Grouping the Child with no common key values using XSLT - xslt-1.0

Below is my input XML. Here I have two different SHOWSHIPMENT files and I want to merge them to one using the data of the first occurrence of SHOWSHIPMENT for all the fields and grouping the second RL_DEATILS into the first SHOWSHIPMENT
INPUT:
<SHOW>
<SHOWSHIPMENT>
<APPLICATIONAREA>
<SENDER>
<LOGICALID>ABC</LOGICALID>
</SENDER>
<RECEIVERID>220911</RECEIVERID>
</APPLICATIONAREA>
<DATAAREA>
<SHIPMENT>
<X_DLV_TAB_ITEM>
<TYPE>A</TYPE>
<TRANSACTION_CODE>RC</TRANSACTION_CODE>
</X_DLV_TAB_ITEM>
<X_DLV_TAB>
<X_DLV_TAB_ITEM>
<TYPE>A</TYPE>
<TRANSACTION_CODE>RC</TRANSACTION_CODE>
<DELIVERY_ID>46689764</DELIVERY_ID>
<NAME>46689764</NAME>
</X_DLV_TAB_ITEM>
<RL_DETAILS>
<ITEM>ONE</ITEM>
<RL_DETAILS_ITEM>
<DELIVERY_DETAIL_ID>14460996</DELIVERY_DETAIL_ID>
<GROSS_WEIGHT>11</GROSS_WEIGHT>
<WEIGHT_UOM_CODE>LB</WEIGHT_UOM_CODE>
<VOLUME>0.2</VOLUME>
<VOLUME_UOM_CODE>CF</VOLUME_UOM_CODE>
<REQUESTED_QUANTITY>5</REQUESTED_QUANTITY>
</RL_DETAILS_ITEM>
</RL_DETAILS>
</X_DLV_TAB>
</SHIPMENT>
</DATAAREA>
</SHOWSHIPMENT>
<SHOWSHIPMENT>
<APPLICATIONAREA>
<SENDER>
<LOGICALID>XYZ</LOGICALID>
</SENDER>
<RECEIVERID>220911</RECEIVERID>
</APPLICATIONAREA>
<DATAAREA>
<SHIPMENT>
<X_DLV_TAB_ITEM>
<TYPE>B</TYPE>
<TRANSACTION_CODE>AB</TRANSACTION_CODE>
</X_DLV_TAB_ITEM>
<X_DLV_TAB>
<X_DLV_TAB_ITEM>
<TYPE>B</TYPE>
<TRANSACTION_CODE>AB</TRANSACTION_CODE>
<DELIVERY_ID>466897665</DELIVERY_ID>
<NAME>46689765</NAME>
</X_DLV_TAB_ITEM>
<RL_DETAILS>
<ITEM>TWO</ITEM>
<RL_DETAILS_ITEM>
<DELIVERY_DETAIL_ID>14460997</DELIVERY_DETAIL_ID>
<GROSS_WEIGHT>5.28333</GROSS_WEIGHT>
<WEIGHT_UOM_CODE>LB</WEIGHT_UOM_CODE>
<VOLUME>0.12</VOLUME>
<VOLUME_UOM_CODE>CF</VOLUME_UOM_CODE>
<REQUESTED_QUANTITY>3</REQUESTED_QUANTITY>
</RL_DETAILS_ITEM>
</RL_DETAILS>
</X_DLV_TAB>
</SHIPMENT>
</DATAAREA>
</SHOWSHIPMENT>
</SHOW>
OUTPUT:
<SHOW>
<SHOWSHIPMENT>
<APPLICATIONAREA>
<SENDER>
<LOGICALID>ABC</LOGICALID>
</SENDER>
<RECEIVERID>220911</RECEIVERID>
</APPLICATIONAREA>
<DATAAREA>
<SHIPMENT>
<X_DLV_TAB_ITEM>
<TYPE>A</TYPE>
<TRANSACTION_CODE>RC</TRANSACTION_CODE>
</X_DLV_TAB_ITEM>
<X_DLV_TAB>
<X_DLV_TAB_ITEM>
<TYPE>A</TYPE>
<TRANSACTION_CODE>RC</TRANSACTION_CODE>
<DELIVERY_ID>46689764</DELIVERY_ID>
<NAME>46689764</NAME>
</X_DLV_TAB_ITEM>
<RL_DETAILS>
<ITEM>ONE</ITEM>
<RL_DETAILS_ITEM>
<DELIVERY_DETAIL_ID>14460996</DELIVERY_DETAIL_ID>
<GROSS_WEIGHT>11</GROSS_WEIGHT>
<WEIGHT_UOM_CODE>LB</WEIGHT_UOM_CODE>
<VOLUME>0.2</VOLUME>
<VOLUME_UOM_CODE>CF</VOLUME_UOM_CODE>
<REQUESTED_QUANTITY>5</REQUESTED_QUANTITY>
</RL_DETAILS_ITEM>
</RL_DETAILS>
<RL_DETAILS>
<ITEM>TWO</ITEM>
<RL_DETAILS_ITEM>
<DELIVERY_DETAIL_ID>14460997</DELIVERY_DETAIL_ID>
<GROSS_WEIGHT>5.28333</GROSS_WEIGHT>
<WEIGHT_UOM_CODE>LB</WEIGHT_UOM_CODE>
<VOLUME>0.12</VOLUME>
<VOLUME_UOM_CODE>CF</VOLUME_UOM_CODE>
<REQUESTED_QUANTITY>3</REQUESTED_QUANTITY>
</RL_DETAILS_ITEM>
</RL_DETAILS>
</X_DLV_TAB>
</SHIPMENT>
</DATAAREA>
</SHOWSHIPMENT>
</SHOW>
In the SHOWSHIPMENT I have X_DLV_TAB_ITEM repeated twice at two different levels SHIPMENT/X_DLV_TAB_ITEM and SHIPMENT/X_DLV_TAB/X_DLV_TAB_ITEM.
Thanks Maryann.


