I am using the following code to plot some data points and it works well in ggplot. However, when I feed this into ggplotly, the visualization and Y-axis labels change completely. Y-axis label shift to right and gets flipped, and the lines in the center get thinner.
Code
library(ggplot2)
library(tidyverse)
library(plotly)
file2 <- read.csv( text = RCurl::getURL("https://gist.githubusercontent.com/gireeshkbogu/806424c1777ff721a046b3e30e85af5a/raw/50ac0b4696f514677b4987b90305fdf879fbcd84/reproducible.examples.txt"), sep="\t")
p <- ggplot(data=subset(file2,!is.na(datetime)),
aes(x=datetime, y=Count,
color=Type,
group=Subject)) +
geom_point(size=4, alpha=0.6) +
scale_y_continuous(breaks=c(0,1))+
theme(axis.text.x=element_text(angle=90, size = 5))+
facet_grid(Subject ~ ., switch = "y") +
theme(axis.title.y=element_blank(),
axis.text.y=element_blank(),
axis.ticks.y=element_blank())+
theme(strip.text.y.left = element_text(angle = 0, size=5)) +
scale_color_manual(values=c("red", "#990000", "#330000", "#00CC99", "#0099FF"))
ggplotly(p)
Ggplot image
Ggplotly image
Reproducible Example
Subject datetime Type Count
user1 4/16/20 15:00 A1 1
user1 3/28/20 13:00 A1 1
user2 4/29/20 15:00 A1 1
user2 5/02/20 09:00 A1 1
user1 2/19/20 18:00 A2 1
user1 4/20/20 16:00 A2 1
Converting ggplot to plotly turns out to be surprisingly complicated! Many ggplot features are silently dropped or incorrectly translated over to plotly.
If I am not mistaken, switch = "y" within your facet_grid is being silently dropped.
In addition, you have too many facets in your plot. Looks like "Subject" is creating 30+ facets. I know that it is tempting to try and fit as much data into one plot, but you are really pushing the limits of what you can do with facets here.
I made some modifications. See if this is something you can work with:
library(ggplot2)
library(tidyverse)
library(plotly)
library(RCurl)
# your original file
file2 <- read.csv( text = RCurl::getURL("https://gist.githubusercontent.com/gireeshkbogu/806424c1777ff721a046b3e30e85af5a/raw/50ac0b4696f514677b4987b90305fdf879fbcd84/reproducible.examples.txt"), sep="\t")
head(file2)
# scaling down the dataframe so that you have fewer facets per plot
file3 <- file2 %>%
as_tibble() %>%
na.omit() %>%
filter(Subject %in% c("User1", "User2", "User3", "User4")) %>%
arrange(Subject, datetime)
head(file3)
# sending the smaller data frame to ggplot
p_2 <- ggplot(data=file3,
aes(x=datetime, y=Count, color=Type, group=Subject)) +
geom_point(size=4, alpha=0.6) +
scale_y_continuous(breaks=c(0,1))+
theme(axis.text.x=element_text(angle=90, size = 5)) +
facet_grid(Subject ~ .) + # removing "Switch" ; it is being dropped by plotly
theme(axis.title.y=element_blank(),
axis.text.y=element_blank(),
axis.ticks.y=element_blank(),
legend.position = "left") + # move legend to left on ggplot
theme(strip.text.y.left = element_text(angle = 0, size=5)) +
scale_color_manual(values=c("red", "#990000", "#330000", "#00CC99", "#0099FF"))
p_2
ggplotly(p_2) %>%
layout(title = "Modified & Scaled Down Plot",
legend = list(orientation = "v", # fine-tune legend directly in plotly,
y = 1, x = -0.1)) # you may need to fiddle with these
The modified code yields me this plot. You will probably need to make a few small groups by "Subject" and call a plot for each group.
Related
I'm working with a subset of weather data for Heathrow downloaded Met Office data. This data set contains no missing values.
Using ggplot, I'd like to create a scatter plot for the maximum temperature (tmax) for Heathrow, with 2018 data plotted against 2019 data (see below for example). There are 12 data points for both 2018 and 2019.
