Kotlin short-cut to assign value to variable using stream function or other - kotlin

Question

for (i in 0 until result.size){ result[i].config= addConfig(taskNames!![i],processKeys!![i]) }
Here result is a list of class which has datamember config and tasNames and processKeys are list of string.
Is there a way in kotlin to map result.config with respective taskNames and processKeys without using traditional loop and mentioning length of result.I am new to kotlin.
class Process {
var processKey: String? = null
var task: List<Task>? = null}
class Task {
var taskName: String? = null
var processVariables: List<ProcessVariable>? = null}
class ProcessVariable {
var name: String? = null
var label: String? = null
var applicableValue: List<String>? = null}
Result is already present with datamember config pf type ProcessVariable

Answer 1

If I understand your problem correctly, you need to combine 3 lists.
So iterating over the lists may be easier to understand than some clever way of list transformations.
You can get rid of the traditional for loop, so you don't need to calculate the size of the loop:
result.forEachIndexed {
i, resultData -> resultData.config = addConfig(taskNames[i], processKeys[i])
}
If you want to combine two lists, you can use the zip method:
val configList = taskNames.zip(processKeys) {tsk, prc -> addConfig(tsk, prc)}
In your example, the result-object was already existing. Maybe it is easier to create new result-objects:
val results = configList.map {
Result(config = it)
}