I have query and result below.
select count(age) countage, age
from table2
group by age
and result
countage age
2 1
4 2
4 3
1 4
2 5
8 6
4 7
8 8
1 9
2 10
I want to have 2 age group. First group 1 to 5 and second group 6 to 10
I like to have total group 1 and group 2 devide by each count age to get percents
For example:
Total count for group 1 (age 1 to 5) = 13 and group 2 ( age 6 to 10 ) = 23
age 1 count = 2 and devide 2 /13 * 100 = 15%
age 2 count = 4 and devide 4 /13 * 100 = 30%
and so on for group 1.
Group 2 do the same calculation as group 1
My query but not working well
WITH t1 AS
(SELECT Age, Count(*) AS n
FROM table2
GROUP BY Age)
SELECT Age, n,
(0.0+n)/(COUNT(*) OVER (PARTITION BY Age))
FROM t1;
Need help. Thank you
If I understand correctly, you want:
select (case when age <= 5 then 'group1' else 'group2' end) as age_group,
count(*),
count(*) * 1.0 / sum(count(*)) over () as ratio_in_group
from table2
group by (case when age <= 5 then 'group1' else 'group2' end);
Or, if you just want this by age, you can do something similar with conditional window functions:
select age, count(*) as cnt,
count(*) * 1.0 / sum(count(*)) over (partition by case when age < 5 then 'group1' else 'group2' end) as ratio_in_group
from table2
group by age;
Related
I have a table of customers that I want to assign a test group. I want to assign a test group based on weighted values.
Example:
Group 1 - 50%
Group 2 - 25%
Group 3 - 20%
Group 4 - 5%
Result:
customer_id
group
1
group 1
2
group 4
3
group 1
4
group 2
5
group 1
6
group 1
7
group 2
8
group 1
9
group 3
10
group 1
If you shuffle the rows randomly you can then split based on the cumulative frequencies. While this works neatly when the fractions are neat I'm not sure if this will meet the most general case you've got.
with data as (
select *,
count(*) over () * 1.0 as cnt,
row_number() over (order by random()) * 1.0 as rn
from T
)
select customer_id,
case when rn / cnt <= 0.50 then 'Group 1'
when rn / cnt <= 0.75 then 'Group 2'
when rn / cnt <= 0.95 then 'Group 3'
when rn / cnt <= 1.00 then 'Group 4'
end as grp
from data;
In DB2 is there a way to assign a column value based on the first x%, then y% and remaining z% of rows?
I've tried using row_number() function but no luck!
Example below
Assuming that the below example count(id) is already arranged in descending order
Input:
ID count(id)
5 10
3 8
1 5
4 3
2 1
Output:
First 30% rows of the above input should be assigned code H, last 30% of the rows will have code L and remaining will have code M. If 30% of rows evaluates to decimal then round up-to 0 decimal place.
ID code
5 H
3 H
1 M
4 L
2 L
You can use window functions:
select t.id,
(case ntile(3) over (order by count(id) desc)
when 1 then 'H'
when 2 then 'M'
when 3 then 'L'
end) as grp
from t
group by t.id;
This puts them into equal sized groups.
For 30-40-30% split with your conditions, you have to be more careful:
select t.id,
(case when (seqnum - 1.0) < 0.3 * cnt then 'H'
when (seqnum + 1.0) > 0.7 * cnt then 'L'
else 'M'
end) as grp
from (select t.id,
count(*) as cnt,
count(*) over () as num_ids,
row_number() over (order by count(*) desc) as seqnum
from t
group by t.id
) t
Try this:
with t(ID, count_id) as (values
(5, 10)
, (3, 8)
, (1, 5)
, (4, 3)
, (2, 1)
)
select t.*
, case
when pst <=30 then 'H'
when pst <=70 then 'M'
else 'L'
end as code
from
(
select t.*
, rownumber() over (order by count_id desc) as rn
, 100*rownumber() over (order by count_id desc)/nullif(count(1) over(), 0) as pst
from t
) t;
The result is:
ID COUNT_ID RN PST CODE
-- -------- -- --- ----
5 10 1 20 H
3 8 2 40 M
1 5 3 60 M
4 3 4 80 L
2 1 5 100 L
I have below data.
ID UserID Grade
1 1 A
2 1 A
3 1 a
4 1 a
5 1 b
6 1 C
7 1 c
8 1 b
9 2 b
10 2 C
11 1 b
12 2 A
I want below results.
RunningNumber UserID Result Count
1 1 a 4
2 1 b 1
3 1 c 2
4 1 b 2
5 2 b 1
6 2 c 1
7 2 a 1
The result will count column Grade (case insensitive) and must be group by UserID.
