I Have a table that has a column that can have values like
Id FileNumber
------------------
1 0025
2 CDE01
3 0035
4 25
5 45
6 250
7 XYZ1
8 2500
Now if I want to select the row that has the FileNumber 25, how can I get that. I do not want the row that has 250 or 2500. The search should only get 0025 and 25. This column is of type varchar. However, I should be able to search by any value like XYZ1 OR 0025 OR 250
I tried using the Like operator eg: WHERE FileNumber Like '%25%' also tried WHERE FileNumber Like '25%' does not give me the desired results
Any help will be greatly appreciated
Based on the sample data, I'll assume the numbers you need to retrieve are integers. So you could cast them to integers if they are numeric using something like this:
CASE WHEN ISNUMERIC(s.col) = 1 THEN CAST(s.col AS INT) END
Example:
WITH sample AS (
SELECT '0025' AS col
UNION ALL
SELECT 'CDE01'
UNION ALL
SELECT '0035'
UNION ALL
SELECT '25'
UNION ALL
SELECT '45'
UNION ALL
SELECT '250'
UNION ALL
SELECT 'XYZ1'
UNION ALL
SELECT '2500')
SELECT CASE WHEN ISNUMERIC(s.col) = 1 THEN CAST(s.col AS INT) END
FROM sample s
You can use that in a derived table/inline view to compare against. It's possible you could add a computed column using the logic to the table.
You want anything that
matches exactly (25)
ends in with only leading zeroes) (0025)
This code does that with some LIKE matching
WITH sample AS (
SELECT '0025' AS col
UNION ALL SELECT 'CDE01'
UNION ALL SELECT '0035'
UNION ALL SELECT '25'
UNION ALL SELECT '45'
UNION ALL SELECT '250'
UNION ALL SELECT 'XYZ1'
UNION ALL SELECT 'XYZ125'
UNION ALL SELECT '125'
UNION ALL SELECT '2500')
SELECT
s.col
FROM
sample s
WHERE
col = '25'
OR
(REPLACE(col, '25', '00') NOT LIKE '%[^0]%' AND col LIKE '%25')
How about this?
SELECT * FROM [TABLE NAME]
WHERE FILENUMBER LIKE '%25'
Please use this to get all the rows from the table having the values that exactly matches the comma seprated values.
SELECT * FROM TABNAME WHERE FILENUMBER in ('25','0025','xyz')
It will select all the rows who contains the filenumber as 25 or 0025 or xyz.
If it's safe to fix the data...do that.
Try something like this
update
set filename = cast(filename as int)
where filename like '%[1-9]%' --has a number in it
and filename like '%[^a-z]%' -- doesn't have a letter in it
Related
I have the below Query. My Expected output would be as below. Please help me make changes to the Query
select
ID,TERM,
case
when TERM like '____1_' then
function_toget_hrs(ID, TERM,sysdate) else null
end fall_hours,
case
when TERM like '____2_' then
function_toget_hrs(ID, TERM,sysdate) else null
end winter_hours
from TABLE_TERM
where ID='12087762'
Expecting one row for each ID. Please help me the ways
Pivoting is what you need:
WITH TABLE_TERM AS
(
SELECT 12087762 AS ID, '202110____1_' AS term, 12 AS func FROM dual UNION ALL
SELECT 12087762 AS ID, '202120____2_' AS term, 16 FROM dual UNION ALL
SELECT 12087762 AS ID, '202140____1_' AS term, 0 FROM dual
)
SELECT *
FROM (SELECT ID
, DECODE(SUBSTR(term,-6),'____1_','fall_hours','winter_hours') AS hrs
, func --function_toget_hrs(ID, TERM,sysdate) for test purposes
FROM TABLE_TERM
WHERE ID = '12087762'
)
PIVOT (SUM(func) FOR hrs IN ('fall_hours','winter_hours'));
I have to test a column of a sql table for invalid values and for NULL.
Valid values are: Any number and the string 'n.v.' (with and without the dots and in every possible combination as listed in my sql command)
So far, I've tried this:
select count(*)
from table1
where column1 is null
or not REGEXP_LIKE(column1, '^[0-9,nv,Nv,nV,NV,n.v,N.v,n.V,N.V]+$');
The regular expression also matches the single character values 'n','N','v','V' (with and without a following dot). This shouldn't be the case, because I only want the exact character combinations as written in the sql command to be matched. I guess the problem has to do with using REGEXP_LIKE. Any ideas?
