How to correct error when aggregating from subquery - sql

I have a query that looks like this:
SELECT store_id,
(CASE WHEN txns_A>0 AND txns_B=0 THEN 'A Only' WHEN txns_A=0 AND txns_B>0 THEN 'B Only' END) A_B_indicator,
sum(1) cnt_customers,
sum(spend_A+spend_B)/sum(txns_A+txns_B) avg_receipt
FROM(
SELECT store_id, cust_id
SUM(CASE WHEN A_B_indicator='A' THEN spend else 0 end) spend_A,
SUM(CASE WHEN A_B_indicator='B' THEN spend else 0 end) spend_B,
SUM(CASE WHEN A_B_indicator='A' THEN spend else 0 end) txns_A,
SUM(CASE WHEN A_B_indicator='B' THEN spend else 0 end) txns_B
FROM table1
GROUP BY store_id, cust_id
) table2;
However, this generates an error because store_id is not in a GROUP BY clause. When I rewrite the query to include a GROUP BY store_id clause, it complains that the aggregate columns are not in the Group By. However, if I add them by rewriting the Group By to be Group BY 1,2,3,4, this also generates an error (Not yet supported place for UDAF Sum).
How can I rewrite this query to be error-free?

You can write this as:
SELECT store_id,
(CASE WHEN SUM(txns_A) > 0 AND SUM(txns_B) = 0 THEN 'A Only'
WHEN SUM(txns_A) = 0 AND SUM(txns_B) > 0 THEN 'B Only'
END) as A_B_indicator,
COUNT(*) as cnt_customers,
SUM(spend_A+spend_B)/sum(txns_A+txns_B) as avg_receipt
FROM (SELECT store_id, cust_id
SUM(CASE WHEN A_B_indicator='A' THEN spend else 0 end) as spend_A,
SUM(CASE WHEN A_B_indicator='B' THEN spend else 0 end) as spend_B,
SUM(CASE WHEN A_B_indicator='A' THEN spend else 0 end) as txns_A,
SUM(CASE WHEN A_B_indicator='B' THEN spend else 0 end) as txns_B
FROM table1
GROUP BY store_id, cust_id
) table2
GROUP BY store_id;

Related

SUM value when another column value is DISTINCT

I was wondering how I can SUM the values of a column based on another column's values being distinct like below. I tried the following two ways, each giving errors due to the aggregate function. I am trying to get NonDistinctTotals with the queries below.
SELECT SUM(InvoiceSaleAmt) AS NonDistinctTotals, SUM(case when count(*) over (partition by InvoiceNo) = 1 then InvoiceSaleAmt else 0 END) as DistinctTotals, SUM(CASE WHEN PaymentType= 'CASH' THEN CashTotal ELSE 0 END) AS CashTotal
FROM #InvoiceTable a
group by LocationId, InvoiceNo
Error: Windowed functions cannot be used in the context of another windowed function or aggregate.
SELECT SUM(InvoiceSaleAmt) AS NonDistinctTotals, SUM(CASE WHEN InvoiceNoin (SELECT DISTINCT InvoiceNofrom #InvoiceTable) THEN InvoiceSaleAmt else 0 END) as DistinctTotals, SUM(CASE WHEN PaymentType= 'CASH' THEN CashTotal ELSE 0 END) AS CashTotal
FROM #InvoiceTable a
group by LocationId, InvoiceNo
Error: Cannot perform an aggregate function on an expression containing an aggregate or a subquery.
Use a subquery:
SELECT SUM(InvoiceSaleAmt) AS NonDistinctTotals,
SUM(case when cnt = 1 then InvoiceSaleAmt else 0 END) as DistinctTotals,
SUM(CASE WHEN PaymentType = 'CASH' THEN CashTotal ELSE 0 END) AS CashTotal
FROM (SELECT it.*, COUNT(*) over (partition by InvoiceNo) as cnt
FROM #InvoiceTable it
) it
GROUP BY LocationId, InvoiceNo