Use as below
SELECT UserID, Grade, COUNT(ID) AS Count
FROM Table1
GROUP BY UserID,Grade;
Updated
SELECT ROW_NUMBER()
OVER (ORDER BY Grade) AS RunningNumber ,
UserID, Grade, COUNT(ID) AS Count
FROM Table1
GROUP BY UserID,Grade;
Just use Group by & count
SELECT ID ,UserID,Grade
COUNT(ID) FROM Tabel
GROUP BY Grade,UserID;
You can use DENSE_RANK for the RunningNumber, COUNT(*)OVER for the count per ID and ROW_NUMBER to take only the first row:
WITH CTE AS
(
SELECT
RunningNumber = DENSE_RANK() OVER (ORDER BY UserID, Grade),
UserID, Result = Grade,
[Count] = COUNT(*) OVER (PARTITION BY UserID, Grade),
RowNum = ROW_NUMBER() OVER (PARTITION BY UserID, Grade ORDER BY ID)
FROM dbo.TableName
)
SELECT RunningNumber, UserID, Result, [Count]
FROM CTE
WHERE RowNum = 1
Demo
$query_not="SELECT count(status) AS sum FROM `user_leave_details`WHERE (status='2' Or status='3') AND user_id_no='$user_id_no'";
$result=mysqli_query($bd,$query_not);
while($arr=mysqli_fetch_array($result))
{
$sum=$arr['sum'];
}
connect.php
<?php
$mysql_hostname = "localhost";
$mysql_user = "root";
$mysql_password = "";
$mysql_database = "";
$bd=mysqli_connect($mysql_hostname,$mysql_user,$mysql_password,$mysql_database);
?>
I have a table that has values and group ids (simplified example). I need to get the average for each group of the middle 3 values. So, if there are 1, 2, or 3 values it's just the average. But if there are 4 values, it would exclude the highest, 5 values the highest and lowest, etc. I was thinking some sort of window function, but I'm not sure if it's possible.
http://www.sqlfiddle.com/#!11/af5e0/1
For this data:
TEST_ID TEST_VALUE GROUP_ID
1 5 1
2 10 1
3 15 1
4 25 2
5 35 2
6 5 2
7 15 2
8 25 3
9 45 3
10 55 3
11 15 3
12 5 3
13 25 3
14 45 4
I'd like
GROUP_ID AVG
1 10
2 15
3 21.6
4 45
Another option using analytic functions;
SELECT group_id,
avg( test_value )
FROM (
select t.*,
row_number() over (partition by group_id order by test_value ) rn,
count(*) over (partition by group_id ) cnt
from test t
) alias
where
cnt <= 3
or
rn between floor( cnt / 2 )-1 and ceil( cnt/ 2 ) +1
group by group_id
;
Demo --> http://www.sqlfiddle.com/#!11/af5e0/59
I'm not familiar with the Postgres syntax on windowed functions, but I was able to solve your problem in SQL Server with this SQL Fiddle. Maybe you'll be able to easily migrate this into Postgres-compatible code. Hope it helps!
A quick primer on how I worked it.
Order the test scores for each group
Get a count of items in each group
Use that as a subquery and select only the middle 3 items (that's the where clause in the outer query)
Get the average for each group
--
select
group_id,
avg(test_value)
from (
select
t.group_id,
convert(decimal,t.test_value) as test_value,
row_number() over (
partition by t.group_id
order by t.test_value
) as ord,
g.gc
from
test t
inner join (
select group_id, count(*) as gc
from test
group by group_id
) g
on t.group_id = g.group_id
) a
where
ord >= case when gc <= 3 then 1 when gc % 2 = 1 then gc / 2 else (gc - 1) / 2 end
and ord <= case when gc <= 3 then 3 when gc % 2 = 1 then (gc / 2) + 2 else ((gc - 1) / 2) + 2 end
group by
group_id
with cte as (
select
*,
row_number() over(partition by group_id order by test_value) as rn,
count(*) over(partition by group_id) as cnt
from test
)
select
group_id, avg(test_value)
from cte
where
cnt <= 3 or
(rn >= cnt / 2 - 1 and rn <= cnt / 2 + 1)
group by group_id
order by group_id
sql fiddle demo
in the cte, we need to get count of elements over each group_id by window function + calculate row_number inside each group_id. Then, if this count > 3 then we need to get middle of the group by dividing count by 2 and then get +1 and -1 element. If count <= 3, then we should just take all elements.
