I have this table
SELECT
[WeldStatus]
,PackageId
FROM [SPMS2].[dbo].[JointHistory]
How can I group by this query to calculate total testpackage and total accept and total remain?
For example for packageid=6030 I need this:
packageid total accept remain
6030 4 3 1
Use CASE and Group By
SELECT
PackageId,
count(*) as total,
sum(case [WeldStatus] when 'Accept' then 1 end) as accept,
sum(case [WeldStatus] when 'accept' then 0 else 1 end) as remain
FROM [SPMS2].[dbo].[JointHistory]
group by PackageId;
SELECT
packageid
,count(*) as 'total'
,sum(case when weldstatus = 'Accept' then 1 else 0 end) as 'accept'
,sum(case when weldstatus is null then 1 else 0 end) as 'remain'
FROM [SPMS2].[dbo].[JointHistory]
group by packageid
"sum(case when..." has saved me so many times. NULLs can be a pain but the case when saves you.
You can use CASE expression with in your aggregation to achieve your desired output.
SELECT
PackageId,
SUM (CASE WHEN WeldStatus = 'Accept' THEN 1 ELSE 0 END) AS AcceptCount,
SUM (CASE WHEN WeldStatus IS NULL THEN 1 ELSE 0 END) AS RemainCount,
COUNT (*) AS Total
FROM [SPMS2].[dbo].[JointHistory]
GROUP BY PackageId
select packageid, SUM(TOTAL), SUM(ACCEPT), SUM(REMAIN) from (
select packageid, 1 as TOTAL,
case
when WeldStatus='Accept' then 1 else 0
END as ACCEPT,
case
when WeldStatus IS NULL then 1 else 0
END as REMAIN
from JointHistory
) group by packageid
If WeldStatus only takes on the values of 'Accept' or NULL, then a simple method is:
SELECT PackageId, count(*) as total,
count(WeldStatus) as accept,
count(*) - count(WeldStatus) as remain
FROM [SPMS2].[dbo].[JointHistory] jh
GROUP BY PackageId;
I'm the first to admit that this relies on the assumption of having a single value or NULL.
SELECT PackageId,
COUNT(*) AS total,
SUM(CASE WHEN [WeldStatus] = 'Accept' THEN 1 END) AS accept,
SUM(CASE WHEN ISNULL([WeldStatus],'') = '' THEN 1 ELSE 0 END) AS remain
FROM [SPMS2].[dbo].[JointHistory]
group by PackageId;
Related
I have a query that looks like this:
SELECT store_id,
(CASE WHEN txns_A>0 AND txns_B=0 THEN 'A Only' WHEN txns_A=0 AND txns_B>0 THEN 'B Only' END) A_B_indicator,
sum(1) cnt_customers,
sum(spend_A+spend_B)/sum(txns_A+txns_B) avg_receipt
FROM(
SELECT store_id, cust_id
SUM(CASE WHEN A_B_indicator='A' THEN spend else 0 end) spend_A,
SUM(CASE WHEN A_B_indicator='B' THEN spend else 0 end) spend_B,
SUM(CASE WHEN A_B_indicator='A' THEN spend else 0 end) txns_A,
SUM(CASE WHEN A_B_indicator='B' THEN spend else 0 end) txns_B
FROM table1
GROUP BY store_id, cust_id
) table2;
However, this generates an error because store_id is not in a GROUP BY clause. When I rewrite the query to include a GROUP BY store_id clause, it complains that the aggregate columns are not in the Group By. However, if I add them by rewriting the Group By to be Group BY 1,2,3,4, this also generates an error (Not yet supported place for UDAF Sum).
How can I rewrite this query to be error-free?
