Partition the date into a weeks from a given date to the last date in the record - sql

Question

I wanted to count the time gap between two rows for the same id if the second is less than an hour after the first, and partition the count for the week.
Suppose given date with time is 2020-07-01 08:00
create table #Temp (
Id integer not null,
Time datetime not null
);
insert into #Temp values (1, '2020-07-01 08:00');
insert into #Temp values (1, '2020-07-01 08:01');
insert into #Temp values (1, '2020-07-01 08:06');
insert into #Temp values (1, '2020-07-01 08:30');
insert into #Temp values (1, '2020-07-08 09:35');
insert into #Temp values (1, '2020-07-15 16:10');
insert into #Temp values (1, '2020-07-15 16:20');
insert into #Temp values (1, '2020-07-17 06:40');
insert into #Temp values (1, '2020-07-17 06:41');
insert into #Temp values (2, '2020-07-01 08:30');
insert into #Temp values (2, '2020-07-01 09:26');
insert into #Temp values (2, '2020-07-01 10:25');
insert into #Temp values (2, '2020-07-09 08:30');
insert into #Temp values (2, '2020-07-09 09:26');
insert into #Temp values (2, '2020-07-09 10:25');
insert into #Temp values (3, '2020-07-21 08:30');
insert into #Temp values (3, '2020-07-21 09:26');
insert into #Temp values (3, '2020-07-21 10:25');
The week should extend up to the last date in the record. Here, the last date is
2020-07-21 10:25
Have to transform the output from this piece of code and divide the duration weekly.
select Id, sum(datediff(minute, Time, next_ts)) as duration_minutes
from (select t.*,
lead(Time) over (partition by id order by Time) as next_ts
from #Temp t
) t
where datediff(minute, Time, next_ts) < 60
group by Id;
Output:
id duration_minutes
1 41
2 230
3 115
The desired output should divide this duration on a weekly basis,
like Week 1, Week 2, Week 3, and so on.
Desired Output:
If the
start date is 2020-07-01 08:00
end date is 2020-07-21 10:25
id | Week 1 | Week 2 | Week 3
--------------------------------------
1 | 30 | 0 | 11
2 | 115 | 115 | 0
3 | 0 | 0 | 115
similarly, if the
start date is 2020-07-08 08:00
id | Week 1 | Week 2
---------------------------
1 | 11 | 0
2 | 115 | 0
3 | 0 | 115

Answer 1

Is this what you want?
select Id,
1 + datediff(second, '2020-07-01 06:00', time) / (24 * 60 * 60 * 7) as week_num,
sum(datediff(minute, Time, next_ts)) as duration_minutes
from (select t.*,
lead(Time) over (partition by id order by Time) as next_ts
from Temp t
) t
where datediff(minute, Time, next_ts) < 60
group by Id, datediff(second, '2020-07-01 06:00', time) / (24 * 60 * 60 * 7)
order by id, week_num;
Here is a db<>fiddle.

Answer 2

I am not able to understand the logic behind the week periods. Anyone, in the example below I am using the following code to set the week:
'Week ' + CAST(DENSE_RANK() OVER (ORDER BY DATEDIFF(DAY, #FirstDate, next_ts) / 7) AS VARCHAR(12))
You can adjust it to ignore the ours, be more precise or something else to match your real requirements.
Apart from that, you just need to perform a dynamic PIVOT. Here is the full working example:
DROP TABLE IF EXISTS #Temp;
create table #Temp (
Id integer not null,
Time datetime not null
);
insert into #Temp values (1, '2020-07-01 08:00');
insert into #Temp values (1, '2020-07-01 08:01');
insert into #Temp values (1, '2020-07-01 08:06');
insert into #Temp values (1, '2020-07-01 08:30');
insert into #Temp values (1, '2020-07-08 09:35');
insert into #Temp values (1, '2020-07-15 16:10');
insert into #Temp values (1, '2020-07-15 16:20');
insert into #Temp values (1, '2020-07-17 06:40');
insert into #Temp values (1, '2020-07-17 06:41');
insert into #Temp values (2, '2020-07-01 08:30');
insert into #Temp values (2, '2020-07-01 09:26');
insert into #Temp values (2, '2020-07-01 10:25');
insert into #Temp values (2, '2020-07-09 08:30');
insert into #Temp values (2, '2020-07-09 09:26');
insert into #Temp values (2, '2020-07-09 10:25');
insert into #Temp values (3, '2020-07-21 08:30');
insert into #Temp values (3, '2020-07-21 09:26');
insert into #Temp values (3, '2020-07-21 10:25');
DROP TABLE IF EXISTS #TEST
CREATE TABLE #TEST
(
[ID] INT
,[week_day] VARCHAR(12)
,[time_in_minutes] BIGINT
)
DECLARE #FirstDate DATE;
SELECT #FirstDate = MIN(Time)
FROM #Temp
INSERT INTO #TEST
select id
,'Week ' + CAST(DENSE_RANK() OVER (ORDER BY DATEDIFF(DAY, #FirstDate, next_ts) / 7) AS VARCHAR(12))
,datediff(minute, Time, next_ts)
from (select t.*,
lead(Time) over (partition by id order by Time) as next_ts
from #Temp t
) t
where datediff(minute, Time, next_ts) < 60
DECLARE #columns NVARCHAR(MAX);
SELECT #columns = STUFF
(
(
SELECT ',' + QUOTENAME([week_day])
FROM
(
SELECT DISTINCT CAST(REPLACE([week_day], 'Week ', '') AS INT)
,[week_day]
FROM #TEST
) DS ([rowID], [week_day])
ORDER BY [rowID]
FOR XML PATH(''), TYPE
).value('.', 'VARCHAR(MAX)')
,1
,1
,''
);
DECLARE #DanymicSQL NVARCHAR(MAX);
SET #DanymicSQL = N'
SELECT [ID], ' + #columns + '
FROM #TEST
PIVOT
(
SUM([time_in_minutes]) FOR [week_day] IN (' + #columns + ')
) PVT';
EXEC sp_executesql #DanymicSQL;