Perhaps I am missing something, but this seems rather simple:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/SHOW">
<!-- process only 1st SHOWSHIPMENT -->
<xsl:apply-templates select="SHOWSHIPMENT[1]"/>
</xsl:template>
<xsl:template match="X_DLV_TAB">
<xsl:copy>
<xsl:apply-templates/>
<!-- add RL_DETAILS from 2nd SHOWSHIPMENT -->
<xsl:apply-templates select="/SHOW/SHOWSHIPMENT[2]/DATAAREA/SHIPMENT/X_DLV_TAB/RL_DETAILS"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

Related

Removing Parent Nodes without affecting child nodes

The XML output i am getting is not in the format that i require so tried some code to change the format but was unable to
This is the output that i am getting
<?xml version="1.0" encoding="UTF-8"?>
<Envelope xmlns="http://schemas.microsoft.com/dynamics/2011/01/documents/Message">
<Header>
<MessageId>{A124-B421-C325-D467}</MessageId>
<Action>find</Action>
</Header>
<Body>
<MessageParts xmlns="http://schemas.microsoft.com/dynamics/2011/01/documents/Message">
<Run xmlns="http://schemas.microsoft.com/dynamics/2008/01/documents/Run">
<RunObject class="entity">
<A1>NA</A1>
<A2>False</A2>
<A3>02</A3>
<A4>ER</A4>
</RunObject>
<RunObject class="entity">
<A1>NA</A1>
<A2>False</A2>
<A3>03</A3>
<A4>ER</A4>
</RunObject>
</Run>
</MessageParts>
</Body>
</Envelope>
This is the XML output that i require
<?xml version="1.0" encoding="UTF-8"?>
<Document>
<Item>
<A3>NA</A3>
<A4>False</A4>
<A2>02</A2>
<A1>ER</A1>
</Item>
<Item>
<A3>NA</A3>
<A4>False</A4>
<A2>03</A2>
<A1>ER</A1>
</Item>
</Document>
This is the code that i have used to change the format of the xml that i was getting
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:m="http://schemas.microsoft.com/dynamics/2011/01/documents/Message"
xmlns:r="http://schemas.microsoft.com/dynamics/2008/01/documents/Run"
exclude-result-prefixes="m r">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- move all elements to no namespace -->
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="m:Envelope"/>
<xsl:template match="m:Header"/>
<xsl:template match="m:MessageId"/>
<xsl:template match="m:Action"/>
<xsl:template match="m:Body"/>
<!-- rename MessageParts to Document + skip the Run wrapper -->
<xsl:template match="m:MessageParts">
<Document>
<xsl:apply-templates select="r:Run/*"/>
</Document>
</xsl:template>
<!-- rename RunObject to Item + reorder child nodes -->
<xsl:template match="r:RunObject[#class='entity']">
<Item>
<xsl:apply-templates select="r:A3" />
<xsl:apply-templates select="r:A4" />
<xsl:apply-templates select="r:A2" />
<xsl:apply-templates select="r:A1" />
</Item>
</xsl:template>
</xsl:stylesheet>
I tried the above code but was not able to change the format of the xml