Group by in sql for two conditions

I have this table
SELECT
[WeldStatus]
,PackageId
FROM [SPMS2].[dbo].[JointHistory]
How can I group by this query to calculate total testpackage and total accept and total remain?
For example for packageid=6030 I need this:
packageid total accept remain
6030 4 3 1
Use CASE and Group By
SELECT
PackageId,
count(*) as total,
sum(case [WeldStatus] when 'Accept' then 1 end) as accept,
sum(case [WeldStatus] when 'accept' then 0 else 1 end) as remain
FROM [SPMS2].[dbo].[JointHistory]
group by PackageId;
SELECT
packageid
,count(*) as 'total'
,sum(case when weldstatus = 'Accept' then 1 else 0 end) as 'accept'
,sum(case when weldstatus is null then 1 else 0 end) as 'remain'
FROM [SPMS2].[dbo].[JointHistory]
group by packageid
"sum(case when..." has saved me so many times. NULLs can be a pain but the case when saves you.
You can use CASE expression with in your aggregation to achieve your desired output.
SELECT
PackageId,
SUM (CASE WHEN WeldStatus = 'Accept' THEN 1 ELSE 0 END) AS AcceptCount,
SUM (CASE WHEN WeldStatus IS NULL THEN 1 ELSE 0 END) AS RemainCount,
COUNT (*) AS Total
FROM [SPMS2].[dbo].[JointHistory]
GROUP BY PackageId
select packageid, SUM(TOTAL), SUM(ACCEPT), SUM(REMAIN) from (
select packageid, 1 as TOTAL,
case
when WeldStatus='Accept' then 1 else 0
END as ACCEPT,
case
when WeldStatus IS NULL then 1 else 0
END as REMAIN
from JointHistory
) group by packageid
If WeldStatus only takes on the values of 'Accept' or NULL, then a simple method is:
SELECT PackageId, count(*) as total,
count(WeldStatus) as accept,
count(*) - count(WeldStatus) as remain
FROM [SPMS2].[dbo].[JointHistory] jh
GROUP BY PackageId;
I'm the first to admit that this relies on the assumption of having a single value or NULL.
SELECT PackageId,
COUNT(*) AS total,
SUM(CASE WHEN [WeldStatus] = 'Accept' THEN 1 END) AS accept,
SUM(CASE WHEN ISNULL([WeldStatus],'') = '' THEN 1 ELSE 0 END) AS remain
FROM [SPMS2].[dbo].[JointHistory]
group by PackageId;