I've attempted this with the below, however it does not work. This appears to be due to the indexing as the code works fine when not attempting to use the indexes within the aes() function.
How can I get this to work?
2018Index <- which(HeathrowData$Year == 2018)
2019Index <- which(HeathrowData$Year == 2019)
scatter<-ggplot(HeathrowData, aes(tmax[2018Index], tmax[2019Index]))
scatter + geom_point()
scatter + geom_point(size = 2) + labs(x = "2018", y = "2019"))
As your data is in long format you need some data wrangling to put the values for your years in separate columns aka you have to reshape your data to wide:
Using some random fake data:
library(dplyr)
library(tidyr)
library(ggplot2)
# Example data
set.seed(123)
HeathrowData <- data.frame(
Year = rep(2017:2019, each = 12),
tmax = runif(36)
)
# Select, Filter, Convert to Wide
HeathrowData <- HeathrowData %>%
select(Year, tmax) %>%
filter(Year %in% c(2018, 2019)) %>%
group_by(Year) %>%
mutate(id = row_number()) %>%
ungroup() %>%
pivot_wider(names_from = Year, values_from = tmax, names_prefix = "y")
ggplot(HeathrowData, aes(y2018, y2019)) +
geom_point(size = 2) +
labs(x = "2018", y = "2019")
I am using the plot_grid() function of the cowplot package to draw ggplots in a grid and would like to know if there is a way to draw plots by column instead of by row?
library(ggplot2)
library(cowplot)
df <- data.frame(
x = c(3,1,5,5,1),
y = c(2,4,6,4,2)
)
# Create plots: say two each of path plot and polygon plot
p <- ggplot(df)
p1 <- p + geom_path(aes(x,y)) + ggtitle("Path 1")
p2 <- p + geom_polygon(aes(x,y)) + ggtitle("Polygon 1")
p3 <- p + geom_path(aes(y,x)) + ggtitle("Path 2")
p4 <- p + geom_polygon(aes(y,x)) + ggtitle("Polygon 2")
plots <- list(p1,p2,p3,p4)
plot_grid(plotlist=plots, ncol=2) # plots are drawn by row
I would like to have plots P1 and P2 in the first column and p3 and p4 in the second column, something like:
plots <- list(p1, p3, p2, p4) # plot sequence changed
plot_grid(plotlist=plots, ncol=2)
Actually I could have 4, 6, or 8 plots. The number of rows in the plot grid will vary but will always have 2 columns. In each case I would like to fill the plot grid by column (vertically) so my first 2, 3, or 4 plots, as the case maybe, appear over each other. I would like to avoid hardcode these different permutations if I can specify something like par(mfcol = c(n,2)).
As you have observed, plot_grid() draws plots by row. I don't believe there's any way to change that, so if you want to maintain using plot_grid() (which would be probably most convenient), then one approach could be to change the order of the items in your list of plots to match what you need for plot_grid(), given knowledge of the number of columns.
Here's a function I have written that does that. The basic idea is to:
create a list of indexes for number of items in your list (i.e. 1:length(your_list)),
put the index numbers into a matrix with the specified number of rows,
read back that matrix into another vector of indexes by column
reorder your list according to the newly ordered indexes
I've tried to build in a way to make this work even if the number of items in your list is not divisible by the intended number of columns (like a list of 8 items arranged in 3 columns).
reorder_by_col <- function(myData, col_num) {
x <- 1:length(myData) # create index vector
length(x) <- prod(dim(matrix(x, ncol=col_num))) # adds NAs as necessary
temp_matrix <- matrix(x, ncol=col_num, byrow = FALSE)
new_x <- unlist(split(temp_matrix, rep(1:ncol(temp_matrix), each=row(temp_matrix))))
names(new_x) <- NULL # not sure if we need this, but it forces an unnamed vector
return(myData[new_x])
}
This all was written with a little help from Google and specifically answers to questions posted here and here.
