While loop until find a word - sql

I have only 2 columns in sql server. The first column (name) starts with the name "abc" in the first line and it ends in the 8th line (Endabc).
I need to have second red color column:
(while the first column starts with "abc" until the word "Endab"c, update second column and put 'abc' in all those lines).
How can i do this?
Thanks.

Your question pre-supposes an ordering column. SQL tables represent unordered sets. So there is no ordering unless that information is in a column.
You can use a conditional sum to identify the groups and then spread the values. Assuming that the ends are not really needed (because a new value starts right away):
select t.*,
max(case when name not like 'End%' then name end) over (partition by grp) as imputed_name
from (select t.*,
count(case when name not like 'End%' then name end) over (order by <ordering col>) as grp
from t
) t
Here is a db<>fiddle.

Related

need to pull a specific record

There is 1 record having duplicate values except in 1 column having x and y
record status
XXXXXXXXXX A
XXXXXXXXXX B
Need to pull A only and remove the other duplicate B
Select record
case
when status in ("'a', 'b'") then ('a')
from xyz
Let suppose you have data as below where Status is repeating for First column
but you are interesting in the status which is of having lower value as given below:
In this case following SQL may help. Here, we are partitioning on key field and ordering the Status so that we can apply filter on rank to get desired result.
WITH sampleData AS
 (SELECT '1234' as Field1,  'A' as STATUS UNION ALL 
  SELECT '1234',  'C' UNION ALL
  SELECT '5678', 'A' UNION ALL 
  SELECT '5678',  'B' )
 select * except(rank) from (
 select *, rank() over (partition by Field1 order by STATUS ASC) rank from sampleData)
 where rank = 1
 order by Field1
Consider below approach
select * from sampledata
qualify 1 = row_number() over win
window win as (partition by field1 order by if(status='A',1,2) )
if applied to sample data in your question - output is

How to check max from range in cursor?

I have a problem with transferring an Excel formula to SQL. My excel formula is: =IF(P2<(MAX($P$2:P2));"Move";"").
The P column in excel is a sequence of numbers.
a | b
------
1
2
7
3 MOVE
4 MOVE
8
9
5 MOVE
10
You can find more example on this screenshot:
I created a cursor with a loop but I don't know how to check max from range.
For example when I iterate for fourth row, I have to check max from 1-4 row etc.
No need for a cursor and a loop. Assuming that you have a column that defines the ordering of the rows (say, id), you can use window functions:
select t.*,
case when a < max(a) over(order by id) then 'MOVE' end as b
from mytable t
One option would be using MAX() Analytic function . But in any case, you'd have an extra column such as id for ordering in order to determine the max value for the current row from the first row, since SQL statements represent unordered sets. If you have that id column with values ordered as in your sample data, then consider using
WITH t2 AS
(
SELECT MAX(a) OVER (ORDER BY id ROWS BETWEEN
UNBOUNDED PRECEDING
AND
CURRENT ROW) AS max_upto_this_row,
t.*
FROM t
)
SELECT a, CASE WHEN max_upto_this_row > a THEN 'Move' END AS b
FROM t2
ORDER BY id;
Demo

Need to result of column based on available column in SQL

I am having one view which is returning the following result:
I need to put identifier just like below image
Required output:
Explanation of Output: If you can see the image 1 and in that image release 1 has 3 dates. From that I need to get 1 as an identifier for the MAX(IMPL_DATE).In RELEASE_ID = 1, We are having 08/20/2016, 08/09/2016 and 10/31/2016. From This 10/31/2016 is the largest date. So, Need Identifier as 1 and other 2 are going to be 0. Same thing with the RELEASE_ID 2 we have 2 dates and from them 01/13/2017 is the largest date so, need 1 in that row and other's going to be 0.
Thanks In advance...
You can do this with window functions:
select t.*,
(case when rank() over (partition by portfolio_id, release_id
order by impl_date desc
) = 1
then 1 else 0
end) as indentifier
from t;
The above will assign "1" to all rows with the maximum date. If you want to ensure that only one row is assigned a value (even when there are ties), then use row_number() instead of rank().

Find preceding and following rows for a matching row in BigQuery?

Is it possible to find rows preceding and following a matching rows in a BigQuery query? For example if I do:
select textPayload from logs.logs_20160709 where textPayload like "%something%"
and say that I get these results back:
something A
something B
How can I also show the 3 rows preceding and following the matching rows? Something like this:
some text 1
some text 2
some text 3
something A
some text 4
some text 5
some text 6
some text 90
some text 91
some text 92
something B
some text 93
some text 94
some text 95
Is this possible and if so how?
While on Zuma Beach - I was thinking of avoiding CROSS JOIN in my original answer.
Check below - should be much cheaper especially for big set
SELECT textPayload
FROM (
SELECT textPayload,
SUM(match) OVER(ORDER BY ts ROWS BETWEEN 3 PRECEDING AND 3 FOLLOWING) AS flag
FROM (
SELECT textPayload, ts, IF(textPayload CONTAINS 'something', 1, 0) AS match
FROM YourTable
)
)
WHERE flag > 0
Of course another way to avoid cross join is to use BigQuery Standard SQL. But still - above solution with no joins at all is better than my original answer
I think, one piece is missing in your example - extra field that will define the order, so I added ts field for this in my answer. This mean I assume your table has two fields involved : textPayload and ts
Try below. Should give you exactly what you need
SELECT
all.textPayload
FROM (
SELECT start, finish
FROM (
SELECT textPayload,
LAG(ts, 3) OVER(ORDER BY ts ROWS BETWEEN 3 PRECEDING AND CURRENT ROW) AS start,
LEAD(ts, 3) OVER(ORDER BY ts ROWS BETWEEN CURRENT ROW AND 3 FOLLOWING) AS finish
FROM YourTable
)
WHERE textPayload CONTAINS 'something'
) AS matches
CROSS JOIN YourTable AS all
WHERE all.ts BETWEEN matches.start AND matches.finish
Please note: depends on type of your ts field - you might need to do some data casting in query for this field. hope not

ORACLE: How to check for and remove repeating column values

For the "B numbers" - (the number to which a call was made), please limit each occurrence to 3. That is, from the list of "A numbers"-(the number that made the call to the "B number"), we may have multiple persons calling the same "B number". In instances where the "B number" appears more than 3 times in the total dial list, please remove them from the subsequent "A numbers" that they may show up for.
I want to figure out how can i check for and remove these repeating "B numbers" when they are greater than 3 occurrences.
Here is a sample list the table structure.
So where the B number occurs more than three time i want to keep the A number but remove the B number. Any Thought?
Limiting your results to 3 B Numbers at most is easy using the row_number() analytic function.
select a_number, b_number
from (select a_number, b_number,
row_number() over (partition by b_number order by null) as rn
from your_table)
where rn <= 3
However, the above query is not explicit about which 3 rows it will preserve (order by null).
If you want to keep the first 3 occurrences of a B Number in your list, then you need a way to explicitly define the order of your list. Do you have some timestamp field perhaps?
In any case, whatever field(s) define(s) the order of your list, use that in the order by clause of the row_number() function call:
row_number() over (partition by b_number order by pick_an_ordering_column)