The below is the query I'm using, I would like to add two more columns in the select statement which I have and noted them in the group by clause but the total results are different. The below script gives me the correct total count but I want to see the totals also for a column called transaction, and a column called employee. The total count should still be the same.
SELECT SUB.YEAR, SUM(SUB.TOTAL_COUNT), SUM(SUB.TOTAL_SPENT)
FROM (
SELECT YEAR, COUNT(*) AS TOTAL_COUNT, SUM($SPENTX) AS TOTAL_SPENT, CUSTOMERID
FROM TABLE A
WHERE YEAR = 2017
GROUP BY YEAR, CUSTOMERID
HAVING SUM($SPENTX)<=1000
) SUB
GROUP BY SUB.YEAR
Related
I have a table that contains unique transactions along with the year of the transaction and the employee who executed it. I need to find the employee with most transactions in each year.
I need a table with each year, the employee w/ most transactions in that year, and the number of transactions they had in that year.
This is as close as I am able to get without producing an error. I am unable to select the employee without producing an aggregation error.
select year, max(num_trans)
from (select year, employee, count(trans_id) as num_trans
from transactions
group by year, employee) as x
group by year
I am curious about how to work around this.
Use distinct on:
select distinct on (year) year, employee, count(*) as num_trans
from transactions
group by year, employee
order by year, count(*) desc;
distinct on is a handy Postgres extension to standard SQL that keeps the first row in a group of rows. The groups are defined by the distinct on key(s). Which row is first is determined by the order by.
I need to identify which Month has the most entries. Ive used the TO_DATE function to format the date column to just the MONTH. Also, SELECT COUNT(*) in combination with the GROUP BY Clause I am able to return all records month and count attributes.
However, I need to be able to only return one row that is the MAX of the COUNT. IVE atempted to do so by adding a HAVING clause but returns an error. I suspect I need a subquery in here somewhere but am unsure as to how to go about it.
SELECT TO_CHAR(P.DATEREGISTERED,'MONTH') MONTH, COUNT(*) COUNT
FROM PET P
GROUP BY TO_CHAR(P.DATEREGISTERED,'MONTH')
HAVING COUNT = MAX(COUNT);
Another Attempt:
SELECT TO_CHAR(P.DATEREGISTERED,'MONTH') MONTH, COUNT(*) COUNT
FROM PET P
GROUP BY TO_CHAR(P.DATEREGISTERED,'MONTH')
HAVING COUNT(*) = (SELECT MAX(TO_CHAR(P.DATEREGISTERED,'MONTH')) FROM PET P);
In the query with alias, you are grouping by Month and getting a count of the number of records and you are checking whether that count is same as the maximum of the "date value" converted to month string. They are not even comparisons of the same type.
The query that you have provided in the answer correctly compares the count on both sides.
Another way to rewrite the query would be
select * from
(SELECT TO_CHAR(P.DATEREGISTERED,'MONTH') MONTH, COUNT(*) COUNT
FROM PET P
GROUP BY TO_CHAR(P.DATEREGISTERED,'MONTH') order by count(*) desc )
where rownum=1
Here we order the records in the subquery by descending order of the count and then getting the first row from that.
The bellow code works and returns the correct response. It is unclear to me as to why it works but the above attempts (w/ aliases) do not.
SELECT TO_CHAR(P.DATEREGISTERED,'MONTH') MONTH, COUNT(*) COUNT
FROM PET P
GROUP BY TO_CHAR(P.DATEREGISTERED,'MONTH')
HAVING COUNT(*) = (SELECT MAX(COUNT(*)) FROM PET P GROUP BY TO_CHAR(P.DATEREGISTERED,'MONTH'));
SELECT price,total_price,SUM(mount) As TotalAmount
FROM sales
group by [date]
is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
You cannot select fields in the SELECT part which is not a part of an Aggregated function or specified in the the GROUP BY clause when using GROUP BY.
You can select "mount" because it's aggregated (SUM), but not price or total_price because they're not aggregated nor part of your group by date
You will need to either change your group by functionality, or the select part.
You have to group by the remaining tables that are not a function, therefore:
SELECT price,total_price,SUM(mount) As TotalAmount
FROM sales
Group by price,total_price
Order by date
I have a table made up of dates and sales totals for the particular date. I would like to be able to query the table and select the following: max sales, the date associated with the max sale figure, sum of all sales, and the minimum date in the table. One additional complication is that there are duplicate max values. I don't care which max value is chosen but I just want one at random. This is for Oracle.
Here is what I tried. It was using a sub query.
Select sales, date, min(date), sum(sales) from table
Where sales = (select distinct(max(sales)) from table)
select
max(sales),
max(date_) keep (dense_rank first order by sales desc),
sum(sales),
min(date_)
from
table_
See also This SQL Fiddle
I need to group by more than one columns but in special case:
I have a table of (Payment_Type,Year,TotalMoney)
I need to get sum of total grouping by payment_type(cash or credit) only and I need to select year in my query how can I do it? my query is:
select Payment_Type,Year,SUM(TotalMoney)
from table
where 1=1
group by Payment_Type,Year
I get an error message as:
Year is not contained in either an aggregate function or the GROUP BY clause
select Payment_Type,Year(YourDateColumn),SUM(TotalMoney)
from table
group by Payment_Type,Year(YourDateColumn)
if your column is named year then
select Payment_Type,[Year],SUM(TotalMoney)
from table
group by Payment_Type,[Year]