You can now see the difference without reordering:
plots <- list(p1,p2,p3,p4)
plot_grid(plotlist=plots, ncol=2)
... and with reordering using the new method:
newPlots <- reorder_by_col(myData=plots, col_num=2)
plot_grid(plotlist=newPlots, ncol=2)
The argument, byrow, has now been added to plot_grid.
In the case where you would like to have num_plots < nrow * ncol the remaining spots will be empty.
You can now call:
library(ggplot2)
df <- data.frame(
x = 1:10, y1 = 1:10, y2 = (1:10)^2, y3 = (1:10)^3, y4 = (1:10)^4
)
p1 <- ggplot(df, aes(x, y1)) + geom_point()
p2 <- ggplot(df, aes(x, y2)) + geom_point()
p3 <- ggplot(df, aes(x, y3)) + geom_point()
cowplot::plot_grid(p1, p2, p3, byrow = FALSE)
I am trying to create a graph based on matrix similar to one below... I am trying to group the Erosion values based on "Slope"...
library(ggplot2)
new_mat<-matrix(,nrow = 135, ncol = 7)
colnames(new_mat)<-c("Scenario","Runoff (mm)","Erosion (t/ac)","Slope","Soil","Tillage","Rotation")
for ( i in 1:nrow(new_mat)){
new_mat[i,2]<-sample(10:50, 1)
new_mat[i,3]<-sample(0.1:20, 1)
new_mat[i,4]<-sample(c("S2","S3","S4","S5","S1"),1)
new_mat[i,5]<-sample(c("Deep","Moderate","Shallow"),1)
new_mat[i,7]<-sample(c("WBP","WBF","WF"),1)
new_mat[i,6]<-sample(c("Intense","Reduced","Notill"),1)
new_mat[i,1]<-paste0(new_mat[i,4],"_",new_mat[i,5],"_",new_mat[i,6],"_",new_mat[i,7],"_")
}
#### Graph part ########
grphs_mat<-as.data.frame(new_mat)
grphs_mat$`Runoff (mm)`<-as.numeric(as.character(grphs_mat$`Runoff (mm)`))
grphs_mat$`Erosion (t/ac)`<-as.numeric(as.character(grphs_mat$`Erosion (t/ac)`))
ggplot(grphs_mat, aes(Scenario, `Erosion (t/ac)`,group=Slope, colour = Slope))+
scale_y_continuous(limits=c(0,max(as.numeric((grphs_mat$`Erosion (t/ac)`)))))+
geom_point()+geom_line()
But when i run this code.. The values are distributed in x-axis for all 135 scenarios. But what i want is grouping to be done in terms of slope but it also picks up the other common factors such as Soil+Rotation+Tillage and place it in x-axis. For example:
For these five scenarios:
S1_Deep_Intense_WBF_
S2_Deep_Intense_WBF_
S3_Deep_Intense_WBF_
S4_Deep_Intense_WBF_
S5_Deep_Intense_WBF_
It separates the S1, S2, S3,S4,S5 but also be able to know that other factors are same and put them in x-axis such that the slope lines are stacked on top of each other in 135/5 = 27 x-axis points. The final figure should look like this (Refer image). Apologies for not being able to explain it better.
I think i am making a mistake in grouping or assigning the x-axis values.
I will appreciate your suggestions.
In the example you give, I didn't get every possible factor combination represented so the plots looked a bit weird. What I did instead was start with the following:
set.seed(42)
new_mat <- matrix(,nrow = 1000, ncol = 7)
And then deduplicated this by summarising the values. A possible relevant step here for you analysis is that I made new variable with the interaction() function that is the combination of three other factors.
library(tidyverse)
df <- grphs_mat
df$x <- with(df, interaction(Rotation, Soil, Tillage))
# The simulation did not yield unique combinations
df <- df %>% group_by(x, Slope) %>%
summarise(n = sum(`Erosion (t/ac)`))
Next, I plotted this new x variable on the x-axis and used "stack" positions for the lines and points.
g <- ggplot(df, aes(x, y = n, colour = Slope, group = Slope)) +
geom_line(position = "stack") +
geom_point(position = "stack")
To make the x-axis slightly more readable, you can replace the . that the interaction() function placed by newlines.
g + scale_x_discrete(labels = function(x){gsub("\\.", "\n", x)})
Another option is to simply rotate the x axis labels:
g + theme(axis.text.x.bottom = element_text(angle = 90))
There are a few additional options for the x-axis if you go into ggplot2 extension packages.