This works:
SELECT A.group_id, avg(A.test_value) AS avg_mid3 FROM
(SELECT group_id,
test_value,
row_number() OVER (PARTITION BY group_id ORDER BY test_value) AS position
FROM test) A
JOIN
(SELECT group_id,
CASE
WHEN count(*) < 4 THEN 1
WHEN count(*) % 2 = 0 THEN (count(*)/2 - 1)
ELSE (count(*) / 2)
END AS position_start,
CASE
WHEN count(*) < 4 THEN count(*)
WHEN count(*) % 2 = 0 THEN (count(*)/2 + 1)
ELSE (count(*) / 2 + 2)
END AS position_end
FROM test GROUP BY group_id) B
ON A.group_id=B.group_id
AND A.position >= B.position_start
AND A.position <= B.position_end
GROUP BY A.group_id
Fiddle link: http://www.sqlfiddle.com/#!11/af5e0/56
If you need to calculate the average values for groups then you can do this:
SELECT CASE WHEN NUMBER_FIRST_GROUP <> 0
THEN SUM_FIRST_GROUP / NUMBER_FIRST_GROUP
ELSE NULL
END AS AVG_FIRST_GROUP,
CASE WHEN NUMBER_SECOND_GROUP <> 0
THEN SUM_SECOND_GROUP / NUMBER_SECOND_GROUP
ELSE NULL
END AS AVG_SECOND_GROUP,
CASE WHEN NUMBER_THIRD_GROUP <> 0
THEN SUM_THIRD_GROUP / NUMBER_THIRD_GROUP
ELSE NULL
END AS AVG_THIRD_GROUP,
CASE WHEN NUMBER_FOURTH_GROUP <> 0
THEN SUM_FOURTH_GROUP / NUMBER_FOURTH_GROUP
ELSE NULL
END AS AVG_FOURTH_GROUP
FROM (
SELECT
SUM(CASE WHEN GROUP_ID = 1 THEN 1 ELSE 0 END) AS NUMBER_FIRST_GROUP,
SUM(CASE WHEN GROUP_ID = 1 THEN TEST_VALUE ELSE 0 END) AS SUM_FIRST_GROUP,
SUM(CASE WHEN GROUP_ID = 2 THEN 1 ELSE 0 END) AS NUMBER_SECOND_GROUP,
SUM(CASE WHEN GROUP_ID = 2 THEN TEST_VALUE ELSE 0 END) AS SUM_SECOND_GROUP,
SUM(CASE WHEN GROUP_ID = 3 THEN 1 ELSE 0 END) AS NUMBER_THIRD_GROUP,
SUM(CASE WHEN GROUP_ID = 3 THEN TEST_VALUE ELSE 0 END) AS SUM_THIRD_GROUP,
SUM(CASE WHEN GROUP_ID = 4 THEN 1 ELSE 0 END) AS NUMBER_FOURTH_GROUP,
SUM(CASE WHEN GROUP_ID = 4 THEN TEST_VALUE ELSE 0 END) AS SUM_FOURTH_GROUP
FROM TEST
) AS FOO
I have a table AssignmentMaster in that I have following columns with data
AssignmentID PaidAmount RefundAmount UserID
1 20 0 1
2 10 5 1
3 30 7 2
4 25 0 3
5 35 15 3
6 10 3 1
7 5 0 3
8 10 0 3
Now I want to find out the TotalNumberofAssignment with respect to userID, i.e. result should be:
UserID TotalAssignment TotalAssignmentofRefundAmount TotalPaidAmount TotalRefundAmount
1 3 2 40 8
2 1 1 30 7
3 4 1 75 15
How I can get above given result in MSSQL.
your any help will help me lot.
SELECT
UserID,
COUNT(AssignmentID) AS TotalAssignment,
SUM(SIGN(RefundAmount)) AS TotalAssignmentofRefundAmount,
SUM(PaidAmount) AS TotalPaidAmount,
SUM(RefundAmount) AS TotalRefundAmount
FROM
MyTable
GROUP BY
UserID
Note:
SIGN(RefundAmount) works if RefundAmount is always >= 0.
If not, change to
SUM(CASE WHEN RefundAmount <> 0 THEN 1 ELSE 0 END) AS TotalAssignmentofRefundAmount
Select UserID,
count(1) as TotalAssignment,
sum( case when RefundAmount = 0 then 0 else 1 end) as TotalAssignmentofRefundAmount,
sum(PaidAmount) as TotalPaidAmount ,
sum(RefundAmount) as TotalRefundAmount
From AssignmentMaster
Group by UserID
To show how to do this using nested SQL:
Select UserTotals.UserID, UserTotals.TotalAssignment,
Refunds.TotalAssignmentofRefundAmount,
UserTotals.TotalPaidAmount, UserTotals.TotalRefundAmount
From (select UserID,
Count(AssignmentID) [TotalAssignment],
Sum(PaidAmount) [TotalPaidAmount],
sum(RefundAmount) [TotalRefundAmount]
From #AssignmentMaster
Group By UserID
) [UserTotals] Left Join
(Select UserID,
Count(AssignmentID) [TotalAssignmentofRefundAmount]
From #AssignmentMaster
Where RefundAmount > 0
Group By UserID
) [Refunds] On Refunds.UserID = UserTotals.UserID
select UserId, count (AssignmentID) as TotalAssignment,
sum(case when RefundAmount = 0 then 0 else 1 end) as TotalAssignmentofRefundAmount,
sum(PaidAmount) as TotalPaidAmound,
sum(RefundAmount) as TotalRefundAmount
from AssignmentMaster
group by UserID;