Instead of:
<xsl:template match="m:Envelope"/>
that removes the Envelope node and all its descendants, you need to remove only the Envelope wrapper and continue processing its contents:
<xsl:template match="m:Envelope">
<xsl:apply-templates/>
</xsl:template>
Likewise for the other wrappers. In fact, you could replace all of these:
<xsl:template match="m:Envelope"/>
<xsl:template match="m:Header"/>
<xsl:template match="m:MessageId"/>
<xsl:template match="m:Action"/>
<xsl:template match="m:Body"/>
with:
<xsl:template match="m:*">
<xsl:apply-templates select="*"/>
</xsl:template>

Changing the output of xml using xslt

How to change the output of the xml.
This is the output that i am getting.
<?xml version="1.0" encoding="UTF-8"?>
<Envelope xmlns="http://schemas.microsoft.com/dynamics/2011/01/documents/Message">
<Header> </Header>
<Body>
<MessageParts xmlns="http://schemas.microsoft.com/dynamics/2011/01/documents/Message">
<Run xmlns="http://schemas.microsoft.com/dynamics/2008/01/documents/Run">
<RunObject class="entity">
<A1>NA</A1>
<A2>False</A2>
<A3>02</A3>
<A4>ER</A4>
</RunObject>
<RunObject class="entity">
<A1>NA</A1>
<A2>False</A2>
<A3>03</A3>
<A4>ER</A4>
</RunObject>
</Run>
</MessageParts>
</Body>
</Envelope>
And the output that i want is this
<?xml version="1.0" encoding="UTF-8"?>
<Envelope>
<Header> </Header>
<Body>
<Document>
<Item>
<A1>NA</A1>
<A2>False</A2>
<A3>02</A3>
<A4>ER</A4>
</Item>
<Item>
<A1>NA</A1>
<A2>False</A2>
<A3>03</A3>
<A4>ER</A4>
</Item>
</Document>
</Body>
</Envelope>
I have tried various things but still i am not to make one final change.
I am not able to change <Runobject class="Entity"> to <Item>.
This the xslt code that i used to alter the xml format
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:s="http://schemas.microsoft.com/dynamics/2008/01/documents/Run"
>
<xsl:output method="xml" indent="yes"/>
**Removes the run tag along with the namespace
<xsl:template match="s:Run">
<xsl:apply-templates select="*"/>
</xsl:template>
**Copies all the tags
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
**Used this code to replace the <RunObject class="entity"> with <Item> but is not working
<xsl:template match="RunObject[#class='Entity']">
<xsl:element name="Item">
<xsl:apply-templates />
</xsl:element>
</xsl:template>
**Removes all namespaces
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#* | node()"/>
</xsl:element>
</xsl:template>
**Copies attributes
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
<!-- template to copy the rest of the nodes -->
<xsl:template match="comment() | text() | processing-instruction()">
<xsl:copy/>
</xsl:template>
</xsl:stylesheet>
I am fairly new to xslt so i mght have certain mistakes while writing the code

There are two reasons why your template:
<xsl:template match="RunObject[#class='Entity']">
<xsl:element name="Item">
<xsl:apply-templates />
</xsl:element>
</xsl:template>
does not match anything:
RunObject is in a namespace, and you are not using a prefix;
XML is case-sensitive; the class attribute contains "entity", not "Entity".
It should work if you do:
<xsl:template match="s:RunObject[#class='entity']">
<xsl:element name="Item">
<xsl:apply-templates />
</xsl:element>
</xsl:template>
Other than that, I believe you could shorten the entire thing considerably - say:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:m="http://schemas.microsoft.com/dynamics/2011/01/documents/Message"
xmlns:r="http://schemas.microsoft.com/dynamics/2008/01/documents/Run"
exclude-result-prefixes="m r">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- move all elements to no namespace -->
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<!-- rename MessageParts to Document + skip the Run wrapper -->
<xsl:template match="m:MessageParts">
<Document>
<xsl:apply-templates select="r:Run/*"/>
</Document>
</xsl:template>
<!-- rename RunObject to Item -->
<xsl:template match="r:RunObject[#class='entity']">
<Item>
<xsl:apply-templates />
</Item>
</xsl:template>
</xsl:stylesheet>

How to remove Namespaces when copying nodes to a different node in XML through XSLT1.0?