I'm new here and would really appreciate some help! I've got a simple r script to plot log transformed data using ggplot and also plot on the 95% confidence and prediction intervals. However, I'm stuck on how to format the axes... I'd like them to be in log scale. I learned this from a tutorial and have tried to go through the script then transform the axes, but it messes up the confidence intervals.
I've tried using:
scale_y_continuous(trans=log2_trans())+
scale_x_continuous(trans=log2_trans())
but that doesn't transform the 95% confidence interval... Any suggestions would be appreciated! Basically, I'm just looking for an easy way to get log scales that look nice on the already nice graph.
Here's my code (I didn't include all the data just a bit for reference):
x <- c(6135.0613509,945.2650501,1927.8260200,110.0000000,
3812.9674276,3.2991626,1173.4923354,945.2650501,
114.2114798,11.2463797)
y <- c(370.00,32.00,2900.00,52.00,1500.00,0.06,16.00,50.00,5.00,11.00)
df <- data.frame(x, y)
# Log transformation
log_x <- log(x)
log_y <- log(y)
# Plot
plot(log_x,log_y)
# Linear Regression - linear model function
model1 <- lm(log_y ~ log_x, data = df)
summary(model1)
abline(model1, col = "lightblue") # Add trendline to plot of log transformed
data
# load ggplot2
library(ggplot2)
# Confidence and Prediction intervals
temp_var <- predict(model1, interval = "prediction")
## Warning in predict.lm(model1, interval = "prediction"): predictions on
## current data refer to _future_ responses
new_df <- cbind(df, temp_var)
ggplot(new_df, aes(log_x, log_y))+
geom_point() +
geom_line(aes(y = lwr), color = "red", linetype = "dashed")+
geom_line(aes(y = upr), color = "red", linetype = "dashed")+
geom_smooth(method = lm, se = TRUE)
I have the following two-part plot which are not aligned:
Side-by-side plots not aligned
These plots are produced by the following code:
require(ggplot2)
require(gridExtra)
set.seed(0)
data <- data.frame(x=rpois(30,5),y=rpois(30,11),z=rpois(300,25))
left.plot <- ggplot(data,aes(x,y))
+ geom_bin2d(binwidth=1)
margin.data <- as.data.frame( margin.table(table(data),1))
right.plot <- ggplot(margin.data, aes(x=x,y=Freq))
+ geom_bar(stat="identity")+coord_flip()
grid.arrange(left.plot, right.plot, ncol=2)
How can I align the rows in the left plot to the bars in the right plot?
Your issues are simple, albeit twofold.
Ultimately you need to use scale_y_continuous() and scale_x_continuous() to set your axis limits to match on eatch figure. That's impeded by the fact that the x value is a factor. Convert it to a numeric and throw in some scaling and you're good to go.
left.plot <- ggplot(data,aes(x,y)) +
geom_bin2d(binwidth=1) +
scale_y_continuous(limits = c(1, 16))
margin.data <- as.data.frame( margin.table(table(data),1))
right.plot <- ggplot(margin.data, aes(x=as.numeric(as.character(x)),y=Freq)) +
geom_bar(stat="identity") +
scale_x_continuous(limits = c(1, 16)) +
xlab("x") +
coord_flip()
Using package ggExtra I was able to get an almost solution
require(ggplot2)
require(ggExtra)
set.seed(0)
data <- data.frame(x=rpois(30,5),y=rpois(30,11),z=rpois(300,25))
left.plot <- ggplot(data,aes(x,y)) + geom_bin2d(binwidth=1)
ggMarginal(left.plot, margins="y", type = "histogram", size=2,bins=(max(data$y)-min(data$y)+1),binwidth=1.06)
I say almost because I had to set manually binwidth=1.06 to align bar and counts.
Manually aligned plots using ggExtra::ggMarginal