I've found similar questions on the site, but I'm still struggling with this. I have a table with information like the below:
AcctNo ChargeOrder ChargeCode
ABC 1 Charge1
ABC 2 Charge2
ABC 3 Charge3
I'm trying to use the XML Path/STUFF functions to return the data like so:
AcctNo Order/Code
ABC 1:Charge1 - 2:Charge2 - 3:Charge3
But I can't seem to figure out how to concatenate my chargeorder and chargecode AND STUFF them into a single field.
In SQL Server, you can use string_agg() -- in the more recent versions:
select acctno,
string_agg(concat(ChargeOrder, ':', ChargeCode), ' - ')
from t
group by acctno;
In older versions, this would be phrased as:
select a.acctno,
stuff( (select concat(' - ', ChargeOrder, ':', ChargeCode)
from t t2
where t2.acctno = a.acctno
for xml path ('')
), 1, 3, ''
)
from (select distinct acctno from t) a
Related
I need to extract a comma separated list from the following:
Return should gives something like
1 : Route#1, Route#2
2 : Route#3, Route#4
3 : Route#5
4 : Route#6
I'm struggling with the STUFF function. So far I have:SELECT STUFF( (SELECT DISTINCT ';' + T4.[Outbound Trucks] FROM #TEMP4 T4 FOR XML PATH('') ),1,1,'') AS MasterRoutes
Result gives me
any help would be really appreciated.
thanks a lof for your time
If your sql server is 2017 or more :
SELECT dorno, STRING_AGG ([Outbound Trucks], ',') as CSV
FROM #TEMP4
GROUP BY dorno
Explanation Here
In you case you can eliminate doublon to like this:
with tmp as (
select distinct dorno, [Outbound Trucks] Truck from #TEMP4
)
SELECT dorno, STRING_AGG (Truck, ',') as CSV
FROM tmp
GROUP BY dorno
I am trying to compare 2 columns and I have to get the only difference for example
select * from table1
Column_1 column_2
---------------- ------------------
Swetha working Swetha is working in Chennai
Raju 10th Raju is studying 10th std
ranjith Ranjith played yesterday
how to play how to play Cricket
My name is my name is john
Output:
If words come in between it should also remove like row 1 and 2
Column_1 column_2 column_3
---------------- ------------------ ------------------------
Swetha working Swetha is working in Chennai is in Chennai
Raju 10th Raju is studying 10th std is studying std
ranjith Ranjith played yesterday played yesterday
how to play how to play Cricket Cricket
My name is my name is john john
This is much more complicated than your previous question. You can break the first column into words and then substitute them individually in the second column. To do that, though, you need a recursive CTE:
with words as (
select t.*, s.*,
max(s.seqnum) over (partition by t.id) as max_seqnum
from t cross apply
(select s.value as word,
row_number() over (order by (select null)) as seqnum
from string_split(col1, ' ') s
) s
),
cte as (
select id, col1, col2,
replace(' ' + col2 + ' ', ' ' + word + ' ', ' ') as result,
word, seqnum, max_seqnum
from words
where seqnum = 1
union all
select cte.id, cte.col1, cte.col2,
replace(cte.result, ' ' + w.word + ' ', ' '),
w.word, w.seqnum, cte.max_seqnum
from cte join
words w
on w.id = cte.id and w.seqnum = cte.seqnum + 1
)
select id, col1, col2, ltrim(rtrim(result)) as result
from cte
where max_seqnum = seqnum
order by id;
Here is a db<>fiddle.
I added an id so each row is uniquely defined. If your version of SQL Server doesn't have the built-in string_split() function, you can easily find a version that does the same thing.
One trick that this uses is for handling the first and last words in the second column. The code adds spaces at the beginning and end. That way, all words in the string are surrounded by spaces, making it easier to replace only complete words.
SQL 2016 definitely has string split. This approach appends an extra space to either side of the split word from Column 2.