I'm new to XSL and i'm trying to copy a node of XML to another node in the same XML using XSLT. I can able to transform the file as expected but the XMLNS attribute is getting added to the destination which I don't want.
I have tried all the option of copy-namespaces='no' using XSLT2.0 but that doesn't work. Also, I cant have a prefix of namespaces in the XSLT and use exclude namespaces to avoid xmlns because the incoming XML file is dynamic and namespaces keep on changing. I can't have all the namespaces declared as a prefix in XSLT.
Incoming XML:
<?xml version="1.0" encoding="UTF-8"?>
<PropertySet>
<Message>
<NotificationHeader>
<BusinessId></BusinessId>
<CorrelationId>0201201916:21:24CKG3N</CorrelationId>
<SourceName></SourceName>
<SourceId></SourceId>
<EventType></EventType>
<SecurityIdentifierId></SecurityIdentifierId>
<ClientRequestId></ClientRequestId>
<TargetId>ESB</TargetId>
<EventTime></EventTime>
<RequestUser></RequestUser>
</NotificationHeader>
<EventList>
<Event>
<PayLoad>
<ListOfActionIo xmlns="http://www.test.com/IO">
<Action>
<ActivityId>4-309C7WV</ActivityId>
<ActivitySRId></ActivitySRId>
<ActivityTemplateId></ActivityTemplateId>
<ActivityUID>4-309C7WV</ActivityUID>
<Category> Notification</Category>
<Comment></Comment>
<Type>Action</Type>
<ListOfDestination>
<Destination>
<DestinationName>NSW Aboriginal Education Consultative Group Incorporated</DestinationName>
</Destination>
<Destination>
<DestinationName>NSW Aboriginal Education Consultative Group Incorporated</DestinationName>
</Destination>
</ListOfDestination>
</Action>
</ListOfActionIo>
</PayLoad>
</Event>
</EventList>
<DestinationList>
<Destination>
<DestinationName></DestinationName>
<DestinationId></DestinationId>
</Destination>
</DestinationList>
</Message>
</PropertySet>
XSLT Code:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes" method="xml" encoding="UTF-8"/>
<xsl:strip-space elements="*"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="//*[name()='Message']/*[name()='DestinationList']//*[name()='Destination']"></xsl:template>
<!--Copy the destination from one node to another node-->
<xsl:template match="//*[name()='Message']/*[name()='DestinationList']">
<xsl:copy>
<xsl:copy-of select="//*[name()='Message']/*[name()='EventList']//*[name()='Destination']"/>
</xsl:copy>
</xsl:template>
<!--Remove the original node from where the destination was copied-->
<xsl:template match="//*[name()='Message']/*[name()='EventList']//*[name()='ListOfDestination']"></xsl:template>
</xsl:stylesheet>
Output:
<PropertySet>
<Message>
<NotificationHeader>
<BusinessId/>
<CorrelationId>0201201916:21:24CKG3N</CorrelationId>
<SourceName/>
<SourceId/>
<EventType/>
<SecurityIdentifierId/>
<ClientRequestId/>
<TargetId>ESB</TargetId>
<EventTime/>
<RequestUser/>
</NotificationHeader>
<EventList>
<Event>
<PayLoad>
<ListOfActionIo xmlns="http://www.test.com/IO">
<Action>
<ActivityId>4-309C7WV</ActivityId>
<ActivitySRId/>
<ActivityTemplateId/>
<ActivityUID>4-309C7WV</ActivityUID>
<Category> Notification</Category>
<Comment/>
<Type>Action</Type>
</Action>
</ListOfActionIo>
</PayLoad>
</Event>
</EventList>
<DestinationList>
<Destination xmlns="http://www.test.com/IO">
<DestinationName>NSW Aboriginal Education Consultative Group Incorporated</DestinationName>
</Destination>
<Destination xmlns="http://www.test.com/IO">
<DestinationName>NSW Aboriginal Education Consultative Group Incorporated</DestinationName>
</Destination>
</DestinationList>
</Message>
</PropertySet>
Expected Output:
Without the Namespaces on the copied node.
<PropertySet>
<Message>
<NotificationHeader>
<BusinessId/>
<CorrelationId>0201201916:21:24CKG3N</CorrelationId>
<SourceName/>
<SourceId/>
<EventType/>
<SecurityIdentifierId/>
<ClientRequestId/>
<TargetId>ESB</TargetId>
<EventTime/>
<RequestUser/>
</NotificationHeader>
<EventList>
<Event>
<PayLoad>
<ListOfActionIo xmlns="http://www.test.com/IO">
<Action>
<ActivityId>4-309C7WV</ActivityId>
<ActivitySRId/>
<ActivityTemplateId/>
<ActivityUID>4-309C7WV</ActivityUID>
<Category> Notification</Category>
<Comment/>
<Type>Action</Type>
</Action>
</ListOfActionIo>
</PayLoad>
</Event>
</EventList>
<DestinationList>
<Destination>
<DestinationName>NSW Aboriginal Education Consultative Group Incorporated</DestinationName>
</Destination>
<Destination>
<DestinationName>NSW Aboriginal Education Consultative Group Incorporated</DestinationName>
</Destination>
</DestinationList>
</Message>
</PropertySet>

