I have a table of transactions. One column is for the vendor ID, and one column is for the amount due. [There are other columns, but they aren't relevant]
id | amount | custid
23 | -31.32 | 904424
24 | -19.94 | 646744
25 | -4.77 | 904424
26 | -29.40 | 972979
I want to run a query that delivers the total for each distinct customer ID.
The goal is to determine how much each customer is owed.
That's basic aggregation:
select custid, sum(amount) total_amount
from mytable
group by custid
Related
I have 2 tables.
Table 1 is a temp variable table:
declare #Temp as table ( proj_num varchar(10), sum_dom decimal(23,8))
My temp table is populated with a list of project numbers, and a month end accounting dollar amount.
For example:
proj_num | sum_dom
11522 | 2477.15
11524 | 26474.20
41865 | 9012.10
Table 2 is a Project Transactions table.
We're concerned with just the following columns:
proj_num
amount
cost_code
tran_date
Individual values will somemething like this:
proj_num | cost_code | amount | tran_date
11522 | LBR | 112.10 | 10/1/2018
11522 | LBR | 1765.90 | 10/2/2018
11522 | MAT | 599.15 | 10/3/2018
11522 | FRT | 57.50 | 10/4/2018
So for this project, since the grand total of $2477.15 is met on 10/3, example output would be:
proj_num | cost_code | amount
11522 | LBR | 1878.00
11522 | MAT | 599.15
I want to sum the amounts (grouped by cost_code, and ordered by tran_date) under the project transaction table until the total sum of values for that project value matches the value in the sum_dom column of the temp table, at which point I will output that data.
Can you help me figure out how to write the query to do that?
I know I should avoid cursors, but I havent had much luck with my attempts so far. I cant seem to get it to keep a running total.
Running sum is done using SUM(...) OVER (ORDER BY ...). You just need to tell where to stop:
SELECT sq.*
FROM projects
INNER JOIN (
SELECT
proj_num,
cost_code,
amount,
SUM(amount) OVER (PARTITION BY proj_num ORDER BY tran_date) AS running_sum
FROM project_transactions
) AS sq ON projects.proj_num = sq.proj_num
WHERE running_sum <= projects.sum_dom
DB Fiddle
I am fairly new to SQL and was wondering if anyone could help with my code.
I am trying to count the distinct number of stores that are tied to a certain Warehouse which is tied to a purchase order.
Example: If there are 100 stores with this PO that came from Warehouse #2 or #5 or etc... then I would like:
| COUNT_STORE | WH_LOCATION |
1 | 100 | 2 |
2 | 25 | 5 |
3 | 56 | 1 |
[]
My Code:
select count(distinct Store_ID) as Count_Store, WH_Location
from alc_Loc
where alloc_PO = 11345
group by Store_ID, WH_Location
When I run this I get a 1 for "count_store" and it shows me the WH_Location multiple times. I feel as if something is not tying in correctly.
Any help is appreciated!
Just remove store_id from the group by:
select count(distinct Store_ID) as Count_Store, WH_Location
from alc_Loc
where alloc_PO = 11345
group by WH_Location;
When you include Store_ID in the group by, you are getting a separate row for each Store_ID. The distinct count is then obviously 1 (or 0 if the store id is NULL).
Apologies if this has been asked elsewhere. I have been looking on Stackoverflow all day and haven't found an answer yet. I am struggling to write the query to find the highest month's sales for each state from this example data.
The data looks like this:
| order_id | month | cust_id | state | prod_id | order_total |
+-----------+--------+----------+--------+----------+--------------+
| 67212 | June | 10001 | ca | 909 | 13 |
| 69090 | June | 10011 | fl | 44 | 76 |
... etc ...
My query
SELECT `month`, `state`, SUM(order_total) AS sales
FROM orders GROUP BY `month`, `state`
ORDER BY sales;
| month | state | sales |
+------------+--------+--------+
| September | wy | 435 |
| January | wy | 631 |
... etc ...
returns a few hundred rows: the sum of sales for each month for each state. I want it to only return the month with the highest sum of sales, but for each state. It might be a different month for different states.