Data
drop table if exists #strings;
go
create table #strings(
Id int,
Column_1 varchar(200),
Column_2 varchar(200));
go
insert #strings(Id, Column_1, Column_2) values
(1, 'Swetha', 'Swetha is working in Chennai'),
(2, 'Raju', 'Raju is studying 10 std'),
(3, 'Swetha working', 'Swetha is working in Chennai'),
(4, 'Raju 10th', 'Raju is studying 10th std');
Query
declare
#add_delim char(1)=' ';
;with
c1_cte(split_str) as (
select ltrim(rtrim(s.[value]))
from
#strings st
cross apply
string_split(st.Column_1, ' ') s),
c2_cte(Id, ndx, split_str) as (
select Id, charindex(#add_delim + s.[value] + #add_delim, #add_delim + st.Column_2 + #add_delim), s.[value]
from
#strings st
cross apply
string_split(st.Column_2, ' ') s
where
st.Column_2 not like '% %')
select
Id, stuff((select ' ' + c.split_str
from c2_cte c
where c.Id = c2.Id and not exists(select 1
from c1_cte c1
where c.split_str=c1.split_str)
order by c.ndx FOR XML PATH('')), 1, 1, '') [new_str]
from c2_cte c2
group by Id;
Results
Id new_str
1 is in Chennai
2 is studying 10 std
3 is in Chennai
4 is studying std
Here is the solution using STRING_SPLIT and STRING_AGG
DBFIDDLE working link
;WITH split_words
AS (
SELECT *
FROM dbo.Strings
CROSS APPLY (
SELECT VALUE
FROM STRING_SPLIT(column_2, ' ')
WHERE VALUE NOT IN (
SELECT VALUE
FROM STRING_SPLIT(column_1, ' ')
)
) a
)
SELECT *
,(
SELECT sw.VALUE + ' ' [text()]
FROM split_words sw
WHERE sw.Column_1 = s.Column_1
AND sw.Column_2 = s.Column_2
FOR XML PATH('')
,TYPE
).value('.', 'NVARCHAR(MAX)') [difference]
FROM dbo.Strings s
For SQL version 2017+ where STRING_AGG is supported
SELECT b.Column_1
,b.Column_2
,STRING_AGG(b.VALUE, ' ')
FROM (
SELECT *
FROM dbo.Strings
CROSS APPLY (
SELECT VALUE
FROM STRING_SPLIT(column_2, ' ')
WHERE VALUE NOT IN (
SELECT VALUE
FROM STRING_SPLIT(column_1, ' ')
)
) a
) b
GROUP BY b.Column_1
,b.Column_2
Results:
WITH
-- your input
input(column_1,column_2,column_3) AS (
SELECT 'Swetha working','Swetha is working in Chennai','is in Chennai'
UNION ALL SELECT 'Raju 10th','Raju is studying 10th std','is studying std'
UNION ALL SELECT 'ranjith','Rantith played yesterday','played yesterday'
UNION ALL SELECT 'how to play','how to play Cricket','Cricket'
UNION ALL SELECT 'My name is','my name is john','john'
)
,
-- need a series of integers
-- you can also try to play with the STRING_SPLIT() function
i(i) AS (
SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5
)
,
-- you can also try to play with the STRING_SPLIT() function
unfound_tokens AS (
SELECT
i
, column_1
, column_2
, TOKEN(column_2,' ',i) AS token
FROM input CROSS JOIN i
WHERE TOKEN(column_2,' ',i) <> ''
AND CHARINDEX(
UPPER(TOKEN(column_2,' ',i))
, UPPER(column_1)
) = 0
)
SELECT
column_1
, column_2
, STRING_AGG(token ,' ') AS column_3
FROM unfound_tokens
GROUP BY
column_1
, column_2
-- out column_1 | column_2 | column_3
-- out ----------------+------------------------------+--------------------------
-- out My name is | my name is john | john
-- out Swetha working | Swetha is working in Chennai | is Chennai
-- out how to play | how to play Cricket | Cricket
-- out Raju 10th | Raju is studying 10th std | is studying std
-- out ranjith | Rantith played yesterday | Rantith played yesterday
I am not sure that the results, while using STRING_AGG or STRING_SPLIT, will preserve the ordering of the words...
Just look over this query that give a different ordering :
WITH
SS1 AS
(SELECT Id, SS.value AS COL1
FROM #strings
CROSS APPLY STRING_SPLIT(Column_1, ' ') AS SS
),
SS2 AS
(SELECT Id, SS.value AS COL2
FROM #strings
CROSS APPLY STRING_SPLIT(Column_2, ' ') AS SS
),
DIF AS
(
SELECT Id, COL2 AS COL
FROM SS2
EXCEPT
SELECT Id, COL1
FROM SS1
)
SELECT DIF.Id, Column_1, Column_2, STRING_AGG(COL, ' ')
FROM DIF
JOIN #strings AS S ON S.Id = DIF.Id
GROUP BY DIF.Id, Column_1, Column_2;
You must try with a very huge amount of data to see if the queries that have been given, will not have a side effect like the unconsistent ordering (I am pretty sure that no consistent order will appear due to parallelism....)
So the only way to preserve a consistent ordering is to create a recursive query that add an indiced value of the word in the sentence...
How to concatenate the strings from multiple rows and multiple columns in SQL Server.
My table is like this:
ItemId AttributeName AttributeValue
---------- ------------- --------------
1 Website www.abc.com
1 Github github.com/abc
1 Facebook facebook.com/abc
2 Website www.123.com
2 Instagram instagram.com/123
and the desired output is:
ItemId Weblinks
---------- -------------
1 Website: www.abc.com; Github: github.com/abc; Facebook: facebook.com/abc
2 Website: www.123.com; Instagram: instagram.com/123
I read from other similar questions that XML PATH is probably required. Please could anyone guide me how to achieve this?
