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I have a recycler view in my application and when the user clicks an item it opens a pop up menu. The user can change some values such as price quantity etc.
The problem occurs when I click the save button it closes the pop up menu but does not show the updated item.
I have set viewstates.visible for the items in the view holder that I want to become visible but when I clic the save button the updated item appears very briefly in a flash but then the item reverts to how it was previously?
If I then go back into the menu to update the qty and price again and press save it appears? But does not appear the first time.
I can provide code when I'm home but just wanted to get people's views as to why this may be happening?
I have set 2 textviews in the recycler view layout and upon creation of the recycler view these 2 textviews visibility is set to gone.
Once the save button is pressed I set the viewstates to visible but this problem occurs?
Do you want to achieve the result like following GIF?
First of all, If you want to update the item in recycleview, you should use mAdapter.NotifyItemChanged(e); method to update.
Based on your description, you push a custom Dialog, change the value in this Dialog, so you Dialog must return value when you change the some item value. So, you should make an event which returns the value when you dismiss the dialog
you would need to add something like:
public class DialogEventArgs : EventArgs
{
public MyModel MyModel { get; set; }
}
public delegate void DialogEventHandler(object sender, DialogEventArgs args);
and then in your dialog add:
public event DialogEventHandler Dismissed;
Then in BtnSaveClick add:
save.Click += (e, a) =>
{
myModel.Name = editText.Text;
if (null != Dismissed)
Dismissed(this, new DialogEventArgs { MyModel = myModel });
Dismiss();
};
Then where you create the dialog, which is probably where you want the value you subscribe to the Dismissed event:
private void MAdapter_ItemClick(object sender, int e)
{
//push a Dialog
var customDialog = new CustomDialog(this, myModels[e]);
customDialog.Show();
customDialog.Dismissed += (s, vee) => {
/* Update the recycleView */
myModels[e]= vee.MyModel;
mAdapter.NotifyItemChanged(e);
};
}
Here is my demo, you can download it and test it.
https://github.com/851265601/XAndroidRecycleViewUpdateOrClick
Related
Is it possible to override the response to a touch interaction for a control in UWP? For example, for a DataGrid XAML control, the default behavior when a row is tapped is to select this row and deselect all other selected rows. Can this be changed to have the tapped row added to the selection as if the control key was pressed?
EDIT: My solution is for Surface Pro in tablet mode so the user would only interact with the app via touch. So I wanted him to be able to select multiple items using touch only. In the image I added, the default behavior if the user clicks on "Chicken Sandwich" is to deselect "Burger" and select "Chicken Sandwich" unless the CTRL key is held down. However using the CTRL key on Surface device without mouse and keyboard would mean that we will need to have the on-screen keyboard on display which would be a bit cumbersome. I would like instead to change the default behavior where if the user clicks on an unselected item it's added to the selection, and if he clicks on a selected item the item it gets removed from selection (in the example below, "Chicken Sandwich" will be added to the selection on first touch and removed from selection on second tap), so basically same functionality as holding the CTRL key down but without using it.
Based on the document, the DataGrid class provides the behavior that selecting multiple items while holding down the SHIFT or CTRL keys during selection. What you need to do is just to set the SelectionMode property as Extended.
Update:
Please check the following code as a sample:
List<object> selectedItems = new List<object>();
bool flag = false;
private void dataGrid_SelectionChanged(object sender, SelectionChangedEventArgs e)
{
if(flag==false)
{
var item = dataGrid.SelectedItem;
if (selectedItems.Contains(item))
{
selectedItems.Remove(item);
}
else
{
selectedItems.Add(item);
}
flag = true;
dataGrid.SelectedItems.Clear();
foreach(var cur in selectedItems)
{
flag = true;
dataGrid.SelectedItems.Add(cur);
}
}
else
{
flag = false;
}
}
I have to detect a click in a row in a table in Cuba framework but I don't find how.
I have a TreeTable. Then I have a button. If I have nothing selected in the table, I want the button disabled. If I click on a item I want the button to be enabled. If I click on a sub-item, I want the button to be disabled.
It is possible, in the action of the button to use a:
trackSelection = true
That will work, but enabled the button too if I click on a sub-item.
Then The idea is, when anything is clicked on the table, then do something. I have only to track the selection of any item, and then do a logic.
How can I track this selection?
I have tried anything like:
table.setClickListener("columnId", new CellClickListener() {
#Override
public void onClick(Entity item, String columnId) {
// TODO Auto-generated method stub
LOG.info("On cell click");
}
});
First, that don't work, even if I click on a cell. Then even if it will work, I have the complete row and not only a cell.
Somebody have an idea?
Thanks
Best regards
You can react on selection change in Table using CollectionDatasource.ItemChangeListener:
employeesDs.addItemChangeListener(event -> {
log.info("Datasource {} item has been changed from {} to {}",
event.getDs(), event.getPrevItem(), event.getItem());
});
See also: https://doc.cuba-platform.com/manual-6.9/datasource_listeners.html
I am working on a Compact Framework application. This particular hardware implementation has a touchscreen, but its Soft Input Panel has buttons that are simply too small to be useful. There are more than one form where typed input is required, so I created a form with buttons laid out like a keypad. The forms that use this "keypad" form are modal dialogs. When a dialog requiring this "keypad" loads, I load the "keypad" form as modeless:
private void CardInputForm_Load(object sender, EventArgs e)
{
...
keypadForm = new KeypadForm();
keypadForm.Owner = this;
keypadForm.SetCallback(keyHandler);
keypadForm.Show();
}
The SetCallback method tells the "keypad" form where to send the keystrokes (as a Delegate).