You are asking the wrong question. You don't want to "remove namespaces" - you want to change the namespace of transformed elements. This is akin to renaming the elements.
Now, since your example is confusing (and too long), consider the following:
XML
<root>
<colors>
<color>red</color>
<color>blue</color>
</colors>
<shapes xmlns="some-unknown-namespace">
<shape>circle</shape>
<shape>square</shape>
</shapes>
<sizes>
<size>small</size>
<size>large</size>
</sizes>
</root>
To change the namespace of shapes (and its descendants, that inherit it!) to no-namespace, without knowing in advance what the original namespace will be, you can do:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[ancestor-or-self::*[name()='shapes']]">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Result
<?xml version="1.0" encoding="UTF-8"?>
<root>
<colors>
<color>red</color>
<color>blue</color>
</colors>
<shapes>
<shape>circle</shape>
<shape>square</shape>
</shapes>
<sizes>
<size>small</size>
<size>large</size>
</sizes>
</root>
Added:
lets modify the code to move the shapes into sizes and remove the shapes node.
OK, let's do that:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="sizes">
<xsl:copy>
<xsl:apply-templates/>
<!-- move the shapes into sizes -->
<xsl:apply-templates select="../*[name()='shapes']/*"/>
</xsl:copy>
</xsl:template>
<!-- remove the shapes element -->
<xsl:template match="*[name()='shapes']"/>
<xsl:template match="*[ancestor::*[name()='shapes']]">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Result
<?xml version="1.0" encoding="UTF-8"?>
<root>
<colors>
<color>red</color>
<color>blue</color>
</colors>
<sizes>
<size>small</size>
<size>large</size>
<shape>circle</shape>
<shape>square</shape>
</sizes>
</root>

XSLT get Node by Index

i am beginner in XSLT and i am using it to transform XML to XML
This is the source XML i receive
Source XML:
<Response>
<Pax>
<Id>1</Id>
</Pax>
<Pax>
<Id>2</Id>
</Pax>
<Travelers>
<Traveler>
<Name>ABC</Name>
</Traveler>
<Traveler>
<Name>XYZ</Name>
</Traveler>
</Travelers>
</Response>
I have written below XSLT
XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="xml" indent="yes" />
<xsl:template match="Response">
<xsl:element name="Root">
<xsl:apply-templates select="Travelers/Traveler"/>
</xsl:element>
</xsl:template>
<xsl:template match="Traveler">
<xsl:element name="Person">
<xsl:element name="PId">
<xsl:value-of select="//Pax/Id[position()]" />
</xsl:element>
<xsl:element name="Name">
<xsl:value-of select="Name" />
</xsl:element>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Output:
<Root>
<Person>
<PId>1</PId>
<Name>ABC</Name>
</Person>
<Person>
<PId>1</PId>
<Name>XYZ</Name>
</Person>
</Root>
I would like to generate below XML output
Expected Output:
<Root>
<Person>
<PId>1</PId>
<Name>ABC</Name>
</Person>
<Person>
<PId>2</PId>
<Name>XYZ</Name>
</Person>
</Root>
As shown in above XML the only issue is with PId, it should have value 2.
Please help. Thanks.