Update a complex SQL query to add a new column with the sum of two columns

The below SQL query creates a table with n number of columns named in the next line.
...., curr_amount, tax_amount, ....
I am having a very tough time updating the below query to create a new column called total and position it exactly after tax_amount column and the total column should contain the values that are obtained after sum of curr_amount & tax_amount.
I have been working on this from more than one day but couldn't figure it out.
P.S. Still a noob here. Thanks alot for your time.
.
SELECT Isnull(t.total_month, 'Total') total_month,
t.tax_amount,
t.curr_amount,
t.usage_qty,
t.kh_qty,
t.bill_cnt
FROM (SELECT dbo.Sigmadf(bm.posted_date, 'YYYY-MM') total_month,
Sum(CASE
WHEN rr.usage_qty IS NULL THEN 0
ELSE Cast (rr.usage_qty AS NUMERIC(18, 2))
END) usage_qty,
Sum(CASE
WHEN bm.curr_amount IS NULL THEN 0
ELSE bm.curr_amount
END) curr_amount,
Sum(CASE
WHEN bm.adj_amount IS NULL THEN 0
ELSE bm.adj_amount
END) adj_amount,
Sum(CASE
WHEN bm.bal_fwd_amount IS NULL THEN 0
ELSE bm.bal_fwd_amount
END) bal_forward,
Sum(CASE
WHEN bm.tax_amount IS NULL THEN 0
ELSE bm.tax_amount
END) tax_amount,
Sum(CASE
WHEN bm.due_amount IS NULL THEN 0
ELSE bm.due_amount
END) due_amount,
Sum(CASE
WHEN bm.last_total_paid_amount IS NULL THEN 0
ELSE bm.last_total_paid_amount * -1
END) paid_amount,
Sum(CASE
WHEN bm.bill_print = 'Y' THEN 1
ELSE 0
END) pdf_cnt,
Sum(CASE
WHEN Isnull(bm.bill_handling_code, '0') = '0' THEN 1
ELSE 0
END) reg_cnt,
Sum(CASE
WHEN Isnull(bm.bill_handling_code, '0') = '1' THEN 1
ELSE 0
END) ftime_cnt,
Sum(CASE
WHEN Isnull(bm.bill_handling_code, '0') = '9999' THEN 1
ELSE 0
END) ltime_cnt,
Count(*) bill_cnt,
Sum(CASE
WHEN bill_status = '01' THEN 1
ELSE 0
END) canc_cnt,
Sum(CASE
WHEN bill_status = '01' THEN
CASE
WHEN rr.usage_qty IS NULL THEN 0
ELSE Cast (rr.usage_qty AS NUMERIC(18, 2))
END
ELSE 0
END) canc_usg,
Sum(CASE
WHEN vis.kh_qty IS NULL THEN 0
ELSE Cast(vis.kh_qty AS NUMERIC(18, 2))
END) kh_qty
FROM bill_master bm WITH (nolock)
INNER JOIN (SELECT bill_no,
Sum(CASE
WHEN vpb.recurr_charge_type IN ( 'T4',
'SLF' )
THEN
CASE
WHEN vpb.print_qty = 'Y'
AND vpb.usage_qty IS NOT NULL
THEN
Cast (vpb.usage_qty AS
NUMERIC(18, 2))
ELSE 0
END
ELSE 0
END) usage_qty
FROM v_print_bills_all vpb
GROUP BY bill_no) rr
ON rr.bill_no = bm.bill_no
LEFT OUTER JOIN vis_bill_master_cr vis WITH (nolock)
ON bm.bill_no = vis.bill_no
WHERE 1 = 1
AND dbo.Trunc(bm.posted_date) >= '20150101'
AND dbo.Trunc(bm.posted_date) <= '20151124'
AND bm.posted_date IS NOT NULL
AND bm.cust_id NOT IN (SELECT cc.code_type cust_id
FROM code_table cc WITH (nolock)
WHERE cc.code_tabname = 'RptExclCust'
AND cc.code_value = 'cust_id')
GROUP BY dbo.Sigmadf(bm.posted_date, 'YYYY-MM') WITH rollup)t
I must say that the explanation is not so clear.
From my understanding, you want the total of two columns.
So, wrap all your query between parenthesis, call it subQuery, and make the sum of the two columns on top:
SELECT subQuery.total_month as bill_date,
subQuery.curr_amount as amount,
subQuery.tax_amount tax,
subQuery.curr_amount + subQuery.tax_amount as [total],
...
FROM
(..your entire query here..) as subQuery

Same part of a subquery in multiple select

I have a table like this
TABLEMAIN
Q1 Name Group Zone Month Type
1 'N1' 'G1' 'Z1' 12 'T1'
4 'N1' 'G3' 'Z2' 12 'T6'
6 'N1' 'G1' 'Z5' 12 'T2'
3 'N2' 'G4' 'Z5' 12 'T4'
.
.
.
And I have something like this to get certain results
Query1:
select
(SUM(CASE Q1>=2 and Q1<=4 THEN 1 ELSE 0 END)) TOTAL,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T1TYPE,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T2TYPE,
Type,
**Zone,**
Month
from
TABLEMAIN
GROUP BY Type, **Zone,** Month;
Query2:
select
(SUM(CASE Q1>=2 and Q1<=4 THEN 1 ELSE 0 END)) TOTAL,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T1TYPE,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T2TYPE,
Type,
**Group,**
Month
from
TABLEMAIN
GROUP BY Type, **Group,** Month;
As you can see I group this table many times in many ways, but this part is the same in every query
select
(SUM(CASE Q1>=2 and Q1<=4 THEN 1 ELSE 0 END)) TOTAL,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T1TYPE,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T2TYPE,
Is there a better way to do this? I'm not sure if I can use a materialized view for this
Perhaps. You can do it all in one query, if you like by using grouping sets:
select SUM(CASE Q1>=2 and Q1<=4 THEN 1 ELSE 0 END) as TOTAL,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) as T1TYPE,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) as T2TYPE
Type, **Zone,**, **Group,** Month
from TABLEMAIN
GROUP BY GROUPING SETS((Type, **Zone,** Month), (Type, **Group,** Month));
This puts all the results in a single table.
I second with #GolezTrol comment. Would like to explain further.
SUBQUERY FACTORING is what you need. The WITH clause, or subquery factoring clause, is part of the SQL-99 standard and was added into the Oracle SQL syntax in Oracle 9.2. The WITH clause may be processed as an inline view or resolved as a temporary table. The advantage of the latter is that repeated references to the subquery may be more efficient as the data is easily retrieved from the temporary table, rather than being required by each reference.
WITH data AS(
<your subquery>
)
SELECT * FROM data
bla bla bla...

