How to call API method that accepts XML in ASP.NET Core Web APIs? - api

Question

The API Method I am calling is:
[HttpPost("PostXml")]
[Consumes("application/xml")]
[Produces("application/xml")]
public Reservation PostXml([FromBody] Reservation res) =>
repository.AddReservation(new Reservation
{
Name = res.Name,
StartLocation = res.StartLocation,
EndLocation = res.EndLocation
});
The client code:
[HttpPost]
public async Task<IActionResult> AddReservationByXml(Reservation reservation)
{
Reservation receivedReservation = new Reservation();
using (var httpClient = new HttpClient())
{
StringContent content = new StringContent(ConvertObjectToXMLString(reservation), Encoding.UTF8, "application/xml");
using (var response = await httpClient.PostAsync("http://localhost:8888/api/Reservation/PostXml", content))
{
string apiResponse = await response.Content.ReadAsStringAsync();
receivedReservation = JsonConvert.DeserializeObject<Reservation>(apiResponse);
}
}
return View(receivedReservation);
}
string ConvertObjectToXMLString(object classObject)
{
string xmlString = null;
XmlSerializer xmlSerializer = new XmlSerializer(classObject.GetType());
using (MemoryStream memoryStream = new MemoryStream())
{
xmlSerializer.Serialize(memoryStream, classObject);
memoryStream.Position = 0;
xmlString = new StreamReader(memoryStream).ReadToEnd();
}
return xmlString;
}
I am failing to call the API method and getting the error:
400One or
more validation errors
occurred.https://tools.ietf.org/html/rfc7231#section-6.5.1|f5452728-4c49abe4d88e559e.1.8095e7c1_An
error occurred while deserializing input
data.
What is wrong here?

Answer 1

You got error from this line
receivedReservation = JsonConvert.DeserializeObject<Reservation>(apiResponse);
Please check the validation of your Reservation Model and detail the values you past
and the content of error you got.

Answer 2

Your XML request should be with the correct case as the c# class. XML is case sensitive.
Try this code.
XmlSerializer xsSubmit = new XmlSerializer(typeof(Reservation));
System.IO.StringWriter sww = new System.IO.StringWriter();
XmlWriter writer = XmlWriter.Create(sww);
xsSubmit.Serialize(writer, reservation);
var xml = sww.ToString();