Here's a relatively simple solution.
When this XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output omit-xml-declaration="yes" indent="yes" />
<xsl:strip-space elements="*" />
<xsl:template match="/*">
<Root>
<xsl:apply-templates select="Pax" />
</Root>
</xsl:template>
<xsl:template match="Pax">
<xsl:variable name="vPosition" select="position()" />
<Person>
<PId>
<xsl:value-of select="Id" />
</PId>
<Name>
<xsl:value-of select="/*/Travelers/*[$vPosition]/Name" />
</Name>
</Person>
</xsl:template>
</xsl:stylesheet>
...is applied to the original XML:
<Response>
<Pax>
<Id>1</Id>
</Pax>
<Pax>
<Id>2</Id>
</Pax>
<Travelers>
<Traveler>
<Name>ABC</Name>
</Traveler>
<Traveler>
<Name>XYZ</Name>
</Traveler>
</Travelers>
</Response>
...the wanted result is produced:
<Root>
<Person>
<PId>1</PId>
<Name>ABC</Name>
</Person>
<Person>
<PId>2</PId>
<Name>XYZ</Name>
</Person>
</Root>

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes" />
<xsl:template match="Response">
<Root>
<xsl:for-each select="Travelers/Traveler">
<Person>
<xsl:variable name="index" select="position()" />
<Pid><xsl:value-of select="//Pax[$index]/Id"/></Pid>
<Name><xsl:value-of select="Name"/></Name>
</Person>
</xsl:for-each>
</Root>
</xsl:template>
</xsl:stylesheet>

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml"/>
<xsl:template match="/Response">
<Root>
<xsl:for-each select="Pax">
<xsl:variable name="pos" select="position()"/>
<Person>
<PId>
<xsl:value-of select="Id"/>
</PId>
<xsl:apply-templates select="//Travelers">
<xsl:with-param name="pos" select="$pos"/>
</xsl:apply-templates>
</Person>
</xsl:for-each>
</Root>
</xsl:template>
<xsl:template match="Travelers">
<xsl:param name="pos"/>
<xsl:for-each select="//Name">
<xsl:if test="position()=$pos">
<xsl:copy-of select="."/>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

can template match process params whose value is xml tag

The XSL below will extract "The Role of Magnetic Focus". but now i have to modify the xsl such that the input tags has to be passed as args.
Input XML:
<w:document>
<w:body>
<w:p>
<w:pPr>
<w:pStyle w:val="articletitle"/>
</w:pPr>
<w:r>
<w:t>The Role of Magnetic Focus</w:t>
</w:r>
</w:p>
<w:p>
<w:pPr>
<w:pStyle w:val="paragraph"/>
</w:pPr>
<w:r>
<w:t>All is well</w:t>
</w:r>
</w:p>
</w:body>
</w:document>
XSL:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ve="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships" xmlns:m="http://schemas.openxmlformats.org/officeDocument/2006/math" xmlns:v="urn:schemas-microsoft-com:vml" xmlns:wp="http://schemas.openxmlformats.org/drawingml/2006/wordprocessingDrawing" xmlns:w10="urn:schemas-microsoft-com:office:word" xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main" xmlns:wne="http://schemas.microsoft.com/office/word/2006/wordml"
>
<xsl:output method="text"/>
<xsl:template match="w:p"/>
<xsl:template match="w:p[w:pPr/w:pStyle/#w:val[matches(., concat('^(articletitle)$'),'i')]]">
<xsl:value-of select="."/><xsl:text>
</xsl:text>
</xsl:template>
</xsl:stylesheet>
I modified the above xsl as below, but i am not able to obtain the required output
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ve="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships" xmlns:m="http://schemas.openxmlformats.org/officeDocument/2006/math" xmlns:v="urn:schemas-microsoft-com:vml" xmlns:wp="http://schemas.openxmlformats.org/drawingml/2006/wordprocessingDrawing" xmlns:w10="urn:schemas-microsoft-com:office:word" xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main" xmlns:wne="http://schemas.microsoft.com/office/word/2006/wordml"
>
<xsl:param name="styleName" select="articletitle"/>
<xsl:param name="para" select="w:p"/>
<xsl:param name="parastyle" select="w:pPr/w:pStyle/#w:val"/>
<xsl:output method="text"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
<xsl:choose>
<xsl:when test="name() = $para">
<xsl:message><xsl:value-of select="name()"/></xsl:message>
<xsl:value-of select="name()"/>
</xsl:when>
</xsl:choose>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Please help.....

Just change:
<xsl:param name="para" select="w:p"/>
to:
<xsl:param name="para" select="'w:p'"/>