Multiple Sums off Same Column

I need this select query to return the sum of the same column based on different where clauses. Basically just looking for a way to merge these multiple select queries. Please see below. Any help is very much appreciated!
DECLARE #prEndDate smalldatetime
SET #prEndDate='2014-01-05'
SELECT Employee, SUM(Amount) as Deduction
FROM bPRDT
WHERE PREndDate=#prEndDate
AND EDLCode=100 AND EDLType='D'
GROUP BY Employee
SELECT Employee, SUM(Amount) as DeductionPlus
FROM bPRDT
WHERE PREndDate=#prEndDate
AND EDLCode=101 AND EDLType='D'
GROUP BY Employee
SELECT Employee, SUM(Amount) as Match
FROM bPRDT
WHERE PREndDate=#prEndDate
AND EDLCode=600 AND EDLType='L'
GROUP BY Employee
SELECT Employee, SUM(Amount) as MatchPlus
FROM bPRDT
WHERE PREndDate=#prEndDate
AND EDLCode=601 AND EDLType='L'
GROUP BY Employee
Finally fixed. Here's what it ended up being:
DECLARE #prEndDate smalldatetime
SET #prEndDate ='2013-12-29'
SELECT
REPLACE(c.SSN,'-',''),
SUM(CASE WHEN a.EDLType='D' AND a.Amount > 0 AND (a.EDLCode=100 OR a.EDLCode=101) THEN a.Amount ELSE 0 END) AS Deferral,
SUM(CASE WHEN a.EDLType='L' AND a.Amount > 0 AND (a.EDLCode=600 OR a.EDLCode=601) THEN a.Amount ELSE 0 END) AS EmployerMatch,
SUM(CASE WHEN a.EDLType='D' AND a.Amount > 0 AND (a.EDLCode=100 OR a.EDLCode=101) THEN a.SubjectAmt ELSE 0 END) AS Compensation415,
SUM(CASE WHEN a.EDLType='D' AND a.Amount > 0 AND (a.EDLCode=100 OR a.EDLCode=101) THEN a.SubjectAmt ELSE 0 END) AS PlanFullYearCompensation,
SUM(CASE WHEN a.EDLType='E' AND a.Amount > 0 AND (a.EDLCode=1 OR a.EDLCode=2 OR a.EDLCode=3) THEN a.Hours ELSE 0 END) AS PlanHours
FROM bPRDT a
JOIN (SELECT DISTINCT SSN, Employee FROM bPREH) c ON a.Employee=c.Employee
WHERE a.PREndDate=#prEndDate
GROUP BY c.SSN
ORDER BY Deferral DESC, c.SSN ASC
You could use UNION or CASE WHEN clauses.
SELECT
Employee,
SUM(CASE WHEN EDLCode=100 AND EDLType='D' THEN Amount ELSE 0 END) as Deduction,
SUM(CASE WHEN EDLCode=101 AND EDLType='D' THEN Amount ELSE 0 END) as DeductionPlus
SUM(CASE WHEN EDLCode=600 AND EDLType='L' THEN Amount ELSE 0 END) as Match
SUM(CASE WHEN EDLCode=601 AND EDLType='L' THEN Amount ELSE 0 END) as MatchPlus
FROM bPRDT
WHERE PREndDate=#prEndDate
GROUP BY Employee
You can move the condition out of the WHERE clause and in to a CASE statement, so you only sum the rows that interest you:
DECLARE #prEndDate smalldatetime
SET #prEndDate='2014-01-05'
SELECT Employee,
SUM(CASE WHEN EDLCode=100 AND EDLType='D' THEN amount ELSE 0 END)
AS Deduction,
SUM(CASE WHEN EDLCode=101 AND EDLType='D' THEN amount ELSE 0 END)
AS DeductionPlus,
SUM(CASE WHEN EDLCode=600 AND EDLType='L' THEN amount ELSE 0 END)
AS Match,
SUM(CASE WHEN EDLCode=601 AND EDLType='L' THEN amount ELSE 0 END)
AS MatchPlus
FROM bPRDT
WHERE PREndDate = #prEndDate
GROUP BY Employee
Group by Employee,EDLCode,EDLType instead of just Employee.