The problem I'm having is that the modeless "keypad" form does not take input. It is displayed as I expect, but I get a beep when I press any of its buttons, and its caption is grayed-out. It seems like the modal dialog is blocking it.
I've read other posts on this forum that says modal dialogs can create & use modeless dialogs. Can anyone shed light on this situation? Is there a problem with my implementation?
I found the answer: Set the keypad form's Parent property, not its Owner property, to the form instance wanting the keystrokes. The keypad dialog's title bar stays grayed out, but the form is active.
private void CardInputForm_Load(object sender, EventArgs e)
{
// (do other work)
keypadForm = new KeypadForm();
keypadForm.Parent = this;
keypadForm.Top = 190; // set as appropriate
keypadForm.Show();
}
Be sure to clean up when done with the parent form. This can be in the parent's Closing or Closed events.
private void CardInputForm_Closing(object sender, CancelEventArgs e)
{
// (do other work)
keypadForm.Close();
keypadForm.Dispose();
}
There are two panels on the keypad form, one with numerals and one with letters and punctuation that I want. There is also an area not on a panel that is common to both, containing buttons for clear, backspace, enter/OK, and cancel. Each panel has a button to hide itself and unhide its counterpart ('ABC', '123', for example). I have all the buttons for input on the keypadForm fire a common event. All it does is send the button instance to the parent. The parent is responsible for determining what action or keystroke is desired. In my case I named the buttons "btnA", "btnB", "btn0", "btn1", "btnCancel", etc. For keystrokes, the parent form takes the last character of the name to determine what key is desired. This is a bit messy but it works. Any form wishing to use the keypad form inherits from a base class, defining a method for callback.
public partial class TimeClockBase : Form
{
public TimeClockBase()
{
InitializeComponent();
}
// (other implementation-specific base class functionality)
public virtual void KeyCallback(Button button)
{
}
}
The click event on the keypad form looks like this.
private void btnKey_Click(object sender, EventArgs e)
{
// play click sound if supported
(Parent as TimeClockBase).KeyCallback(sender as Button);
}
The method in the parent form looks like this.
public override void KeyCallback(Button button)
{
switch (button.Name)
{
case "btnCancel":
// setting result will cause form to close
DialogResult = DialogResult.Cancel;
break;
case "btnClear":
txtCardID.Text = string.Empty;
break;
// (handle other cases)
}
}
I'm trying to speed up my windows phone 7 page load times. I have a 'static' page that has a dynamically created in a Panorama control - static meaning that the content never changes.
On the first load I look at my config file, create the individual PanoramaItem controls and add them to the main Panorama control. I'm trying to keep a List in a static place so that the initial creation would only happen once and I could just add a fully rendered version to my Panorama control when the page was rendered.
Works fine on first load, but when I try to add the cached PanoramaItems to the Panorama control I get the message "Element is already the child of another element". This makes sense since I already added before. But I can see a way to disconnect the PanoramaItems with the first Panorama control...
I could be going about the control caching thing all wrong as well... Let me know if there's another way to do this.
You can use Panorama.Items.Remove(pivotItem) for this
As an example
With the following page fields
PanoramaItem pi;
bool blahShown = false;
On the press of this button, the control is first instantiated and displayed and on subsequent presses removed and readded without instantiation.
private void button1_Click(object sender, RoutedEventArgs e)
{
if (pi == null) {
pi = new PanoramaItem();
pi.Header = "blah";
}
if (blahShown) {
Pano.Items.Remove(pi);
blahShown = false;
} else {
Pano.Items.Add(pi);
blahShown = true;
}
}
i am facing one problem in SCSF.
I have two workspaces
MdiWorkspace
DeckWorkspace
i have two views in a module
Viewer (display in mdiworkspace)
Property Viewer (in deckworkspace)
in Viewer i have a button in toolbar whose purpose is to display PropertyViewer (another View).
how can i display this PropertyViewer in deckworkspace agaist button click event.
NOTE: i am not using Command[CommandName].AddInvoker(control, "click:) and CommandHandler
I'm going to assume your toolbar sits in a SmartPart that implements the MVP pattern. Have the button click event handler in the SmartPart fire an event that its presenter will handle. Your presenter code would look like this:
// Presenter code
protected override void OnViewSet()
{
this.View.ToolbarButtonClick += View_ToolbarButtonClick;
}
public void View_ToolbarButtonClick(object sender, EventArgs e)
{
// remove the handler so the property viewer
// will only be added the first time
this.View.OnToolbarButtonClick -= View_ToolbarButtonClick;
var propertyView = new PropertyViewer();
this.WorkItem.Workspaces[WorkspaceNames.MyDeckWorkspace].Show(propertyView);
}