I have a table AssignmentMaster in that I have following columns with data
AssignmentID PaidAmount RefundAmount UserID
1 20 0 1
2 10 5 1
3 30 7 2
4 25 0 3
5 35 15 3
6 10 3 1
7 5 0 3
8 10 0 3
Now I want to find out the TotalNumberofAssignment with respect to userID, i.e. result should be:
UserID TotalAssignment TotalAssignmentofRefundAmount TotalPaidAmount TotalRefundAmount
1 3 2 40 8
2 1 1 30 7
3 4 1 75 15
How I can get above given result in MSSQL.
your any help will help me lot.
SELECT
UserID,
COUNT(AssignmentID) AS TotalAssignment,
SUM(SIGN(RefundAmount)) AS TotalAssignmentofRefundAmount,
SUM(PaidAmount) AS TotalPaidAmount,
SUM(RefundAmount) AS TotalRefundAmount
FROM
MyTable
GROUP BY
UserID
Note:
SIGN(RefundAmount) works if RefundAmount is always >= 0.
If not, change to
SUM(CASE WHEN RefundAmount <> 0 THEN 1 ELSE 0 END) AS TotalAssignmentofRefundAmount
Select UserID,
count(1) as TotalAssignment,
sum( case when RefundAmount = 0 then 0 else 1 end) as TotalAssignmentofRefundAmount,
sum(PaidAmount) as TotalPaidAmount ,
sum(RefundAmount) as TotalRefundAmount
From AssignmentMaster
Group by UserID
To show how to do this using nested SQL:
Select UserTotals.UserID, UserTotals.TotalAssignment,
Refunds.TotalAssignmentofRefundAmount,
UserTotals.TotalPaidAmount, UserTotals.TotalRefundAmount
From (select UserID,
Count(AssignmentID) [TotalAssignment],
Sum(PaidAmount) [TotalPaidAmount],
sum(RefundAmount) [TotalRefundAmount]
From #AssignmentMaster
Group By UserID
) [UserTotals] Left Join
(Select UserID,
Count(AssignmentID) [TotalAssignmentofRefundAmount]
From #AssignmentMaster
Where RefundAmount > 0
Group By UserID
) [Refunds] On Refunds.UserID = UserTotals.UserID
select UserId, count (AssignmentID) as TotalAssignment,
sum(case when RefundAmount = 0 then 0 else 1 end) as TotalAssignmentofRefundAmount,
sum(PaidAmount) as TotalPaidAmound,
sum(RefundAmount) as TotalRefundAmount
from AssignmentMaster
group by UserID;
Related
I have a table data:
ID Sale Weekday
1 12 1
2 15 2
3 16 3
4 17 4
5 18 5
6 11 1
7 13 2
8 14 3
9 15 4
10 20 5
11 25 1
12 14 2
13 18 3
14 21 4
15 11 5
.. ..
I'd like to turn it into:
Mo Tu We Th Fr
12 15 16 17 18
11 13 14 15 20
25 14 18 21 11
..
Thank you!
Try this
SELECT SUM(case when Weekday = 1 then Sale else 0 end) as mn,
SUM(case when Weekday = 2 then Sale else 0 end) as Tu,
SUM(case when Weekday = 3 then Sale else 0 end) as We,
SUM(case when Weekday = 4 then Sale else 0 end) as Th,
SUM(case when Weekday = 5 then Sale else 0 end) as Fr
FROM
(
SELECT *,
Row_number()OVER(partition by weekday ORDER BY ID ) as seq_no
FROM tablename
) A
Group by seq_no
As mentioned in sample data if your table has all 5 days for all the week
SELECT SUM(case when Weekday = 1 then Sale else 0 end) as mn,
SUM(case when Weekday = 2 then Sale else 0 end) as Tu,
SUM(case when Weekday = 3 then Sale else 0 end) as We,
SUM(case when Weekday = 4 then Sale else 0 end) as Th,
SUM(case when Weekday = 5 then Sale else 0 end) as Fr
FROM
(
SELECT *,
( ( Row_number()OVER(ORDER BY ID ) - 1 ) / 5 ) + 1 seq_no
FROM tablename
) A
Group by seq_no
SQL FIDDLE DEMO
You could use the pivot operator together with a partitioned row_number like this:
select
max([1]) as 'Mo',
max([2]) as 'Tu',
max([3]) as 'We',
max([4]) as 'Th',
max([5]) as 'Fr'
from
(
select *, row_number() over (partition by weekday order by id) rn
from your_table
) a
pivot (max(sale) for weekday in ([1],[2],[3],[4],[5])) p
group by rn;
Lets say I have a table Tbl (Represents simple timelogs for work made on different customers)
Five columns
Id: int
TimeUse: float
IdCustomer: int
Created: DateTime
TimeCalc: float
I have a number of records in this table, (TimeCalc is initialized to value = 0)
What I want my SQL to do is:
when TimeUse for all foregoing records on a specific customer accumulates to a value < 10 then the value in TimeCalc should be 0
when TimeUse for all foregoing records on a specific customer accumulates to a value >= 10 then the value in TimeCalc should be = TimeUse for the record...
