Nums3.delimited_value)
GROUP BY CAST(Nums1.delimited_value AS VARCHAR)
,ISNULL(CAST(Nums2.delimited_value AS VARCHAR),'')
,ISNULL(CAST(Nums3.delimited_value AS VARCHAR),'')
,CAST(Nums4.delimited_value AS VARCHAR) WITH ROLLUP
If you will potentially have more than 3 or 4, you'll want to expand your code accordingly.
I have some key values that I want to parse out of my SQL Server table. Here are some examples of these key values:
R50470B50469
B17699C88C68AM
R22818B17565C32G16SU
B1444
What I am wanting to get out of the string, is all the numbers that occur after the character 'B' but before any other letter character if it exists such as 'C'. How can I do this in SQL?
WITH VALS(Val) AS
(
SELECT 'R50470B50469' UNION ALL
SELECT 'R22818B17565C32G16SU' UNION ALL
SELECT 'R22818B17565C32G16SU' UNION ALL
SELECT 'B1444'
)
SELECT SUBSTRING(Tail,0,PATINDEX('%[AC-Z]%', Tail))
FROM VALS
CROSS APPLY
(SELECT RIGHT(Val, LEN(Val) - CHARINDEX('B', Val)) + 'X') T(Tail)
WHERE Val LIKE '%B%'
I Have a table that has a column that can have values like
Id FileNumber
------------------
1 0025
2 CDE01
3 0035
4 25
5 45
6 250
7 XYZ1
8 2500
Now if I want to select the row that has the FileNumber 25, how can I get that. I do not want the row that has 250 or 2500. The search should only get 0025 and 25. This column is of type varchar. However, I should be able to search by any value like XYZ1 OR 0025 OR 250
I tried using the Like operator eg: WHERE FileNumber Like '%25%' also tried WHERE FileNumber Like '25%' does not give me the desired results
Any help will be greatly appreciated
Based on the sample data, I'll assume the numbers you need to retrieve are integers. So you could cast them to integers if they are numeric using something like this:
CASE WHEN ISNUMERIC(s.col) = 1 THEN CAST(s.col AS INT) END
Example:
WITH sample AS (
SELECT '0025' AS col
UNION ALL
SELECT 'CDE01'
UNION ALL
SELECT '0035'
UNION ALL
SELECT '25'
UNION ALL
SELECT '45'
UNION ALL
SELECT '250'
UNION ALL
SELECT 'XYZ1'
UNION ALL
SELECT '2500')
SELECT CASE WHEN ISNUMERIC(s.col) = 1 THEN CAST(s.col AS INT) END
FROM sample s
You can use that in a derived table/inline view to compare against. It's possible you could add a computed column using the logic to the table.
You want anything that
matches exactly (25)
ends in with only leading zeroes) (0025)
This code does that with some LIKE matching
WITH sample AS (
SELECT '0025' AS col
UNION ALL SELECT 'CDE01'
UNION ALL SELECT '0035'
UNION ALL SELECT '25'
UNION ALL SELECT '45'
UNION ALL SELECT '250'
UNION ALL SELECT 'XYZ1'
UNION ALL SELECT 'XYZ125'
UNION ALL SELECT '125'
UNION ALL SELECT '2500')
SELECT
s.col
FROM
sample s
WHERE
col = '25'
OR
(REPLACE(col, '25', '00') NOT LIKE '%[^0]%' AND col LIKE '%25')
How about this?
SELECT * FROM [TABLE NAME]
WHERE FILENUMBER LIKE '%25'
Please use this to get all the rows from the table having the values that exactly matches the comma seprated values.
SELECT * FROM TABNAME WHERE FILENUMBER in ('25','0025','xyz')
It will select all the rows who contains the filenumber as 25 or 0025 or xyz.
If it's safe to fix the data...do that.
Try something like this
update
set filename = cast(filename as int)
where filename like '%[1-9]%' --has a number in it
and filename like '%[^a-z]%' -- doesn't have a letter in it