This can also be done with a 2 step query:
SELECT t.id, STRING_AGG(t.sites, ' ') as Weblinks
FROM (
SELECT id, CONCAT(attrName, ': ', attrValue, ';') as sites
FROM test
) as t
GROUP BY t.id
ORDER BY t.id;
The inner concatenates attribute value and name in the desired format, while the outer aggregates the results per user id. Coming from MySQL I find that simpler for some reason.
Demo: here
UPDATE: based on #Panagiotis comment
SELECT t.id, STRING_AGG(CONCAT(t.attrName, ': ', t.attrValue, ';'), ' ') as Weblinks
FROM test t
GROUP BY t.id
ORDER BY t.id;
Demo 2: here
You can use FOR XML PATH() :
SELECT DISTINCT T.ItemId, STUFF(Weblinks, 1, 1, '') AS Weblinks
FROM table T CROSS APPLY
( SELECT CONCAT(';', T1.AttributeName, ':', T1.AttributeValue)
FROM table T1
WHERE T1.ITEMID = T.ITEMID
FOR XML PATH('')
) T1(Weblinks);
I have a table that save personnel code.
When I select from this table I get 3 rows result such as:
2129,3394,3508,3534
2129,3508
4056
I want when create select result combine in one row such as:
2129,3394,3508,3534,2129,3508,4056
or distinct value such as:
2129,3394,3508,3534,4056
You should ideally avoid storing CSV data at all in your tables. That being said, for your first result set we can try using STRING_AGG:
SELECT STRING_AGG(col, ',') AS output
FROM yourTable;
Your second requirement is more tricky, and we can try going through a table to remove duplicates:
WITH cte AS (
SELECT DISTINCT VALUE AS col
FROM yourTable t
CROSS APPLY STRING_SPLIT(t.col, ',')
)
SELECT STRING_AGG(col, ',') WITHIN GROUP (ORDER BY CAST(col AS INT)) AS output
FROM cte;
Demo
I solved this by using STUFF and FOR XML PATH:
SELECT
STUFF((SELECT ',' + US.remain_uncompleted
FROM Table_request US
WHERE exclusive = 0 AND reqact = 1 AND reqend = 0
FOR XML PATH('')), 1, 1, '')
Thank you Tim
I need some help with my query...I am trying to get a count of names in each house, all the col#'s are names.
Query:
SELECT House#,
COUNT(CASE WHEN col#1 IS NOT NULL THEN 1 ELSE 0 END) +
COUNT(CASE WHEN col#2 IS NOT NULL THEN 1 ELSE 0 END) +
COUNT(CASE WHEN col#3 IS NOT NULL THEN 1 ELSE 0 END) as count
FROM myDB
WHERE House# in (house#1,house#2,house#3)
GROUP BY House#
Desired results:
house 1 - the count is 3 /
house 2 - the count is 2 /
house 3 - the count is 1
...with my current query the results for count would be just 3's
In this case, it seems that counting names is the same as counting the commas (,) plus one:
SELECT House_Name,
LEN(Names) - LEN(REPLACE(Names,',','')) + 1 as Names
FROM dbo.YourTable;
Another option since Lamak stole my thunder, would be to split it and normalize your data, and then aggregate. This uses a common split function but you could use anything, including STRING_SPLIT for SQL Server 2016+ or your own...
declare #table table (house varchar(16), names varchar(256))
insert into #table
values
('house 1','peter, paul, mary'),
('house 2','sarah, sally'),
('house 3','joe')
select
t.house
,NumberOfNames = count(s.Item)
from
#table t
cross apply dbo.DelimitedSplit8K(names,',') s
group by
t.house
Notice how the answers you are getting are quite complex for what they're doing? That's because relational databases are not designed to store data that way.
On the other hand, if you change your data structure to something like this:
house name
1 peter
1 paul
1 mary
2 sarah
2 sally
3 joe
The query now is:
select house, count(name)
from housenames
group by house
So my recommendation is to do that: use a design that's more suitable for SQL Server to work with, and your queries become simpler and more efficient.
One dirty trick is to replace commas with empty strings and compare the lengths:
SELECT house +
' has ' +
CAST((LEN(names) - LEN(REPLACE(names, ',', '')) + 1) AS VARCHAR) +
' names'
FROM mytable
You can parse using xml and find count as below:
Select *, a.xm.value('count(/x)','int') from (
Select *, xm = CAST('<x>' + REPLACE((SELECT REPLACE(names,', ','$$$SSText$$$') AS [*] FOR XML PATH('')),'$$$SSText$$$','</x><x>')+ '</x>' AS XML) from #housedata
) a
select House, 'has '+cast((LEN(Names)-LEN(REPLACE(Names, ',', ''))+1) as varchar)+' names'
from TempTable