XSLT get Node by Index - xslt-1.0

Question

i am beginner in XSLT and i am using it to transform XML to XML
This is the source XML i receive
Source XML:
<Response>
<Pax>
<Id>1</Id>
</Pax>
<Pax>
<Id>2</Id>
</Pax>
<Travelers>
<Traveler>
<Name>ABC</Name>
</Traveler>
<Traveler>
<Name>XYZ</Name>
</Traveler>
</Travelers>
</Response>
I have written below XSLT
XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="xml" indent="yes" />
<xsl:template match="Response">
<xsl:element name="Root">
<xsl:apply-templates select="Travelers/Traveler"/>
</xsl:element>
</xsl:template>
<xsl:template match="Traveler">
<xsl:element name="Person">
<xsl:element name="PId">
<xsl:value-of select="//Pax/Id[position()]" />
</xsl:element>
<xsl:element name="Name">
<xsl:value-of select="Name" />
</xsl:element>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Output:
<Root>
<Person>
<PId>1</PId>
<Name>ABC</Name>
</Person>
<Person>
<PId>1</PId>
<Name>XYZ</Name>
</Person>
</Root>
I would like to generate below XML output
Expected Output:
<Root>
<Person>
<PId>1</PId>
<Name>ABC</Name>
</Person>
<Person>
<PId>2</PId>
<Name>XYZ</Name>
</Person>
</Root>
As shown in above XML the only issue is with PId, it should have value 2.
Please help. Thanks.

Answer 1

Here's a relatively simple solution.
When this XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output omit-xml-declaration="yes" indent="yes" />
<xsl:strip-space elements="*" />
<xsl:template match="/*">
<Root>
<xsl:apply-templates select="Pax" />
</Root>
</xsl:template>
<xsl:template match="Pax">
<xsl:variable name="vPosition" select="position()" />
<Person>
<PId>
<xsl:value-of select="Id" />
</PId>
<Name>
<xsl:value-of select="/*/Travelers/*[$vPosition]/Name" />
</Name>
</Person>
</xsl:template>
</xsl:stylesheet>
...is applied to the original XML:
<Response>
<Pax>
<Id>1</Id>
</Pax>
<Pax>
<Id>2</Id>
</Pax>
<Travelers>
<Traveler>
<Name>ABC</Name>
</Traveler>
<Traveler>
<Name>XYZ</Name>
</Traveler>
</Travelers>
</Response>
...the wanted result is produced:
<Root>
<Person>
<PId>1</PId>
<Name>ABC</Name>
</Person>
<Person>
<PId>2</PId>
<Name>XYZ</Name>
</Person>
</Root>

Answer 2

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes" />
<xsl:template match="Response">
<Root>
<xsl:for-each select="Travelers/Traveler">
<Person>
<xsl:variable name="index" select="position()" />
<Pid><xsl:value-of select="//Pax[$index]/Id"/></Pid>
<Name><xsl:value-of select="Name"/></Name>
</Person>
</xsl:for-each>
</Root>
</xsl:template>
</xsl:stylesheet>

Answer 3

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml"/>
<xsl:template match="/Response">
<Root>
<xsl:for-each select="Pax">
<xsl:variable name="pos" select="position()"/>
<Person>
<PId>
<xsl:value-of select="Id"/>
</PId>
<xsl:apply-templates select="//Travelers">
<xsl:with-param name="pos" select="$pos"/>
</xsl:apply-templates>
</Person>
</xsl:for-each>
</Root>
</xsl:template>
<xsl:template match="Travelers">
<xsl:param name="pos"/>
<xsl:for-each select="//Name">
<xsl:if test="position()=$pos">
<xsl:copy-of select="."/>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>