You can write this as:
SELECT store_id,
(CASE WHEN SUM(txns_A) > 0 AND SUM(txns_B) = 0 THEN 'A Only'
WHEN SUM(txns_A) = 0 AND SUM(txns_B) > 0 THEN 'B Only'
END) as A_B_indicator,
COUNT(*) as cnt_customers,
SUM(spend_A+spend_B)/sum(txns_A+txns_B) as avg_receipt
FROM (SELECT store_id, cust_id
SUM(CASE WHEN A_B_indicator='A' THEN spend else 0 end) as spend_A,
SUM(CASE WHEN A_B_indicator='B' THEN spend else 0 end) as spend_B,
SUM(CASE WHEN A_B_indicator='A' THEN spend else 0 end) as txns_A,
SUM(CASE WHEN A_B_indicator='B' THEN spend else 0 end) as txns_B
FROM table1
GROUP BY store_id, cust_id
) table2
GROUP BY store_id;
I was wondering how I can SUM the values of a column based on another column's values being distinct like below. I tried the following two ways, each giving errors due to the aggregate function. I am trying to get NonDistinctTotals with the queries below.
SELECT SUM(InvoiceSaleAmt) AS NonDistinctTotals, SUM(case when count(*) over (partition by InvoiceNo) = 1 then InvoiceSaleAmt else 0 END) as DistinctTotals, SUM(CASE WHEN PaymentType= 'CASH' THEN CashTotal ELSE 0 END) AS CashTotal
FROM #InvoiceTable a
group by LocationId, InvoiceNo
Error: Windowed functions cannot be used in the context of another windowed function or aggregate.
SELECT SUM(InvoiceSaleAmt) AS NonDistinctTotals, SUM(CASE WHEN InvoiceNoin (SELECT DISTINCT InvoiceNofrom #InvoiceTable) THEN InvoiceSaleAmt else 0 END) as DistinctTotals, SUM(CASE WHEN PaymentType= 'CASH' THEN CashTotal ELSE 0 END) AS CashTotal
FROM #InvoiceTable a
group by LocationId, InvoiceNo
Error: Cannot perform an aggregate function on an expression containing an aggregate or a subquery.
Use a subquery:
SELECT SUM(InvoiceSaleAmt) AS NonDistinctTotals,
SUM(case when cnt = 1 then InvoiceSaleAmt else 0 END) as DistinctTotals,
SUM(CASE WHEN PaymentType = 'CASH' THEN CashTotal ELSE 0 END) AS CashTotal
FROM (SELECT it.*, COUNT(*) over (partition by InvoiceNo) as cnt
FROM #InvoiceTable it
) it
GROUP BY LocationId, InvoiceNo
This question already has an answer here:
How to use an Alias in a Calculation for Another Field
(1 answer)
Closed 4 years ago.
select
category, count(category) as 'TotalCounts',
COUNT(case kind when 'avail'then 1 else null end) as 'avail',
Count(case kind when 'offers' then 1 else null end) as 'offers',
COUNT(CASE contactMethod WHEN 'SMS' then 1 else null END) as 'SMS',
COUNT(case contactMethod when 'call' then 1 else null end) as 'call',
CONVERT(varchar(254),COUNT (case when max_biz_status='A' OR
max_biz_status ='B' then 1 else null end) * 100 / count(category)) +'%'
as 'Percetange'
from reports
group by category
order by TotalCounts
Instead of calculating again in Convert method i want to use avail* 100 / TotalCounts like i did in order by when i used TotalCounts.
i tried:
CONVERT(varchar(254),avail * 100 / TotalCounts) +'%' as 'Percetange'
but i get 'invalid column name' for avail and TotalCounts
You can't do that because your TotalCounts column is made from your result set.
you can try to use a subquery to contain it then calculation.
if your mssql version support CONCAT function you can use it let the SQL clearer.