I guess this regexp will work:
NOT REGEXP_LIKE(column1, '^([0-9]+|n\.?v\.?)$', 'i')
Note that , is not a separator, . means any character, \. means the dot character itself and 'i' flag could be used to ignore case instead of hard coding all combinations of upper and lower case characters.
No need to use regexp (performance will increase by large data) - plain old TRANSLATE is good enough for your validation.
Note that the first translate(column1,'x0123456789','x') remove all numeric charcters from the string, so if you end with nullthe string is OK.
The second translate(lower(column1),'x.','x') removes all dots from the lowered string so you expect the result nv.
To avoid cases as n.....v.... you also limit the string length.
select
column1,
case when
translate(column1,'x0123456789','x') is null or /* numeric string */
translate(lower(column1),'x.','x') = 'nv' and length(column1) <= 4 then 'OK'
end as status
from table1
COLUMN1 STATUS
--------- ------
1010101 OK
1012828n
1012828nv
n.....v....
n.V OK
Test data
create table table1 as
select '1010101' column1 from dual union all -- OK numbers
select '1012828n' from dual union all -- invalid
select '1012828nv' from dual union all -- invalid
select 'n.....v....' from dual union all -- invalid
select 'n.V' from dual; -- OK nv
You can use:
select count(*)
from table1
WHERE TRANSLATE(column1, ' 0123456789', ' ') IS NULL
OR LOWER(column1) IN ('nv', 'n.v', 'nv.', 'n.v.');
Which, for the sample data:
CREATE TABLE table1 (column1) AS
SELECT '12345' FROM DUAL UNION ALL
SELECT 'nv' FROM DUAL UNION ALL
SELECT 'NV' FROM DUAL UNION ALL
SELECT 'nV' FROM DUAL UNION ALL
SELECT 'n.V.' FROM DUAL UNION ALL
SELECT '...................n.V.....................' FROM DUAL UNION ALL
SELECT '..nV' FROM DUAL UNION ALL
SELECT 'n..V' FROM DUAL UNION ALL
SELECT 'nV..' FROM DUAL UNION ALL
SELECT 'xyz' FROM DUAL UNION ALL
SELECT '123nv' FROM DUAL;
Outputs:
COUNT(*)
5
or, if you want any quantity of . then:
select count(*)
from table1
WHERE TRANSLATE(column1, ' 0123456789', ' ') IS NULL
OR REPLACE(LOWER(column1), '.') = 'nv';
Which outputs:
COUNT(*)
9
db<>fiddle here
I have column with below data:
Change
18 MCO-005329
A ECO-12239
0 ECO-25126
X1 ECO-05963
NA MCO-003778
C ECO-08399
MCO-003759
ECO-00643217
NULL
I want to extract the output like below:
MCO-005329
ECO-12239
ECO-25126
ECO-05963
MCO-003778
ECO-08399
MCO-003759
ECO-00643217
I have implemented the code like below:
select DISTINCT change,
case when change like 'MCO%' THEN change when change like 'ECO-%' THEN change
when change like '%MCO-%' then LTRIM(RTRIM(SUBSTRING(change,10,19) ))
when change like '%ECO-%' then LTRIM(RTRIM(SUBSTRING(change,10,19) ))
else '' end x from table
You can parse out the values from your requirements using SPLIT_STRING, outer apply, and a simple where clause without relying on hard coding any specific string length or position values, its dynamic.