I have messed around with Case routines with subqueries, but can't get it working.
BEFORE
Id TimeUse IdCustomer Created TimeCalc
1 2 1 14/09/09 0
2 5 2 14/09/10 0
3 2 1 14/09/11 0
4 5 2 14/09/12 0
5 4 1 14/09/13 0
6 2 2 14/09/14 0
7 4 1 14/09/15 0
8 1 1 14/09/16 0
9 3 2 14/09/17 0
10 2 1 14/09/18 0
11 4 2 14/09/19 0
AFTER
Id TimeUse IdCustomer Created TimeCalc
1 2 1 14/09/09 0
2 5 2 14/09/10 0
3 2 1 14/09/11 0
4 5 2 14/09/12 0
5 4 1 14/09/13 0
6 2 2 14/09/14 2
7 4 1 14/09/15 0
8 1 1 14/09/16 1
9 3 2 14/09/17 3
10 2 1 14/09/18 2
11 4 2 14/09/19 4
Can this be solved in an SQL update?
In SQL Server 2012+, you can do this with a cumulative sum:
select Id, TimeUse, IdCustomer, Created,
(case when sum(timeuse) over (partition by idcustomer order by id) < 10 then 0
else timeuse
end) as timecalc
from table t;
You can do the same thing in earlier versions using outer apply or a subquery.
If you want an update, just use a CTE:
with toupdate as (
select t.*,
(case when sum(timeuse) over (partition by idcustomer order by id) < 10 then 0
else timeuse
end) as new_timecalc
from table t
)
update toupdate
set timecalc = new_timecalc;
EDIT:
The following will work in any version of SQL Server:
with toupdate as (
select t.*,
(case when (select sum(t2.timeuse)
from table t2
where t2.idcustomer = t.idcustomer and
t2.id <= t.id
) < 10 then 0
else timeuse
end) as new_timecalc
from table t
)
update toupdate
set timecalc = new_timecalc;
I have the following Result from Select statement
UnitId UnitType GroupId
1 1 1
2 1 1
3 1 2
4 2 2
5 2 2
6 2 2
7 2 2
I need the following result for each group Id
GroupId CountBasedOnUnitType1 CountBasedOnUnitType2
1 2 0
2 1 4
Thanks in advance.
Try this
SELECT * FROM
(
SELECT GroupId,
UnitType
FROM Table1
) x
Pivot
(
Count(UnitType)
For UnitType in ([1], [2])
) p
Fiddle Demo
Output
GroupId 1 2
1 2 0
2 1 4
Does in necessarily need to have OVER?
select
GroupID,
sum(case when UnitType = 1 then 1 else 0 end) CountBasedOnUnitType1,
sum(case when UnitType = 2 then 1 else 0 end) CountBasedOnUnitType2
from table
group by GroupID
Please help me to solve the problem
My real table is:
id group numberOfLevel(counted column)
1 10 4
2 10 2
3 11 2
4 11 1
5 11 3
6 11 2
7 21 1
8 21 2
9 30 1
10 40 2
But i want to show:
group 1st_level 2nd_level 3rd_level over4th_level
10 0 1 0 1
11 1 2 1 0
21 1 1 0 0
30 1 0 0 0
40 0 1 0 0
Which way do i need to use to show the table?
Please share experience ?
This is a basic pivot query, an ANSII SQL case expession can be used in such a query,
and it should work on most databases:
select group_nr,
sum( case when numberOfLevel = 1 then 1 else 0 end ) As level_1st,
sum( case when numberOfLevel = 2 then 1 else 0 end ) As level_2nd,
sum( case when numberOfLevel = 3 then 1 else 0 end ) As level_3rd,
sum( case when numberOfLevel >= 4 then 1 else 0 end ) As over4th_level
from table1
group by group_nr
;
demo: http://sqlfiddle.com/#!2/4bd04/4
Don't use group as a column name, because group is a keyword in SQL.
MySQL table is like this (VoteID is PK):
VoteID VoteValue CommentID
1 -1 1
2 -1 1
3 1 1
4 -1 1
5 1 2
6 1 2
7 -1 2
I need a result:
CommentID Plus Minus
1 1 3
2 2 1
Sum of "Pluses", Sum of "Minuses" groupped by CommentID
Is it possible to get desired in one SQL expression?
SELECT
CommentID,
SUM(CASE WHEN VoteValue > 0 THEN 1 ELSE 0 END) AS PLUS,
SUM(CASE WHEN VoteValue < 0 THEN 1 ELSE 0 END) AS MINUS
FROM
mytable
GROUP BY
CommentID
You need a query in the lines of:
SELECT CommentID,
SUM(IF(VoteValue > 0, 1, 0)) AS Plus,
SUM(IF(VoteValue < 0, 1, 0)) AS Minus
FROM yourTable
GROUP BY CommentID
ORDER BY CommentID