SELECT t1.*,CONCAT((max_biz_statusCnt * 100 /TotalCounts),'%')as 'Percetange'
FROM
(
select
category,
count(*) as 'TotalCounts',
COUNT(case kind when 'avail'then 1 else null end) as 'avail',
Count(case kind when 'offers' then 1 else null end) as 'offers',
COUNT(CASE contactMethod WHEN 'SMS' then 1 else null END) as 'SMS',
COUNT(case contactMethod when 'call' then 1 else null end) as 'call',
COUNT (case when max_biz_status='A' OR max_biz_status ='B' then 1 else null end) 'max_biz_statusCnt'
from reports
group by category
) t1
order by TotalCounts
You can't use avail or TotalCounts as you just created them, so they aren't in scope, using a common-table expression is one way to fix this:
WITH cte AS (
SELECT
category,
COUNT(category) AS TotalCounts,
COUNT(case kind WHEN 'avail' THEN 1 ELSE NULL END) AS avail,
COUNT(case kind WHEN 'offers' THEN 1 ELSE NULL END) AS offers,
COUNT(CASE contactMethod WHEN 'SMS' THEN 1 ELSE NULL END) AS SMS,
COUNT(case contactMethod WHEN 'call' THEN 1 ELSE NULL END) AS [call]
FROM
reports
GROUP BY
category)
SELECT
*,
CONVERT(varchar(254),avail * 100 / TotalCounts) +'%' AS Percetange --(sic)
FROM
cte
ORDER BY
TotalCounts;
I have the following data:
In SQL Server How can I have group by weekdate so I have only one row for each weekdate, example for the weekdate 2015-11-14:
Any clue?
Use conditional aggregation.
select cast(weekdate as date),
sum(case when permittype = 0 then total else 0 end) as permittype0,
sum(case when permittype = 1 then total else 0 end) as permittype1
from tablename
group by cast(weekdate as date)
I would do this using conditional aggregation:
select weekdate,
sum(case when permittype = 0 then total else 0 end) as permitttype0,
sum(case when permittype = 1 then total else 0 end) as permitttype1
from followingdata t
group by weekdate
order by weekdate;
You can also use pivot syntax, if you prefer.
I have a table like this
TABLEMAIN
Q1 Name Group Zone Month Type
1 'N1' 'G1' 'Z1' 12 'T1'
4 'N1' 'G3' 'Z2' 12 'T6'
6 'N1' 'G1' 'Z5' 12 'T2'
3 'N2' 'G4' 'Z5' 12 'T4'
.
.
.
And I have something like this to get certain results
Query1:
select
(SUM(CASE Q1>=2 and Q1<=4 THEN 1 ELSE 0 END)) TOTAL,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T1TYPE,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T2TYPE,
Type,
**Zone,**
Month
from
TABLEMAIN
GROUP BY Type, **Zone,** Month;
Query2:
select
(SUM(CASE Q1>=2 and Q1<=4 THEN 1 ELSE 0 END)) TOTAL,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T1TYPE,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T2TYPE,
Type,
**Group,**
Month
from
TABLEMAIN
GROUP BY Type, **Group,** Month;
As you can see I group this table many times in many ways, but this part is the same in every query
select
(SUM(CASE Q1>=2 and Q1<=4 THEN 1 ELSE 0 END)) TOTAL,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T1TYPE,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) T2TYPE,
Is there a better way to do this? I'm not sure if I can use a materialized view for this
Perhaps. You can do it all in one query, if you like by using grouping sets:
select SUM(CASE Q1>=2 and Q1<=4 THEN 1 ELSE 0 END) as TOTAL,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) as T1TYPE,
(CASE WHEN Type = 'T1' THEN SUM(CASE WHEN Q1=4 THEN 1 ELSE 0 END)) as T2TYPE
Type, **Zone,**, **Group,** Month
from TABLEMAIN
GROUP BY GROUPING SETS((Type, **Zone,** Month), (Type, **Group,** Month));
This puts all the results in a single table.
I second with #GolezTrol comment. Would like to explain further.
SUBQUERY FACTORING is what you need. The WITH clause, or subquery factoring clause, is part of the SQL-99 standard and was added into the Oracle SQL syntax in Oracle 9.2. The WITH clause may be processed as an inline view or resolved as a temporary table. The advantage of the latter is that repeated references to the subquery may be more efficient as the data is easily retrieved from the temporary table, rather than being required by each reference.
WITH data AS(
<your subquery>
)
SELECT * FROM data
bla bla bla...