This query
SELECT `state`, MAX(order_sum) as topmonth
FROM (SELECT `state`, SUM(order_total) order_sum FROM orders GROUP BY `month`,`state`)
GROUP BY `state`;
| state | topmonth |
+--------+-----------+
| ca | 119586 |
| ga | 30140 |
returns the correct number of rows with the correct data. BUT I would also like the query to give me the month column. Whatever I try with GROUP BY, I cannot find a way to limit the results to one record per state. I have tried PartitionBy without success, and have also tried unsuccessfully to do a join.
TL;DR: one query gives me the correct columns but too many rows; the other query gives me the correct number of rows (and the correct data) but insufficient columns.
Any suggestions to make this work would be most gratefully received.
I am using Apache Drill, which is apparently ANSI-SQL compliant. Hopefully that doesn't make much difference - I am assuming that the solution would be similar across all SQL engines.
This one should do the trick
SELECT t1.`month`, t1.`state`, t1.`sales`
FROM (
/* this one selects month, state and sales*/
SELECT `month`, `state`, SUM(order_total) AS sales
FROM orders
GROUP BY `month`, `state`
) AS t1
JOIN (
/* this one selects the best value for each state */
SELECT `state`, MAX(sales) AS best_month
FROM (
SELECT `month`, `state`, SUM(order_total) AS sales
FROM orders
GROUP BY `month`, `state`
)
GROUP BY `state`
) AS t2
ON t1.`state` = t2.`state` AND
t1.`sales` = t2.`best_month`
It's basically the combination of the two queries you wrote.
Try this:
SELECT `month`, `state`, SUM(order_total) FROM orders WHERE `month` IN
( SELECT TOP 1 t.month FROM ( SELECT `month` AS month, SUM(order_total) order_sum FROM orders GROUP BY `month`
ORDER BY order_sum DESC) t)
GROUP BY `month`, state ;
I have a query that filters results for products which have had orders sent after an user-input date, and calculates what the quantity becomes if the order was sent after that date.
SELECT *, [OnHand]+[OrderJoin.Quantity] AS Qty After
FROM Query3
WHERE (((Query3.ShippedDate)>[Enter End Date] And (Query3.ShippedDate) Is Not Null));
However, I need a way for it to recognise duplicates and update it based on those.
e.g. I have this
ID | Product Name | Qty Before | Qty Shipped | Qty After
11 | Chocolate | 80 | 20 | 100
11 | Chocolate | 80 | 10 | 90
And I'd need a way for it to show Qty After as 110 (after the 10 and 20 shipped)
If I understand correctly, you want an aggregation query. This would be something like this:
SELECT id, ProductName,
OnHand]+ SUM([OrderJoin.Quantity]) AS Qty After
FROM Query3
WHERE Query3.ShippedDate > [Enter End Date] And
Query3.ShippedDate) Is Not Null
GROUP BY id, ProductName, OnHand;
I note that OrderJoin is not defined, but that is the structure of your original query.
Lets says I have the following database table (date truncated for example only, two 'id_' preix columns join with other tables)...
+-----------+---------+------+--------------------+-------+
| id_table1 | id_tab2 | date | description | price |
+-----------+---------+------+--------------------+-------+
| 1 | 11 | 2014 | man-eating-waffles | 1.46 |
+-----------+---------+------+--------------------+-------+
| 2 | 22 | 2014 | Flying Shoes | 8.99 |
+-----------+---------+------+--------------------+-------+
| 3 | 44 | 2015 | Flying Shoes | 12.99 |
+-----------+---------+------+--------------------+-------+
...and I have a query like the following...
SELECT id, date, description FROM inventory ORDER BY date ASC;
How do I SELECT all the descriptions, but only once each while simultaneously only the latest year for that description? So I need the database query to return the first and last row from the sample data above; the second it not returned because the last row has a later date.
Postgres has something called distinct on. This is usually more efficient than using window functions. So, an alternative method would be:
SELECT distinct on (description) id, date, description
FROM inventory
ORDER BY description, date desc;
The row_number window function should do the trick:
SELECT id, date, description
FROM (SELECT id, date, description,
ROW_NUMBER() OVER (PARTITION BY description
ORDER BY date DESC) AS rn
FROM inventory) t
WHERE rn = 1
ORDER BY date ASC;