SELECT D2.*
FROM
(
select '18 MCO-005329'
union select 'A ECO-12239'
union select '0 ECO-25126'
union select 'X1 ECO-05963'
union select 'NA MCO-003778'
union select 'C ECO-08399'
union select 'MCO-003759'
union select 'ECO-00643217'
union select NULL
) T(Change)
outer apply
(
select value
from
string_split(Change, ' ') d
) d2
where d2.value like '%-%' or d2.value is null
If you dont want nulls then smiply remove or d2.value is null
https://learn.microsoft.com/en-us/sql/t-sql/queries/from-transact-sql?view=sql-server-ver15
https://learn.microsoft.com/en-us/sql/t-sql/functions/string-split-transact-sql?view=sql-server-ver15
You could use CHARINDEX() and RIGHT() as
SELECT *, RIGHT(Change, CHARINDEX('-', REVERSE(Change)) + 3)
FROM
(
VALUES
('18 MCO-005329'),
('A ECO-12239'),
('0 ECO-25126'),
('X1 ECO-05963'),
('NA MCO-003778'),
('C ECO-08399'),
('MCO-003759'),
('ECO-00643217'), ('hhh kkk-k'),
(NULL)
) T(Change)
In H2 Database when i have applied order by on varchar column Numbers are coming first then Alphabets. But need to come Alphabets first then Numbers.
I have tried with
ORDER BY IF(name RLIKE '^[a-z]', 1, 2), name
but getting error like If condition is not available in H2.
My Column Data is Like
A
1-A
3
M
2-B
5
B-2
it should come like
A
B-2
M
1-A
2-B
3
5
try this out
SELECT MYCOLUMN FROM MYTABLE ORDER BY REGEXP_REPLACE (MYCOLUMN,'(*)(\d)(*)','}\2') , MYCOLUMN
One thing can be done is by altering the ASCII in order by clause.
WITH tab
AS (SELECT 'A' col FROM DUAL
UNION ALL
SELECT '1-A' FROM DUAL
UNION ALL
SELECT '3' FROM DUAL
UNION ALL
SELECT 'M' FROM DUAL
UNION ALL
SELECT '2-B' FROM DUAL
UNION ALL
SELECT '5' FROM DUAL
UNION ALL
SELECT 'B-2' FROM DUAL)
SELECT col
FROM tab
ORDER BY CASE WHEN SUBSTR (col, 1, 1) < CHR (58) THEN CHR (177) || col ELSE col END;
I have Used CHR(58) as ASCII value of numbers end at 57. and CHR(177) is used as this is the maximum in the ASCII table.
FYR : ASCII table
Given the example dataset, I'm not sure if you need further logic than this- so I'll refrain from making further assumptions:
DECLARE #temp TABLE (myval char(3))
INSERT INTO #temp VALUES
('A'), ('1-A'), ('3'), ('M'), ('2-B'), ('5'), ('B-2')
SELECT myval
FROM #temp
ORDER BY CASE WHEN LEFT(myval, 1) LIKE '[a-Z]'
THEN 1
ELSE 2
END
,LEFT(myval, 1)
Gives output:
myval
A
B-2
M
1-A
2-B
3
5
Query:
select *
from etm
where emp_id LIKE '009090%'
AND directnumber LIKE '111 123 12345x 67%'
AND cellnumber LIKE '123456789%'
AND phone LIKE '111 123 12345x 67';
database: oracle 11g
Select query doesn't return any records when the LIKE operator has small X character (12345x) in it.
When I replace it with any other character (small/capital) it works ((12345Y)), but replacing it with the small x also does not work.
I cannot modify the query, is there anything can be done at database level while inserting the data?
we are importing data in bulk.
I can't see an issue - here's a test case to demonstrate:
with sample_data as (select '123x 456' str from dual union all
select '123 456' str from dual union all
select '123x' str from dual union all
select 'abcx 93s' str from dual)
select *
from sample_data
where str like '123x%';
STR
--------
123x 456
123x
So, you can see my search has pulled back rows where the str column starts with 123x.
However, if I search for rows starting with 123y then no rows are returned:
with sample_data as (select '123x 456' str from dual union all
select '123 456' str from dual union all
select '123x' str from dual union all
select 'abcx 93s' str from dual)
select *
from sample_data
where str like '123y%';
no rows selected.
since there are no rows where the str column starts with 123y.
Is it a similar case with your data, where there aren't any rows that match all the filter conditions when you have an x in one or more of the like conditions?
I haven't verified this query but it should work.
select *
from etm
where emp_id LIKE '009090%'
AND (directnumber LIKE '111%' or directnumber LIKE '123%' .....)
AND cellnumber LIKE '123456789%'
AND (phone LIKE '111' or phone LIKE '123' .......);
Reference :
https://community.oracle.com/thread/1096523?start=0&tstart=0